SOLUTION

R, = (200lblft)(4 ft) = Sgg rO

1

R n = :([50 lb/ft)(3 ft) = zz5 tb2

+J:r, = g'

{xzo = 6'

A - 800Lb +2251b =0

MA - (8001bX2 f0 + Q25lb)(5 f0 = 0

A=575lbl<

Me = 475b .rt *) 1

t+/al,!

PROBLEM 5.70

Determine the reactions at the beam supports for the given loading.

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PROBLEM 5,71

Determine the reactions at the beam supports for the given

loading.

SOLUTION1

nr=i@kN/mX6 m)

=12kNRo =(2kN/m)(10m)

=20kN

*1 >r, =o' A-12kN-2okN=o

(xMr\

{>lro = g, M A- $2t<NX2m)-(20 kNX5 m) =0

L=32.0kN1<

Mo=r\ .OtN'm) {

pRopRrErARy MArERtaL.o 20r3 rhe Mccrrw-Hirr,C;Ylil:';# ,ll,i,X};;;):['i iil!";illii:I;i!,,:i!,!f;;:i i':i,:il:i'r;;;;;;;

"' rlistributed in nnt fitrtn or b1' Ltnv means'

;ou orc uti"g it tvithout permission'

635