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Drawing a Straight line. Popular Lecture Series Arif Zaman LUMS. Need for Straight Line. Sewing Machine converts rotary motion to up/down motion. Want to constrain pistons to move only in a straight line. How do you create the first straight edge in the world? (Compass is easy) - PowerPoint PPT Presentation
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Drawing a Straight line
Popular Lecture Series
Arif Zaman
LUMS
Need for Straight Line
Sewing Machine converts rotary motion to up/down motion.
Want to constrain pistons to move only in a straight line.
How do you create the first straight edge in the world? (Compass is easy)
Windshield wipers, some flexible lamps made of solid pieces connected by flexible joints.
Steam engine equipped with Watt's parallelogram.
Five hinges link the rods. Two hinges link
rods to fixed points One hinge links a
rod to the piston rod. To force the piston rod to move in a straight line,
to avoid becoming jammed in the cylinder. The dashed line shows how this whole assembly
can be simplified by using three rods and hinge.
James Watt’s Steam Engine
Watt’s Simplified Version
Engineer, Mathematician, Accountant
Engineer: 19 + 20 is approximately 40 Mathematician: 19 + 20 = 39 Accountant: Closes the door, and in a low
voice, whispers “What would you like it to be?”
A Straight Line
The linkage problem attracted designers, and pure mathematicians.
Mathematicians wanted an exact straight line. P. L. Tschebyschev (1821-1894) tried unsuccessfully. Some began to doubt the existence of an exact solution. Peaucellier (1864) devised a linkage that produces straight-line
motion, called the “Peaucellier's cell”. Soon, a great many solutions of the problem were found. Solutions were found that would produce various curves of which
the straight line is only a particular case.
Inversion
x → 1/xis an inversion that maps (0,1] to [1,∞) and vice versa
x → c2/x similarlymaps (0,c] to [c,∞)
In two dimensions this maps the inside of a circle to the outside
x y = c2 is an inversion
Circles that are Tangent to the Center get Mapped to Straight Lines under Inversion TO SHOW:
E and be are inverses ABC and ADE are similar
right triangles AC/AB = AE/AD AC · AD = AB · AE But AC · AD = c2
So AB · AE = c2
This shows that E is the inverse of B.
Since B was an arbitrary point on the circle, we have shown that a circle gets mapped to a line.
ASSUMPTIONS Yellow circle is circle of
inversion, with center A Green circle has diameter
smaller than the radius of the yellow circle, and goes through its center
C and D are inverses, i.e. AC · AD = c2
B is any point on the green circle
E is the point where AB intersects the perpendicular line from D
E
B
A C D
The Peaucellier Inversion
AE2 + BE2 = AB2
EC2 + BE2 = BC2
AC · AD = (AE – EC)(AE + EC) = AE2 – EC2
= AB2 – BC2
is a constant! All we need to do is to
fix A and move C
B
A C E D
The Peaucellier Cell
Small red circle constrains C to move in a circle
Red vertical line is image of above circle
Large red circle is the circle of inversion
Yellow circle is the limit of movement
Green circle is just for fun
Hart’s Solution
Linkages are in middle of rods, where the green “imaginary line” intersects the blue rods.
Green circle is inversion. Red circle mapped to red
horizontal line Centers of yellow and red
circles are fixed.
Hart’s Inversion
Points O, P and Q are marked on a line parallel to FB and AD
AOP ≡ AFB, FOQ ≡ FAD OP/FB = OA/FA is fixed OQ/AD = FO/FA is fixed. OP · OQ = FB · AD · cons FB · AD = AC · AD =
constant (same as Peaucellier)
F B
O P Q
A C E D
Kempe’s Double Rhomboid
Rhomboid has two pairs of adjacent sides equal.
Here we use two similar rhomboids
This solution is not based on any inversion.
Why it works
By parallel lines, the two a’s and the two b’s are equal.
The two rhomboids are similar, hence a=b.
This means that CD is a horizontal line.
But C is fixed so D moves in a straight line.
a
a b
C D
b
What happened next…
Algebraic methods have shown how one can approximate any curve using linkages.
You can design a machine to sign your name!
This problem is not interesting any more, but other similar problems are. Seehttp://www.ams.org/new-in-math/cover/linkages1.html
Enjoy Mathematics