EdExcel a Level Chemistry Unit 9 Mark Scheme Jan 2000

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  • 8/16/2019 EdExcel a Level Chemistry Unit 9 Mark Scheme Jan 2000

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    Winter 2000 CH4 Mark Scheme

    1

    1.  (a) C 69.8 / 12 = 5.8 / 1.16 5

    H 11.6 / 1 = 11.6 1 / 1.16 10

    O 18.6 / 16 = 1.16 / 1.16 1 

    EF is C5H10O(1)  2

    (b) (i) amount NaOH = 0.0374dm3 × 0.211moldm–3  (1) 

    = 7.89 × 10–3 mol

    amount of W = 7.89 × 10–3 mol(1) 

    Mr  = 1.36 g = 172 (gmol–1)(1) 

    7.89×10–3 molNote: can get 3 marks for correct calculation which

    ‘assumes’ second mark. 3

    (ii) Emp formula mass = 86 thus MF is Cl0H20O2(1) 

    (some reasoning needed for this mark) 1

    (iii) C9H19COOC2H5 + NaOH ➤   C9H19COONa + C2H5OH (2) 

    correct ester formula (1) balanced equation (1) or ionic equation

    Note: max (1) if added up formulae used or wrong ester formula

    or RCOOC2H5  2

    [8]

    2.  (a) Correct arrows involving C=C and H–Br(1) Correct intermediate with positive charge(1) 

    Correct arrow from Br– towards carbon atom (1) 

    C CCH CH CH CHBrCHH H

    H HH H

    H

    C C3 3 3 3

    :Br–

    H Br   3

    Note: if product is 1-bromo product max 2 for full correct mechanism.

    (b) (i)  Reagent : magnesium(1)

    dry ethoxyethane / ether(1)

    iodine catalyst / warm under reflux (or at room temperature)(1)  3

    (ii)  Reagent : aqueous or dilute sodium hydroxide(1) 

    Conditions: boil / heat under reflux(1)  2

    (c)  Reagent : carbon dioxide (solid)(1) 

     Reagent second stage: water or dilute named acid (1)

    Note: a route using methanal followed by oxidation can score (2) marks 2

    (d)

    CCH

    CH

    CHCH

    H

    O

    C C HO3

    3

    33  (2)

      2

    Note: if one branched and one straight chain on correct ester linkage (1) [12]

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  • 8/16/2019 EdExcel a Level Chemistry Unit 9 Mark Scheme Jan 2000

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    Winter 2000 CH4 Mark Scheme

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    3. (a) NN C

    HH O

    C

    O

    n

     

    Correct structure if linkage (1)

    Some evidence of continuation of molecule (1)  2

    (b) Peak at A : C=O (1)

    Peak at B :  C– O (1)

    Spectrum is that of benzene – 1,4- dicarboxylic acid (1)  3

    (c) (i) To prevent the volatile reactant / dimethyl benzene boiling off  (1)

    (ii) Because the diacid is soluble in hot water (1) 

    (iii) M.Pt not sharpor different from / not consistent with / less than data book  (1)  3

    (d) (i)

    C C

    F FH HF FH H

    F FH HF FH H

    C CC CC C

    n n

    or 

    (or H...F...F...H on chain)

    Correct repeating structure (1)

    Some evidence of continuation of molecule (1)  2

    (ii) Kevlar : condensation(1) 

    PDFE : addition (1)  2

    (e) (i) more carbon dioxide per kJ of energy (1)

    therefore more global warming/ more greenhouse gas produced (1)  2

    (ii) Some reference to need for special arrangements for filling tank /dangerous in the event of a crash /more weight as gas tank

    weighs more than petrol tank / more likely to leak because gas

    under pressure (1)  1[15]

    4.  (a) (i)

    CH CHCl CH OH

    CH CH(OH) COO Na

    CH CHCl COOH

    COOH

    COOH

    3

    3

    32

    +–

    A

    C

    B

    D

      4 × 1 = 4

    B consequential on A

    C consequential on B

    (ii) 2-chloropropan-1-ol (mark consequentially) 1

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  • 8/16/2019 EdExcel a Level Chemistry Unit 9 Mark Scheme Jan 2000

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    Winter 2000 CH4 Mark Scheme

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    (b)C H COCl C H CONH C H CN C H CH NH5 5 5 522 2 2 2 2 2

    NH P O Na/C H OH3 5 5

    4

    2 2

    or LiAlH

    (1) (1) (1) (1) (1)  

    or

    C H COCl C H COOH C H CH OH C H CH Br

    C H CH NH

    5 5 5 5

    5

    2 2

    2 2

    3

    2 2 2 2

    2

    H O LiAlH KBr/concH SO2   4   42

    (1)

    (1)

    (1) (1)

    (1)NH

     5

    (c) (i)

    NH + NaNO + 2HCl N NCl + 2H O + NaCl22 2+ –

     

    1 for diazo cation + (1) for rest of equation 2

    (ii) if greater than 5♦ C X decomposes (1)

    if less than 0 ♦ C rate (of formation of X) is too slow (1)  2

    (iii) N N

    OH   (1)(1)

     for N=N link  for link to correct ring

    next to –OH  2

    [16]

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