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Data Interpretation & Data Sufficiency 1

1 to 5:

CHRONICLEIAS ACADEMYA CIVIL SERVICES CHRONICLE INITIATIVE

DATA INTERPRETATION

& DATA SUFFICIENCY

ANSWERS (38)

5. (d) B is ahead and his speed is more than that ofA and they will never meet again under thegiven conditions.

Solutions for questions 6 to 10:

6. (d) For this question, if we know the principalamount, we could have found the rate ofinterest.

7. (a) Statement A alone is not sufficient butstatement B can alone solve the query.

According to B, from which the

value of M can be obtained.

8. (c) Statement A is sufficient, From A we findthat the number of boys are 20.

From statement B

B = G + 9

∵ B = B + 9

⇒ B = 45

The number of boys can be calculated by boththe statements alone, thus option (c)

9. (a) Statement B is sufficient to solve the query.Let the number be N.

Hence . The difference between

two digits = 2.

10. (c) According to statement (A) when there is adifference of 2 marks, the difference in %ageis 4%

Hour Speed (km/hr) CumulativeDistance

A B A B Relative Distance

1 20 25 20 25 5

2 30 40 50 65 15

3 20 35 70 100 30

4 15 20 85 120 35

5 25 15 110 135 25

6 15 25 125 160 35

7 25 35 150 195 45

8 35 10 185 205 20

9 20 15 205 220 15

10 30 15 235 235 0

11 15 25 250 260 10

12 10 15 260 275 15

1. (a) A's average speed over the first 7 hours =150/7 kmph;

B's maximum speed = 40 kmph, B's minimumspeed = 10 kmph,

Average of B's maximum and minimumspeeds = 25 kmph ⇒ (150/7)x100/25≅85%

2. (c) Maximum relative distance = 45 km at theend of 7 hours

3. (c) Zero relative distance takes place after 10hours

4. (d) B's average speed during first 6 hours = 160/6; B's average speed during last 6 hours =(275 - 160)/6 = 115/6

Ratio is 160 : 115 which is closest to 7 : 5 (23x 7 = 161)

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2 Data Interpretation & Data Sufficiency

Passmarks = 32% + 1 = 16 + 1 = 17 marks.

According to statement (B) 10% » 5 marks.

Passmarks = 30% + 2 = 15 + 2 = 17 marks.Hence, since both the statements alone aresufficient to answer.

Solutions for questions 11 to 15:

11. (a) Average marks of all the students in the year

1996 = . Required

percentage = .

12. (c) Percentage increase in marks =.

13. (c) Out of the fractions 1200/980, 700/520, 970/875, 900/740 and 1000/820, the largestfraction is 700/520.

14. (b) The highest increase was in the year 1997,i.e. increase of 90 marks.

15. (c) Required percentage = .

Solutions for questions 16 to 20:

Note down the corresponding values of Profit,Revenue & Expenditure on the bar graphitself, keeping in mind, Profit = Revenue -Expenditure. The values read from the graphshould satisfy this condition for each year.Here corresponding values are given in theform of a table to make the solution easier tounderstand:

YEAR 1989 1990 1991 1992 1993 1994 1995

Profit 25 37 44 55 60 75 90

Reven 125 137 145 185 195 210 250

Expend 110 125 115 170 180 190 200

16. (c)% increase of profit for various years are-

1993 →

1994 →

1990 →

1992 →

17. (d) Average Revenue = (Total Revenue)/(Number of years)

=

=

18. (d) From the table, it can be seen that growth inexpenditure as compared to the previous yearwas maximum in 1992.

19. (d) Total Revenue = 1247

Total Expenditure = 110 + 125 + 137 + 170+ 180 + 190 + 200 = 1112

∴% =

= 89%

20. (b) % profit in 1995 =

∴ Profit in 1996 = 90 × 1.2 = 108 lakh

Solutions for questions 21 to 25:

21. (a) For Lipton production = 1.64 ("000 tonnes)Capacity Utilisation = 64.8% ∼ 65%

65% = 13/20, so maximum productioncapacity = (20×1.64)/13 = 32.8/13 ∼ 2.53 ('000tonnes)

22. (d) Data insufficient, because different varietiesof coffee of the same brand may havedifferent prices. We cannot assume that therewill be only one variety of coffee of eachbrand.

23. (b) Total Sales Value (incl. Others) = 132.8 (Rs.Cr.)

Sales value (BB + Nestle + Lipton + MAX) =[31.15 + 26.75 + 15.25 + 17.45] = 90.60 (Rs.Cr.)

Total sales value of others = 132.8 - 90.60 =42.2 (Rs. Cr)

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Data Interpretation & Data Sufficiency 3

Others /Total = 42.2/132.8 ∼ 1/3 (approx.)

% share of others = 33.33% (approx.)

Hence, the closest option will be the correctanswer i.e. 32%.

24. (c) Total prod capacity = [100×Total prod. ('000tonnes)] /(%Capacity utilisation)

= (100×11.63)/61.3

= 1160/50 (approx.)

= 19.3 ('000 tonnes)

Here we are taking approximate value of thedenominator to be less than the actual valueHence, the closest option will be the correctanswer i.e. 18,900.

25. (d) Unutilised capacity of a company is given by.

(100 - %capacity utilisation) (Production in'000 tonnes)/(% capacity utilisation)

Substituting the corresponding values fromthe table, we get that maximum unutilisedcap. is for MAC i.e. (100 - 59.35) × (1.54)/59.35 ∼ 1.05 ('000 tonnes)

Solutions for questions 26 to 28:

26. (b) Let sales in 2000 be x, 2001 be y and 2002 be z

From the statement B

⇒ x =

⇒ =

The equation implies that x > 2 (y + z)

Thus sales in 2000 in higher than 2001.

Thus option (b)

27. (a) From the first statement we get (1/2x) + (1/x) = (1/601), which can be solved.

28. (c) CP of the pens is given in the first statementwhile profit in the second, both will give theanswer.

Solutions for questions 29 to 31:

The following information is given:

(a) Only R can be repeated

(b) If Q, then T.

(c) If R, then R appears atleast twice

(d) P ≠ first or last

(e) If T, then Q.

29. (d) R can be used as RR.

T can be used with Q and vice-versa. It isonly S which cannot be used on a 2 - letterpassword. Since the only possible letter to gowith S is P, but then P will have to be eitherthe first or the last letter, which is not allowed.

30. (c ) P cannot be first or last hence cannot be usedas a single - letter password. Q and T mustbe together, hence cannot be used as a singleletter password.

Hence, S alone can be used as a single letterpassword.

31. (a) R _ _ _ _ S

R must be repeated, then at most only twoplaces are vacant.

These two places must be filled in by T andQ. P cannot be included as the other letterwill be either T or Q. none of which can beincluded alone.

Solutions for questions 32 to 33:

32. (d) 12(N) + 1(E) + 7(S) + 5(W) + 1(C) = 26⇒ 26 / 251 = 10.35%

33. (d) Exact No. of Children incase of being morethan 3 is not given, hence average cannot bedetermined.

Solutions for questions 34 to 39:

34. (c) Sum of three quotations = 120× 3 = 360. FromA & B both, we get the third quotation as Rs.145 which is higher than 139.

35. (b) Using B statement alone, we can make Venndiagram and get the answer as 120.

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4 Data Interpretation & Data Sufficiency

36. (b) From the second statement we can calculatethe original speed to be 40/2 = 20 kmph.Now the new speed is 1/4th of that i.e. 5kmph. Now an equation can be made tocalculate the distance that is D/5 - D/20 =40/60 hrs. Solving this the distance after theengine trouble can be calculated and 40 canbe added in that in order to calculate thetotal distance. First statement alone does notgive anything sufficient. Thus b is the answer.

37. (d) We cannot find the answer from A alone orB alone or their combination as infinite valuesof x can be obtained.

38. (c) As the flight time is 6 hours, so flight arrivedat 12 AM as per Nairobi time. But in Mumbaiit was 3 AM, so we can find the answer as

90 + 108 = 198. Number of people going fromD to F and G = 82 + 20 = 102. So difference= 96.

44. (d) Number of people going to A from B and C= 20 + 28 = 48. Going by options, we see that4th option is correct.

45. (a)

Solutions for questions 46 to 50:

46. (a) Required amount = 0.12 × 20 = 2.4 crore.

47. (d)

17 + 1/4 × 20 = 22

Hence Ans. is 1 & Option (d).

48. (c) Expenditure 2nd Year = 19%

Expenditure 4th year = 22%

Net Rise = 3%

% Rise =3/19×100= 15%

Thus in 2 years.

Month Opening Demand Reserve Production Working Stock in Units 20% Requirement Days/Month (A) (B) (C) (B+C–A)

Jan 50 300 60 310 22

Feb 60 500 100 540 19

Mar 100 400 80 380 21

Apr 80 100 20 40 21

May 20 200 40 220 22

Jun 40 300 60 320 20Year Arts Science Commerce Total

89-90 61 29 70 160

90-91 12 46 142 200

91-92 65 113 62 240

92-93 80 33 163 276

3 hrs by using both the statements.

39. (c) Using both the statements we can find theanswer. From A, age of Sangeeta is 20 yrs.From B, we can say that 20 = 1/3 (F - 5)» F = 65 yrs.

Solutions for questions 40 to 45:

40. (d) Visual question.

41. (d) The information given is for 8 major locationsin the Zoo. There can be many more minorlocations in the Zoo for which informationabout movement of people is not given.

42. (a) Total people visiting E = 24 + 64 + 86 + 42 +112 + 6 + 68 = 402.

Hence required percentage = 42/402 × 100 =10%.

43. (b) Number of people going from B to F and G =

49. ( c) The difference between the expenditure inyear 2 and year 1 is 2, which is equal todifference in the expenditure between year 5and year 3 and between year 4 and year 3.

50. (b) The rate of increase in expenses from year 3to year 5 is 10%. So expenditure in year 6 =22 × 1.1 = 24.2 crore.

Solutions for questions 51 to 55:

51. (b) 20% of May Demand (200) = 20% of 200 = 40

52. (c) Production requirement for Mar = Demand +Reserve - Opening Stock = 400 + 80 - 100 = 380

53. (a) February. Refer table.

54. (d) May. Refer table.

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Data Interpretation & Data Sufficiency 5

⇒ Number of students in 91-92 = 1.25s x1.2= 1.5s = 240

⇒ Number of students in 92-93 = 240 x 1.15 =276 and number of students in 89-90 = s = 160while number of students in 90-91 = 1.25s = 200

65. (a) % increase =

66. (a) The % decrease is highest for Arts studentsin 1990-91, when the number of studentsbecomes less than one-fifth of that in theprevious year.

67. (b) 1990-91: Arts = 12, Commerce = 142

Solutions for questions 68 to 72:

68. (b) Number of Maruti cars sold in 1 994 = 40%=1000,000 Number of Fiat cars sold in 1994» 20% = 500,000

69. (d) Fiat in 1995 → 1125

Fiat in 1996 → 818

Fiat in 1997 → 1167

Ambassador in 1997 → 334

Ambassador in 1998 → 423

On observation we can see that all thestatements are true.

70. (d) Choice A is false

Number of cars sold by Fiat in 1994 (inthousands) 20/100 × 100/40 × 1000 = 500

Number of cars sold by Fiat in 1996(in thousands) = 5/100 × 100/70 × 2000= 1000/7

% decrease is close to 71% Hence (A) is false

Although percentage share is almost samefor the two years, the total sale is substantiallydifferent. (B) is false.

The increase in total production is from 1500 to3000, which is exactly 100%. Hence (C) is false

55. (b) One worker in January (22 working day)

Gives = 22 × 8 = 176 Man hours

Total Man hours required = 310 × 10 = 3100

Number of worker required = 3100/176=17.6i.e. 18 workers.

No. of workers required to be laid off = 20 -18 = 2.

Solutions for questions 56 to 59:

56. (d) Let, the player P3 score 'x' runs more.

According to the condition given, we have

Hence option (4) is the correct choice.

57. (b) The required percentage

= 38%

58. (a) Except P3, P7, P10 and P11 all the playerssatisfy the condition given in the question.

59. (d) Runs scored by P5 = 1440.

Runs scored by P2 = 1070.

Difference = 1140 - 1070 = 370 runs.

Required percentage = 370/1070=35%.

Solutions for questions 60 to 64:

60. (d)

61. (c)

62. (b)

63. (a)

64. (c)

Solutions for questions 65 to 67:

Let number of students in 89-90 = s

⇒ Number of students in 90-91 = 1.25s

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6 Data Interpretation & Data Sufficiency

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71. (d) Ford Escort in 1995 → 750

Ford Escort in 1996 → 272.7

Ford Escort in 1997 → 333.3

Ford Escort in 1998 → 285.7

72. (b) Total number of cars sold in

1994 →

1995 → 1500 x 100/40

1996 → 3000 x 100/55 → Maximum

1997 → 1500 x 100/45

1998 → 2000 x 100/70

Solutions for questions 73 to 75:

73. (b) From statement A only 11 is the two digitprime which satisfies the condition.

i.e. 112= 121

113 = 1331

From statement B only 9 is such number

when 92= 81 and 8 + 1 = 9

93 = 729 and 7 + 2 + 9 = 18

74. (b) From statement A alone, A worked for 14½days and B worked for 14 days, so theytogether will be able to finish the work in lessthan 14½. So A alone is sufficient.

From statement B alone, When the slowerperson starts the work, the work takes 29days. So, when the faster person starts thework, the work would be completed in lessthan 29 days.

So, they together need less than 29/2 days tocomplete the work.

So B alone is sufficient.

75. (b) According to statement A, n = pq, whereboth p and q are prime numbers and p ≠ q.Thus, n is divisible by the positive integers 1,p, q, pq, and no others. Statement A alone istherefore sufficient to determine the numberof positive divisor of n which is 4.

In second case, as 23 is divisible by twonumbers i.e. 1 & 23, hence n is also divisibleby two positive integers.

Hence we can arrive at the answer using eitherof the two statements thus option (b) is correct.