POLYMATH Report No Title Ordinary Differential Equations 27-may-2013

Calculated values of DEQ variables Variable

Initial value

Minimal value

Maximal value

Final value

1 t 1.0E-08 1.0E-08 120. 120.

2 Nmeoh 0 0 71.56195 71.56195

3 V 150. 150. 199.5121 199.5121

4 Nhac 300. 11.56195 300. 11.56195

5 Nmeac 0 0 4.591274 1.747356

6 Nh2o 0 0 288.4381 288.4381

7 Fmeoho 3. 3. 3. 3.

8 Cmeoh 0 0 0.3584856 0.3584856

9 Chac 2. 0.058038 2. 0.058038

10

Cmeac 0 0 0.029753 0.0087662

11

Ch2o 0 0 1.445711 1.445711

12

T 350. 350. 350. 350.

13

Cmeoho 5. 5. 5. 5.

14

Xmeac 0 0 0.0149807 0.0046853

15

Ptotal 101.3 101.3 101.3 101.3

16

Ftotal 100. 100. 100. 100.

17

k 1.669907 1.669907 1.669907 1.669907

18

Tr 0.6910168 0.6910168 0.6910168 0.6910168

19

K 0.6922768 0.6922768 0.6922768 0.6922768

20

vo 0.6 0.6 0.6 0.6

21

Pvmeac 196.3743 196.3743 196.3743 196.3743

22

Fmeac 0 0 2.904062 0.9082698

23

rhac 0 -0.0193004 0 -0.0041729

Differential equations

1 d(Nmeoh)/d(t) = rhac * V + Fmeoho

2 d(V)/d(t) = vo - Fmeac * 74 / 943.4

3 d(Nhac)/d(t) = rhac * V

4 d(Nmeac)/d(t) = -rhac * V - Fmeac

5 d(Nh2o)/d(t) = -rhac * V

Explicit equations 1 Fmeoho = 3

2 Cmeoh = Nmeoh / V

3 Chac = Nhac / V

4 Cmeac = Nmeac / V

5 Ch2o = Nh2o / V

6 T = 350

7 Cmeoho = 5

8 Xmeac = Nmeac / (Nmeoh + Nhac + Nmeac + Nh2o)

9 Ptotal = 101.3

10 Ftotal = 100

11 k = (8.88 * 10 ^ 8) * exp(-7032.1 / T)

12 Tr = T / 506.5

13 K = 5.2 * exp((-8000 / 1.978) * ((1 / 298) - (1 / T)))

14 vo = Fmeoho / Cmeoho

15 Pvmeac = 4750 * exp(10.703 - (11.0088 / Tr) - 5.4361 * (ln(Tr)) + 0.3058 * Tr ^ 6)

16 Fmeac = Xmeac * (Pvmeac / Ptotal) * Ftotal

17 rhac = -k * ((Cmeoh * Chac) - ((Cmeac * Ch2o) / K))

General Total number of equations 22

Number of differential equations 5

Number of explicit equations 17

Elapsed time 2.315 sec

Solution method RKF_45

Step size guess. h 0.000001

Truncation error tolerance. eps 0.000001

Data file: c:\users\israel\desktop\diseño\trabajo para presentar\destilacion reactiva.pol