des Fisicas Del Gas Natural (Graficas y Tablas)

INGENIERIA DE GAS NATURAL I Propiedades Físicas

SECTION 23Physical Properties

This section contains a number of charts, correlations, and procedures for the prediction of physical properties of hydrocarbons and components found with them. Fig. 23-1 lists the nomenclature used in this section. Fig. 23-2 is a table containing frequently used physical properties for a number of hydrocarbons and other selected components. Immediately following is a detailed list of references and footnoted explanation for the values in Fig. 23-2. Physical properties for eighteen selected compounds can be found in GPA Standard 2145, “Table of Physical Constants of Paraffin Hydrocarbons and Other Components of Natural Gas.”







Fig.3


Fig.4


Fig.5


Fig. 6


Fig. 7


FIG. 8


FIG. 9


FIG. 10


Fig. 11


Fig. 12


FIG.13


Fig. 14


Fig. 15

Fig. 16


Fig. 17


Fig. 18

Fig. 19


Fig. 20

Fig. 21


Fig. 22


Fig. 23


TABLA 2-10

ComponenteFracciónmolar , yi

Factor deconversión

GPM

H2O

H2S

N2

C1

CO2

C2

C3 27,4816

i-C4 32,626

n-C4 31,4433

i-C5 36,1189

n-C5 36,1189

i5 - C6 41,3897

C6 41,0157

C7 46,002

C8 51,0516

C9 56,1354

C10 61,2298

∑ = ∑ =


FIG. 25


FIG. 26


Fig. 27


FIG. 2-28


TABLA 2-12


FIG. 29


FIG. 30


FIG. 31


FIG. 32


Fig. 33

Planilla: Determinación del estado de una mezcla de hidrocarburosPresión: lpcaTemperatura: °F

TABLA 2-14

ComponenteFracciónmolar , Zi

Constante "Ki"

Zi/Ki Zi * Ki

H2S

N2

C1

CO2

C2

C3

i-C4

n-C4

i-C5

n-C5

C6

C7

C8

C9

C10

∑ = ∑ = ∑ =


Ecuación para el Cálculo de la Separación Instantánea de los Hidrocarburos

F = L + V F = 1,0 L + V = 1,0

F.z i = moles del componente “i” en la carga.

V.y i = moles del componente “i” en el gas.

L.x i = moles del componente “i” en el líquido

F*z i = L*x i + V*y i

Ki=yix i F = 1,0

zi = L*x i zi = x i * (L + V*K)i

x i=zi

L+V∗K i∑i=1

n

x i=∑i=1

n ziL+V∗K i = 1,0

Punto de Burbujeo:

zi = L*x i + V*yi

Ki=yix i

xi=yiK i

zi = L*(

y iK i ) + V*yi zi = yi [(

LK i ) + V]

∑i=1

n

yi=∑i=1

n zi∗K iL+V∗K i = 1,0

Cuando L = 1,0 y V = 0

∑i=1

n

yi=∑i=1

n

zi∗K i=1,0

∑i=1

n

x i=∑i=1

n ziL+V∗K i

Punto de rocío: cuando L = 0 y V = 1,0

∑i=1

n

x i=∑i=1

n ziK i

=1,0


FIG. 2-34

FIG. 2-35


FIG. 2-36

FIG. 2-37


ANEXOS



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