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DoD Maintenance SymposiumBirmingham, Alabama
Standard Aero’s Lean / Cellular Transformation -Delivering Affordable Readiness
Dave Shaw - CEOOctober 24, 2005
1
COPYRIGHT STANDARD AERO 2005 ©
Standard Aero Profile
Commercial53%
Defense47%
Depot Engine MROKnoxville, TennesseeSan Antonio, TexasTillburg, HollandWinnipeg, Canada
Field Engine MROSydney AustraliaMontreal & Vancourver, Canada
Enterprise ServicesField & Depot TransformationLogistics Readiness
Balanced Customer Mix
95 Years in Business (Founded in 1911)$793M in Annual Sales (2004)1,300 Customers Worldwide2,500 Employees (US, Canada, Europe, Asia) ISO 9001 and ISO 14001 Registered FacilitiesFAA, DOT, JAA ApprovedPrivately held by The Carlyle Group
AE3007
PW100
CF/TF34
PT6A
GTCPAPU/ RE220
MRO Products
Divisional StructureCompany Background
Technical Focus
LM1600
TF40/TF50
A250/T703
AE2100
T56/501
MRO68%
CRS32%
Engi ne e r s / Te c hni c a l
3 3 %
P r oduc t i on11%
M gm t / S uppor t
5 6 %
2
COPYRIGHT STANDARD AERO 2005 ©
Best Value Readiness
Best ValueReadiness
StandardAero’s
Best ValueReadiness
Adopting a performance-based total engine
management system leveraging decades of
global MRO learning curve experience and integrating
Reliability Centered Maintenance into our
proprietary build practices
Operating a lean/cellular MRO facility focused on reducing variability, an engineered repair vs.
replace approach, inventory and supply chain
management, fast throughput, and exacting
process control
=
= Total CostHours Flown
+
Systems EngineeringRCM
EnterpriseLean / Cellular MRO
Minimum CPEFH
(Min Removals x Min Event Cost)
(Max Time on Wing)
=
3
COPYRIGHT STANDARD AERO 2005 ©
Main Drivers of Best Value Readiness
Design
Operation
Maintenance
Financing
Total Value of Readiness
4
COPYRIGHT STANDARD AERO 2005 ©
Proprietary Reliability Centered Maintenance (RCM)Process can be used to determine optimum workscope
10 100 1000 10000 1000000.01
0.05
5
Hours TSO
0.1
0.5
1
10
50
99.999
9590
99.99
63.2
Weibull Distribution Maximum Likelihood (Shape) = 2.23 (Scale) = 4,497.5 Hours TSO# of Failures = 155# of Suspensions = 0
F(t) = 1 - e-(t/÷)^÷
÷÷
T56 Engine
DEC
AD
ES O
F R
EAL-
WO
RLD
DA
TA
TECH DATA +CUSTOMIZATION