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Individual Homework #15 Design and Analysis of Experiments Pr 0. A B AB y - - + 16 + - - 11 - + - 18 + + + 9 A effect = (11+9)/2-(16+18)/2 = -7 B effect = (18+9)/2+(16+11)/2 = 0 AB effect = (16+9)/2-(11+18)/2 = -2 The model regression coefficients are 1/2 the effect values. 6.1

Design and Analysis of Experiments Ind HW#15

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Individual Homework #15

Design and Analysis of Experiments

Pr 0.ABABy

--+16

+--11

-+-18

+++9

A effect = (11+9)/2-(16+18)/2 = -7

B effect = (18+9)/2+(16+11)/2 = 0

AB effect = (16+9)/2-(11+18)/2 = -2

The model regression coefficients are 1/2 the effect values.6.1

b and c appear to be high as well as ac interaction but negatively.

Anova table confirms that the factors mentioned above are significantc) y (hours)= 40.83 + 5.66*B + 3.41*C 4.41*AC

d)

Residuals are normally distributed and with a constant variance. There seem to be no problem with NID(0.).e) + , + , -