Individual Homework #14Design and Analysis of Experiments

5.19

Anova table shows that cycle time, temperature and operator are significant and so is the interaction between cycle time and temperature and between cycle time and operator. Interaction between temperature and operator at ∝=0.05 is not significant and the interaction between the three factors is not significant either. Residuals plot show that assumptions of constant variance and normal distribution are met.

5.21

The anova table shows that when the model is tried with interactions there is no degrees of freedom left for error, thus an additive model was ran with temperature, day and pressure as factors, in this way enough degrees of freedom are left to calculate MSe. Temperature is significant as well as days (blocks) and so it correct to block the experiment on days to separate its MS from MSe. Residuals plot show that model assumptions are reasonably met.