Dr. Sangeeta Khanna Ph.D 1...Dr. Sangeeta Khanna Ph.D Dr. Sangeeta Khanna Ph.D 7 CHEMISTRY COACHING CIRCLE D:\Important Data\2016\+1\Org\Test\GT-8\Grand Test -8 (organic Chemistry)

$Page 1: Dr. Sangeeta Khanna Ph.D 1...Dr. Sangeeta Khanna Ph.D Dr. Sangeeta Khanna Ph.D 7 CHEMISTRY COACHING CIRCLE D:\Important Data\2016\+1\Org\Test\GT-8\Grand Test -8 (organic Chemistry)$
Dr. Sangeeta Khanna Ph.D 1 CHEMISTRY COACHING CIRCLE D:\Important Data\2016\+1\Org\Test\GT-8\Grand Test -8 (organic Chemistry) Level - 1.docx

Dr. Sangeeta Khanna Ph.D


LEVEL – 1 TOPIC: Organic Chemistry & Inorganic Chemistry

READ INSTRUCTIONS CAREFULLY

1. The test is of 1 hour duration.

2. The maximum marks are 200.

3. This test consists of 50 questions.

SECTION – A (Single Answer Type) Negative Marking [-1]

This Section contains 50 multiple choice questions. Each question has four choices A), B), C) and D) out of which ONLY ONE is correct. (Mark only One choice) 50 × 4 = 200 Marks

1. What will be the product of following reaction

a. b. c. d. B Sol. Markovnikoff’s addition of HBr on alkene. 2. Find incorrect Match

I II a. CH3CHO & CH2 = CH – OH Functional Isomers b. Tautomers

c. 2CH

OH

|C3CH and H

OH

|CCH3CH Tautomers

d. Geometrical Isomer C 3. Which of the following is correct order of stability of conformation of cyclohexane

a. Chair form > Boat form > Twist boat > Half chair b. Chair form > Twist Boat > Boat > Half chair c. Chair form > Half chair > Twist Boat > Boat d. Boat > Half chair > Twist Boat > Chair B

CH3 HBr

In absence of peroxide

CH3

Br

CH3

Br

Br

CH3 H3C

H H

and

CH3

H

H

CH3

O

O

and

OH

OH

CH3 Br



4. Which of the following will give methane

a. Decarboxylation of ethanoic acid b. Wurtz reaction of methyl chloride c. Reduction of ethanol with Red P and HI d. Hydrogenation of ethene A

Sol. 24

elimSoda

3COCHCOOHCH ;

33ether dry

Na

3CHCHClCH ;

33

HI

P dRe

52CHCHOHHC

2H

22CHCH

5. Which of the following reaction is not correct

a. 3

|

|3

Oxidation

KMnO3

|

3 CH

CH

OH

CCHCHH

CH

CCH

3

4

3

b. 233NCH

33 NCH

CH

CHCHCHCHCHCHCH

2

22

/\

c. 2|

2NBS

23 CHCH

Br

CHCHCHCH

d. ClCHCHCHCHCHCH 223Peroxide

HCl23

D Sol. Antimarkovnikoff’s Rule is not observed with HCl 6. Which of the following is the correct order of increasing +M effect?

a. b. c. d. A 7. Which of the following is aromatic?

a. b. c. d.

D Sol. It is pyridine, 6e– system

O

>

NH2

>

OH OH

>

NH2

>

O

>

OH O NH2

N

H

N

H

N

> >

NH2 O OH



8. Arrange the following carbanions in decreasing order of stability:

)P(

Θ

2 HCCH )Q(

2

Θ

HCPh )R(

2

Θ

2 HCCHCH

a. P > Q > R > S b. S > Q > P > R c. S > Q > R > P d. Q > S > R > P C

Sol. S is most stable as it is aromatic; (Benzy lic)

stabilised Resonance = Q ; )ally lic(

sonanceReR

9. Which of the following has unstable enol form?

a. b. c. d.

C

Sol.

10. What is the correct IUPAC name of following compound:

3||

3 CHH

Cl

CCHCHH

CHCH

CCH

32

a. 2-Chloro-5-Methylheptane b. 2-Chloro-5-ethylhept-3-ene

c. 2-Chloro-5-methylhept-3-ene d. 2-Ethyl-5-Chlorohex-3-ene

C

11. What is the relationship between the two structures shown?

a. Constitutional isomers (structural isomers) b. Stereoisomers c. Different drawing of the same conformation of the same compound d. Different conformation of the same compound A

Sol. Position isomers 12. The major product obtained in the reaction

CH3

Br2hv

is

(S)

O O

O

O O O

O

O

H

H

OH

stable

Anti Aromatic unstable

CH3 Cl

CH3 Cl



CH3Br Br

a. b. c. d. C

Sol. Tert carbon is most reactive in halogenations 13. In the reaction Product A is a. b. c. d.

B 14. In the reaction sequence:

Product will be:

a. CH3 –

O

C| |

–CH3 and CH3 –CHO b. CH3 COOCH3 and CH3COOH

c. \/

3

3

CH

CHCHOH and CH3 –CH2OH d. CH3 – CH = CH2 and CH2 = CH2

A Sol. 15. Identify the compound A and B in the following reaction sequence:

CaC2(s) + H2O () A (g) 4HgSO

4SO2H B()

a. A is ethylene, B is acetaldehyde b. A is acetylene, B is propionaldehyde c. A is ethane , B is ethanol d. A is acetylene, B is acetaldehyde D

Sol.

CH3

Br CH2Br

C C H2; lindlar catalyst

A

CH = CH

(cis form)

CH = CH

(trans form)

C – CH2

O

O

C C CH3 Zn/H2O

Product

H

O O

CH3

CH3

CH3

H3C

H

H C

O

O

O

Zn/H2O CH3 – C – CH3 + HCHO + ZnO

O

CH CH HOH

CH CH

H OH

Tautomerise CH3CHO

HOH

CaC2

CH2 – CH2



Cl

H3C

Br

Br

Cl

16. Which of the following will be dehydrohalogenated most rapidly ?

a. b. c. d.

D

Sol. Due to formation of most stable product benzene.

17. The addition of HBr is faster to the alkene

a. CH2 = CH2 b. CH3 – CH = CH – CH3

c. (CH3)2C = CH2 d. CH3 – CH = CH2

C

Sol. Because ‘C’ give more stable carbocation.

stable) (More ncarbocatio 3

3

3

|32

3

|3 CH

CH

CCHBrHCH

CH

CCH

In ‘B’ and ‘D’, 2° carbocation while in ‘A’ 1° carbocation is formed.

18. Which of the following alkene is most stable?

a. b.

c. d.

A

Sol. 6 H + no van der Waal repulsion

19. Which of the following is not correctly matched

I II

a. Electrophilic substitution

b. BrH

CH

CCHH

CH

CCH

3

|3

h

2Br2

3

|3

Free radical substitution

c. CH3 – CH = CH2 22|K770

ClCHCHH

Cl

C2 Electrophilic substitution

d. 3|

3HBr

23 CHH

Br

CCHCHCHCH Electrophilic Addition

C

Sol. It is Allylic substitution & free Radical

CH3 C = C

H H

CH3

C = C H H

CH2 – CH2 – CH3 H

CH3 C = C

H

H H

C = C H

H CH3

CH3

CH3Cl

Anhyd. AlCl3

CH3



20. The correct structure of 2-Methyl-5-(methylethyl)-4-propyloctane is:

a. b.

c. d.

D

21. Which of the following hydrocarbon will be formed on Kolbe’s electrolysis of 2-methylbutanoic acid.

a. 2,5-Dimethylhexane b. Hexane

c. 2,3-Dimethyl butane d. 3,4-Dimethyl hexane

D

Sol. 2|

||

23erisedim

|

23

|

23 H

CH

CH

CH

CH

CH

CCHCHH

CH

CCHCHCOOHH

CH

CCHCH

3

3323

22. An alkyl halide on reaction with sodium and dryether give hexane. Alkyl halide is

a. ClH

CH

CCH

3|

3 b. CH3 – CH2 – CH2 – Cl

c. 2|

2 H

Cl

CCHCH d. CH3 – CH2 – CH2 – CH2 – CH2 – CH2 – Cl

B

Sol. RRClR2actionRe

Wurtz ;

23. Which of the following reagent is used to convert 2-methyl butanoic acid to butane.

a. Ni + H2 b. Sodalime,

c. Red P + HI d. Kolbe’s electrolysis

B

Sol. 3223

|

23 CHCHCHCHH COO H

CH

CCHCH

3

24. Acetylenic hydrocarbons are acidic because:

a. acetylene belongs to the class of alkynes with general formula CnH2n-2.

b. acetylene has only one hydrogen atom at each carbon atom.

c. acetylene contains least number of hydrogen atoms among the hydrocarbons.

d. sigma electron density of C-H bond in acetylene is nearer a carbon which has 50% s-character.

D



25. Arrange the following alkanes in decreasing order of their heat of combustion:

a. X > Y > Z b. Z > X > Y c. Z > Y > X d. X > Z > Y C Sol. Branching decreases Rate of Combustion 26. Which of the following compound possesses chiral carbon?

a. b. c. d.

D

Sol. A tetrahedral carbon to which four different groups are attached is chiral carbon. 27. Which of the following compounds will not exhibit enolization? a. b. c. d. C

Sol. No - H in C. 28. Acylium cation has two resonating structures (I) and (II),

OCROCRIII

Which statement is correct for (I) and (II)? a. (I) is more stable than (II) c. Stability of (II) is more than (I) c. Both have same stability d. (II) Structure has incomplete octet B Sol. All atoms have complete octet in (II) structure 29. The fluoride which is soluble in water is

a. CaF2 b. BaF2 c. SrF2 d. BeF2 D

Sol. All group II fluorides are insoluble except BeF2

CH3 C CH3

CH3

CH3

(X) (Y) (Z)

CH2 CH CH2

OH

CH2 CH CH2

OH

Cl Cl

CH2 CH CH2

OH Cl Cl

CH2 CH CH2

OH

Br Cl

CH3 – C – CH3

O

CH2 – C – H

O

Ph – C – CH3

O

CH3

O

CH3 H3C

H3C



30. Which of the following statements is true for all the alkali metals?

a. Their nitrates decomposes on heating to give the corresponding nitrites and oxygen.

b. Their chlorides are deliquescent and crystallizes as hydrates.

c. They react with water to form hydroxide and hydrogen.

d. They readily react with halogen to form ionic halides, M+X–.

C

Sol. (A) 4 LiNO3 2Li2O + 4NO2 + O2

2NaNO3 2NaNO2 + O2 (similar decomposition with the nitrates of K, Rb and Cs)

(B) Only LiCl is deliquescent and crystallizes as a hydrate LiCl.2H2O

(C) 2M + 2H2O 2M+ + 2OH– + H2 (M = an alkali metal)

(D) Halides of Li are covalent in nature

31. The alkali metal which can emit its outermost electron under the influence of even candle light is:

a. Na b. Rb c. K d. Cs

D

Sol. Cs because of its low IE emits electron under the influence of even candle light.

32. Consider the following abbreviations for hydrated alkali metal ions:

X = [Li(H2O)n]+; Y = [K(H2O)n]

+; Z = [Cs(H2O)n]+

Which is the correct order of conductance of hydrated alkali metal ions?

a. X > Y > Z b. Z > Y > X c. X = Y = Z d. Z > X > Y

B

Sol. Smaller cation, will have more ionic conductance. Size of hydrated ion decreases from Li+ to Cs+, so

conductance increases.

33. A Metal M readily forms water soluble sulphate MSO4, water insoluble hydroxide M(OH)2 and oxide.

The hydroxide is soluble in NaOH. The metal M is

a. Be b. Mg c. Ca d. Sr

A

Sol. The metal M is Be. Its oxide BeO has high melting point. Its hydroxide dissolves in NaOH to form

sodium beryllate.

berry llate Sodium422 ])OH(Be[NaNaOH2)OH(Be

BeSO4 is highly soluble in water. Be(OH)2 is insoluble in water

34. For one of the element various successive ionisation energies (in kJ mol-1) are given below:

Ionisation

energy

1st

577.5

2nd

1810

3rd

2750

4th

11580

5th

14820

The element is

a. magnesium b. aluminium c. silicon d. phosphorus

B

Sol. 3rd ionisation energy = 2750 kJ/mol

4th ionisation nergy = 11580 kJ/mol

4th ionisation energy is much hieher than 3rd ionisation energy, it means removal of 4th electron is from the stable configuration Al3+(2s2, 2p6), hence aluminium is the element.



35. Match the list I with List II and select the correct answer using the code given below the lists:

List – I (Methods to remove Hardness of water)

List – II (Compound used)

P. Clark’s method 1. Na2[Na4(PO3)6]

Q. Calgon’s method 2. NaAlSiO4

R. Permutit method 3. Resin – OH

S. Synthetic resins method 4. Ca(OH)2

P Q R S P Q R S a. 3 4 1 2 b. 2 1 4 3 c. 4 1 2 3 d. 4 3 2 1 C 36. Match List I with List II and select the correct answer using the code given below the lists:

List I List II

1. Heavy water (a) Bicarbonates of Mg of and Ca in water

2. Temporary hard water (b) No foreign ions in water

3. Soft water (c) D2O

4. Permanent hard water (d) Sulphates and chlorides of Mg and Ca in water Codes: a. 1 – c, 2 – d, 3 – b, 4 – a b. 1 – b, 2 – a, 3 – c, 4 – d

c. 1 – b, 2 – d, 3 – c, 4 – a d. 1 – c, 2 – a, 3 – b, 4 – d

D

Sol. Heavy water – D2O

Temporary Hard water – Bicarbonates of Mg/Ca in water

Soft water – No foreign ions in water

Permanent hard water – Sulphates and chlorides of Mg/Ca in water

Soft water – No foreign ions in water

Permanent hard water – Sulphates and chlorides of Mg/Ca in water

37. Which of the following statements are not true about trimethyl and trisilyl amine?

a. Trimethyl amine has a pyramidal shape while trisilyl amine has a planer shape

b. Nitrogen atom in both trimethyl and trisilyl amines is in a state of sp3 and sp2 hybridization

respectively

c. Lone pair of electrons present in p-orbitals of nitrogen in trisilyl amine from p-d bond with the

vacant d-orbitals of silicon atom

d. Trisilyl amine is more basic in comparison to trimethyl amine because of the availability of the

lone pair of electrons on Nitrogen atom

D

Sol. In (SiH3)3N, lone pair of nitrogen is delocalized in vacant ‘d’ orbital, so it is not a base.

38. Which of the following can be used as chain terminating agent for silicone

a. (CH3)2SiCl2 b. (CH3)3SiCl c. CH3SiCl3 d. all B



Sol.

39. An alkene on ozonolysis give 3

||

3CH

O

CCH and CH3 – CH2CH2 – CHO. Alkene will be

a. 3

||

3CHH

CH

CCH

CH

CCH

33

b. 322

|

3CHCHCHCH

CH

CCH

3

c. d.32

CHCHCHC

CH

CH

\/

3

3

B

40. HClACCOAHOH

ClCoke

hot dRe2

What are A & C

a. C, CO2 b. CO2, COCl2 c. CO2, CCl4 d. CO2, CO

B

Sol. HCl2COOCCl

lCCO2CCO

2

HOH

)C(

Cl

)A(2

\

/2

41. Which of the following allotrope is thinnest crystalline form of carbon.

a. Fullerene b. graphite c. coal d. Graphine

D

42. Wrong statement among the following is

a. Diamond is the best conductor of heat but insulator.

b. Graphite act as bad conductor of heat but good conductor of electricity.

c. Bucky ball, C60, has 20 six membered & 12 five membered ring.

d. In Fullerene, a six-membered ring is fused with either six or five-membered rings but a five-

membered ring is also fused with five membered ring.

D

HOH

Cl Si CH3

CH3

CH3

R

Si OH

R

+ HO Si CH3

CH3

CH3

R

Si O Si CH3

R

CH3

CH3

+ H2O



43. Except BF3, the fluorides of Al, Ga, In and Tl do not act as Lewis acids. a. In the halides of Al, Ga, In and Tl, the electron deficiency at central atom decreases because of

back bonding by F. b. BF3 is covalent whereas fluorides of third group elements are ionic.

c. BF3 is monomer whereas other halides are dimmers. d. BF3 is small molecule whereas others are bigger molecules. B

44. A doctor by mistake administers a dilute Ba(NO3)2 solution to a patient for radiographic investigations. Which of the following should be the best to prevent the adsorption of soluble barium and subsequent barium poisoning? a. NaCl b. Na2SO4 c. NaHCO3 d. NH4Cl B

Sol.BaSO4 is most insoluble compound. 45. Solvay’s process cannot be used to synthesize

a. NaHCO3 b. Na2CO3 c. K2CO3 d. all C

Sol.Intermediate compound KHCO3 is soluble so cannot be ppted. 46. Which of the following pair of compounds are soluble in NaOH.

a. PbO & CuO b. SnO & BeO c. BaO & Al2O3 d. T2O & SiO2 B

Sol. CuO, BaO, T2O are insoluble. 47. Which of the following silicate have shairing of one corner of tetrahedral.

a. Orthosilicate b. Pyrosilicate c. Ring silicate d. Sheet silicate B

48. In which of following cases is the value of x maximum?

a. CaSO4 xH2O b. BaSO4 xH2O

c. MgSO4 xH2O d. All have the same value of x. C

Sol. MgSO4 is maximum hydrated 49. The following compounds have been arranged in the order of their increasing thermal stabilities.

Identify the correct order, K2CO3(I), Na2CO3(II), Rb2CO3(III), Li2CO3(IV)

a. I < II < III < IV b. IV < II < III < I c. IV < II < I < III d. II < IV < III < I C Sol. The thermal stabilities of carbonates increase down the group due to increase in metallic character

i.e. electropositive character. Further bigger cation stabilize bigger anion through crystal lattice energy effects.

50. H2O2 act as oxidising agent with a. Ozone b. FeSO4 in acidic medium c. K2Cr2O7 in acidic medium d. Cl2 – water B

Sol. Ozone and Cl2 – water oxidise H2O2 to O2

Documents

Dr. Sangeeta Khanna Ph.D 1...Dr. Sangeeta Khanna Ph.D Dr. Sangeeta Khanna Ph.D 7 CHEMISTRY COACHING CIRCLE D:\Important Data\2016\+1\Org\Test\GT-8\Grand Test -8 (organic Chemistry)