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8/17/2019 Elastic Theory Method
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REINFORCED CONCRETE BEAM DESIGNElastic Theory Method
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The term plain concrete is used to describeany concrete mass used without anystrengthening materials. The physical
to stone and include the ability to withstandgreat pressure. Concrete is a combinationconstruction material made of cement, ash,
gravel, limestone, and granite. Some types of concrete include sand, chemical mixtures,and water.
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A composite material that combines concretewith steel reinforcements
The combination of these materials provide a strong durable building material that could
cater both compressive and tensile strength.
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ADVANTAGES DISADVANTAGES
1. Ability to be casted 1. Low Tensile Strength
2. Economical 2. Low Ductility
3. Durable 3. Volume Instability
4. Fire Resistance 4. Low strength-weight ration
5. Energy Efficient
6. On site Fabrication
7. Aesthetic Properties
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Number of bars
Diameter
(mm) 1 2 3 4 5 6 7 8 9
6
8
28
50
57
101
85
151
113
201
142
252
170
302
198
352
226
402
255
453
12
16
20
25
32
40
113
201
314
491
804
1257
226
402
628
983
1608
2513
339
603
942
1474
2412
3770
452
804
1256
1966
3216
5027
565
1005
1570
2457
4020
6283
678
1206
1884
2946
4824
5740
791
1407
2198
3439
5628
8796
904
1608
2512
3932
6432
10053
1017
1809
2826
4423
7236
11310
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Plain sections through the beam beforebending remain plain after bending.
The concrete above the neutral axis carries all
the compression The tensile steel carries all the tension The concrete shrinks in and thus grips the
steel bars firmly so that there is no slipbetween the steel and surrounding concrete.
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Design of reinforced concrete structures started in thebeginning of this century following purely empiricalapproach.
Thereafter came the so called rigorous elastic theory where
t s assume t at concrete s e ast c an re n orc ng steebars and concrete act together elastically.
The load-deflection relation is linear and both concrete andsteel obey Hooke’s law.
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The method is designated as working stress method as theloads for the design of structures are the service loads or theworking loads.
The failure of the structure will occur at a much higher load.
e rat o o t e a ure oa s to t e wor ng oa s s t efactor of safety.
Accordingly, the stresses of concrete and steel in a structuredesigned by the working stress method are not allowed toexceed some specified values of stresses known as
permissible stresses.
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The permissible stresses are determined dividing thecharacteristic strength (fcu) of the material by therespective factor of safety.
The values of the factor of safet de end on the rade of the material and the type of stress. Thus, forconcrete in bending compression, the permissiblestress of grade M 20 is 7 N/mm2 , which is obtained bydividing the characteristic strength (fcu) of M 20concrete by a number 3 and then rationalising the
value to 7.
This permissible stress is designated by(Pcb @ Pst).
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In the elastic theory, structures having different materials aremade equivalent to one common material. In the reinforcedconcrete structure, concrete and reinforcing steel are,therefore, converted into one material.
This is done by transformation using the modular ratio mwhich is the ratio of modulus of elasticity of steel andconcrete. Thus, m = Es/Ec. where Es is the modulus of elasticity of steel which is 200000 N/mm2 .
However, concrete has different modulus, as it is not aperfectly elastic material.
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N=? j= ? R=?
P= percentage of steel d1 =Effective depth Ast = Area of steel
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n = The distance
from the top face of
the beam to the NA
which indicates the
depth of concrete in
compression in a
beam is denoted by
d n
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Referring to table,
515.205mm²
Number of bars
Diameter
(mm) 1 2 3 4 5 6 7 8 9
6 28 57 85 113 142 170 198 226 255
10
12
16
20
25
32
40
79
113
201
314
491
804
1257
157
226
402
628
983
1608
2513
236
339
603
942
1474
2412
3770
314
452
804
1256
1966
3216
5027
393
565
1005
1570
2457
4020
6283
471
678
1206
1884
2946
4824
5740
550
791
1407
2198
3439
5628
8796
628
904
1608
2512
3932
6432
10053
707
1017
1809
2826
4423
7236
11310
Use 5nos Y12 (565mm2 )
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.
d = d1 + 1/2øBar + cd = 321mm + ½ (12mm) +25mm
= 352.5mm @ 355 mm
Spacing
150– [ (12 x 3) + (25 x 2)] = 32
2
= 32 ≥ 10 mm
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A simple supported beam is to span 3.6m carrying a uniformload of 60 KN inclusive of self weight. The beam is to be 150mm wide and the stresses in steel and concrete respectivelyare to be 140 N/mm² and 10N/mm² (m=15)
eterm ne t e constant n , , an an c oose a su ta eeffective depth, overall depth and area of steel of the beam.
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