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Day 1 - Do Now. Take 1 minute to answer the question: Why would we want to measure force? (i.e. under what circumstances is measuring force useful?) Please write an example. Sir Isaac Newton. Newton’s 2 nd Law. - PowerPoint PPT Presentation
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Day 1 - Do Now
• Take 1 minute to answer the question:
– Why would we want to measure force? (i.e. under what circumstances is measuring force useful?)
– Please write an example.
Newton’s 2nd Law
• Newton’s 2nd Law gives us the ability to calculate how much force is required to move an object
Playing with the formula
F F• F= ma OR m= -------- OR a= --------- a m • Units: unit for force is N (Newton)
m = kga = m/sec2
Newton = Kg xm sec2
2nd Law Quick Practice
• A 100 Kg linebacker hits the running back while accelerating at 3 m/s2. What is the force the linebacker hits the running back? Answer in Newtons
Day 2 - Do Now
• Please take two minutes to answer this question:
• What is the funniest or most fun race you have ever participated in or have seen?
Scenario
• One Saturday morning you and your eleven friends decide to have a wagon race. Each wagon team has a total of four people, arranged in the following manner and shown below in the diagrams:
• Wagon 1 – 2 people pushing the wagon and 2 people sitting in the wagon
• Wagon 2 - 3 people pushing the wagon and 1 person sitting in the wagon
• Wagon 3 - 1 person pushing the wagon and 3 people sitting in the wagon
Units
Symbol UnitDistance d m (meter)
Mass m kg (kilogram)
Velocity v m/sAcceleration a m/s2
Time s s (second)
Force (Newton) N kg . m/s2
Step 1
1. Using the information contained in the prompt, calculate the acceleration of each wagon. Show all work and be sure to include all units in your calculations and answers.
Force on Wagon #1
Force of Each Person Pushing the WagonPerson number Force (N)1 532 55
ΣF= F1+F2 = 53N+55N = 108N
Mass of Wagon #1
Mass of Each Person in the Wagon
Person number Mass (kg)3 314 37
Σm= m3+m4 = 31kg+37kg = 68kg
Force on Wagon #2
Force of Each Person Pushing the Wagon
Person number Force (N)5 556 317 11
ΣF= F5+F6+F7 = 55N+31N+11N = 97N
Mass on Wagon #3
Mass of Each Person in the Wagon
Person number Mass (Kg)10 2711 4612 19
ΣF= F10+F11+F12 = 27N+46N+19N = 92N
Day 3 - Do Now
• What kind of information can you calculate using the formula F=ma?
• How can you use these problems in real life?
Table Assumptions
2a. Assuming that each wagon maintains a constant acceleration for five seconds, construct a table which compares the speed and time of each wagon. Your table should represent every second from resting to five seconds.
Using the Table
2b. Using the table you created, construct a single graph plotting the speed vs. time data for each of the three wagons.
Calculating distance
• What is the distance travelled by each wagon?Wagon 1• d = ½ at2
• d = ½ (1.59 m/s2) 5 s 2
• d = ½ (1.59 m/s2) (25 s2)• d= ½ (39.75)• d= 19.88