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Def: The power series centered at x = a:
1
x is the variable and the c’s are constants (coefficients)
Lecture 29 – Power Series
)()()( 2210
0
axcaxccaxcn
nn
0,!
1a
ncn
!
!3!211)0(
!
1 32
0 k
xxxxx
n
k
n
n
2,
2
11
acn
n
n
1
2
01 2
)2()1(
8
)2(
4
2
2
1)2(
2
1k
kk
n
nn
n xxxx
2
For any power series, exactly one of the following is true:
.3
.2
.1 x allfor converges
ax only for converges
) (in allfor )absolutelyconverges( RR,x
) ( outside allfor diverges & RR,x
divergeor convergemay ,or at & R x Rx
Example 1 – Radius and Interval of Convergence
3
n
n
n x
n
n
x !
)!1(lim
1
Ratio Test:
!
!3!211
!
32
0 k
xxxx
n
x k
n
n
Series converges for
Example 2 – Radius and Interval of Convergence
4
n
n
n xn
xn
)10(!
)10(! )1(lim
1
Ratio Test:
k
n
n xkxxxn )10(! )10(!2)10(10! 2
1
Series converges for
Example 3 – Radius and Interval of Convergence
5
n
n
n x
n
n
x
)2(1
)2(lim
1
Ratio Test:
k
xxxx
n
x k
n
n )2(
3
)2(
2
)2(2
2 32
1
Example 3 – continued (testing endpoints)
6
R
:Interval ,
k
xxxx
n
x k
n
n )2(
3
)2(
2
)2(2
2 32
1
:2
1x
:2
1x
Example 4 – Radius and Interval of Convergence
7
n
n
n
x
3
1lim
Root Test:
k
k
n
n
nn
n xxxxx
3
)1(
9
)1(
3
11
3
1
3
1 2
00
Example 4 – continued (testing endpoints)
8
00 3
1
3
1
n
n
nn
n xxR :Interval ,
:4x
:2x
Example 5 – Radius and Interval of Convergence
9
Geometric Series:
1
2
01 2
)1()1(
8
)2(
4
2
2
1
2
21k
kk
nn
nn xxxx
001
2
21
2
1
2
21
nn
nn
nn
nn xx
Example 5 – continued – what is the converging value?
10
Geometric Series:
1
2
01 2
)1()1(
8
)2(
4
2
2
1
2
21k
kk
nn
nn xxxx
0 2
2
2
1
n
nx
The geometric series:
.1 when 1
2
|r|r
aarara
11
Lecture 30 – More Power Series
As a power series with a = 1, r = x and cn = 1 for all n:
.1 when 1
11 2
|x|
xxx
In other words, the function f(x) can be written as a power series.
0
1
1)(
n
nxx
xf
1 ,1 :Interval with 1R
Create new power series for other functions through:sum, difference, multiplication, division, composition
anddifferentiation and integration
12
0
1
1)(
n
nxx
xf 1,1 :Interval with 1R
)3()( xfxg
Example 1
13
1
)(2x
xxh
0
1
1)(
n
nxx
xf 1,1 :Interval with 1RExample 2
14
Consider the graphs:
1
)(2x
xxh
1,1 :Interval 753 xxxx
xy 1
33 xxy
535 xxxy
7537 xxxxy 11
)(xh1
15
tan)( 1 xxf
0
1
1
n
nxx
1,1 :Interval with 1RExample 3
16
tan 1 x
Need to solve for C. Set x = 0 to get:
12
)1(0
12
n
nn
n
x tan 1 x
:1x :1x
Test endpoints???
17
)1ln()( xxf
0
1
1
n
nxx
1,1 :Interval with 1RExample 4
18
)1ln( x
Need to solve for C. Set x = 0 to get:
1
)1(0
1
n
nn
n
x )1ln( x
:1x :1x
Test endpoints???