Dbms Record[1]

INDEXS.No Program Page

No1. (a)Create a table to represent sb_account of a bank consisting of

account_no,customer-name , balance-amount.(b)Write a PL/SQL block to implement deposit and withdraw. Withdraw should not be allowed if the balance goes below Rs.1000.

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2. Create the following two tables:College-info

College-infoCollege-info consists of fields : college-code, college-name, addressFaculty-info consists of fields : college-code, faculty-code, faculty-name, qualification, college-code is foreign key.(a)Generate queries to do the following: (i) List all those faculty members whose experience is greater than or equal to 10 years and have M.Tech degree. (ii) List all those faculty members, who have at least 10 years of experience but do not have M.Tech degree.

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3. Create the following tables for library-information systems :Book: (Accession -no, title, publisher, author, status)Status could be issued, present, in the library, dent for binding, and cannot be issued.(a)Write a trigger which sets the status of a book to “cannot be issued “, if it is published 20 years back.

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4. Create the following tables for library-information systems :Book : (Accession- no, title, publisher, author, status, date-of -purchase)Status could be issued, present, in the library, dent for binding, and cannot be issued.Generate queries to do the following :(i) List all those books which are new arrivals. The books which are requires during the last 6 months are categorized as new arrivals.(ii) List all those books that cannot be issued and purchased 20 years ago.

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5. Create the following tables: Student (roll-no, name, date-of-birth, course-id)Course (course-id, name, fee, duration)(a)Generate the queries to do the following: (i) List all those students who are greater than 18 years of age and have opted or MCA course.

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(ii) List all those courses whose fee is grater than that of MCA course.S.No Program Page

No6. Create the following table :

Student(roll-no,name subject-opted) Subject(faculty-code, faculty-name, specialization)(a)Generate queries to do the following : (i) Find the number of students who haveenrolles for the subject “DBMS” (ii) Find all those faculty members who have not offered any subject.

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7. Create the following table : Item (item-code, item-name, qty-in-stock, reorder-level) Supplier (supplier-code, supplier-name, address) Can-Supply (supplier-code, item-code) (a) Generate queries to do the following: (i) List all those suppliers who can supply the given item. (ii) List all those items which cannot be supplied by given company.

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8. Create the following table: Student(roll-no,marks,category, district, state) Student-rank(roll-no, marks,rank) (a)Generate queries to do the following : (i) List all those students who have come from tamilnadu state and secured a rank above 100. (ii) List all those students who have come from Anshra Pradesh state and belong togiven category who have secured a rank above 100.

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9. Create the following table: Branch (branch-id, branch-name, branch-city) Customer (customer-id, customer-name, customer-city, branch-id) (a) Generate queries to do the following: (i) List all those customers who live in the same city as the branch in which theyhave account. (ii) List all those customers who have an account in a given branch city

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10. Create the following tables:Book (accession no, title, publisher, year, date-of-purchase, status)Member (member-id, number-of-books-issued, max-limit)Book-issue (accession-no, member-id, date-of-issue) (a) Generate the following to do the following: (i) List all those books which are due from the students to be returned. A book is considered to be issued 15 days back and yet not returned. (ii) List all those members who cannot be issued any more books

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11. Create the following tables: 38

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Book (accession no, title, publisher, year, date-of-purchase, status) Member (member-id, number-of-books-issued, max-limit) Book-issue (accession-no, member-id, date-of-issue) (a) Write a PL/SQL procedure to issue the book. (b)Write a trigger to set the status of student to “back listed” if they have taken book but not returned even one year.

12. Create the following Book (accession-no, title, publisher, year, date-of-purchase) Book-place (accession-no, rack-id, rack-position) Member (member-id, name, number-of-books-issued, max-limit, status) Book-issue (accession-no, member-id, date-of-purchase) (a) Write a PL/SQL procedure to issue the book (b) Write a trigger to set the status of the book neither to “lost” which is neither issued nor in the library.

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13. Create the following Book (accession-no, title, publisher, year, date-of-purchase) Member (member-id, name, number-of-books-issued, max-limit, status) Book-issue (accession-no, member-id, date-of-purchase ,due-date) (a) Write a PL/SQL to list all those students who are defaulters. Astudent is considered to be a defaulter if he has not returned a book even after the due-date (b) Write a trigger to set the status of the student to” back listed” if they have taken book but not returned even after one year.

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14. Create the following tables: Branch (branch-id, branch-name, branch_-city) Customer (customer-id, customer-name, customer-city, branch-id) (b) Generate queries to do the following: (i) List all those customers who live in the same city as the branch in which they have account. (ii) List all those customers who have an account in more than one branch.

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15. Create the following tables: Branch (branch-id, branch-name, branch_-city) Customer (customer-id, customer-name, customer-city, branch-id) (a) Generate queries to do the following: (i)List all those branches who have more than 2 customers. (ii) List all those customers who have an account in more than one branch.

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16. Create the following table: Student (roll-no, name, category, district, state)

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Student-rank (roll-no, marks, rank) (b) Generate queries to do the following :

(i) List names of the students who are having same rank bur they should reside in different districts. (ii) List details of students they belongs to same category with same tank.

17. Create the following tables: Student (roll-no, name, date-of-birth, course-id) Course (course-id, name, fee, duration) (a) Generate queries to do the following: (i) List all those student who are between 10-19 years of age and have opted for MCAcourse. (ii) List all those courses in which number of students are less than 10.

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18. Create the following tables: Student (roll_no, name,date_of_birth,course-id) Course (course-id, name, fee, duration, status) (a) Write PL/SQL procedure to do the following: Set the status of course to “not offered” in which the number of candidate is less than 5.

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19. Create the following tables: Student (roll_no, name,date_of_birth,course-id) Course (course-id, name, fee, duration, status) (a) Write PL/SQL procedure to do the following: Set the status of course to “not offered” in which the number of candidate is less than 5.

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20. Create the following tables:Student (roll-no, name, date_of_birth, course-id)Course (course-id, name, fee, duration, status)(a) Write PL/SQL procedure to do the following: Set the status of course to “offered” in which the number of candidate are at least 10 otherwise not offered.

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21. Create the following tablesItem(item_code,item_name,qty_in_stock,reorder_level)Supplier(supplier_code,supplier_name,address)Can_supply(supplier_code,item_code)(a)Create a form to accept the data from the user with appropriate validation checks(b)Create a report to list the items whose qty_in_stock is less than or equal to their reorder levels.

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22. Create the following table :Item (item-code, item-name, qty-in-stock, reorder-level)

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Supplier (supplier-code, supplier-name, address) Can-Supply (supplier-code, item-code) (a)Write PL/SQL procedure to do the following: Set the status of the supplier to “important” if the supplier can supply more than five items.

23. create the following tablesItem(item_code,item_name,qty_in_stock,reorder_level)Supplier(supplier_code,supplier_name,address,status)Can_supply(supplier_code,item_code)(a)Create a form to accept the data from the user with appropriate validation checks(b)Write PL/SQL procedure to do the following (i) Generate a report of those items that are supplied by those suppliers whose status is“important”.

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24. create the following tablesStudent(roll_no,marks,category,district,state)Student_rank(roll_no,marks,rank)

(a)Create a form to accept the data from the user with appropriate validation checks.(b)Write a PL/SQL procedure to do the following (i)Generate a report to list of those districts from which the first hundred rankers come from

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25. create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code,status)Faculty(faculty_code,faculty_name,specialization)

(a)Write a PL/SQL procedure to the following: Set the status of the subject to “not offered” if the subject is not opted by at least 5 students.

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26. create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code,status)Faculty(faculty_code,faculty_name,specialization)(a)Write a PL/SQL procedure to the following:Set the status of the subject to “not offered” if the subject is not offered by any of the faculty members.

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27. create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code)Faculty(faculty_code, faculty_name, specialization)(a)Generate the queries to do the following

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(i) Find the number of students who have enrolled for the subject ‘DBMS’.(ii)Find all those subjects which are not offered by any faculty member.

28. create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code)Faculty(faculty_code, faculty_name, specialization)(a)Generate the queries to do the following (i)Find the number of students who have enrolled for the subject ‘DBMS’. (ii)Find all those subjects which are offered by more than one faculty member.

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29. create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code)Faculty(faculty_code, faculty_name, specialization)(a)Generate the queries to do the following (i)Find the number of students who have enrolled for the subject ‘OS’. (ii)Find all those students who have opted for more than 5 subjects.

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30. create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code)Faculty(faculty_code, faculty_name, specialization)(a)Generate the queries to do the following (i)Find the number of students who have not enrolled for the subject ‘DBMS’. (ii)Find all those subjects which are offered by more than one faculty member.

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S.No Program Page No

1. Steps For Creating A Data Source 112

2. Steps To Create A Form 114

3. Steps To Generate A Report 121

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1. (a)Create a table to represent sb_account of a bank consisting of account_no,customer-name , balance-amount.(b)Write a PL/SQL block to implement deposit and withdraw. Withdraw should not be allowed if the balance goes below Rs.1000.

PROGRAM:

Creating Tables:

SQL> create table sb_account 2 ( ACC_NO varchar(10) primary key, 3 cust_name varchar(15), 4 balance number(10));

Table created.

Inserting values in to table:

SQL> insert into sb_account values2 ('&ACC_NO','&cust_name',&balance);

Enter value for acc_no: 101Enter value for cust_name: abcdEnter value for balance: 15000old 2: ('&ACC_NO','&CUST_NAME','&BALANCE')new 2: ('101','abcd','15000')

1 row created.

SQL> /Enter value for acc_no: 102Enter value for cust_name: defgEnter value for balance: 1000old 2: ('&ACC_NO','&CUST_NAME','&BALANCE')new 2: ('102','defg','1000')

1 row created.SQL> select * from sb_account;

ACC_NO CUST_NAME BALANCE------------ ----------------- --------------101 abcd 15000102 defg 1000103 fhdkd 2000

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104 dfhdl 25000

(b) PL/SQL Code: SQL> declare

2 bal number(10); 3 acno varchar(10); 4 min_bal constant number(7,2):=1000.00; 5 amount number(10); 6 ch number(1); 7 begin 8 dbms_output.put_line(to_char(1)||'.deposit'); 9 dbms_output.put_line(to_char(2)||'.Withdraw'); 10 dbms_output.put_line('enter choice'); 11 ch:=&ch; 12 acno:=&acno; 13 select balance into bal from sb_account where acc_no=acno; 14 amount:=&amount; 15 if(ch=1) then 16 update sb_account set balance=balance+amount where acc_no=acno; 17 dbms_output.put_line('deposited'); 18 else 19 if (bal-amount)<min_bal then 20 dbms_output.put_line('cant withdraw'); 21 else 22 update sb_account set balance=balance-amount where acc_no=acno; 23 dbms_output.put_line('withdrawn'); 24 end if; 25 end if; 26* end;SQL> /Enter value for ch: 1old 11: ch:=&ch;new 11: ch:=1;Enter value for acno: 101old 12: acno:=&acno;new 12: acno:=101;Enter value for amount: 1000old 14: amount:=&amount;new 14: amount:=1000;

1.deposit2.Withdrawenter choice

deposited

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PL/SQL procedure successfully completed.

SQL> select * from sb_account;

ACC_NO CUST_NAME BALANCE---------- --------------- ----------101 abcd 16000102 defg 1000103 fhdkd 2000104 dfhdl 25000

SQL>/ (reexecuting yhe same PL/SQL code)Enter value for ch: 2old 11: ch:=&ch;new 11: ch:=2;Enter value for acno: 102old 12: acno:=&acno;new 12: acno:=102;Enter value for amount: 1000old 14: amount:=&amount;new 14: amount:=1000;enter choice1.deposit2.Withdraw

cant withdraw

PL/SQL procedure successfully completed.SQL> / (reexecuting yhe same PL/SQL code)

Enter value for ch: 2old 11: ch:=&ch;new 11: ch:=2;Enter value for acno: 103old 12: acno:=&acno;new 12: acno:=103;Enter value for amount: 1000old 14: amount:=&amount;new 14: amount:=1000;

enter choice1.deposit2.Withdraw

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withdrawn

PL/SQL procedure successfully completed.SQL> select * from sb_account;

ACC_NO CUST_NAME BALANCE---------- --------------- ----------101 abcd 16000102 defg 1000103 fhdkd 1000104 dfhdl 25000

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2. Create the following two tables:College-infoCollege-infoCollege-info consists of fields : college-code, college-name, addressFaculty-info consists of fields : college-code, faculty-code, faculty-name, qualification, college-code is foreign key.

(a) Generate queries to do the following:(i) List all those faculty members whose experience is greater than or equal to 10 years and have M.Tech degree.(ii) List all those faculty members, who have at least 10 years of experience but do not have M.Tech degree.

Program: Creating tables: SQL>create table college_info.

(college_code number(5) primary key, college_name varchar(15), address varchar(15));

Table created.

SQL>create table faculty_info 2 ( faculty_code number(5) primary key, 3 college_code number(5), 4 faculty_name varchar(15), 5 qualification varchar(15), 6 experience number(2), 7 address varchar(15),

8constraints fk foreign key(college_code) references college_info( college_code ));

Table created.

Inserting Values Into Tables:

SQL> insert into college_info values 2 (&college_code,'&college_name','&address');

Enter value for college_code: 101Enter value for college_name: xyzEnter value for address: old alwal 1;old 2: (&college_code,'&college_name','&address')new 2: (101,'xyz','old alwal 1;')

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1 row created.

SQL> /Enter value for college_code: 202Enter value for college_name: abcEnter value for address: old alwal 2;old 2: (&college_code,'&college_name','&address')new 2: (202,'abc','old alwal 2;')

1 row created

SQL> insert into faculty_info values (&faculty_code,&college_code,'&faculty_name','&qualification','&experience','&ad

dress')Enter value for faculty_code: 1111Enter value for college_code: 101Enter value for faculty_name: ssssEnter value for qualification: M.TechEnter value for experience: 10Enter value for address: zzzzzzz

old 2: (&faculty_code,&college_code,'&faculty_name','&qualification','&experience','&address')new 2: (1111,101,'ssss','M.Tech','10','zzzzzzz')

1 row created.

SQL> /Enter value for faculty_code: 2222Enter value for college_code: 202Enter value for faculty_name: yyyyEnter value for qualification: M.PhilEnter value for experience: 20Enter value for address: xxxxxxold 2: (&faculty_code,&college_code,'&faculty_name','&qualification','&experience','&address')new 2: (2222,202,'yyyy','M.Phil','20','xxxxxx')

1 row created.

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SQL> select * from college_info;

COLLEGE_CODE COLLEGE_NAME ADDRESS---------------------- --------------------- ----------------- 101 xyz old alwal 1; 202 abc old alwal 2; 303 def old alwal 3; 404 ghi old alwal 4; 505 klm old alwal 5;

SQL> select * from faculty_info;

FACTY_C0 COLLE_CODE FATY_NAME QUALIF EXPERI ADDRESS-------------- ------------------ ----------------- ----------- -------- ------------- 1111 101 ssss M.Tech 10 zzzzzzz 2222 202 yyyy M.Phil 20 xxxxxx3333 303 dddd M.Tech 15 ccccc 4444 404 ffff B.Sc 5 vvvvv55555 505 rrrr M.Tech 5 qqqqq

(a) Query:

(i)SQL> select faculty_name from faculty_info where experience>=10 and qualification='M.Tech);

Output:

FACULTY_NAME--------------------ssssdddd (ii) Query: SQL> select faculty_name from faculty_info where experience>10 and qualification!= 'M.Tech');Output:

FACULTY_NAME ------------------------ yyyy

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3. Create the following tables for library-information systems :Book: (Accession -no, title, publisher, author, status)Status could be issued, present, in the library, dent for binding, and cannot be issued.Write a trigger which sets the status of a book to “cannot be issued “, if it is published 20 years back.

PROGRAM:

Creating Tables:

SQL> create table libr_info 2 ( accession_no varchar(4) primary key, 3 title varchar(8), 4 published date, 5 author varchar(5), 6 status varchar(14));

Table created

Inserting Values Into Table: . SQL> insert into libr_info values 2 ('&accession_no','&title','&publisher','&author','&status');

Enter value for accession_no: mc24Enter value for title: icgEnter value for published: 06-mar-1985Enter value for author: ghijEnter value for status: issuedold 2: ('&accession_no','&title','&publisher','&author','&status')new 2: ('mc24','icg','06-mar-1985','ghij','issued')

1 row created.

SQL> /Enter value for accession_no: mc25Enter value for title: dcnEnter value for published: 06-apr-2005Enter value for author: ijklEnter value for status: cannot issueold 2: ('&accession_no','&title','&publisher','&author','&status')new 2: ('mc25','dcn','06-apr-2005','ijkl','cannot issue')

1 row created.

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SQL> select * from libr_info;

ACCE TITLE PUBLISHED AUTHO STATUS-------- -------- ---------------- --------- -----------mc21 dbms 06-JAN-86 abcd bindingmc22 or 06-FEB-00 cdef presentmc23 os 06-SEP-99 efgh issuedmc24 icg 06-MAR-85 ghij issuedmc25 dcn 06-APR-05 ijkl cannot issue

SQL> create or replace trigger t03 before insert or update on libr_info for each row begin if (:new.published<'01-jan-1989') then update libr_info set status='cant issue'; end if; end;SQL> /

Trigger created.

insert into libr_info *ERROR at line 1:

ORA-04098: trigger 'SCOTT. LIBR_TRIGGER' is invalid and failed re-validation ORA-06512: at "SCOTT.T03”.line 3 ORA-04088: error during execution of trigger 'SCOTT.T03’

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4. Create the following tables for library-information systems :Book : (Accession- no, title, publisher, author, status, date-of -purchase)Status could be issued, present, in the library, dent for binding, and cannot be issued.(a) Generate queries to do the following :

(i) List all those books which are new arrivals. The books which are requires during the last 6 months are categorized as new arrivals.

(ii) List all those books that cannot be issued and purchased 20 years ago.

PROGRAM:

Creating table:

SQL> create table library_info 2 (accession_no varchar(7) primary key, 3 title varchar(15), 4 publisher varchar(10), 5 author varchar(10), 6 status varchar(10) 7 date_of_purcahse date;

Table created.

Inserting into table:

SQL>insert into library_info values('&accession_no','& title','&publisher','&author','&status','&date_of_purcahse' );

Enter value for accession_no: mc1122Enter value for title: dbmsEnter value for publisher: tataEnter value for author: ramakrsihEnter value for status: newEnter value for date_of_purcahse: 06-mar-08old 2: ('&accession_no','& title','&publisher','&author','&status','&date_of_purcahse' )new 2: ('mc1122','dbms','tata','ramakrsih','new','06-mar-08' )

1 row created. SQL> /

Enter value for accession_no: mc5566Enter value for title: c++Enter value for publisher: hhhhhEnter value for author: aaaaaEnter value for status: isuued

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Enter value for date_of_purcahse: 12-sep-1986

old 2: ('&accession_no','& title','&publisher','&author','&status','&date_of_purcahse' )new 2: ('mc5566','c++','hhhhh','aaaaa','isuued','12-sep-1986' )

1 row created.

SQL> select * from library_info;

ACCESSI TITLE PUBLISHER AUTHOR STATUS DATE_OF_P------- --------------------- ---------------- ------------ ------------ -----------------mc1122 dbms tata ramakrsih present 06-MAR-08mc2233 os Mcgrahill Galvin present 05-JAN-05mc3344 or ssss wwww binding 25-SEP-08mc4455 icg ggggg xxxxx issued 01-AUG-08mc5566 c++ hhhhh aaaaa issued 12-SEP-86mc6677 eit jjjjj lllll issued 15-JAN-85

6 rows selected.

(a) Queries: (i) SQL> select * from library_info where(months_between(sysdate,date_of_purcahse)<=6)

ACCESSION_NO TITLE PUBLISHER AUTHOR STATUS DATE_OF_PURCAHSE---------------------- -------- ---------------- ----------- - --------- ------------------------------mc3344 or ssss wwwww binding 25-SEP-08mc4455 icg ggggg xxxxx issued 01-AUG-08

SQL> select * from library_info where(months_between(sysdate,date_of_purcahse)/12>=20);

ACCESSI TITLE PUBLISHER AUTHOR STATUS DATE_OF_P------------ -------- ----------------- ------------ ------------ ---------- ---------mc5566 c++ hhhhh aaaaa isuued 12-SEP-86mc6677 eit jjjjj lllll issued 15-JAN-85

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5. Create the following tables: Student (roll-no, name, date-of-birth, course-id) Course (course-id, name, fee, duration)

(a) Create a form to accept the data from the user with appropriate validation checks(b) Generate the queries to do the following:

(i) List all those students who are greater than 18 years of age and have opted for MCA course.(ii) List all those courses whose fee is grater than that of MCA course.

PROGRAM:

Creating tables:

SQL> create table course 2 (course_id varchar(6) primary key, 3 name varchar(10), 4 fee number(6), 5 duration number(2));

Table created.

Inserting into values:

SQL> insert into course values 2 ('&course_id','& name ',&fee ,&duration );Enter value for course_id: 123Enter value for name: M.C.AEnter value for fee: 25400Enter value for duration: 3old 2: ('&course_id','& name ',&fee ,&duration )new 2: ('123','M.C.A ',25400 ,3 )

1 row created.

SQL> /Enter value for course_id: 456Enter value for name: B.TechEnter value for fee: 36000Enter value for duration: 4old 2: ('&course_id','& name ',&fee ,&duration )new 2: ('456','B.Tech ',36000 ,4 )

1 row created.

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SQL> select * from course;

COURSE NAME FEE DURATION------------ -------- ------- ---------------123 M.C.A 25400 3456 B.Tech 36000 4789 M.B.A 20000 2012 Bio-Tech 40000 3156 Food-Tech 10000 3

SQL> create table student 2 (roll_no varchar(5) primary key, 3 name varchar(5), 4 date_of_birth date, 5 course_id varchar(5), 6 constraints fk1 foreign key(course_id) references course(course_id));

Table created.

SQL> insert into student values 2 ('&roll_no','& name','& date_of_birth','&course_id');Enter value for roll_no: nmca1Enter value for name: aaaaEnter value for date_of_birth: 01-jan-1986Enter value for course_id: 123old 2: ('&roll_no','& name','& date_of_birth','&course_id')new 2: ('nmca1','aaaa','01-jan-1986','123')

1 row created.

SQL> /Enter value for roll_no: nmca2Enter value for name: bbbbEnter value for date_of_birth: 25-feb-2000Enter value for course_id: 456old 2: ('&roll_no','& name','& date_of_birth','&course_id')new 2: ('nmca2','bbbb','25-feb-2000','456')

1 row created.

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SQL> select * from student;

SQL> select * from student;

ROLL_ NAME DATE_OF_B COURS--------- -------- ---------------- -------------nmca1 aaaa 01-JAN-86 123nmca2 bbbb 25-FEB-00 456nmca3 cccc 30-MAR-87 123nmca4 dddd 15-APR-99 123nmca5 eeee 08-MAY-87 789nmca6 ffff 26-JUN-83 012

6 rows selected.

(a) Queries:(i) SQL>select * from student where(months_between(sysdate,date_of_birth)/12>18)and course_id='123'

ROLL_ NAME DATE_OF_B COURS-------- --------- ---------------- ----------nmca1 aaaaa 10-JAN-86 123nmca3 ccccc 30-MAR-87 123

(ii) SQL> select * from course where fee>25400;

COURSE NAME FEE DURATION----------- ---------- ------- ---------------456 B.Tech 36000 4012 Bio-Tech 40000 3

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6. Create the following table : Student(roll-no,name subject-opted) Subject(faculty-code, faculty-name, specialization)

(a) Generate queries to do the following :(i) Find the number of students who haveenrolles for the subject “DBMS”(ii) Find all those faculty members who have not offered any subject.

PROGRAM:

Creating the table:

SQL> create table subject_06 2 (faculty_code varchar(5), 3 faculty_name varchar(5), 4 specilization varchar(5) primary key);

Table created.SQL> create table student_06

2 (roll_no varchar(5) primary key, 3 name varchar(5), 4 subject_opted varchar(5), 5 constraints fk2 foreign key(subject_opted) references

subject_06(specilization));

Table created.

Inserting the values into table:

SQL> insert into subject_06 values 2 ('&faculty_code','&faculty_name','&specilization');Enter value for faculty_code: mca01Enter value for faculty_name: abcdeEnter value for specilization: dbmsold 2: ('&faculty_code','&faculty_name','&specilization')new 2: ('mca01','abcde','dbms')

1 row created.

SQL> /Enter value for faculty_code: mca04Enter value for faculty_name: pqrstEnter value for specilization: icgold 2: ('&faculty_code','&faculty_name','&specilization')new 2: ('mca04','pqrst','icg')

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1 row created.SQL> insert into student_06 values 2 ('&roll_no','&name ','& subject_opted');Enter value for roll_no: mc001Enter value for name: abcEnter value for subject_opted: dbmsold 2: ('&roll_no','&name ','& subject_opted')new 2: ('mc001','abc ','dbms')

1 row created.

SQL> /Enter value for roll_no: mc002Enter value for name: defEnter value for subject_opted: osold 2: ('&roll_no','&name ','& subject_opted')new 2: ('mc002','def ','os')

1 row created.

SQL> select * from subject_06;

FACUL FACUL SPECI----------- ----------- ---------mca01 abcde dbmsmca02 fghij comca03 klmno osmca04 pqrst icgmca05 uvwxy or

SQL> select * from student_06;

ROLL_ NAME SUBJE---------- ---------- ----------mc001 abc dbmsmc002 def osmc003 ghi ormc004 klm dbmsmc005 nop dbms

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(a) Queries:

(i)SQL> select * from student_06 where subject_opted='dbms';

ROLL_ NAME SUBJE--------- ---------- ----------mc001 abc dbmsmc004 klm dbmsmc005 nop dbms

(ii) SQL> select * from subject_06 where specilization not in (select subject_opted from student_06);

FACUL FACUL SPECI--------- ---------- ---------mca02 fghij comca04 pqrst icg

(or)

SQL> select * from subject_06 where specilization!= all('dbms','os','or');

FACUL FACUL SPECI----------- ----------- ----------mca02 fghij comca04 pqrst icg

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7. Create the following table : Item (item-code, item-name, qty-in-stock, reorder-level) Supplier (supplier-code, supplier-name, address) Can-Supply (supplier-code, item-code) (a) Create a form to accept the data from the user with appropriate validation checks. (b) Generate queries to do the following: (i) List all those suppliers who can supply the given item. (ii) List all those items which cannot be supplied by given company.

PROGRAM:

Creating the tables:

SQL> create table item 2 (item_code varchar(5) primary key, 3 item_name varchar(6), 4 qty_in_stock number(3), 5 reorder_level number(3));

Table created.

SQL> create table supplier 2 (supplier_code varchar(5) primary key, 3 supplier_name varchar(6), 4 address varchar(10));

Table created.

SQL> create table can_supply (supplier_code varchar(5), item_code varchar(5), constraints fk3 foreign key(supplier_code) references supplier(supplier_code), constraints fk4 foreign key(item_code) references item(item_code));

Table created.

Inserting the values into tables:

SQL> insert into item values 2 ('&item_code','& item_name ',&qty_in_stock,&reorder_level);Enter value for item_code: i303Enter value for item_name: drivesEnter value for qty_in_stock: 30Enter value for reorder_level: 18

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old 2: ('&item_code','&item_name','&qty_in_stock','&reorder_level')new 2: ('i303','drives','30','18')

1 row created.

SQL> /Enter value for item_code: i404Enter value for item_name: keysEnter value for qty_in_stock: 35Enter value for reorder_level: 20old 2: ('&item_code','&item_name','&qty_in_stock','&reorder_level')new 2: ('i404','keys','35','20')

1 row created.

SQL> insert into supplier values 2 ('&SUPPLIER_CODE','&SUPPLIER_NAME','&ADDRESS');Enter value for supplier_code: s111Enter value for supplier_name: abcdEnter value for address: xxxxold 2: ('&supplier_code','&supplier_name','&address')new 2: ('s111','abcd','xxxx')

1 row created.

SQL> /Enter value for supplier_code: s222Enter value for supplier_name: efghEnter value for address: yyyyold 2: ('&supplier_code','&supplier_name','&address')new 2: ('s222','efgh','yyyy')

1 row created.SQL> insert into can_supply values 2 ('&supplier_code','&item_code');Enter value for supplier_code: s222Enter value for item_code: i202old 2: ('&supplier_code','&item_code')new 2: ('s222','i202')

1 row created.SQL> /Enter value for supplier_code: s333Enter value for item_code: i303old 2: ('&supplier_code','&item_code')new 2: ('s333','i303')

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1 row created.

SQL> select * from item;

ITEM_ ITEM_N QTY_IN_STOCK REORDER_LEVEL-------- ----------- --------------------- -----------------------i101 cpu 25 5i202 mouse 20 15i303 drives 30 18i404 keys 35 20i505 pens 21 13

SQL> select * from supplier;

SUPPL SUPPLI ADDRESS-------- ----------- --------------s111 abcd xxxxs222 efgh yyyys333 ijkl zzzzs444 mnop wwwws555 rstu vvvv

(a) Queries: (i) SQL> select * from supplier where supplier_code = (select supplier_code from can_supply where item_code = (select item_code from item where item_name='drives'));

SUPPL SUPPLI ADDRESS--------- ---------- -------------s333 ijkl zzzz

(ii) SQL> select * from item where item_code not in (select item_code from can_supply where supplier_code = ( select supplier_code from supplier where supplier_name='ijkl'));

ITEM_ ITEM_N QTY_IN_STOCK REORDER_LEVEL------- --------- ---------------------- -------------------------i101 cpu 25 5i202 mouse 20 15i404 keys 35 20i505 pens 21 13

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8. Create the following table: Student(roll-no,marks,category, district, state) Student-rank(roll-no, marks,rank) (a) Generate queries to do the following : (i) List all those students who have come from tamilnadu state ans secured a rank above 100. (ii) List all those students who have come from Anshra Pradesh state and belong to given category who have secured a rank above 100.

PROGRAM:


SQL>create table student_07 2 (roll_no varchar(6) primary key, 3 marks number(3), 4 category varchar(15), 5 district varchar(10), 6 state varchar(18));Table created.

SQL> create table student_rank 2 (roll_no varchar(6),

3 marks number(3), 4 rank number(5), 5 constraints fk_7 foreign key(roll_no) references student_07(roll_no));

Table created.

Inserting values into tables:

SQL> insert into student_07 values 2 ('&roll_no','&marks','&category','&district','&state');

Enter value for roll_no: nmca01Enter value for marks: 150Enter value for category: apptitudeEnter value for district: chennaiEnter value for state: tamilnaduold 2: ('&roll_no','&marks','&category','&district','&state')new 2: ('nmca01','150','apptitude','chennai','tamilnadu')

1 row created.

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SQL>/Enter value for roll_no: nmca05Enter value for marks: 350Enter value for category: reasoningEnter value for district: kurnoolEnter value for state: andhrapradeshold 2: ('&roll_no','&marks','&category','&district','&state')new 2: ('nmca05','350',' reasoning','kurnool','andhrapradesh')

1 row created.

SQL> insert into student_rank values 2 ('&roll_no','&marks','&rank');

Enter value for roll_no: nmca01Enter value for marks: 150Enter value for rank: 50old 2: ('&roll_no','&marks','&rank')new 2: ('nmca01','150','7')

1 row created.

SQL> /Enter value for roll_no: nmca02Enter value for marks: 200Enter value for rank: 150old 2: ('&roll_no','&marks','&rank')new 2: ('nmca02','200','150')

1 row created

SQL> select * from student_07;

ROLL_N MARKS CATEGORY DISTRICT STATE----------- ----------- ----------------- ------------- ----------nmca01 150 apptitude chennai tamilnadunmca02 200 apptitude mailadu tamilnadunmca03 250 reasoning trivan tamilnadunmca04 300 reasoning hyd andhrapradeshnmca05 350 reasoning kurnool andhrapradeshnmca06 400 apptitude guntur andhrapradeshnmca07 450 apptitude vizag andhrapradesh

7 rows selected.

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SQL> select * from student_rank;

ROLL_N MARKS RANK----------- ----------- ----------nmca01 150 400nmca02 200 350nmca03 250 300nmca04 300 250nmca05 350 200nmca06 400 150nmca07 450 50

7 rows selected.

(a) Queries:

(i) select * from student_07 where state='tamilnadu' and roll_no in (select roll_no from student_rank where rank>100);

ROLL_N MARKS CATEGORY DISTRICT STATE----------- ---------- ---------------- -------------- ---------nmca02 200 apptitude mailadu tamilnadunmca03 250 reasoning trivan tamilnadu (ii) SQL> select * from student_07 where state='andhrapradesh' and category='apptitude' and roll_no in (select roll_no from student_rank where rank>100);

ROLL_N MARKS CATEGORY DISTRICT STATE----------- ---------- ---------------- -------------- ------------

nmca06 400 apptitude guntur andhrapradesh

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9. Create the following table: Branch (branch-id, branch-name, branch-city) Customer (customer-id, customer-name, customer-city, branch-id) (a) Create a form to accept the data from the user with appropriate validation checks (b) Generate queries to do the following: (i) List all those customers who live in the same city as the branch in which they have account. (ii) List all those customers who have an account in a given branch city.

PROGRAM:


SQL> create table branch_09 2 (branch_id varchar(6) primary key, 3 branch_name varchar(8), 4 branch_city varchar(15)):

Table created.

SQL> create table customer_09 2 (customer_id varchar(6) primary key,

3 customer_name varchar(10), 4 customer_city varchar(15),

5 branch_id varchar(6), 6constraints fk09 foreign key(branch_id) references branch_09(branch_id));Table created.

SQL> insert into branch_09 values 2 ('&branch_id','&branch_name','&branch_city');Enter value for branch_id: sbh01Enter value for branch_name: sbhEnter value for branch_city: hydold 2: ('&branch_id','&branch_name','&branch_city')new 2: ('sbh01','sbh','hyd')

1 row created.

SQL> /Enter value for branch_id: sbh02Enter value for branch_name: sbhEnter value for branch_city: hydold 2: ('&branch_id','&branch_name','&branch_city')

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new 2: ('sbh02','sbh','hyd')

SQL> insert into customer_09 values 2 ('&customer_id','&customer_name','&customer_city','&branch_id');

Enter value for customer_id: cus01Enter value for customer_name: abcdeEnter value for customer_city: hydEnter value for branch_id: sbh01old 2: ('&customer_id','&customer_name','&customer_city','&branch_id')new 2: ('cus01','abcde','hyd','sbh01')

1 row created.

SQL> /Enter value for customer_id: cuso2Enter value for customer_name: fghijEnter value for customer_city: kurnoolEnter value for branch_id: sbh02old 2: ('&customer_id','&customer_name','&customer_city','&branch_id')new 2: ('cuso2','fghij','kurnool','sbh02')

1 row created.SQL> select * from branch_09;

BRANCH BRANCH_N BRANCH_CITY------------- ---------------- ---------------------sbh01 sbh hydsbh02 sbh hydsbh03 sbh kurnoolicci01 icci hydicci02 icci hydicci03 icci kurnool

6 rows selected.

SQL> select * from customer_09;

CUSTOM CUSTOMER_N CUSTOMER_CITY BRANCH------------ --------------------- ------------------------ ---------------cus01 abcde hyd sbh01cuso2 fghij kurnool sbh02cus03 klmno hyd sbh03cus04 pqrst xxxx icci01cus05 uvwxy hyd icci02

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cus06 sjfkdl kurnool icci03

6 rows selected. (a) Queries:

(i) select * from customer_09 where branch_id in (select branch_id from branch_09 where branch_city=customer_city);

CUSTOM CUSTOMER_N CUSTOMER_CITY BRANCH------------ -------------------- ------------------------ -------------cus01 abcde hyd sbh01cus05 uvwxy hyd icci02cus06 sjfkdl kurnool icci03

(ii) SQL> select * from customer_09 where branch_id in (select branch_id from branch_09 where branch_city='kurnool');

CUSTOM CUSTOMER_N CUSTOMER_CITY BRANCH------------ ------------------- ------------------------ ------------cus03 klmno hyd sbh03cus06 sjfkdl kurnool icci03

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10. Create the following tables: Book (accession no, title, publisher, year, date-of-purchase, status) Member (member-id, number-of-books-issued, max-limit) Book-issue (accession-no, member-id, date-of-issue) (b) Generate the following to do the following: (i) List all those books which are due from the students to be returned. A book is

considered to be isuued 15 days back and yet not returned. (ii) List all those members who cannot be issued any more books

PROGRAM:


SQL> create table book_10 2 (accession_no varchar(7) primary key, 3 title varchar(10), 4 publisher varchar(10), 5 year date, 6 date_of_purchase date, 7 status varchar(8));Table created.

SQL> create table memeber 2 (memeber_id varchar(5) primary key, 3 name varchar(8), 4 number_of_books_issued number(2), 5 max_limit number(2));

Table created.

SQL> create table book_issue 2 (accession_no varchar(7), 3 memeber_id varchar(5), 4 date_of_issue date, 5 constraints fk_10 foreign key(accession_no) references book_10(accession_no), 6 constraints fk10 foreign key(memeber_id) references memeber(memeber_id));

Table created.

Inserting values into table:

SQL> insert into book_10 values

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2 ('&ACCESSION_NO','&TITLE','&PUBLISHER','&YEAR','& DATE_OF_PURCHASE','&STATUS');

Enter value for accession_no: mca2110Enter value for title: dbmsEnter value for publisher: tataEnter value for year: 06-sep-2005Enter value for date_of_purchase: 08-oct-2006Enter value for status: issuedold 2: ('&ACCESSION_NO','&TITLE','&PUBLISHER','&YEAR','&

DATE_OF_PURCHASE','&STATUS')new 2: ('mca2110','dbms','tata','06-sep-2005','08-oct-2006','issued')

1 row created.

SQL> /Enter value for accession_no: mca2115Enter value for title: c++Enter value for publisher: lllEnter value for year: 19-dec-2000Enter value for date_of_purchase: 20-apr-2001Enter value for status: notissueold 2: ('&ACCESSION_NO','&TITLE','&PUBLISHER','&YEAR','&

DATE_OF_PURCHASE','&STATUS')new 2: ('mca2115','c++','lll','19-dec-2000','20-apr-2001','notissue')

1 row created.

SQL> insert into memeber values 2 ('&MEMEBER_ID','&NAME','&NUMBER_OF_BOOKS_ISSUED','&MAX_LIMIT');Enter value for memeber_id: mc21Enter value for name: xxxxxEnter value for number_of_books_issued: 2Enter value for max_limit: 3old 2: ('&MEMEBER_ID','&NAME','&NUMBER_OF_BOOKS_ISSUED','&MAX_LIMIT')new 2: ('mc21','xxxxx','2','3')

1 row created

SQL> /Enter value for memeber_id: mc22Enter value for name: yyyyyEnter value for number_of_books_issued: 3Enter value for max_limit: 3old 2: ('&MEMEBER_ID','&NAME','&NUMBER_OF_BOOKS_ISSUED','&MAX_LIMIT')

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new 2: ('mc22','yyyyy','3','3')

1 row created.

SQL> insert into book_issue values 2 ('&ACCESSION_NO','&MEMEBER_ID','&DATE_OF_ISSUE');

Enter value for accession_no: mca2114Enter value for memeber_id: mc25Enter value for date_of_issue: 27-sep-2008old 2: ('&ACCESSION_NO','&MEMEBER_ID','&DATE_OF_ISSUE')new 2: ('mca2114','mc25','27-sep-2008')

1 row created.

SQL> /Enter value for accession_no: mca2115Enter value for memeber_id: mc26Enter value for date_of_issue: 15-sep-2008old 2: ('&ACCESSION_NO','&MEMEBER_ID','&DATE_OF_ISSUE')new 2: ('mca2115','mc26','15-sep-2008')

1 row created.

SQL> select * from book_10;

ACCESSI TITLE PUBLISHER YEAR DATE_OF_PUR STATUS------------ -------- -------------------------- -------------------- ----------mca2110 dbms tata 06-SEP-05 08-OCT-06 issuedmca2111 os galvin 01-JAN-01 01-FEB-01 issuedmca2112 or sharma 02-MAR-99 06-DEC-00 notissuemca2113 icg xxxxx 05-APR-95 06-MAY-96 issuedmca2114 dcn yyyyy 06-OCT-96 08-NOV-97 issuedmca2115 c++ ll 19-DEC-00 20-APR-01 notissue

6 rows selected.

SQL> select * from memeber;

MEMEB NAME NUMBER_OF_BOOKS_ISSUED MAX_LIMIT---------- --------- ------------------------------------------ ------------------mc21 xxxxx 2 3mc22 yyyyy 3 3mc33 llllll 2 3mc24 mmmmm 3 3mc25 rrrrr 3 3mc26 pppp 3 4

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6 rows selected.

SQL> select * from book_issue;

ACCESSI MEMEB DATE_OF_I------- ----- ---------mca2110 mc21 01-OCT-08mca2111 mc22 20-SEP-08mca2112 mc33 06-OCT-08mca2113 mc24 25-SEP-08mca2114 mc25 27-SEP-08mca2115 mc26 15-SEP-08

6 rows selected.

(b) Queries:

(i)SQL> select * from book_issue where (months_between(sysdate,date_of_issue)*30>15);

ACCESSI MEMEB DATE_OF_ISSUE------------ ----------- -----------------------mca2111 mc22 20-SEP-08mca2115 mc26 15-SEP-08

(ii) SQL> select * from memeber where number_of_books_issued=max_limit;

MEMEB NAME NUMBER_OF_BOOKS_ISSUED MAX_LIMIT----------- -------- ------------------------------------------ -----------------mc22 yyyyy 3 3mc24 mmmmm 3 3mc25 rrrrr 3 3

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11. Create the following tables: Book (accession no, title, publisher, year, date-of-purchase, status) Member (member-id, number-of-books-issued, max-limit) Book-issue (accession-no, member-id, date-of-issue) (b) Write a PL/SQL procedure to issue the book. Write a trigger to set the status of student to “back listed” if they have taken book

but not returned even one year.

PROGRAM:

Creating Tables:

SQL> create table book_11 2 (accession_no varchar(7) primary key, 3 title varchar(10), 4 publisher varchar(10), 5 year date, 6 date_of_purchase date, 7 status varchar(8));

Table created.SQL> create table member

2 (memeber_id varchar(5) primary key, 3 name varchar(8), 4 number_of_books_issued number(2), 5 max_limit number(2));

Table created.

SQL> create table book_issue 2 (accession_no varchar(7), 3 memeber_id varchar(5), 4 date_of_issue date, 5 constraints fk_10 foreign key(accession_no) references book_10(accession_no), 6 constraints fk10 foreign key(memeber_id) references memeber(memeber_id));

Table created


SQL> insert into book_11 values 2 ('&accession_no','&title','&publisher','&year','&date_of_purchase','&status');Enter value for accession_no: mca2110

37

Enter value for title: dbmsEnter value for publisher: tataEnter value for year: 06-sep-2005Enter value for date_of_purchase: 08-oct-2001Enter value for status: issuedold 2: ('&accession_no','&title','&publisher','&year','&date_of_purchase','&status')new 2: ('mca2110','dbms','tata','06-sep-2005','08-oct-2001','issued')

1 row created.

SQL> /Enter value for accession_no: mca2111Enter value for title: orEnter value for publisher: galvinEnter value for year: 01-jan-2001Enter value for date_of_purchase: 01-feb-2001Enter value for status: issuedold 2: ('&accession_no','&title','&publisher','&year','&date_of_purchase','&status')new 2: ('mca2111','or','galvin','01-jan-2001','01-feb-2001','issued')

1 row created.

SQL> insert into member values 2 ('&MEMBER_ID','&NAME','&NUMBER_OF_BOOKS_ISSUED','&MAX_LIMIT');Enter value for member_id: mc21Enter value for name: xxxxxEnter value for number_of_books_issued: 2Enter value for max_limit: 3old 2: ('&MEMBER_ID','&NAME','&NUMBER_OF_BOOKS_ISSUED','&MAX_LIMIT')new 2: ('mc21','xxxxx','2','3')

1 row created.

SQL> /Enter value for member_id: mc22Enter value for name: yyyyyEnter value for number_of_books_issued: 3Enter value for max_limit: 3old 2: ('&MEMBER_ID','&NAME','&NUMBER_OF_BOOKS_ISSUED','&MAX_LIMIT')new 2: ('mc22','yyyyy','3','3')

1 row created.

38

SQL> insert into book_issue_11 values 2 ('&ACCESSION_NO','&MEMBER_ID','&DATE_OF_ISSUE');Enter value for accession_no: mca2110Enter value for member_id: mc21Enter value for date_of_issue: 01-oct-2007old 2: ('&ACCESSION_NO','&MEMBER_ID','&DATE_OF_ISSUE')new 2: ('mca2110','mc21','01-oct-2007')

1 row created.

SQL> /Enter value for accession_no: mca2111Enter value for member_id: mc22Enter value for date_of_issue: 20-sep-2008old 2: ('&ACCESSION_NO','&MEMBER_ID','&DATE_OF_ISSUE')new 2: ('mca2111','mc22','20-sep-2008')


ACCESSI TITLE PUBLISHER YEAR DATE_OF_P STATUS------------ ------- ----------------- -------- ---------------- -----------mca2110 dbms tata 06-SEP-05 08-OCT-01 issuedmca2111 or galvin 01-JAN-01 01-FEB-01 issuedmca2112 os sharma 02-MAR-99 06-DEC-00 notissuemca2113 icg xxxxx 05-APR-95 06-MAY-96 issuedmca2114 dcn yyyyy 06-OCT-96 08-NOV-97 issuedmca2115 c++ llll 19-DEC-00 20-APR-01 notissue

6 rows selected.

SQL> select * from member;

MEMBE NAME NUMBER_OF_BOOKS_ISSUED MAX_LIMIT---------- -------- ----------------------------------------- ----------------mc21 xxxxx 2 3mc22 yyyyy 3 3mc23 lllll 2 3mc24 mmmmm 3 3mc25 rrrrr 3 3mc26 ppppp 3 4

6 rows selected

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SQL> select * from book_issue_11;

ACCESSI MEMBE DATE_OF_I------------ ----------- ----------------mca2110 mc21 01-OCT-07mca2111 mc22 20-SEP-08mca2112 mc23 06-OCT-08mca2113 mc23 25-SEP-07mca2114 mc24 27-SEP-07mca2115 mc25 15-SEP-08

6 rows selected.

PROCEDURE:

SQL>create or replace procedure p11 isac_no book_11.accession_no%type;sta book_11.status%type;bookissued exception;begin

ac_no:='&ac_no'; select status into sta from book_11 where accession_no=ac_no; if(sta='notissue') then update book_11 set status='issued' where accession_no=ac_no; dbms_output.put_line('book issued'); else raise bookissued; end if; exception when bookissued then dbms_output.put_line('already book has been issued');

end;SQL>/Enter value for ac_no: mca2112old 6: ac_no:='&ac_no';new 6: ac_no:='mca2112';book issued

SQL>exec p11; Book issued.

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3L/SQL procedure successfully completed.

select * from book_11;

ACCESSI TITLE PUBLISHER YEAR DATE_OF_P STATUS------------ ---------- ---------------- -------- ----------------- -----------mca2110 dbms tata 06-SEP-05 08-OCT-01 issuedmca2111 or galvin 01-JAN-01 01-FEB-01 issuedmca2112 os sharma 02-MAR-99 06-DEC-00 issuedmca2113 icg xxxxx 05-APR-95 06-MAY-96 issuedmca2114 dcn yyyyy 06-OCT-96 08-NOV-97 issuedmca2115 c++ llll 19-DEC-00 20-APR-01 notissue

6 rows selected.

Trigger:

SQL> create or replace trigger t12 before insert or update on book_issue for each row begin if(:new.date_of_issue<'01-jan-2007') then update book_11 set status='back listed'; end if; end;SQL> /

Trigger created.

Execution of trigger:

SQL> insert into book_issue values ('mca2156','mc27','01-dec-2006')SQL> /insert into book_issue *ERROR at line 1:ORA-04098: trigger 'SCOTT.BOOKTRIGGER' is invalid and failed re-validationORA-06512: at "SCOTT.T12", line 3ORA-04088: error during execution of trigger 'SCOTT.T12'

41

12. Create the following Book (accession-no, title, publisher, year, date-of-purchase) Book-place (accession-no, rack-id, rack-position) Member (member-id, name, number-of-books-issued, max-limit, status) Book-issue (accession-no, member-id, date-of-purchase) (a) Write a PL/SQL procedure to issue the book (b) Write a trigger to set the status of the book neither to “lost” which is neither issued nor in the library.

PROGRAM:

Creating Tables:

SQL> create table book_12 2 (accession_no varchar(7) primary key, 3 title varchar(10), 4 publisher varchar(8), 5 year number(4), 6 date_of_purchase date, 7 status varchar(11));

Table created.

SQL> create table book_place_12 2 (accession_no varchar(7), 3 rack_id varchar(5), 4 rack_position varchar(5), 5 constraints fkk foreign key(accession_no) references book_12(accession_no));

Table created.

SQL> create table member_12 2 (member_id varchar(7) primary key, 3 name varchar(5), 4 no_of_bokks_issued number(2), 5 max_limit number(2), 6 status varchar(11));

Table created. SQL> create table book_issue_12 2 (accession_no varchar(7), 3 member_id varchar(7), 4 date_of_issue date,

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5 constraints fk12 foreign key(accession_no) references book_12(accession_no), 6 constraints fk_12 foreign key(member_id) references member_12(member_id));

Table created.

Inserting Values into table:

(i) Into table book_12 SQL> insert into book_12 values 2 ('&accession_no','&title','&publisher',&year,'&date_of_purchase','&status'); Enter value for accession_no: mca2113Enter value for title: icgEnter value for publisher: wwwwwEnter value for year: 2005Enter value for date_of_purchase: 13-oct-2006Enter value for status: issuedold 2: ('&accession_no','&title','&publisher',&year,'&date_of_purchase','&status')new 2: ('mca2113','icg','wwwww',2005,'13-oct-2006','issued')

1 row created.

SQL> /Enter value for accession_no: mca2114Enter value for title: dcnEnter value for publisher: ggggEnter value for year: 2007Enter value for date_of_purchase: 25-jan-2007Enter value for status: not issuedold 2: ('&accession_no','&title','&publisher',&year,'&date_of_purchase','&status')new 2: ('mca2114','dcn','gggg',2007,'25-jan-2007','not issued')

1 row created.


ACCESSI TITLE PUBLISHE YEAR DATE_OF_P STATUS------------ -------- -------------- -------- ---------------- ----------mca2110 dbms tata 2000 06-OCT-01 issuedmca2111 os xxxx 1995 15-NOV-96 not issuedmca2112 or yyyy 2001 14-OCT-01 not issuedmca2113 icg wwwww 2005 13-OCT-06 issuedmca2114 dcn gggg 2007 25-JAN-07 not issued

43

mca2115 c++ jjjj 1995 09-SEP-96 not issued

6 rows selected.

(ii) Into book_place_12

SQL> insert into book_place_12 values 2 ('&ACCESSION_NO','&RACK_ID','&RACK_POSITION');Enter value for accession_no: mca2110Enter value for rack_id: 01Enter value for rack_position: 11old 2: ('&ACCESSION_NO','&RACK_ID','&RACK_POSITION')new 2: ('mca2110','01','11')

1 row created.

SQL> /Enter value for accession_no: mca2111Enter value for rack_id: 02Enter value for rack_position: 12old 2: ('&ACCESSION_NO','&RACK_ID','&RACK_POSITION')new 2: ('mca2111','02','12')

1 row created.

SQL> select * from book_place_12;ACCESSI RACK_ ID RACK_POSI------------ ------------ -----------------mca2110 01 11mca2111 02 12mca2112 03 00mca2113 04 14mca2114 05 01mca2115 06 15

6 rows selected.

(iii) Into table member_12

SQL> insert into member_12 values ('&MEMBER_ID','&NAME',&NO_OF_BOKKS_ISSUED,&MAX_LIMIT,'&STATUS');Enter value for member_id: m1211Enter value for name: abcd

44

Enter value for no_of_bokks_issued: 2Enter value for max_limit: 4Enter value for status: can issue

old 2: ('&MEMBER_ID','&NAME',&NO_OF_BOKKS_ISSUED,&MAX_LIMIT,'&STATUS')new 2: ('m1211','abcd',2,4,'can issue')

1 row created.

SQL> /Enter value for member_id: mc1212Enter value for name: efghEnter value for no_of_bokks_issued: 4Enter value for max_limit: 4Enter value for status: cant issueold 2: ('&MEMBER_ID','&NAME',&NO_OF_BOKKS_ISSUED,&MAX_LIMIT,'&STATUS')new 2: ('mc1212','efgh',4,4,'cant issue')

1 row created.

SQL> select * from member_12;

MEMBER_ NAME NO_OF_BOKKS_ISSUED MAX_LIMIT STATUS------- ----- ------------------ ---------- -----------mc1211 abcd 2 4 can issuemc1212 defg 4 4 cant issuemc1213 efgh 4 4 cant issuemc1214 ghij 1 3 can issuemc1215 jklm 0 4 can issuemc1216 mnop 3 4 can issue

6 rows selected..

(iv) Into book-issue SQL> insert into book_issue_12 values

2 ('&accession_no','&member_id','&date_of_issue');

Enter value for accession_no: mca2110Enter value for member_id: m1211Enter value for date_of_issue: 01-sep-2008old 2: ('&accession_no','&member_id','&date_of_issue')

45

new 2: ('mca2110','m1211','01-sep-2008')

1 row created.

SQL> /Enter value for accession_no: mca2111Enter value for member_id: mc1212Enter value for date_of_issue: 05-sep-2008old 2: ('&accession_no','&member_id','&date_of_issue')new 2: ('mca2111','mc1212','05-sep-2008')

1 row created.


ACCESSI MEMBER_ DATE_OF_I------------ -------------- ----------------mca2110 m1211 01-SEP-08mca2111 mc1212 05-SEP-08mca2112 mc1213 01-OCT-08mca2113 mc1214 08-SEP-08mca2114 mc1215 05-OCT-08mca2115 mc2116 25-SEP-08

6 rows selected.

(b) PROCEDURE: SQL> create or replace procedure p12 is 2 ac_no book_12.accession_no%type; 3 sta book_12.status%type; 4 bookissued exception; 5 begin 6 ac_no:='&ac_no'; 7 select status into sta from book_12 where accession_no=ac_no; 8 if(sta='not issued') then 9 update book_12 set status='issued' where accession_no=ac_no; 10 dbms_output.put_line('book issued'); 11 else 12 raise bookissued; 13 end if; 14 exception 15 when bookissued then 16 dbms_output.put_line('already book has been issued');

46

17 end; 18 /Enter value for ac_no: mca2111old 6: ac_no:='&ac_no';new 6: ac_no:='mca2111';

Procedure created.

SQL> exec p12;

book issued



ACCESSI TITLE PUBLISHE YEAR DATE_OF_P STATUS------------- -------- --------------- -------- ----------------- ------------mca2110 dbms tata 2000 06-OCT-01 issuedmca2111 os xxxx 1995 15-NOV-96 issuedmca2112 or yyyy 2001 14-OCT-01 not issuedmca2113 icg wwwww 2005 13-OCT-06 issuedmca2114 dcn gggg 2007 25-JAN-07 not issuedmca2115 c++ jjjj 1995 09-SEP-96 not issued

6 rows selected.

SQL>create or replace trigger t122 before insert or update on book_place_12 for each row begin

if((:new.rack_position=00)) then update book_12 set status='lost'; end if;

end;SQL> /

Trigger created.

47

13. Create the following Book (accession-no, title, publisher, year, date-of-purchase) Member (member-id, name, number-of-books-issued, max-limit, status) Book-issue (accession-no, member-id, date-of-purchase ,due-date) (a) Write a PL/SQL to list all thos estudents who are defaulters. A student is considered

to be a defaulter if he has not returned a book even after the due-date (b) Write a trigger to set the status of the student to“back listed”if they have taken book

but not returned even after one year.

PROGRAM:

Creating Tables:

SQL> create table book_13 2 (accession_no varchar(7) primary key, 3 title varchar(10), 4 publisher varchar(8), 5 year number(4), 6 date_of_purchase date, 7 status varchar(11));

Table created.

SQL> create table member_13 2 (member_id varchar(7) primary key, 3 name varchar(5), 4 no_of_books_issued number(2), 5 max_limit number(2), 6 status varchar(11));

Table created.

SQL> create table book_issue_13 2 (accession_no varchar(7), 3 member_id varchar(7), 4 date_of_issue date, 5 Due_date date, 6 constraints fk13 foreign key(accession_no) references book_13(accession_no), 7 constraints fk_13 foreign key(member_id) references member_13(member_id));

Table created.

48


ACCESSI TITLE PUBLISHE YEAR DATE_OF_P STATUS------- ---------- -------- ---------- --------- -----------mca2110 dbms tata 2000 06-OCT-01 issuedmca2111 os xxxx 1995 15-NOV-96 not issuedmca2112 or yyyy 2001 14-OCT-01 not issuedmca2113 icg wwwww 2005 13-OCT-06 issuedmca2114 dcn gggg 2007 25-JAN-07 not issuedmca2115 c++ jjjj 1995 09-SEP-96 not issued

6 rows selected.

SQL> select * from member_13;

MEMBER_ NAME NO_OF_BOOKS MAX_LIMIT STATUS------- ----- ----------- ---------- -----------mc1211 abcd 2 4 can issuemc1212 defg 4 4 cant issuemc1213 efgh 4 4 cant issuemc1214 ghij 1 3 can issuemc1215 jklm 0 4 can issuemc1216 mnop 3 4 can issue

6 rows selected.


ACCESSI MEMBER_ DATE_OF_I DUE_DATE------- ------- --------- ---------mca2110 mc1211 01-SEP-07 01-SEP-08mca2111 mc1212 05-SEP-08 10-OCT-08mca2112 mc1213 01-OCT-05 30-OCT-07mca2113 mc1214 08-SEP-08 28-SEP-08mca2114 mc1215 05-OCT-08 28-OCT-08mca2115 mc1216 25-SEP-07 25-SEP-08

6 rows selected.

49

Procedure:

SQL> declare 2 cursor c13 is select * from book_issue_13 where months_between(sysdate,date_of_isue)/12>1; 3 str_ac_no book_issue_13.accession_no%type; 4 str_m_id book_issue_13.member_id%type; 5 dt_issuedate book_issue_13.date_of_isue%type; 6 dt_due book_issue_13.due_date%type; 7 begin 8 dbms_output.put_line('DEFAULTERS'); 9 dbms_output.put_line('acession_no member_id date_of_issue due_date '); 10 open c13; 11 loop 12 fetch c13 into str_ac_no,str_m_id,dt_issuedate,dt_due ; 13 dbms_output.put_line(str_ac_no ||str_m_id ||dt_issuedate ||dt_due); 14 exit when c13 % notfound; 15 end loop; 16 close c13; 17* end;

SQL> /

DEFAULTERSacession_no member_id date_of_issue due_datemca2110 mc1211 01-SEP-07 01-SEP-08mca2112 mc1213 01-OCT-05 30-OCT-07mca2115 mc1216 25-SEP-07 25-SEP-08


]Trigger:

SQL> create or replace trigger t13 before insert or update on book_issue for each row begin if(:new.date_of_issue<'01-jan-2007') then update book_13 set status='back listed'; end if; end;SQL> /

50

Trigger created.

Execution of trigger:

SQL> insert into book_issue values ('mca2156','mc27','01-dec-2006')SQL> /insert into book_issue *ERROR at line 1:ORA-04098: trigger 'SCOTT.BOOKTRIGGER' is invalid and failed re-validationORA-06512: at "SCOTT.T12", line 3ORA-04088: error during execution of trigger 'SCOTT.T12'

51

14. Create the following tables: Branch (branch-id, branch-name, branch_-city) Customer (customer-id, customer-name, customer-city, branch-id) (b) Generate queries to do the following: (i) List all those customers who live in the same city as the branch in which they have account. (ii) List all those customers who have an account in more than one branch. PROGRAM:

Creation of tables:

SQL> create table branch15 (branch_id number(5) primary key, branch_name varchar(15), branch_city varchar(15));

Table created.

SQL> create table customer15 (customer_id number(5) primary key, customer_name varchar(15), customer_city varchar(15));Table created.

SQL> create table branchcust15 (branch_id number(5), customer_id number(5), constraint fk_15 foreign key(branch_id) references branch15(branch_id), constraint fk_1555 foreign key(customer_id) references customer15(customer_id));

Table created.

Inserting values:

SQL> insert into branch15 values (&branch_id,'&branch_name','&branch_city');Enter value for branch_id: 001Enter value for branch_name: sbhEnter value for branch_city: hydold 2: (&branch_id,'&branch_name','&branch_city')new 2: (001,'sbh','hyd')

52

1 row created.

SQL> /Enter value for branch_id: 002Enter value for branch_name: andhraEnter value for branch_city: vizagold 2: (&branch_id,'&branch_name','&branch_city')new 2: (002,'andhra','vizag')

1 row created.

SQL> insert into customer15 values (&customer_id,'&customer_name','&customer_city');Enter value for customer_id: 101Enter value for customer_name: abcdEnter value for customer_city: khamamold 2: (&customer_id,'&customer_name','&customer_city')new 2: (101,'abcd','khamam')

1 row created.

SQL> /Enter value for customer_id: 102Enter value for customer_name: defgEnter value for customer_city: hydold 2: (&customer_id,'&customer_name','&customer_city')new 2: (102,'defg','hyd')

1 row created

SQL> insert into branchcust15 values (&branch_id,&customer_id);Enter value for branch_id: 10Enter value for customer_id: 101old 2: (&branch_id,&customer_id)new 2: (10,101)

1 row created.

SQL> /Enter value for branch_id: 10Enter value for customer_id: 102old 2: (&branch_id,&customer_id)new 2: (10,102)

1 row created.

53

SQL> select * from branch15;

BRANCH_ID BRANCH_NAME BRANCH_CITY---------- --------------- --------------- 10 sbh khamam 11 icici hyd 12 andhra secun 13 indian vizag 14 hdfc kurnool

SQL> select * from customer15;

CUSTOMER_ID CUSTOMER_NAME CUSTOMER_CITY-------------------- ------ ------------------- ----------------------- 101 abcd khamam 102 defg hyd 103 fghi secun 104 ijkl kurnool 105 lmno vizag 106 opqr hyd 107 stuv secun 108 wxyz secun 109 afrg secun

9 rows selected.

SQL> select * from branchcust15;

BRANCH_ID CUSTOMER_ID------------------ -------------------- 10 101 11 102 12 105 13 106 14 108 11 101 12 101 13 105 14 105 12 105

10 rows selected.

54

(b) Queries:

(i) select * from customer15 where customer_id in (select customer_id from branchcust15 where branch_id in (select branch_id from

branch15 where customer_city=branch_city));CUSTOMER_ID CUSTOMER_NAME CUSTOMER_CITY-------------------- -------------------------- -----------------------= 101 abcd khamam 102 defg hyd 105 lmno vizag

(ii) select * from customer15 where customer_id in (select customer_id from branchcust15 group by customer_id having count(branch_id)>1);

CUSTOMER_ID CUSTOMER_NAME CUSTOMER_CITY-------------------- --------------------------- ------------------------ 101 abcd khamam 105 lmno vizag

55

15. Create the following tables: Branch (branch-id, branch-name, branch_-city) Customer (customer-id, customer-name, customer-city, branch-id) (b) Generate queries to do the following: (i)List all those branches who have more than 2 customers. (ii) List all those customers who have an account in more than one branch. PROGRAM:

Creation of tables:

SQL> create table branch15 (branch_id number(5) primary key, branch_name varchar(15), branch_city varchar(15));

Table created.

SQL> create table customer15 (customer_id number(5) primary key, customer_name varchar(15), customer_city varchar(15));Table created.

SQL> create table branchcust15 (branch_id number(5), customer_id number(5), constraint fk_15 foreign key(branch_id) references branch15(branch_id), constraint fk_1555 foreign key(customer_id) references customer15(customer_id));

Table created.

Inserting values:

SQL> insert into branch15 values (&branch_id,'&branch_name','&branch_city');Enter value for branch_id: 001Enter value for branch_name: sbhEnter value for branch_city: hydold 2: (&branch_id,'&branch_name','&branch_city')new 2: (001,'sbh','hyd')

1 row created.

56

SQL> /Enter value for branch_id: 002Enter value for branch_name: andhraEnter value for branch_city: vizagold 2: (&branch_id,'&branch_name','&branch_city')new 2: (002,'andhra','vizag')

1 row created.

SQL> insert into customer15 values (&customer_id,'&customer_name','&customer_city');Enter value for customer_id: 101Enter value for customer_name: abcdEnter value for customer_city: khamamold 2: (&customer_id,'&customer_name','&customer_city')new 2: (101,'abcd','khamam')

1 row created.

SQL> /Enter value for customer_id: 102Enter value for customer_name: defgEnter value for customer_city: hydold 2: (&customer_id,'&customer_name','&customer_city')new 2: (102,'defg','hyd')

1 row created

SQL> insert into branchcust15 values (&branch_id,&customer_id);Enter value for branch_id: 10Enter value for customer_id: 101old 2: (&branch_id,&customer_id)new 2: (10,101)

1 row created.

SQL> /Enter value for branch_id: 10Enter value for customer_id: 102old 2: (&branch_id,&customer_id)new 2: (10,102)

1 row created.

57

SQL> select * from branch15;

BRANCH_ID BRANCH_NAME BRANCH_CITY---------- --------------- --------------- 10 sbh khamam 11 icici hyd 12 andhra secun 13 indian vizag 14 hdfc kurnool

SQL> select * from customer15;

CUSTOMER_ID CUSTOMER_NAME CUSTOMER_CITY-------------------- ------ ------------------- ----------------------- 101 abcd khamam 102 defg hyd 103 fghi secun 104 ijkl kurnool 105 lmno vizag 106 opqr hyd 107 stuv secun 108 wxyz secun 109 afrg secun

9 rows selected.

SQL> select * from branchcust15;

BRANCH_ID CUSTOMER_ID------------------ -------------------- 10 101 11 102 12 105 13 106 14 108 11 101 12 101 13 105 14 105 12 105

(i)select * from branch15 where branch_id in (select branch_id from branchcust15 group by branch_id having count(customer_id)>2);

58

BRANCH_ID BRANCH_NAME BRANCH_CITY---------- ------- --------- -------------- --------------- 12 andhra secun

(ii) select * from customer15 where customer_id in (select customer_id from branchcust15 group by customer_id having count(branch_id)>1);

CUSTOMER_ID CUSTOMER_NAME CUSTOMER_CITY-------------------- --------------------------- ------------------------ 101 abcd khamam 105 lmno vizag

59

16. Create the following table: Student (roll-no, name, category, district, state) Student-rank (roll-no, marks, rank) (b) Generate queries to do the following : (i) List names of the students who are having same rank bur they should reside in

different districts. (ii) List details of students they belongs to same category with same tank. PROGRAM:

Creation of tables:

SQL> create table student16 2 (roll_no number(5) primary key, 3 name varchar(15), 4 category varchar(10), 5 district varchar(15), 6 state varchar(5));

Table created.

SQL> create table student_rank16 2 (roll_no number(5), 3 marks number(5), 4 rank number(3), 5 constraint fk_16 foreign key(roll_no)references student16(roll_no));

Table created.

Inserting Values:

SQL> insert into student16 values (&roll_no,'&name','&category','&district','&state');Enter value for roll_no: 09Enter value for name: abcEnter value for category: mathsEnter value for district: rrrEnter value for state: vvvold 2: (&roll_no,'&name','&category','&district','&state')new 2: (09,'abc','maths','rrr','vvv')

1 row created.

60

SQL> /Enter value for roll_no: 10Enter value for name: defEnter value for category: mathsEnter value for district: xxxEnter value for state: yyyold 2: (&roll_no,'&name','&category','&district','&state')new 2: (10,'def','maths','xxx','yyy')

1 row created.

.

SQL> insert into student_rank16 values (&roll_no,&marks,&rank);Enter value for roll_no: 09Enter value for marks: 200Enter value for rank: 25old 2: (&roll_no,&marks,&rank)new 2: (09,200,25)

1 row created.

SQL> /Enter value for roll_no: 10Enter value for marks: 150Enter value for rank: 50old 2: (&roll_no,&marks,&rank)new 2: (10,150,50)

1 row created.

SQL> select * from student16;

ROLL_NO NAME CATEGORY DISTRICT STATE ------------- -------- ---------------- ------------- --------- 9 abc maths rrr vvv 10 def maths xxx yyy 11 ghi apptitude zzz bbb 12 jkl apptitude ttt ppp 13 mno reasoning xxx yyy 14 pqr reasoning sss ccc 15 stu apptitude www qqq

7 rows selected

61

SQL> select * from student_rank16;

ROLL_NO MARKS RANK ------------- ---------- -------- 9 200 25 10 150 50 11 150 50 12 300 20 13 150 50 14 400 10 15 150 50

create view A as select category,count(category) from student group by category having count(category)>1;

create view B as select student.rollno,A.category from student,A where student.category=a.category;

create view C as select rank,count(rank) from student_rank group by rank having count(rank)>1;

create view D as select student_rank.rollno,C.rank from student,C where student_rank.rank=C.rank;

create view E as select B.rollno,B.category,D.rank where B.rollno=D.rollno;

select student.rollno,student.name,student.district,student.state,E.category,E.rank where student.rollno=E.rollno;

62

http://student.name/

63

17. Create the following tables: Student (roll-no, name, date-of-birth, course-id) Course (course-id, name, fee, duration) (b) Generate queries to do the following: (i) List all those student who are between 10-19 years of age and have opted for MCA

course. (ii) List all those courses in which number of students are less than 10.

PROGRAM:

Creation of tables:

SQL> create table course17 2 ( course_id number(5) primary key, 3 name varchar(15), 4 fee number(10), 5 duration number(3));

Table created.

SQL> create table student17 2 ( roll_no number(5) primary key, 3 name varchar(15), 4 date_of_birth date, 5 course_id number(5), 6 constraints fk17 foreign key(course_id)references course17(course_id));

Table created.


SQL> insert into course17 values 2 (&course_id,'&name',&fee,&duration);

Enter value for course_id: 101Enter value for name: MCAEnter value for fee: 24700Enter value for duration: 3old 2: (&course_id,'&name',&fee,&duration)new 2: (101,'MCA',24700,3)

1 row created.

64

SQL> /Enter value for course_id: 102Enter value for name: MBAEnter value for fee: 20000Enter value for duration: 2old 2: (&course_id,'&name',&fee,&duration)new 2: (102,'MBA',20000,2)

1 row created.

SQL> /Enter value for course_id: 103Enter value for name: MScEnter value for fee: 15000Enter value for duration: 2old 2: (&course_id,'&name',&fee,&duration)new 2: (103,'MSc',15000,2)

1 row created.

SQL> insert into student17 values 2 (&roll_no,'&name','&date_of_birth',&course_id);

Enter value for roll_no: 27Enter value for name: rsEnter value for date_of_birth: 06-oct-1986Enter value for course_id: 103old 2: (&roll_no,'&name','&date_of_birth',&course_id)new 2: (27,'rs','06-oct-1986',103)

1 row created.

SQL> /Enter value for roll_no: 28Enter value for name: stEnter value for date_of_birth: 06-JUN-95Enter value for course_id: 103old 2: (&roll_no,'&name','&date_of_birth',&course_id)new 2: (28,'st','06-JUN-95',103)

1 row created.

65

SQL> select * from course17;

COURSE_ID NAME FEE DURATION ---------------- --------- ----- --------------- 101 MCA 24700 3 102 MBA 20000 2 103 MSc 15000 2


ROLL_NO NAME DATE_OF_B COURSE_ID ------------- --------- ----------------- --------------- 1 ab 01-JAN-90 101 2 bc 02-FEB-02 101 3 cd 03-MAR-88 101 11 ef 04-APR-85 101 12 fg 05-MAY-02 102 13 gh 06-JUN-95 102 19 ij 07-JUL-86 103 20 kl 08-AUG-89 103 21 lm 07-JUL-86 103 22 mn 08-AUG-89 103 23 no 01-JAN-99 103 24 op 02-FEB-00 103 25 pq 03-MAR-98 103 26 qr 04-APR-96 103 27 rs 06-OCT-86 103 28 st 06-JUN-95 103

16 rows selected.


COURSE_ID NAME FEE DURATION ---------------- --------- ------ ---------------- 101 MCA 24700 3 102 MBA 20000 2 103 MSc 15000 2

QUERIES:

(i) SQL> select * from student17 where roll_no in 2 (select roll_no from student17 where

66

3 (months_between(sysdate,date_of_birth)/12 between 18 and 19) ) 4* and course_id = (select course_id from course17 where name='MCA'); ROLL_NO NAME DATE_OF_B COURSE_ID -------------- ---------- ----------------- ---------------- 1 ab 01-JAN-90 101 11 ef 04-APR-90 101

(ii) select * from course17 where course_id in (select course_id from student17 group by course_id having count(roll_no)<10);

COURSE_ID NAME FEE DURATION ---------------- --------- ------- --------------- 101 MCA 24700 3 102 MBA 20000 2

67

18. Create the following tables: Student (roll_no, name,date_of_birth,course-id) Course (course-id, name, fee, duration, status) (b) Write PL/SQL procedure to do the following: Set the status of course to “not offered” in which the number of candidate is less than 5.

PROGRAM:

Creation of tables:

SQL> create table course18 2(course_id number(5) primary key, 3 name varchar(15), 4 fee number(10), 5 duration number(3), 6 status varchar(12));

Table created.

SQL> create table student18 2( roll_no number(5) primary key, 3 name varchar(15), 4 date_of_birth date, 5 course_id number(5), 6 constraints fk18 foreign key(course_id)references course17(course_id));

Table created.




1 row created.

68


1 row created.

SQL> insert into student17 values

2 (&roll_no,'&name','&date_of_birth',&course_id);Enter value for roll_no: 27Enter value for name: rsEnter value for date_of_birth: 06-oct-1986Enter value for course_id: 103old 2: (&roll_no,'&name','&date_of_birth',&course_id)new 2: (27,'rs','06-oct-1986',103)

1 row created.


1 row created.


COURSE_ID NAME FEE DURATION STATUS ---------------- --------- ------- --------------- ----------- 101 MCA 24700 3 offered 102 MBA 20000 2 offered 103 MSc 15000 2 offered

69



16 rows selected.

PROCEDURE:

SQL> declare 2 c_id course18.course_id%type; 3 ctr number; 4 cursor c18 is select course_id from course18; 5 begin 6 open c18; 7 loop 8 fetch c18 into c_id; 9 select count(roll_no) into ctr from student18 where course_id=c_id; 10 if(ctr<5) then 11 update course18 set status='not offered' where course_id=c_id; 12 dbms_output.put_line('tables has been updated'); 13 end if; 14 exit when c18 % notfound; 15 end loop; 16 close c18; 17 end;

18 /

70

OUTPUT:

tables has been updatedtables has been updated

PL/SQL procedure successfully completed. SQL>select * from course18;

COURSE_ID NAME FEE DURATION STATUS ---------------- --------- -------- --------------- ------------ 101 MCA 24700 3 not offered 102 MBA 20000 2 not offered 103 MSc 15000 2 offered

71

19. Create the following tables: Student (roll_no, name,date_of_birth,course-id) Course (course-id, name, fee, duration, status) (b) Write PL/SQL procedure to do the following: Set the status of course to “not offered” in which the number of candidate is less than 5.

PROGRAM:

Creation of tables:

SQL> create table course19 2(course_id number(5) primary key, 3 name varchar(15), 4 fee number(10), 5 duration number(3), 6 status varchar(12));

Table created.

SQL> create table student19 2( roll_no number(5) primary key, 3 name varchar(15), 4 date_of_birth date, 5 course_id number(5), 6 constraints fk18 foreign key(course_id)references course17(course_id));

Table created.




1 row created.

72


1 row created.



1 row created.


1 row created.


COURSE_ID NAME FEE DURATION STATUS ---------------- --------- ------- --------------- ----------- 101 MCA 24700 3 offered 102 MBA 20000 2 offered 103 MSc 15000 2 offered

73



16 rows selected.

PROCEDURE:

SQL> declare 2 c_id course18.course_id%type; 3 ctr number; 4 cursor c18 is select course_id from course18; 5 begin 6 open c18; 7 loop 8 fetch c18 into c_id; 9 select count(roll_no) into ctr from student18 where course_id=c_id; 10 if(ctr<5) then 11 update course18 set status='not offered' where course_id=c_id; 12 dbms_output.put_line('tables has been updated'); 13 end if; 14 exit when c18 % notfound; 15 end loop; 16 close c18; 17 end;

18 /

74

OUTPUT:

tables has been updatedtables has been updated

PL/SQL procedure successfully completed. SQL>select * from course18;

COURSE_ID NAME FEE DURATION STATUS ---------------- --------- -------- --------------- ------------ 101 MCA 24700 3 not offered 102 MBA 20000 2 not offered 103 MSc 15000 2 offered

75

20. Create the following tables: Student (roll-no, name, date_of_birth, course-id) Course (course-id, name, fee, duration, status) (b) Write PL/SQL procedure to do the following: Set the status of course to “offered” in which the number of candidate ist atleast 10 otherwise not offered.

PROGRAM:

Creation of tables :

SQL> create table course20 2 (course_id number(5) primary key, 3 name varchar(15), 4 fee number(10), 5 duration number(3), 6 status varchar(12));

Table created.

SQL> SQL> create table student20 2 ( roll_no number(5) primary key, 3 name varchar(15), 4 date_of_birth date, 5 course_id number(5), 6 constraints fk18 foreign key(course_id)references course17(course_id));

Table created.


SQL> insert into course20 values 2 (&course_id,'&name','&fee','&duration','&status') 3 ;Enter value for course_id: 101Enter value for name: MCAEnter value for fee: 24700Enter value for duration: 3Enter value for status: old 2: (&course_id,'&name','&fee','&duration','&status')new 2: (101,'MCA','24700','3','')

76

1 row created.

SQL> /Enter value for course_id: 102Enter value for name: MBAEnter value for fee: 20000Enter value for duration: 2Enter value for status: old 2: (&course_id,'&name','&fee','&duration','&status')new 2: (102,'MBA','20000','2','')

1 row created.



1 row created.


1 row created.


COURSE_ID NAME FEE DURATION STATUS ---------------- --------- ------- --------------- ----------- 101 MCA 24700 3 102 MBA 20000 2 103 MSc 15000 2

77



16 rows selected.

PROCEDURE:

SQL> declare 2 c_id course18.course_id%type; 3 ctr number; 4 cursor c20 is select course_id from course20; 5 begin 6 open c20; 7 loop 8 fetch c20 into c_id; 9 select count(roll_no) into ctr from student20 where course_id=c_id; 10 if(ctr>=10) then 11 update course20 set status='offered' where course_id=c_id; 12 else 13 update course20 set status=' not offered' where course_id=c_id; 14 end if; 15 exit when c20 % notfound; 16 dbms_output.put_line('table has been updated'); 17 end loop;

78

18 close c20; 19 end;

OUTPUT:table has been updatedtable has been updatedtable has been updated



COURSE_ID NAME FEE DURATION STATUS---------------- --------- ------- ----------------

------------ 101 MCA 24700 3 not offered 102 MBA 20000 2 not offered 103 MSc 15000 2 offered

79

21. create the following tables Item(item_code,item_name,qty_in_stock,reorder_level) Supplier(supplier_code,supplier_name,address) Can_supply(supplier_code,item_code) (a)Create a form to accept the data from the user with appropriate validation checks (b)Create a report to list the items whose qty_in_stock is less than or equal to their reorder levels.

Program:Creating Tables:

SQL> create table item 2 (item_code varchar(5) primary key, 3 item_name varchar(6), 4 qty_in_stock number(3), 5 reorder_level number(3));

Table created.

SQL> create table supplier 2 (supplier_code varchar(5) primary key, 3 supplier_name varchar(6), 4 address varchar(10));

Table created.

SQL> create table can_supply (supplier_code varchar(5), item_code varchar(5), constraints fk3 foreign key(supplier_code) references supplier(supplier_code), constraints fk4 foreign key(item_code) references item(item_code));

Table created.

SQL> select * from item;

ITEM_ ITEM_N QTY_IN_STOCK REORDER_LEVEL----- ------ ------------ -------------i101 cpu 25 5i202 mouse 20 15i303 drives 30 18i404 keys 35 20

80

i505 pens 21 13

SQL> select * from supplier;

SUPPL SUPPLI ADDRESS----- ------ ----------s111 abcd xxxxs222 efgh yyyys333 ijkl zzzzs444 mnop wwwws555 rstu vvvv

SQL> select * from can_supply;

SUPPL ITEM_----- -----s111 i101s222 i202s333 i303s444 i404s555 i505

Creation of form

*Steps for creation of form refer index

The resulting form is as shown below

81

Creation of report

*Steps for creation of report refer index

The resulting reportis as shown below

82

22.Create the following table : Item (item-code, item-name, qty-in-stock, reorder-level) Supplier (supplier-code, supplier-name, address) Can-Supply (supplier-code, item-code) b) Write PL/SQL procedure to do the following: Set the status of the supplier to “important” if the supplier can supply more than five

items.

PROGRAM: Creating tables:

SQL> create table item22 2 (item_code number(5) primary key, 3 item_name varchar(15), 4 qty_in_stock number(5), 5 record_level number(5));

Table created.

SQL> create table supplier22 2 (supp_code number(5) primary key, 3 supp_name varchar(15), 4 address varchar(15), 5 status varchar(15));

Table created.

SQL> create table can_supply22 2 (supp_code number(5), 3 item_code number(5), 4 constraint fk22 foreign key(supp_code) references supplier22(supp_code), 5 constraint fh_22 foreign key(item_code) references item22(item_code));

Table created

Inserting Values Into Tables:

SQL> insert into item22 values 2 (&item_code,'&item_name',&qty_in_stock,&record_level);

83

Enter value for item_code: 1111Enter value for item_name: xxxxEnter value for qty_in_stock: 20Enter value for record_level: 15old 2: (&item_code,'&item_name',&qty_in_stock,&record_level)new 2: (1111,'xxxx',20,15)

1 row created.

SQL> /Enter value for item_code: 2222Enter value for item_name: yyyyEnter value for qty_in_stock: 15Enter value for record_level: 10old 2: (&item_code,'&item_name',&qty_in_stock,&record_level)new 2: (2222,'yyyy',15,10)

1 row created.

SQL> insert into supplier22 values 2 (&supp_code,'&supp_name','&address','&status');Enter value for supp_code: 1001Enter value for supp_name: abcdEnter value for address: 1234Enter value for status: processingold 2: (&supp_code,'&supp_name','&address','&status')new 2: (1001,'abcd','1234','processing')

1 row created.

SQL> /Enter value for supp_code: 2002Enter value for supp_name: defgEnter value for address: 4567Enter value for status: processingold 2: (&supp_code,'&supp_name','&address','&status')new 2: (2002,'defg','4567','processing')

1 row created.

SQL> select * from item22;

ITEM_CODE ITEM_NAME QTY_IN_STOCK RECORD_LEVEL------------------ ------------------- --------------------- ----------------------- 1111 xxxx 20 15 2222 yyyy 15 10

84

3333 zzzz 10 5 4444 aaaa 25 15 5555 bbbb 15 15 6666 cccc 7 5

SQL> select * from supplier22;

SUPP_CODE SUPP_NAME ADDRESS STATUS ----------------- ------------------ -------------- -------------- 1001 abcd 1234 processing 2002 defg 4567 processing 3003 hijk 7890 processing

SQL> insert into can_supply22 values 2 (&supp_code,&item_code);Enter value for supp_code: 1001Enter value for item_code: 1111old 2: (&supp_code,&item_code)new 2: (1001,1111)

1 row created.

SQL> /Enter value for supp_code: 2002Enter value for item_code: 2222old 2: (&supp_code,&item_code)new 2: (2002,2222)

1 row created.

SQL> select * from can_supply22;

SUPP_CODE ITEM_CODE------------------ ------------------ 1001 1111 2002 2222 1001 2222 3003 1111 1001 3333 3003 2222 1001 4444 2002 4444 1001 5555 1001 6666

85

9 rows selected.

PROCEDURE: SQL> declare 2 s_c supplier22.supp_code%type; 3 ctr number; 4 cursor c22 is select supp_code from supplier22; 5 begin 6 open c22; 7 loop 8 fetch c22 into s_c; 9 select count(item_code) into ctr from can_supply22 where supp_code=s_c; 10 if(ctr>5) then 11 update supplier22 set status='important' where supp_code=s_c; 12 dbms_output.put_line('table updated'); 13 end if; 14 exit when c22 % notfound; 15 end loop; 16 close c22; 1 17 end; 18 /Output:

table updated



SUPP_CODE SUPP_NAME ADDRESS STATUS ---------------- ----------------- --------------- ----------- 1001 abcd 1234 important 2002 defg 4567 processing 3003 hijk 7890 processing

86

23.Create the following tablesItem(item_code,item_name,qty_in_stock,reorder_level)Supplier(supplier_code,supplier_name,address,status)Can_supply(supplier_code,item_code)Generate a report of those items that are supplied by those suppliers whose status is “important

Program:

SQL> create table item22(item_code number(5) primary key,item_name varchar(15), qty_in_stock number(5),record_level number(5));

Table created.

SQL> create table supplier22(supp_code number(5) primary key,supp_name varchar(15), address varchar(15),status varchar(15));

Table created.

SQL> create table can_supply22(supp_code number(5),item_code number(5),constraint fk22 foreign key(supp_code) references supplier22(supp_code),constraint fh_22 foreign key(item_code) references item22(item_code));

Table created

Inserting Values Into Tables

SQL> insert into item22 values(&item_code,'&item_name',&qty_in_stock,&record_level);Enter value for item_code: 1111Enter value for item_name: xxxxEnter value for qty_in_stock: 20Enter value for record_level: 15old 2: (&item_code,'&item_name',&qty_in_stock,&record_level)new 2: (1111,'xxxx',20,15)

1 row created.

SQL> /Enter value for item_code: 2222

87

Enter value for item_name: yyyyEnter value for qty_in_stock: 15Enter value for record_level: 10old 2: (&item_code,'&item_name',&qty_in_stock,&record_level)new 2: (2222,'yyyy',15,10)

1 row created.

SQL> insert into supplier22 values(&supp_code,'&supp_name','&address','&status');Enter value for supp_code: 1001Enter value for supp_name: abcdEnter value for address: 1234Enter value for status: processingold 2: (&supp_code,'&supp_name','&address','&status')new 2: (1001,'abcd','1234','processing')

1 row created.

SQL> /Enter value for supp_code: 2002Enter value for supp_name: defgEnter value for address: 4567Enter value for status: processingold 2: (&supp_code,'&supp_name','&address','&status')new 2: (2002,'defg','4567','processing')

1 row created.

SQL> select * from item22;

ITEM_CODE ITEM_NAME QTY_IN_STOCK RECORD_LEVEL---------- --------------- ------------ ------------ 1111 xxxx 20 15 2222 yyyy 15 10 3333 zzzz 10 5 4444 aaaa 25 15 5555 bbbb 15 15 6666 cccc 7 5


SUPP_CODE SUPP_NAME ADDRESS STATUS---------- --------------- --------------- --------------- 1001 abcd 1234 processing 2002 defg 4567 processing 3003 hijk 7890 processing

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SQL> insert into can_supply22 values 2 (&supp_code,&item_code);Enter value for supp_code: 1001Enter value for item_code: 1111old 2: (&supp_code,&item_code)new 2: (1001,1111)

1 row created.

SQL> /Enter value for supp_code: 2002Enter value for item_code: 2222old 2: (&supp_code,&item_code)new 2: (2002,2222)

1 row created.

SQL> select * from can_supply22;

SUPP_CODE ITEM_CODE---------- ---------- 1001 1111 2002 2222 1001 2222 3003 1111 1001 3333 3003 2222 1001 4444 2002 4444 1001 5555 1001 6666

9 rows selected.

Procedure

SQL> declare 2 s_c supplier23.supp_code%type; 3 ctr number; 4 cursor c23 is select supp_code from supplier23;

89

5 begin 6 open c23; 7 loop 8 fetch c23 into s_c; 9 select count(item_code) into ctr from can_supply23 where supp_code=s_c; 10 if(ctr>5) then 11 update supplier23 set status='important' where supp_code=s_c; 12 dbms_output.put_line('table updated'); 13 end if; 14 exit when c23 % notfound; 15 end loop; 16 close c23; 1 17 end; 18 /Output:

table updated



SUPP_CODE SUPP_NAME ADDRESS STATUS ---------------- ----------------- --------------- ----------- 1001 abcd 1234 important 2002 defg 4567 processing 3003 hijk 7890 processingCreation of Report

*Steps for creation of Report same as given in Problem21.

The report generated is as follows.

90

24.Create the following tables

Student(roll_no,marks,category,district,state)Student_rank(roll_no,marks,rank)Generate a report to list of those districts from which the first hundred rankers come from.

Creating the tables

SQL> Create table student8(roll_no number(4) primary key,marks number(4),category varchar(2),district varchar(15),state varchar(15));

ROLL_NO MARKS CATEGORY DISTRICT STATE

6780 200 A warangal andhra pradesh

6781 180 A ranga reddy andhra pradesh

6782 176 A nizambad andhra pradesh

6783 175 A nalgonda andhra pradesh

6784 173 A khammam andhra pradesh

6785 170 A adilabad andhra pradesh

6786 168 B tiruchhi tamilnadu

6787 167 B kanchi tamilnadu

6788 165 B kanchi tamilnadu

6789 164 B drwad karnataka

6790 160 B hubli karnataka

6791 159 B erode Tamilnadu

6792 158 B erode Tamilnadu

6793 157 B hubli karnataka

6794 156 B krishna andhra pradesh

6795 153 B guntur andhra pradesh

6796 152 B kadapa andhra pradesh

6797 150 C prakasham andhra pradesh

6798 148 C nellore andhra pradesh

91

SQL> create table student_rank(roll_no number(4),marks number(4),rank number(3),constraints fk81 foreign key(roll_no) references student8(roll_no));

ROLL_NO MARKS RANK

6781 180 2

6780 200 1

6782 176 8

6783 175 10

6784 173 25

6785 170 32

6786 168 41

6787 167 59

6788 165 72

6789 164 84

6790 160 100

6791 159 110

6792 158 129

6793 157 143

6794 156 164

6795 153 170

6796 152 179

6797 150 184

6798 148 197

Creation of ReportSteps for creation of Report refer indexThe report generated is as follows.

92

25.Create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code,status)Faculty(faculty_code,faculty_name,specialization)

Write a PL/SQL procedure to the following:Set the status of the subject to “not offered” if the subject is not opted by at least 5 students.

Creating the table

SQL> Create table faculty25(faculty_code number(4) primary key,faculty_name varchar(25),specialization varchar(10));

FACULTY_CODE FACULTY_NAME SPECIALIZATION

5678 Syed Nazia Begum M.Tech

5679 M Suhasini M.Sc

5680 S Zareena M.com

5681 B Sujana Kumari MCA

5682 K Balaramudu MBA

5683 G Gopinath MA

5684 M Rama Krishna B.Sc

5685 B Ramesh B.Com

5686 D.Anilkumar Reddy M.Tech

5687 J.Haribabu M.Sc

5688 S.Mahammad Goush M.com

5689 L.Sudhakar MCA

5690 O.Sivaprasad BA

5691 G.Manesh B.Tech

5692 M.Nagaraju BE

SQL> Crete table student25(roll_no number(4) primary key,name varchar(19),subject_opted varchar(15));

ROLL_NO NAME SUBJECT_OPTED

5687 A.Nagedra DBMS

5688 B.Adinarayana History

5689 B.Ayyawaru Physics

5690 B.Dastagiri History

5691 B.Ramakrishna Physics

5692 B.Ramesh Physics

5693 C.Jayaraju Physics

5694 C.Rajashekar Physics

5695 C.Subramanyam DBMS

5696 C.Venkatasiva Physics

93

5697 D.Anilkumar Reddy History

5698 D.Udaykiran History

5699 G.Ganganna DBMS

5700 G.Gurappa Accounts

5701 G.Manesh Accounts

5702 G.Suresh History

5703 G.Venkataramana Accounts

5704 J.Haribabu DBMS

5705 K.Diwakar Reddy Physics

5706 K.Gourisankar DBMS

5707 K.Ramakrishna OS

5708 K.Ramakrishna History

5709 K.Ramesh OS

5710 K.Ramesh DBMS

5711 K.Sankar Reddy DBMS

5712 K.Sivasankar History

5713 L.Sudhakar DBMS

5714 M.Nagaraju Accounts

5715 M.Nagarjuna Physics

5716 M.Raghavendra Reddy DBMS

5717 O.Sivaprasad OS

5718 P.Bashakar Accounts

5719 P.Moulali OS

5720 P.Nagaraju Physics

5721 P.Rafi OS

5722 P.Sreeramulu Accounts

5723 P.Tirupalu OS

5724 S.Anwar Basha OS

5725 S.Baba OS

5726 S.Gangaraju OS

5727 S.Ibrahim DBMS

5728 S.Jilani Basha Accounts

5729 S.Mahammad Goush OS

5730 T.Babaiah History

5731 T.Balagangi Reddy Accounts

5732 T.Sreenivasulu DBMS

5733 Y.Vijayaram OS

5734 N.jagan Electronics

5735 K.Hari Babu Chemistry

SQL> create table subject_rank25(subject_code number(4) primary key,subject_name varchar(15),faculty_code number(4),status varchar(18));

SUBJECT_CODE SUBJECT_NAME FACULTY_CODE STATUS

9110 Accounts 5688 Offered

94

9111 DBMS 5681 Offered

9112 History 5683 Offered

9113 OS 5678 Offered

9114 Physics 5687 Offered

9115 Electronics 0 Offered

9116 Chemistry 0 Offered

ProcedureSQL> create or replace procedure PRO25isz1 subject_rank25.subject_code%type;ctr number;cursor c1 is select subject_code from subject_rank25;beginopen c1;loopfetch c1 into z1;select count(roll_no) into ctr from student25 where subject_opted=z1;if(ctr<5) thenupdate subject_rank25 set status='Not offered' where subject_code=z1;end if;exit when c1%notfound;end loop;close c1;end;

PL/SQL procedure successfully completed

SQL> select * from subject_rank25;SUBJECT_CODE SUBJECT_NAME FACULTY_CODE STATUS






9115 Electronics 0 Not offered

9116 Chemistry 0 Not offered

26.Create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code,status)Faculty(faculty_code,faculty_name,specialization)Write a PL/SQL procedure to the following:

95

Set the status of the subject to “not offered” if the subject is not offered by any faculty

Creating the table








5683 G Gopinath MA


5685 B Ramesh B.Com




5689 L.Sudhakar MCA



5692 M.Nagaraju BE



5687 A.Nagedra DBMS
















96







5709 K.Ramesh OS

5710 K.Ramesh DBMS









5719 P.Moulali OS


5721 P.Rafi OS


5723 P.Tirupalu OS


5725 S.Baba OS

5726 S.Gangaraju OS

5727 S.Ibrahim DBMS






5733 Y.Vijayaram OS



SQL> create table subject_rank25(subject_code number(4) primary key,subject_name varchar(15),faculty_code number(4),status varchar(18));

SUBJECT_CODE SUBJECT_NAME FACULTY_CODE STATUS







97


ProcedureSQL> create or replace procedure PRO25isz1 subject_rank25.subject _code%type;fac subject_rank25.faculty_code%type;ctr number;cursor c1 is select faculty_code as fac from subject_rank25;beginopen c1;loopfetch c1 into z1;if(fac=0) thenupdate subject_rank25 set status='Not offered' where subject_code=z1;end if;exit when c1%notfound;end loop;close c1;end;

PL/SQL procedure successfully completed

SQL> select * from subject_rank25; Subject_code Subject_namefaculty_code staus



27.Create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code)Faculty(faculty_code, faculty_name, specialization)

Generate the queries to do the followinga. Find the number of students who have enrolled for the subject ‘DBMS’.b. Find all those subjects which are not offered by any faculty member.

98

SQL> create table subject_rank(subject_code number(4),subject_name varchar(15),faculty_code number(4));

SUBJECT_CODE SUBJECT_NAME FACULTY_CODE

1 9113 OS 5678

2 9114 Physics 5679

3 9110 Accounts 5680

4 9111 DBMS 5681

5 9112 History 5683

6 9114 Physics 5687


8 9111 DBMS 5689

9 9112 History 5690

10 9115 Electronics 0

11 9116 Chemistry 0








5683 G Gopinath MA


5685 B Ramesh B.Com




5689 L.Sudhakar MCA



5692 M.Nagaraju BE

SQL> create table student27(roll_no number(4) primary key,name varchar(19),subject_opted varchar(15));


11001 A.Nagedra DBMS





99


















11023 K.Ramesh OS

11024 K.Ramesh DBMS









11033 P.Moulali OS


11035 P.Rafi OS


11037 P.Tirupalu OS


11039 S.Baba OS

11040 S.Gangaraju OS

11041 S.Ibrahim DBMS






11047 Y.Vijayaram OS



100

Queries(a) select count(roll_no) from student27 where subject_opted='DBMS';

COUNT(ROLL_NO)

11

(b) select subject_name from subject_rank where faculty_code=0;

SUBJECT_NAME

Electronics

Chemistry


Generate the queries to do the followingFind the number of students who have enrolled for the subject ‘DBMS’.Find all those subjects which are offered by more than one faculty member.

Creating the Tables



1 9113 OS 5678

101

2 9114 Physics 5679


4 9111 DBMS 5681

5 9112 History 5683

6 9114 Physics 5687


8 9111 DBMS 5689

9 9112 History 5690


11 9116 Chemistry 0








5683 G Gopinath MA


5685 B Ramesh B.Com




5689 L.Sudhakar MCA



5692 M.Nagaraju BE










102
















11023 K.Ramesh OS

11024 K.Ramesh DBMS









11033 P.Moulali OS


11035 P.Rafi OS


11037 P.Tirupalu OS


11039 S.Baba OS











Queries

103

(i)SQL> select count(roll_no) from student27 where subject_opted='DBMS';

COUNT(ROLL_NO)

11

(ii)SQL> select subject_code,subject_name,count(subject_code) from subject_rank group by subject_code having count(subject_code)>1;

SUBJECT_CODE SUBJECT_NAME COUNT

9114 Physics 2

9110 Accounts 2

9111 DBMS 2

9112 History 2


Generate the queries to do the following(i)Find the number of students who have enrolled for the subject ‘OS’.(ii)Find all those students who have opted for more than 5 subjects.


Select * from subject_rank;


1 9113 OS 5678

2 9114 Physics 5679


4 9111 DBMS 5681

104

5 9112 History 5683

6 9114 Physics 5687


8 9111 DBMS 5689

9 9112 History 5690


11 9116 Chemistry 0








5683 G Gopinath MA


5685 B Ramesh B.Com




5689 L.Sudhakar MCA



5692 M.Nagaraju BE


select * from student27;










105















11023 K.Ramesh OS

11024 K.Ramesh DBMS









11033 P.Moulali OS


11035 P.Rafi OS


11037 P.Tirupalu OS


11039 S.Baba OS











Queries

106

(i)select count(subject_opted) from student27 group by subject_opted having subject_opted =’OS’;

COUNT(SUBJECT_OPTED)

10

(ii)select rollno,student_name,count(rollno) from subject_opted group by rollno having count(rollno)>5;

COUNT(ROLLNO)

0

30. Create the following tablesStudent(roll_no,name,subject_opted)Subject_rank(subject_code,subject_name,faculty_code)Faculty(faculty_code, faculty_name, specialization)

Generate the queries to do the followinga. Find the number of students who have not enrolled for the subject ‘DBMS’.b. Find all those subjects which are offered by more than one faculty member.

Creating Tables

SQL>create table subject_rank(subject_code number(4),subject_name varchar(15),faculty_code number(4));

Select * from subject_rank;


1 9113 OS 5678

2 9114 Physics 5679


4 9111 DBMS 5681

5 9112 History 5683

6 9114 Physics 5687

107


8 9111 DBMS 5689

9 9112 History 5690


11 9116 Chemistry 0








5683 G Gopinath MA


5685 B Ramesh B.Com




5689 L.Sudhakar MCA



5692 M.Nagaraju BE
















108










11023 K.Ramesh OS

11024 K.Ramesh DBMS

Queries

(i)SQL> select count(roll_no) from student27 having subject_opted!='DBMS';

COUNT(ROLL_NO)

38

(ii)SQL> select subject_code,subject_name,count(subject_code) from subject_rank group by subject_code having count(subject_code)>1;

SUBJECT_CODE SUBJECT_NAME COUNT

9114 Physics 2

9110 Accounts 2

9111 DBMS 2

9112 History 2

109

Steps For Creating A Data Source

STEPS FOR CREATING DATA SOURCE

Step1: Go to control panel select administrative tools->Data Source (ODBC) icon .Step2: Then a dialogue box appears naming ODBC Data Source then click on Add and then select the option Microsoft ODBC for Oracle and click finish then a dialogue appear naming Microsoft ODBC for Oracle SetUpStep 3: Now enter the values as

Data Source Name as nmca10 User Name as scott/tiger(password) (is SQL is opened with host string is given

as oracle then scott/tiger@oracle)Then click ok

Step4: Then that data source name is entered into the ODBC Data Source Administrator.In this way we connect the data source to database

110

:

111

Steps To Create A Form

Steps To Create A Form :

Step1: Open Microsoft Visual Basic 6.0Step2: Open standard EXE Step 3: It generates an empty form as shown.Step 3: Select the required no of labels by selecting icon Label and enter the label names

in the properties table in Caption rowStep 4: Select the required no of text fields by selecting the icon Text Step 5: create an adodc icon by selecting Project ->Components then a dialogue box

appears then a dialogue appears Step 6: Tick on Microsoft ADO Data Control 6.0 (OLEDB) the click apply and then

ok.Step 7: choose the icon adodc create the adodc1 box as shownStep 8: Select the required command fields by selecting the icon Command Button and

And enter the command names like add,save,delete in the properties table in Caption row.Step 8: Now select the adodc1 box and enter the command type as table in properties

table

112

Step 9: Now select the command string the a dialogue box appears in the box select the use ODBC Data source Name and enter the data source name i.e nmca10 as shown.

Step 10: Now select the Resource type in properties table then a dialodue box appears select the table for which the form being created as shown an then select ok.

Step 11: Now select the Data Source as adodc1 and Data Field as necessary (Eg: Course_id);

Step 12: In order to write code for the command buttons double click the command button then a window appears the write the code as follows

(i) for add: Private Sub Command1_Click()Adodc1.Recordset.AddNewEnd Sub

(ii) for save: Private Sub Command1_Click()Adodc1.Recordset.updateEnd Sub

(iii) for delete: Private Sub Command1_Click()Adodc1.Recordset.updateEnd Sub

Step 13: In order to give Validation checks select required text box on which we have to define validate and same as step11and write the code as follows.

Fro Eg to text 3 Private Sub Text3_Change()

If (Text3.Text) = 0 ThenMsgBox ("fee cant be zero")Text3.SetFocusEnd IfEnd but the following must be used

Step 14: In order to execute the form click start button the menu bar and the form iscreated as follows:

Step 15: For example we have generated the for and have add the values as follows Course_id as 1111 Name as Commerce

Fee as 15000 Duration as 3 Step 16: In order to see the added recored go to SQL promt and gine the following

command

SQL> select * from course;

COURSE NAME FEE DURATION------------ -------- ----- ---------------1111 Commerce 15000 3123 M.C.A 25400 3456 B.Tech 36000 4789 M.B.A 20000 2012 Bio-Tech 40000 3

113

156 Food-Tech 10000 3

6 rows selected.

Output of Step 3:

114

Output of Step 5:

Output of Step 6:

115

Output of Step 7:

Output of Step 9:

116

Output of step10:

Output of step11:

117

Output of step12 & 13:

Output of step 14:

118

Steps To Generate A ReportSTEPS TO GENERATE REPORT

119

Step1: Create form on the table for which a report has to generated.

Step2: Now select option projects->add from->VB Wizard form.

Step3: a dialogue box appears naming Data Form wizard-Introduction click on Next.

Step4: A dialogue box appears naming Data Form wizard-Database Type select the option remote(ODBC) and click Next.

Step5:A dialogue box appears naming Data Form wizard-Connection Information and enter the values for ODBC Connect Data as DSN : nmca10(name of the data source) UID : scott PWD :tiger Then click on Next.

Step6: A dialogue box appears naming Data Form wizard-Forms select the Form Layout as Grid(database) and Binding code as AOD Data control if we want to select all the rows or if we want to retrieve data based upon a condition then select the ption as AOD Code and click on Next.Step 7: A dialogue box appears naming Data Form wizard-Record Source then select the record source as table name (eg item22) then it displays available fields

select all the fields if we want to retrive entire data if not select those columns on which a condition should be specified. Step8: A dialogue box appears naming Data Form wizard-Control Section delete all the available controls and click on NextStep9: A dialogue box appears naming Data Form wizard-Finished then select finish.Step10: Then report is generatedStep11: In order to give a condition double click the report and insert the SQL query and then run the report.

120

Step2:

:

Step3:

121

Step4:

Step5:

Step6:

122

Step7:

123

Step8:

Step9:

Step10:

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Documents

Dbms Record[1]