EC20075Q

8132019 EC20075Q

httpslidepdfcomreaderfullec20075q 122

Correspondence Programme Classroom Programme All India Mock Test Series Postal Test Series Online Test Series Online Classroom Prog

Head Office A114-115 Bhilai ndash 490 020 (CG) For Details Contact 0788-4034176 +91-97131-13156 +91-93026-97686

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For Details Contact +91-97138-85449 +91-99169-39408

EEEElectronics amp Communication 20lectronics amp Communication 20lectronics amp Communication 20lectronics amp Communication 2007070707

983121983086983089 983156983151 983121983086983090983093 983139983137983154983154983161 983151983150983141 983149983137983154983147 983141983137983139983144

Q1 If E denotes expectation the variance of a random variable X is given by

(A) [ ]2 2 E X E X minus (B) [ ]2 2

E X E X + (C) 2 E X (D) [ ]2

E X

Q2 The following plot shows a function y which varies linearly with x The value of the integral

2

1

I y dx= int

(A) 10 (B) 25 (C) 40 (D) 50

Q3 For 1|| ltlt x coth ( x) can be approximated as

(A) x (B)2

x (C)1

x

(D)2

1

x

Q4 0

sin( 2)limθrarr

θ

θ is

(A) 05 (B) 1 (C) 2 (D) not defined

Q5 Which one of the following function is strictly bounded

(A)2

1

x (B)

xe (C)2 x (D)

2 xeminus

Q6 For the function xeminus

the linear approximation around x = 2 is

(A)2(3 ) x eminusminus (B) 1 xminus

(C) 2])21(223[ minus+minus+ e x (D)2minuse

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983109983107 991251 983090983088983088983095 wwwgateacademycoin



Branch Office Bangalore (Karnataka) For Details Contact +91-97138-85449 +91-99169-39408

Q7 An independent voltage source in series with an impedance s S s Z R jX = + delivers a maximum average

power to a load impedance L Z when

(A) L s s Z R jX = + (B) L s Z R= (C) L s Z jX = (D) L s s Z R jX = minus

Q8 The RC circuit shown in the figure is

(A) A low-pass filter (B) A high-pass filter

(C) A band-pass filter (D) A band-reject filter

Q9 The electron and hole concentration in an intrinsic semiconductor are in per3cm at 300 K Now if

acceptor impurities are introduced with a concentration of 983105983118 per983091983139983149 (Where 983105983118 gtgt in ) the electron

concentration per983091983139983149 at 300 K will be

(A) in (B) A+ Ni

n (C)A

Ninminus (D)

2

AN

in

Q10 In a n p+ junction diode under reverse bias the magnitude of electric field is maximum at

(A) the edge of the depletion region on the p-side

(B) the edge of the depletion region on the n-side

(C) the n p+

junction

(D) the centre of the depletion region on the n-side

Q11 The correct full wave rectifier circuit is

8132019 EC20075Q






(A) (B)

(C) (D)

Q12 In a transconductance amplifier it is desirable to have

(A) a large input resistance and a large output resistance

(B) a large input resistance and a small output resistance

(C) a small input resistance and a large output resistance

(D) a small input resistance and a small output resistance

Q13 X = 01110 and Y = 11001 are two 5-bit binary numbers represented in tworsquos complement format Thesum of X and Y represented in tworsquos complement format using 6 bits is

(A) 100111 (B) 001000 (C) 000111 (D) 101001

Q14 The Boolean function Y = AB + CD is to be realized using only 2ndashinput NAND gates The minimum

number of gates required is

(A) 2 (B) 3 (C) 4 (D) 5

Q15 If the closed-loop transfer function of a control system is given as

983155 983093983124983080983155983081983080983155 983083 983090983081983080983155 983083 983091983081

minus= then it is

(A) an unstable system (B) an uncontrollable system

(C) a minimum phase system (D) a non-minimum phase system

8132019 EC20075Q






Q16 If the Laplace transform of a signal y(t ) iss

983089983129983080983155983081

983080983155 983089983081=

minus then its final value is

(A) 1minus (B) 0 (C) 1 (D) Unbounded

Q17 If )(τ R is the autocorrelation function of a real wide-sence stationary random process then which of the

following is NOT true

(A) ( ) ( ) R R= minusτ τ (B) | ( ) | (0) R Rleτ

(C) )()( τ τ minusminus= R R (D) The mean square value of the process is R(0)

Q18 If )( f S is the power spectral density of a real wide-sense stationary random process then which of the

following is ALWAYS true

(A) (0) ( )S S f ge (B) 0)( ge f S (C) )()( f S f S minus=minus (D) intinfin

infinminus

= 0)( df f S

Q19 A plane wave of wavelength λ is traveling in a direction making an angleo30 with positive x-axis and

o90 with positive y-axis The E

field of the plane wave can be represented as ( 0 E is constant)

(A)

3

0

j t x z

E y E e

minus minus

=

π π ω

λ λ (B)

3

0ˆ

j t x z

E y E e

minus minus

=

π π ω

λ λ

(C)

3

0ˆ

j t x z

E y E e

+ +

=

π π ω

λ λ (D)

3

0ˆ

j t x z

E y E e

minus +

=

π π ω

λ λ

Q20 If C is a closed curve enclosing a surface S then the magnetic field intensity H the current density j

and the electric flux density D

are related by

(A) S C

D H d s J d l

t

part= +

part int int int

(B) S S

D H d t J d d s

t

part= +

part int intint

(C) S C

D H d s J d l

t

part= +

part intint int

(D) C S

D H d t J d s

t

part= +

part int intint

Q21 to Q75 carry two marks each

Q21 It is given that M X X X 21 are M non-zero orthogonal vectors The dimension of the vector space

spanned by the 2M vectors 21 M X X X M X X 2minus is

(A) 2 M (B) M + 1

(C) M (D) Dependent on the choice of M X X X 21

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Q22 Consider the function 2)( 2 minusminus= x x x f The maximum value of )( x f in the closed interval [- 4 4] is

(A) 18 (B) 10 (C) - 225 (D) Indeterminate

Q23 An examination consists of two papers Paper 1 and Paper 2 The probability of failing in Paper 1 is 03

and that in Paper 2 is 02 Given that a student has failed in Paper 2 the probability of failing in Paper 1 is06 The probability of a student failing in both the papers is

(A) 05 (B) 018 (C) 012 (D) 006

Q24 The solution of the differential equation22

22

y ydx

yd k minus= under the boundary conditions

(i) 1 y y = at 0= x and

(ii) 2 y y = at infin= x where k 1 y and 2 y are constants is

(A) 2

2

21 ) exp()( yk x y y y +minusminus= (B) 121 ) exp()( yk x y y y +minusminus=

(C) 1 2 1( )sin ( ) y y y h x k y= minus + (D) 221 ) exp()( yk x y y y +minusminus=

Q25 The equation 04423 =minus+minus x x x is to be solved using the Newton-Raphson method If x = 2 is taken as

the initial approximation of the solution then the next approximation using this method will be

(A)3

2 (B)

3

4 (C) 1 (D)

2

3

Q26 Three functions )()( 21 t f t f and )(3 t f which are zero outside the interval [0 T] are shown in the figureWhich of the following statements is correct

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(A) )(1 t f and )(2 t f are orthogonal (B) )(1 t f and )(3 t f are orthogonal

(C) )(2 t f and )(3 t f are orthogonal (D) )(1 t f and )(2 t f are orthonormal

Q27 If the semi-circular contour D of radius of radius 2 is as shown in the figure then the value of the integral

2

1

( 1) D

dss minusint is

(A) jx (B) π jminus (C) π minus (D) π

Q28 Two series resonant filters are as shown in the figure Let the 3-dB bandwidth of Filter 1 be 1 B and that of

filter 2 be 2 B The value of2

1

B

B is

(A) 4 (B) 1 (C)2

1 (D)

4

1

Q29 For the circuit shown in the figure the Thevenin voltage and resistance looking into X ndash Y are

(A)4

V 23

Ω (B)2

4V3

Ω (C)4 2

V3 3

Ω (D) 4V 2Ω

8132019 EC20075Q






Q30 In the circuit shown C V is 0 volts at t = 0 sec For t gt 0 the capacitor current )(t ic where t is in seconds

is given by

(A) 050 exp ( minus 25t) mA (B) 025 exp ( minus 25t) mA

(C) 050 exp ( minus 125t) mA (D) 025 exp( minus 625t) mA

Q31 In the AC network shown in the figure the phasor voltage ABV (in volts) is

(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang

Q32 A p n+ junction has a built-in potential of 08 V The depletion layer width at a reverse bias of 12 V is

2microm For a reverse bias of 72 V The depletion layer width will be

(A) 4microm (B) 49microm (C) 8microm (D) 12microm

Q33 Group I lists four types of p ndash n junction diodes Match each device in Group I with one of the option inGroup II to indicate the bias condition of that device in its normal mode of operation

Group I Group II

(P) Zener Diode (1) Forward bias

(Q) Solar cell (2) Reverse bias

(R) LASER diode

(S) Avalanche photodiode

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(A) P ndash 1 Q ndash 2 R ndash 1 S ndash 2 (B) P ndash 2 Q ndash 1 R ndash 1 S ndash 2

(B) P ndash 2 Q ndash 2 R ndash 1 S ndash 1 (D) P ndash 2 Q ndash 1 R ndash 2 S ndash 2

Q34 The DC current gain (β ) of a BJT is 50 Assuming that the emitter injection efficiency is 0955 the base

transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995

Q35 Group I lists four different semiconductor devices Match each device in Group I with its characteristic

property in Group II

Group I Group II

(P) BJT (1) Population inversion

(Q) MOS Capacitor (2) Pinch-off voltage

(R) LASER diode (3) Early effect

(S) JFET (4) Flat-band voltage


(C) P ndash 3 Q ndash 4 R ndash 1 S ndash 2 (D) P ndash 3 Q ndash 2 R ndash 1 S ndash 4

Q36 For the Op-Amp circuit shown in the figure 0V is

(A) minus 2 V (B) minus 1 V (C) minus 05 V (D) 05 V

Q37 For the BJT circuit shown assume that the β of the transistor is very large and 70 V V BE = The mode of

operation of the BJT is

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8132019 EC20075Q


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(A) CBACBACBACBAX +++= (B) CBACBACBACBAX +++=

(C) ACBCABX ++= (D) CACBBAX ++=

Q44 The following binary values were applied to the X and Y inputs of the NAND latch shown in the figure in

the sequence indicated below

X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =

The corresponding stable P Q outputs will be

(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======

Q45 For the circuit shown the counter state )( 01QQ follows the sequence

(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

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(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip

Q46 An 8255 chip is interfaced to an 8085 microprocessor system as an IO mapped IO as shown in the figure

The address lines 0A and 1A of the 8085 are used by the 8255 chip to decode internally its three ports and

the Control register The address lines 3A to 7A as well as the MIO signal are used for address

decoding The range of addresses for which the 8255 chip would get selected is

(A) F8H ndash FBH (B) F8H ndash FCH (C) F8H ndash FFH (D) F0H ndash F7H

Q47 The 3ndashdB bandwidth of the low-pass signal )(e-t t u where )(t u is the unit step function is given by

(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz

Q48 A Hilbert transformer is a

(A) non-linear system (B) non-causal system

(C) time-varying system (D) low-pass system

Q49 The frequency response of a linear time-invariant system is given by5

H ( )1 10

f j f

=+ π

The step

response of the system is

(A)5

5(1 ) ( )t e u t minusminus (B) 55 1 ( )t

e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus

Q50 A 5-point sequence ][n x is given as

1]3[ =minus x 1]2[ =minus x 0]1[ =minus x 1]1[5]0[ == x x

Let )( ω je X denote the discrete-time Fourier transform of ][n x The value of ω π

π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

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(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +

Q57 The state space representation of a separately excited DC servo motor dynamics is given as

1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω

where ω is the speed of the motor ai is the armature current and u is the armature voltage The transfer

functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +

Q58 In delta modulation the slope overload distortion can be reduced by

(A) decreasing the step size (B) decreasing the granular noise

(C) decreasing the sampling rate (D) increasing the step size

Q59 The raised cosine pulse p(t ) is used for zero ISI in digital communications The expression for p(t ) with

unity roll-off factor is given by2 2

sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =

minus The value of p(t ) at

W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin

Q60 In the following scheme if the spectrum M(f) of m(t) is as shown then the spectrum Y( f ) of y(t ) will be

8132019 EC20075Q






Q61 During transmission over a certain binary communication channel bit errors occur independently with

probability p The probability of AT MOST one bit in error in a block of n bits is given by

(A)n p (B)

n pminus1

(C)nn

p pnp )1()1( 1 minus+minus minus (D)

n p)1(1 minusminus

Q62 In a GSM system 8 channels can co-exist in 200 kHz bandwidth using TDMA A GSM based cellular

operator is allocated 5 MHz bandwidth Assuming a frequency reuse factor of 5

1 ie a five-cell repeat

pattern the maximum number of simultaneous channels that can exist in one cell is

(A) 200 (B) 40 (C) 25 (D) 5

Q63 In a Direct Sequence CDMA system the chip rate is6

1022881 times chips per second If the processing gain

is desired to be AT LEAST 100 the date rate

(A) must be less than or equal to31028812 times bits per sec

(B) must be greater than3

1028812 times bits per sec

8132019 EC20075Q






(C) must be exactly equal to31028812 times bits per sec

(D) can take any value less than3


Q64 An air-filled rectangular waveguide has inner dimensions of 983091983139983149983255 983090983139983149983086 The wave impedance of the 983090983088983124983109

mode of propagation in the waveguide at a frequency of 30 GHz is (free space impedance0 377η = Ω )

(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H

field (in Am) of a plane wave propagating in free space is given by

0 0

5 3 5ˆ ˆcos ( ) sin

2 H x t z y t z

π = ω minus β + ω minus β +

η η

The time average power flow density in Watts is

(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E

field in a rectangular waveguide of inner dimensions a x b is given by

02

2ˆsin sin( )

x E H t z y

h a a

ωmicro π π = ω minus β

Where 0 H is a constant and a and b are the dimensions along the x-axis and the y-axis respectively The

mode of propagation in the waveguide is

(A) 20TE (B) 11TM (C) 20TM (D) 10TE

Q67 A load of 50Ω is connected in shunt in a 2-wire transmission line of 0 50 Z = Ω as shown in the figure

The 2-port scattering parameter matrix (S-matrix) of the shunt element is

(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q






Q68 The parallel branches of a 2-wire transmission line are terminated in 100Ω AND 200Ω resistors as

shown in the figure The characteristic impedance of the line is 0 50 Z = Ω and each section has a length of

4

λ The voltage reflection coefficient Γ at the input is

(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2

λ dipole is kept horizontally at a height of

2

0λ above a perfectly conducting infinite ground plane The

radiation pattern in the plane of the dipole E

( plane) looks approximately as

(A) (B)

(C) (D)

Q70 A right circularly polarized (RCP) plane wave is incident at an angle of0

60 to the normal on an air-

dielectric interface If the reflected wave is linearly polarized the relative dielectric constant 2r ε is

500

Z

4

4

500

Z

500

Z

4

100

200

RCPLinearly polarized

060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3

Common Data Question 71 72 amp 73

The figure shows the high-frequency capacitance-voltage (C - V) characteristics of a Metal 2SiO silicon

(MOS) capacitor having an area of4 2

1 10 cmminustimes Assume that the permittivities 0 r( )ε ε of silicon and 2SiO

are-12

1 10 Fcmtimes and-13

35 10 Fcmtimes respectively

Q71 The gate oxide thickness in the MOS capacitor is

(A) 50 nm (B) 143 nm (C) 350 nm (D) microm1

Q72 The maximum depletion layer width in silicon is

(A) microm1430 (B) microm8570 (C) 1microm (D) microm1431

Q73 Consider the following statements about the C ndash V characteristics plot

S1 The MOS Capacitor has an n ndash type substrate

S2 If positive charges are introduced in the oxide the C ndash V plot will shift to the left

Then which of the following is true

(A) Both S1 and S2 are true (B) S1 is true and S2 is false

(C) S1 is false and S2 is true (D) Both S1 and S2 are false

Common Data Question 74 amp 75

Two 4-ray signal constellations are shown It is given that 1φ and 2φ constitute an orthonormal basis for

the two constellations Assume that the four symbols in both the constellations are equiprobable Let 0N

2denote the power spectral density of white Gaussian noise

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Q74 The ratio of the average energy of constellation 1 to the average energy of Constellation 2 is

(A)24a (B) 4 (C) 2 (D) 8

Q75 If these constellations are used for digital communications over an AWGN channel then which of thefollowing statements is true

(A) Probability of symbol error for Constellation 1 is lower

(B) Probability of symbol error for constellation 1 is higher

(C) Probability of symbol error is equal for both the constellations

(D) The value of 0N will determine which of the two constellations has a lower probability of symbol

error

Statement for Linked Answer Questions 76 amp 77

Consider the Op-Amp circuit shown in the figure

Q76 The transfer function 0( ) ( )t V s V s is

(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +

Q77 If 1 sin( )iV V t = ω and 0 2 sin( )V V t = ω + φ then the minimum and maximum values of φ (in radians) are

respectively

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(A) and2 2

minusπ π (B) 0 and

2

π (C) and 0minusπ (D) and 0

2

minusπ


AN 8085 assembly language program is given below

Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT

Q78 The contents of the accumulator just after execution of the ADD instruction in line 4 will be

(A) C3H (B) EAH (C) DCH (D) 69H

Q79 After execution of line 7 of the program the status of the CY and Z flags will be

(A) CY = 0 Z = 0 (B) CY = 0 Z = 1 (C) CY = 1 Z = 0 (D) CY = 1 Z = 1


Consider a linear system whose state space representation is )()( t Axt x = If the initial state vector of the

system is

minus=

2

1)0( x then the system response is

minus=

minus

minus

t

t

e

et x

2

2

2)( If the initial state vector of the system

changes to

minus=

1

1)0( x then the system response becomes

minus=

minus

minus

t

t

e

et x )(

Q80 The eigenvalue and eigenvector pairs )( ii vλ for the system are

(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2

minus minus minus minus

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(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12

Q81 The system matrix A is

(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10


An input to a 6-level quantizer has the probability density function )( x f as shown in the figure Decisiion

boundaries of the quantizer are chosen so as t maximize the entropy of the quantizer output It is given that3 consecutive decision boundaries are lsquo-1rsquo lsquo0rsquo and lsquo1rsquo

Q82 The value of a and b are

(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba

Q83 Assuming that the reconstruction levels of the quantizer are the mid-points of the decision boundaries the

ratio of signal power to quantization noise power is

(A)9

152 (B)

3

64 (C)

3

76 (D) 28

Statement For Linked Answer Questions 84 amp 85

In the Digital-to-Analog converter circuit shown in the figure below 10VVR = and R 10 k = Ω

Q84 The current i is

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C d P Cl P All I di M k T t S i P t l T t S i O li T t S i O li Cl P

(A) 3125 Amicro (B) 625 Amicro (C) 125 Amicro (D) 250 Amicro

Q85 The voltage 0V is

(A) 0781 Vminus (B) 1562 Vminus (C) 3125 Vminus (D) 6250 Vminus

END OF THE QUESTION PAPER

8132019 EC20075Q






Q7 An independent voltage source in series with an impedance s S s Z R jX = + delivers a maximum average

power to a load impedance L Z when

(A) L s s Z R jX = + (B) L s Z R= (C) L s Z jX = (D) L s s Z R jX = minus

Q8 The RC circuit shown in the figure is

(A) A low-pass filter (B) A high-pass filter

(C) A band-pass filter (D) A band-reject filter

Q9 The electron and hole concentration in an intrinsic semiconductor are in per3cm at 300 K Now if

acceptor impurities are introduced with a concentration of 983105983118 per983091983139983149 (Where 983105983118 gtgt in ) the electron

concentration per983091983139983149 at 300 K will be

(A) in (B) A+ Ni

n (C)A

Ninminus (D)

2

AN

in

Q10 In a n p+ junction diode under reverse bias the magnitude of electric field is maximum at

(A) the edge of the depletion region on the p-side

(B) the edge of the depletion region on the n-side

(C) the n p+

junction

(D) the centre of the depletion region on the n-side

Q11 The correct full wave rectifier circuit is

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(A) (B)

(C) (D)







(A) 100111 (B) 001000 (C) 000111 (D) 101001



(A) 2 (B) 3 (C) 4 (D) 5


983155 983093983124983080983155983081983080983155 983083 983090983081983080983155 983083 983091983081

minus= then it is



8132019 EC20075Q







983089983129983080983155983081

983080983155 983089983081=










infinminus

= 0)( df f S




(A)

3

0

j t x z

E y E e

minus minus

=

π π ω

λ λ (B)

3

0ˆ

j t x z

E y E e

minus minus

=

π π ω

λ λ

(C)

3

0ˆ

j t x z

E y E e

+ +

=

π π ω

λ λ (D)

3

0ˆ

j t x z

E y E e

minus +

=

π π ω

λ λ



are related by

(A) S C

D H d s J d l

t

part= +

part int int int

(B) S S

D H d t J d d s

t

part= +

part int intint

(C) S C

D H d s J d l

t

part= +

part intint int

(D) C S

D H d t J d s

t

part= +

part int intint




(A) 2 M (B) M + 1


8132019 EC20075Q










(A) 05 (B) 018 (C) 012 (D) 006


22

y ydx


(i) 1 y y = at 0= x and


(A) 2

2





(A)3

2 (B)

3

4 (C) 1 (D)

2

3


8132019 EC20075Q









2

1

( 1) D

dss minusint is




1

B

B is

(A) 4 (B) 1 (C)2

1 (D)

4

1


(A)4

V 23

Ω (B)2

4V3

Ω (C)4 2

V3 3

Ω (D) 4V 2Ω

8132019 EC20075Q







is given by




(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang





Group I Group II



(R) LASER diode


8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q






(A) (B)

(C) (D)







(A) 100111 (B) 001000 (C) 000111 (D) 101001



(A) 2 (B) 3 (C) 4 (D) 5


983155 983093983124983080983155983081983080983155 983083 983090983081983080983155 983083 983091983081

minus= then it is



8132019 EC20075Q







983089983129983080983155983081

983080983155 983089983081=










infinminus

= 0)( df f S




(A)

3

0

j t x z

E y E e

minus minus

=

π π ω

λ λ (B)

3

0ˆ

j t x z

E y E e

minus minus

=

π π ω

λ λ

(C)

3

0ˆ

j t x z

E y E e

+ +

=

π π ω

λ λ (D)

3

0ˆ

j t x z

E y E e

minus +

=

π π ω

λ λ



are related by

(A) S C

D H d s J d l

t

part= +

part int int int

(B) S S

D H d t J d d s

t

part= +

part int intint

(C) S C

D H d s J d l

t

part= +

part intint int

(D) C S

D H d t J d s

t

part= +

part int intint




(A) 2 M (B) M + 1


8132019 EC20075Q










(A) 05 (B) 018 (C) 012 (D) 006


22

y ydx


(i) 1 y y = at 0= x and


(A) 2

2





(A)3

2 (B)

3

4 (C) 1 (D)

2

3


8132019 EC20075Q









2

1

( 1) D

dss minusint is




1

B

B is

(A) 4 (B) 1 (C)2

1 (D)

4

1


(A)4

V 23

Ω (B)2

4V3

Ω (C)4 2

V3 3

Ω (D) 4V 2Ω

8132019 EC20075Q







is given by




(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang





Group I Group II



(R) LASER diode


8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q







983089983129983080983155983081

983080983155 983089983081=










infinminus

= 0)( df f S




(A)

3

0

j t x z

E y E e

minus minus

=

π π ω

λ λ (B)

3

0ˆ

j t x z

E y E e

minus minus

=

π π ω

λ λ

(C)

3

0ˆ

j t x z

E y E e

+ +

=

π π ω

λ λ (D)

3

0ˆ

j t x z

E y E e

minus +

=

π π ω

λ λ



are related by

(A) S C

D H d s J d l

t

part= +

part int int int

(B) S S

D H d t J d d s

t

part= +

part int intint

(C) S C

D H d s J d l

t

part= +

part intint int

(D) C S

D H d t J d s

t

part= +

part int intint




(A) 2 M (B) M + 1


8132019 EC20075Q










(A) 05 (B) 018 (C) 012 (D) 006


22

y ydx


(i) 1 y y = at 0= x and


(A) 2

2





(A)3

2 (B)

3

4 (C) 1 (D)

2

3


8132019 EC20075Q









2

1

( 1) D

dss minusint is




1

B

B is

(A) 4 (B) 1 (C)2

1 (D)

4

1


(A)4

V 23

Ω (B)2

4V3

Ω (C)4 2

V3 3

Ω (D) 4V 2Ω

8132019 EC20075Q







is given by




(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang





Group I Group II



(R) LASER diode


8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q










(A) 05 (B) 018 (C) 012 (D) 006


22

y ydx


(i) 1 y y = at 0= x and


(A) 2

2





(A)3

2 (B)

3

4 (C) 1 (D)

2

3


8132019 EC20075Q









2

1

( 1) D

dss minusint is




1

B

B is

(A) 4 (B) 1 (C)2

1 (D)

4

1


(A)4

V 23

Ω (B)2

4V3

Ω (C)4 2

V3 3

Ω (D) 4V 2Ω

8132019 EC20075Q







is given by




(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang





Group I Group II



(R) LASER diode


8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q









2

1

( 1) D

dss minusint is




1

B

B is

(A) 4 (B) 1 (C)2

1 (D)

4

1


(A)4

V 23

Ω (B)2

4V3

Ω (C)4 2

V3 3

Ω (D) 4V 2Ω

8132019 EC20075Q







is given by




(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang





Group I Group II



(R) LASER diode


8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q







is given by




(A) 0 (B)o5 30ang (C)

o125 30ang (D)o17 30ang





Group I Group II



(R) LASER diode


8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q









transport factor is

(A) 0980 (B) 0985 (C) 0990 (D) 0995



Group I Group II











8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q


8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q


8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q










X 0 Y 1 X 0 Y 0 X 1 Y 1= = = = = =


(A) 1Q0Por0Q1P0Q1P0Q1P ========

(B) 1Q0P1Q0Por1Q0P0Q1P ========

(C) 1Q0Por0Q1P1Q1P0Q1P ========

(D) 1Q1P1Q1P0Q1P ======


(A) 00 01 10 11 00 hellip (B) 00 01 10 00 01 hellip

0I

1I

2I

3I

1S 0S

0

1

1

0

A B

4-to-1MUX Y

0I

1I

2I

3I

1S 0S

0

1

1

0

C

4-to-1MUX Y X

0 D 0

Q 1 D 1

Q

gt gt

Clock

8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q






(C) 00 01 11 00 01 hellip (D) 00 10 11 00 10 hellip







(A)1

Hz2π

(B)1

2 1 Hz2

minusπ

(C) infin (D) 1 Hz





H ( )1 10

f j f

=+ π

The step


(A)5


e u t minus

minus

(C) ( ) )(15

1 5t ue

t minusminus (D) 51

1 ( )5

t

e u t minus

minus




π

ω d e X

j

intminus

)( is

(A) 5 (B) π 10 (C) π 16 (D) π 105 j+

CS

1A

0A0A1A

7A

6A

5A

4A

3A

MIO

8255

8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q


8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q






(A)1

(s 1) (s 20)+ + (B)

1

s(s 1) (s 20)+ +

(C)100

s(s 1) (s 20)+ + (D)

100

s(s 1) (s 005s)+ +


1 1 0

1 10 10aa

d

dt u

idi

dt

minus

= + minus minus

ω ω


functionω(s)

U(s)

of the motor is

(A)2

10

11 11s s+ + (B)

2

1

11 11s s+ + (C)

2

10 10

11 11

s

s s

+

+ + (D)

2

1

11 11s s+ +






sin 4( )

4 (1 16 )

Wt p t

Wt w t

π

π =


W t

4

1= is

(A) - 05 (B) 0 (C) 05 (D) infin


8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q








(A)n p (B)

n pminus1

(C)nn


n p)1(1 minusminus





(A) 200 (B) 40 (C) 25 (D) 5







8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q











(A) 308 Ω (B) 355 Ω (C) 400 Ω (D) 461 Ω

Q65 The H


0 0


2 H x t z y t z


η η


(A)983088 η

983089983088983088 (B)

100

983088 η (C) 50 983090

983088 η (D)

50

983088 η

Q66 The E


02

2ˆsin sin( )

x E H t z y

h a a




(A) 20TE (B) 11TM (C) 20TM (D) 10TE



(A)

minus

minus

2

1

2

121

21

(B)

01

10 (C)

minus

minus

3

1

3

232

31

(D)

minus

minus

4

1

4

343

41

8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q








4


(A)5

7 jminus (B)

7

5minus (C)

7

5 j (D)

7

5

Q69 A2


2




(A) (B)

(C) (D)




500

Z

4

4

500

Z

500

Z

4

100

200


060 060

11 r

t

2r

Air

Dielectric

8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q






(A) 2 (B) 3 (C) 2 (D) 3





are-12

















8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q







(A)24a (B) 4 (C) 2 (D) 8






error




(A)1

1

sRC

sRC

minus

+ (B)

1

1

sRC

sRC

+

minus (C)

1

1 sRC minus (D)

1

1 sRC +


respectively

8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q






(A) and2 2


2


2

minusπ



Line 1 MVI A B5H

2 MVI B 0EH

3 XRI 69H

4 ADD B

5 ANI 9BH

6 CPI 9FH

7 STA 3010H

8 HLT







system is

minus=

2


minus=

minus

minus

t

t

e

et x

2

2


changes to

minus=

1


minus=

minus

minus

t

t

e

et x )(


(A)

minusminus

minusminus

2

12and

1

11 (B)

1 12 and 1

1 2


8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q






(C)1 1

1 and 21 2

minus minus minus

(D)

minus

minusminus

2

11and

1

12


(A)

minus 11

10

(B)

minusminus 21

11

(C)

minusminus 11

12

(D)

minusminus 32

10





(A)1 1

and6 12

= =a b (B)1 3

and5 40

= =a b

(C)1 1

and4 16

= =a b (D)24

1and

3

1== ba



(A)9

152 (B)

3

64 (C)

3

76 (D) 28




8132019 EC20075Q








8132019 EC20075Q








Documents

EC20075Q