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• Course Roadmap• Rectification• Bipolar Junction Transistor
6.101 Spring 2020 Lecture 3 1
Acnowledgements:Neamen, Donald: Microelectronics Circuit Analysis and Design, 3rd EditionThe Art Of Electronics by Horowitz and Hill
6.101 Course Roadmap
• Passive components: RLC – with RF• Diodes• Transistors: BJT, MOSFET, antennas• Op‐amps, 555 timer, ECG• Switch Mode Power Supplies• Fiber optics, PPG• Applications
6.101 Spring 2020 Lecture 3 2
6.101 Spring 2020 Lecture 3 3
Time Domain Analysis
])cos()[cos(2
cos
cos*)cos(
ttKAtAv
ttKAAv
mcmcm
cc
cmmc
Fourier Series ‐ Ramp
6.101 Spring 2020 Lecture 3 4
function [ t, sum ] = ramp(number)%generate a ramp based on fixed number of terms%t = 0:.1:pi*4; % display two full cycles with 0.1 spacing
sum = 0for n=1:number
sum = sum + sin(n*t)*(-1)^(n+1)/(n*pi);end
plot(t, sum)shg
end
Rectifier Circuits
6.101 Spring 2020 5
C F R L
1N4001
3a) Half-wave rectifier circuit diagram
120 V 60 Hz
+
v OUT
-
Pri Sec
12.6 VCT RMS
C F R L
3b) Full-wave rectifier circuit diagram
1N4001
+
v OUT
-
Pri Sec
12.6 VCT RMS
1N4001
120 V 60 Hz
R L
3c) Bridge rectifier circuit diagram
CF
+
v OUT
-
Pri Sec
12.6 VCT RMS120 V 60 Hz
4x 1N4001
+
+
+
Vout =
Vout =
Vout =
RC >> 16.6ms why?
Lecture 3
CT: center tap
Full Wave Bridge vs Center Tapped
6.101 Spring 2020 Lecture 3 6
Center tapped advantages:
• Lower diode voltage drop (high efficiency)
• Secondary windings carries ½ average current (thinner windings, easier to wind)
• Used in computer power supplies
Physical Wiring Matters
6.101 Spring 2020 Lecture 3 7
Power Supply Ripple Voltage Calculation
6.101 Spring 2020 8Lecture 3
D2 conduction angle in degrees
5 V Adapters
6.101 Spring 2020 Lecture 3 9
300 ma
1000 ma500 ma
Diode AC Resistance
6.101 Spring 2020 10Lecture 3
Log Amplifier
6.101 Spring 2020 Lecture 3 11
-
+
+15
LF356
2
34
76
vin
vout+
_ -15
1.5k
1N914
0.1F
0.1F
ID
IR
bypass caps0.1uf caps (2)
ID IS (e
qVDkT
1) ISe
qVDkT
IR = - ID
Vout = - VD
6.101 Spring 2020 12
Bipolar Junction Transistors
• BJT can operate in a linear mode (amplifier) or can operate as a digital switch.
• Current controlled device• Two families: npn and pnp.• BJT’s are current controlled
devices• NPN – 2N2222• PNP – 2N2907• VCE ~30V, 500 mw power
NPN
PNP
base
emitter
collector
ib
ic = βib
ib + ic
Lecture 3
Why BJT’s ?
• Preferred device for demanding analog application, both integrated and discrete (lower noise)
• Great for high frequency applications; characteristics well understood.
• High reliability makes it a key device in automotive applications.
• Lower output resistance at emitter vs source• Larger gm compared to FET
6.101 Spring 2020 Lecture 3 13
6.101 Spring 2020 14Lecture 3
BJT Symbols
6.101 Spring 2020 Lecture 3 15
2N22222N3904
12 3
2N3906P2N2222 pinout reversed
Packaging
6.101 Spring 2020 Lecture 3 16
TO-3TO-220
TO-18
BJT Current Relationship
6.101 Spring 2020 Lecture 3 17
NPN
base
emitter
collector
ic = βib
ib + ic
1
)1(
EC
BE
BC
BCE
iiii
iiiii
hFE = β = large signal (DC)gain at fixed current
hFE < hfe
6.101 Spring 2020 Lecture 3 18
max voltage
max continuous current
max power at 25o C
6.101 Spring 2020 Lecture 3 19
hFE = f(Ic) peaksat ~ 0.5-10ma
β
hFE @1.0ma < hfe @1.0ma
6.101 Spring 2020 Lecture 3 20
hFE & Current & Temperature Characteristics
NPN Common Emitter V‐I Relationship
6.101 Spring 2020 Lecture 3 21
β = ?
(James) Early Voltage
6.101 Spring 2020 Lecture 3 22
A large VA is desirable for high voltage gains ~ 30-50v.
VA is determined by transistor design and varies with base width, base and collector doping concentration.
Early effect: the rise of Ic due to base-width modulation.
Tek 575 Curve Tracer
6.101 Spring 2020 Lecture 3 23
• Vertical axis: current• Horizontal axis: voltage• Voltage sweep: positive
and negative with resistor current limit 0‐20v; 0‐200v!
• Input: fixed current steps (0.001‐200ma); 240 steps
• Tests: diodes, BJT, MOSFETs• Calibrate zero current step
Mcube
6.101 Spring 2020 Lecture 3 24
• Tests: – Diodes (forward
drop)– BJT (type, beta)– MOSFET (type,
VTH and more)
• Auto terminal identification
RLC – BJT MOSFET Testor
6.101 Spring 2020 Lecture 3 25
BJT Configurations
Voltage Gain
Current Gain
Power Gain
Common Emitter X X X
Common Collector X X
Common Base X X
6.101 Spring 2020 Lecture 3 26
Common emitter: hgh input impedance, for general amplification of voltage, current and power from low power, high impedance sources.
Common collector: aka "emitter follower" for high input impedance and current gain without voltage gain, as in an amplifier output stage.
Common base: low input impedance for low impedance sources, for high frequency response. Grounding the base short circuits the Miller capacitance from collector to base and makes possible much higher frequency response.
Circuit analysis by inspection
6.101 Spring 2020 Lecture 3 27
General Configuration
6.101 Spring 2020 Lecture 3 28
CommonEmitter
CommonCollector
CommonBase
Transistor Configurations
6.101 Spring 2020 Lecture 3 29
+15V
+
Vin
-
+
VOUT
-
RL
R1
+
+
R2
[a] Common Emitter Amplifier [b] Common Collector [Emitter Follower] Amplifier
RE RE
+15V
+Vin
-
+
VOUT
-
RL
R1
+
+
R2
+
[c] Common Base Amplifier
TRANSISTOR AMPLIFIER CONFIGURATIONS
R2
+15V
R 1
+
Vin
-
+VOUT
-
RE
+
+
Common Emitter Operation – Quiescent Point
6.101 Spring 2020 Lecture 3 30
Load Line – Operating Point
6.101 Spring 2020 Lecture 3 31
+20 V
910R2
2N3904
91 BFCR1
+
vout
-
ICQ • Find Vout open circuit voltage: 20V• Find ICQ max = 20/(910 +91) = ~20ma• Draw load line.
• For RE = 0, just choose Q at ½ VCC for maximum swing.
• For RE > 0, set Q at ½ [VCC – VRE]. • For ICQ = 10 mA, VRL = 9.1V, VRE = 0.91V,
VCE = 10V. For ICQ = 10.5mA, VRL = 9.6V, VRE = 0.96V, VCE = 9.5V
Transistor Bias Instability
6.101 Spring 2020 Lecture 3 32
I R V I R VI R V I R VI R R V V
IV VR R
IV V
R R
B B C E CC
B B F B E CC
B B F E CC
BCC
B F E
CF CC
B F E
0 70 7
0 7
0 71
0 72
.
..
.
.
RB
+15V
2N3904
IC = 4 mA
RE = 2200
IB
IE = 4 mA
CEBFE
BFCF
IIIIII
,1,100
R RV V
I
R V VmA
R k
R k kR k
B F EF CC
C
B
B
B
B
0 7
100 2200 100 15 0 74
220 14304
10
220 358138
3
.
.
8.8V
Variation of Collector Current with βOne Resistor
6.101 Spring 2020 Lecture 3 33
RB
+15V
2N3904
IC = 4 mA
RE = 2200
IB
IE = 4 mA
IC F2.9 mA 50
4.0 mA 100
5.0 mA 200
5.4 mA 300
IC=2.5 mA
Variation of Collector Current with Beta
IC F VCC 0.7V
RB F RE
2
Two Resistor Biasing
6.101 Spring 2020 Lecture 3 34
R2
RE =2200
+15V
R 1
2N3904
IC = 4 mA
IC = 4 mA
VTH= VB
RTH= RB
RE = 2200
2N3904
IC = 4 mA
VB
IB
+15V
RB
[a][b]
[c]
VB R1
R1 R2
Vcc 3 RB R1 / /R2 R1R2
R1 R2
4
Thevenin Circuit
6.101 Spring 2020 Lecture 3 35
Two Resistor Biasing
6.101 Spring 2020 Lecture 3 36
R2
RE =2200
+15V
R 1
2N3904
IC = 4 mA
IC = 4 mA
VTH= VB
RTH= RB
RE = 2200
2N3904
IC = 4 mA
VB
IB
+15V
RB
[a][b]
[c]
V I R V I RV I R V I RV V I R I R I R R
IV VR R
IV V
R R
B B B C E
B B B F B E
B B B F B E B B F E
BB
B F E
CF B
B F E
0 7 00 7
0 7
0 75
0 76
..
.
.
.
VVV
VkmAVVkkmA
B
B
B
B
4.1010070968
7010024247.0100220224
Assume RB = 22kΩ,
βRE = 220kΩ and ignore RB
Two Resistor Biasing
6.101 Spring 2020 Lecture 3 37
V RR R
V
R R R VV
R VV
R
R R RR R
B CC
CC
B
1
1 2
1 2 1 1 1
1 2 1
1 2
1510 4
145
1450 45
..
..
Given VB= 10.4 V and RB= 22kΩ, we can now solve equations (3) and (4) for R1 and R2.
R RR R
R k
R RR R
k
RR
k
R kR k use kR R k k use k
B1 2
1 2
1 1
1 1
12
1
1
1
2 1
22
0 450 45
22
0 45145
22
0 310 2270 9 680 45 0 45 70 9 319 33
.
.
.
..
.. . . .
Variation of Collector Current with βTwo Resistor Biasing
6.101 Spring 2020 Lecture 3 38
IC IC F
3.7 mA 2.9 mA 50
4.0 mA 4.0 mA 100
4.2 mA 5.0 mA 200
4.3 mA 5.4 mA 300
IC=0.6 mA IC=2.5 mA
Variation of Collector Current with Beta 67.0
EFB
BFC RR
VVI
I VkCF
F
10 4 0 722 2200
. .
Two Resistor One Resistor
Base Current – Resistor Divider
6.101 Spring 2020 Lecture 3 39
68K
33K
IC F
3.7 mA 50
4.0 mA 100
4.2 mA 200
4.3 mA 300
IC=0.6 mAib
Make small compared to the current through R2
ib
See handout: Transistor bias stability
Common Collector – Emitter Follower Biasing
• Β = 100, iB = 7.5ma/100 =‐ 75µa• Using Thevenin equivalent,
RB = R1||R2, VB =
6.101 Spring 2020 Lecture 3 40
+15V
R 1
2N3904
7.5 mA
1.0 k7.5 mA
R2
A
B
7.5 V
2N3904
7.5 mA
+15V
VB
RB
IB
21
115RR
R
VB = IBRB + 0.6V + 7.5VVB = [75 µA x 10k] + 0.6V + 7.5VVB = 750 mV + 0.6V + 7.5VVB = 8.9V
[15 R1] ÷ [R1 + R2] = 8.9V15 R1 = 8.9 x [R1 + R2][15−8.9] R1 = 8.9 R2R1 = 1.44 R2[R1 x R2] ÷ [R1 + R2] = 10 kΩ
[1.44R2 x R2] ÷ [1.44 R2 + R2] = 10kΩR2 = 16.9 kΩ (use 16 kΩ)R1 = 1.44 R2 = 24.4 kΩ (use 24 kΩ)
Common Collector – Emitter Follower Biasing
• With R1 = 24kΩ, R2 = 16 kΩ, the current through the voltage divider is 15 ÷ [40 kΩ] = 375 µA.
• The 75 µA base current is 20% of 375 µA.
• With R1 = 2 kΩ, will need a divider current that is ~ 4.1 mA. (75 µA is only ~2% of 4.1 mA, which is negligible)
• The voltage drop across R2 will be [15 V – 8.1 V] = 6.9 V; R2 = 1.7 kΩ
• But input impedance will be low = ~890Ω
• Use bootstrapping configuration
6.101 Spring 2020 Lecture 3 41
= 24.4 kΩ (use 24 kΩ)
+15V
R 1
2N3904
7.5 mA
8.1 V
1.0 k7.5 mA
R2
A
B
IDivider
Bootstrapping – Higher Input Impedance
6.101 Spring 2020 Lecture 3 42
Horowitz and Hill Figure 2.80
The base is connected to the emitter through with R3 and C2 . At signal frequency, C2 is a short so both ends of R3 are at the same voltage – so no current flows. Therefore R1 and R2 cannot load the input. So R3 appears to be very high.
In real life, there is a small AC voltage across R3. The AC current through R3 is 0.006 ÷ 4.7kΩ = 1.1 µA.
Result: “stiff” biasing with high input resistance at signal frequency.
6.101 Spring 2020 Lecture 3 43
“Our treatment of bipolar transistors is going to be quite different from that of many other books. It is a common practice to use the h-parameter (hybrid pi) model and equivalent circuit. In our opinion that is unnecessarily complicated and unintuitive. . . you also have the tendency to lose sight of which parameters of transistors behavior you can count on and more important, which ones can vary over large ranges.”
The Art of Electronics, Horowitz & Hill 3rd edition page 71
Commom Emitter – Hybrid π
6.101 Spring 2020 Lecture 3 44
RB
+15V
2N3904
ICRL
C +
vout
_
IB
+
TRANSISTOR AMPLIFIER CONFIGURATIONS WITH HYBRID- EQUIVALENT CIRCUITS
Rs
+vin
_
Rs
r
RL
ib
+
vout
_
c
e
b
+vin
_
RB
COMMON EMITTER AMPLIFER
0 g m r
gm ICQ
VTH
r0 VA
ICQ
Early Voltage
inv1
Lm
m
o
Lov
Lo
b
Lbo
in
outv
Rg
g
RAthen
rR
riRi
vvA
1
1
Common Emitter with Emitter Degeneration
6.101 Spring 2020 Lecture 3 45
• Input resistance (β+1)RE
• Voltage gain reduced by (1+gm RE)• Voltage gain less dependent on β
(linearity)
ELvEo
Eo
Lo
Eob
Lbo
in
outv
RRAthenRrif
RrR
RriRi
vvA
/;1
;111
1
outv1
inv1
Common Collector (Emitter Follower)
6.101 Spring 2020 Lecture 3 46
1;1
;1'
11'
11
1
vEo
Eos
Eo
Eosb
Ebo
in
outv
AthenRrif
RrRR
RrRiRi
vvA
• Buffer with unity gain• High input resistance driving low
output resistance (current gain).
mvVVI
g
rg
THTH
CQm
m
26
0
outv1inv1
Low Frequency Hybrid‐ Equation Chart
6.101 Spring 2020 Lecture 3 47
High gain, better high frequency responseLow input resistance
Unity gain, low output resistanceHigh input resist.
High gain applicationsModerate input resistance
High output resistance
Hybrid‐π Parameters
6.101 Spring 2020 Lecture 3 48
g mq
kT
IC
0 hfe (datasheet)C Cob (datasheet)
g m
2 (C C ) fT (transit frequency datasheet)
C g m
2 fTrC
rx (low frequency) : datasheet or estimate 50100(high frequency) : estimate 25
Miller Effect* – Common Emitter
6.101 Spring 2020 Lecture 3 49
)](1[ LCmM RRgCC
* Agarwal & Lang Foundations of Analog & Digital Electronics Circuits p 861
hfe and High Frequency Limits
6.101 Spring 2020 Lecture 3 50
Small signal current gain versus frequency, hfe, of a BJT biased in a common emitter configuration:
For hfe = 1 = fT, (transit frequency )
For 2N3904*, IC =1ma, VCE=10V , cπ=25pF, cμ=2pF
CrjCrjrg
ivghCjv
rvi m
b
bemfebe
beb
11
hT gm
2 ftCwhere C (c c )
kHzpFKcRgr
fRgofgainafor
MHzpF
mhof
LmhLm
T
3202)100(5.22
12
1100
240272
04.0
*Lundberg, Kent: Become One with the Transistor p29
Miller effect reduces high frequency limit!