EB09 Equation Solving

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    Equation Solving

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    Iterative Techniques for solving

    equations

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    There are situations when finding an exact

    solution to a given equation is not easy or

    sometimes not possible. For example,

    0xx sin

    x-0.75x-4.5x+4.75=0

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    For such equations we use iterative methods

    for finding approximate solutions.

    The methods discussed in this lecture are:

    1. Bisection Method

    2. Newton-Raphson Method

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    Theorem

    Let be a continuous function on such

    that then there exist a number

    such that .

    f ba, 0bfaf bac , 0cf

    a b

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    Newton Raphson Method

    1x2x3x

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    Step 1: Start with an initial guess, .

    Step 2: Calculate

    Step 3: Calculate

    and so on.

    The nth iteration is given by

    1x

    1

    1

    12

    xfxfxx

    2

    2

    23

    xf

    xfxx

    n

    n

    nnxf

    xfxx 1

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    The iterations should be done until we get the

    solution of desired accuracy.

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    While solving problems in business and

    finance we need to solve several type of

    mathematical equations or system of

    equations.

    Example:

    A person selects 5 stocks and invest equal

    money in them for equal time period. The

    returns from first 4 stocks are 20%, 30%, -15%

    and 35%. What should be the return from the

    5th stock so that the average return from the 5

    stocks is 25%?

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    OpenOffice.org Calc provides a tool to solve such

    equations. This tool is known as Goal Seek.

    Tools

    Goal Seek

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    To solve the above equation using Goal Seek, open

    the sheet OneVariable_1.

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    Goal Seek for solving a polynomial

    equation

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    A person deposits Rs. 20,000 in an account everyyear at a certain interest rate. If the money is

    deposited at the beginning of each year then

    what should be the interest rate so that hereceive 1,50,000 at the end of 5th year.

    Example:

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    To solve the problem we need to set up the

    following equation:

    150000120000120000

    120000120000120000

    2

    345

    rr

    rrr

    To find the value ofr we need to solve a 5th

    degree polynomial equation which could be

    very difficult.

    Let us see how to use Goal Seek to solve such

    an equation. Go to the sheet OneVariable_3.

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    Solving System of Linear Equations

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    Consider a system of linear equations:

    To solve this system of linear equations means

    to find the values ofx,y andz which satisfy all

    the above equations.

    3333

    2222

    1111

    dzcybxa

    dzcybxa

    dzcybxa

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    Matrix Method for Solving System of

    Linear Equations

    Step 1: Consider the matrices:

    Step 2: The system of equations can be written

    as

    3

    2

    1

    333

    222

    111

    d

    d

    d

    B

    z

    y

    x

    X

    cba

    cba

    cba

    A ,,

    BAX 20 MSF

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    This function computes the inverse of a

    matrix.

    Suppose a matrix is stored in cells B16:C17

    then its inverse can be computed by

    =MINVERSE(B16:C17)

    The MINVERSE Function

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    The MINVERSE Function

    In order to execute this function you first

    select a 2x2 range and then pressCTRL+SHIFT+ENTER.

    Pressing ENTER alone will not work!

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    This function computes the product of two

    matrices.

    Suppose we have two matrices B16:C17 and

    H16:H17 then their product is computed as

    =MMULT(B16:C17,H16:H17)

    The MMULT Function

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    The MMULT Function

    In order to execute this function you first

    select a 2x1 range and then pressCTRL+SHIFT+ENTER.

    Pressing ENTER alone will not work!

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    A company wants to pay an obligation of

    Rs 2 million after 10 years. In order to do so it

    decides to invest in the following bonds:

    An Immunization Problem

    Bond Coupon YTM Maturity Face Value

    A 8% 8% 13 1000

    B 6% 8% 20 1000

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    How much should be invested in each of the

    bonds so that the obligation is metirrespective of the change in the yield?

    An Immunization Problem

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    The Strategy

    Let VA and VB be the amounts invested in

    bonds A and B respectively. Then

    DDVVD

    VV

    V

    V

    V

    V

    BB

    AA

    BA

    1

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    The Strategy (Cont)

    Here DA and DB are the durations of bonds A

    and B respectively, and V is the present value

    of the obligation

    DDV

    VD

    V

    V

    V

    V

    V

    V

    B

    B

    A

    A

    BA

    1

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