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8/3/2019 Differentiation Lvl 1
1/4
1. A curve has the equation 22113 xxy !
(i) Find an expression fordy
dx. [3]
(ii) Find the equation of the tangent to the curve at the point where
the curve crosses they-axis. [3]
2. A curve has equation14
3 2
!
x
xy ,
(i) finddx
dy, [3]
(ii)find also the coordinates of the stationary points. [4]
3. Differentiate the following with respect tox:
(a) 31
3y x
x! [2]
(b)2
2 1
xy
x
!
[3]
(c) y = 47 2 x [2]
(d)2
1!
xy
x[2]
(e) 22 xx [3]
(f) y = 4 3( 2) (2 1)x x [3]
4. Given that 34 ! xxy , expressdx
dyin the form
34
x
bax.
Find the value ofa and b. [3]
8/3/2019 Differentiation Lvl 1
2/4
6. Given that 2 2! y x x , finddy
dx. [3]
7. Given thatx
xy2
4 ! find the value ofdx
dywhenx =
4
1. [3]
8. Find the equation of the normal to the curve12
2
!
xxy where the curve cuts thex-axis. [6]
9.
The diagram shows part of the graph of the curve3
22
!
x
xxy .
(i) Given that2)3(
1d
d
!
x
k
x
y. Find the value ofk. [4]
(ii) R,Sand Tare intersections of the graph with the axes. PR is the normal tothe curve at R. Find the equation ofPR. [3]
(iii) Find the ratio of the area of triangle PSR to triangle TPR. [3]
5. A curve has the equationx
xy
21
3
! .
(i) Finddx
dy.
[2]
(ii) Find the equation of the normal to the curve at the pointy = 1. [4]
y
R
S P T x
3
22
!
x
xxy
8/3/2019 Differentiation Lvl 1
3/4
10. Given that2
)23( 10!
xy , find the value of
dx
dywhenx =
3
1.
[3]
11. (a) Differentiate with respect to x
(i) 47 2 x [2]
(ii)
x
x
31
52
[3]
12. For the curve 12)4( 2 ! xxy , calculate the coordinates of
(a) the points of intersection with the axis, [3]
(b) the turning points and determine the nature of the turning points. [7]
Hence sketch the curve. [2]
13. A curve has the equation2
42
!
x
xy .
(a)Find the gradient of the curve at the point where the curve meets the x-axis. [4]
(b)Show that the curve has no stationary points. [1]
14. A curve 16204 2 ! xxy cuts they-axis atA, thex-axis atB and C respectively.
(i) Write down the coordinates ofA,B and C. [3]
(ii) Find the coordinates of the point Pon the curve such that the
tangent to the curve at P is parallel to the lineAC. [4]
15. The equation of a curve is given by
2
3 , 11
xy xx
! {
.
i) Show that the gradient of the curve at the point Pwhere1
2x ! is -9. [3]
ii) Find the equation of the normal at point P. [2]
iii) This normal cuts thex andy axes at Q and R respectively. Find the coordinatesof the midpoint ofQR. [3]
8/3/2019 Differentiation Lvl 1
4/4
16. Given that 32 ! xxy , show that32
125 2
!
x
xx
dx
dy. Hence find the
equation of the normal to the curve at the point 4!x . [7]
17. (i) Express in partial fractions,)3)(2(
15622
2
xx
xx. [4]
(ii) Using the result of (i), find the first derivative of)3)(2(
15622
2
xx
xx, expressing your answer
in the form 22
2
232
x
cbx
x
a. State the value of the constants a,b and c. [4]
18. Given the equation of a curve is2)2(
12
!
x
xy .
Finddx
dyand the equation of the normal to the curve whenx = -4. [7]