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DC circuits Physics Department, New York City College of Technology

DC circuits Physics Department, New York City College of Technology

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DC circuits

Physics Department, New York City College of Technology

Key words Electromotive

force (emf) Terminal voltage Resistors in

parallel and in series

Kirchhoff’s rules Junction rule Loop rule

Capacitors in series and in parallel

RC cuicuits

emf

Electromotive force (emf) refers to the potential difference between the terminals of a source when no current flows out. Its symbol is .

Terminal voltage Terminal voltage is the

potential difference between the terminals of a source when current flows, and is calculated as is the emf r is the internal

resistance of the battery

IrV

Example #1 A 65-Ω resistor is

connected to the terminals of a battery whose emf is 12V and whose internal resistance is 0.5Ω. Calculate (a) the current in the circuit, (b) the terminal voltage of the battery, and (c) the power dissipated in the resistor R and in the battery's internal resistance r.

Example #1—continued

AV

rRI

IrVab

183.05.065

12

, Since

(a)

(b) VAVIrVab 9.11)5.0)(183.0(12

(c)

.02.0)5.0()183.0(

isr in and

,18.2)65()183.0(

is Rin dissipatedpower The

22

22

WARIP

WARIP

r

R

Resistors in series

The equivalent resistance for resistors in series is

...321 RRRReq

Resistors in parallel

The equivalent resistance for resistors in parallel is ...

1111

321

RRRReq

Voltage drop along wire

Disc 18, #1 Disc 18, #2 Disc 18, #6

Series/parallel resistors

Disc 17, #23 Disc 17, #24

Example #2

Two 100Ω resistors are connected (a) in parallel, and (b) in series, to a 24V battery. What is the current through each resistor and what is the equivalent resistance of each circuit?

Example #2—continued

(a)

21

so resistor,each through

flow tosplitsbattery thefrom Icurrent totalThe

III

AIII

AV

R

VIA

V

R

VI

48.0

24.0100

24,24.0

100

24

21

22

11

50 so

,50

1

100

2

100

1

100

11

eq

eq

R

R

Example #2—continued

(b)

AV

RR

VI

RRIIRIRV

VVV

12.0100100

24

)(

and resistors,both in same theis I

21

2121

21

200or

,20012.0

0.24

21 RRRA

V

I

VR

eq

eq

Kirchhoff’s rules The junction rule: at any junction point,

the sum of all currents entering the junction must equal the sum of all currents leaving the junction. It is based on the conservation of electric charge.

The loop rule: the sum of the changes in potential around any closed path of a circuit must be zero. It is based on the conservation of energy.

Example #3

Calculate the currents I1, I2, and I3.

Example #3—continued

(a) .

a,point at rulejunction sKirchhoff'Apply

213 III

(b) .0414530

loop,upper the torule loop sKirchhoff'Apply

31 II

(c) .080)120(30

loop,outer the torule loop sKirchhoff'Apply

21 II

Example #3—continued

(d) 1.4I3.821

30I80I

get we(c), Eq. From

11

2

(e) I73.01.141

30I45I

get we(b), Eq. From

11

3

Example #3—continued

AI

AI

AI

IIIII

7.1

6.2

87.0

.4.18.373.01.1

(a), Eq. into (e) and (d) Substitute

3

2

1

11231

Capacitors in series and in parallel

The equivalent capacitance for capacitors in series is

The equivalent capacitance for capacitors in parallel is

...1111

321

CCCCeq

...321 CCCCeq

RC circuits In the charging

process,

In the discharging process,

The time constant is

Switch

C

R

ε

)1( / RCtc eV

RCtc eVV /

0

RC

RC charging curve

Disc 18, #28