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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 1
Chapter 3Systems of Linear Equations
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 2
3.5 Using Linear Inequalities in One Variable to Make
Predictions
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 3
Example: Using Models to Compare Two Quantities
One Budget® office rents pickup trucks for $39.95 per day plus $0.19 per mile. One U-Haul® location charges $19.95 per day plus $0.49 per mile (Sources: Budget; U-Haul)
1. Find models that describe the one-day cost of renting a pickup truck from the companies.2. Use graphs of your models to estimate for which mileages Budget offers the lower price.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 4
Solution
1. Let B(d) be the one-day cost (in dollars) of driving a Budget pickup truck d miles.
Let U(d) be the one-day cost (in dollars) of driving a U-Haul pickup truck d miles.
Equations of B and U are
C = B(d) = 0.19d + 39.95C = U(d) = 0.49d + 19.95
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 5
Solution2. Sketch a graph of B and U in the same coordinate
system. Since the height of a point represents a price, Budget offers the lower price for mileages over approximately 66.7 miles.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 6
Addition Property of Inequalities
If a < b, then a + c < b + c
Similar properties hold for ≤, >, and ≥.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 7
Multiplication Property of Inequalities
• For a positive number c, if a < b, then ac < bc.• For a negative number c, if a < b, then ac > bc.
Similar properties hold for ≤, >, and ≥.
In words, when we multiply both sides of an inequality by a positive number, we keep the inequality symbol. When we multiply by a negative number, we reverse the inequality symbol.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 8
Linear inequality in one variable
Definition
A linear inequality in one variable is an inequality that can be put into one of the forms
mx + b < 0 mx + b > 0mx + b ≤ 0 mx + b ≥ 0
where m and b are constants and m ≠ 0.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 9
Solution of an inequality in one variable
Definition
We say a number is a solution of an inequality in one variable if it satisfies the inequality. The solution set of an inequality is the set of all solutions of the inequality. We solve an inequality by finding its solution set.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 10
Example: Solving a Linear Inequality
Solve the inequality –2x ≥ 10.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 11
Solution
Divide both sides of the inequality by –2, a negative number:
Since we divided by a negative number, we reversed the direction of the inequality. The solution set is the set of all numbers less than or equal to –5.
2 10x 2 102 2
xx
5x
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 12
Reversing an Inequality Symbol
Warning
It is a common error to forget to reverse an inequality symbol when you multiply or divide both sides of an inequality by a negative number.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 13
Interval Notation
We can use interval notation to describe the solution set of an inequality. An interval is the set of real numbers represented by the number line or by an unbroken portion of it.
Examples of inequalities, their graphs, and interval notation are shown on the next slide.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 14
Words, inequalities, graphs, and interval notation
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 15
Example: Solving a Linear Inequality
Solve –3(4x – 5) – 1 ≤ 17 – 6x. Describe the solution set as an inequality, in a graph, and in interval notation.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 16
Solution 3 4 5 1 17 6x x 12 15 1 17 6x x
12 14 17 6x x 12 14 17 66 6xx x x
6 14 17x 146 14 1 147x 6 3x 6 36 6x
12
x
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 17
Solution
We can graph the solution set on a number line, or we can describe the solution set in interval notation as shown below:
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 18
Solution
To verify, we check that for inputs greater than or1
,2
equal to the outputs of y = –3(4x – 5) – 1 are
less than or equal to the outputs of y = 17 – 6x. See the next slide for illustrations of the graphing calculator screens.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 19
Solution
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 20
Three-Part Inequalities
3 ≤ x ≤ 7 means the values of x are both greater than or equal to 3 and less than or equal to 7. We described the solution in a graph below and in interval notation by [3, 7].
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 21
Words, inequalities, graphs, and interval notations
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 22
Interval Notation vs. Ordered Pair
Warning
We use notation such as (3, 7) two ways:
when we work with one variable, the interval (3, 7) is the set of numbers between 3 and 7;
when we work with two variables, such as x and y, the ordered pair (3, 7) means x = 3 and y = 7.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 23
Example: Solving a Three-Part Inequality
Solve –5 < 2x – 1 < 7.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 24
Solution
Get x alone in the “middle part” of the inequality by applying the same operations to all three parts of the inequality: 5 2 1 7x
5 21 1711x
4 2 8x
24
2 22 8x
2 4x
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 25
Solution
So, the solution set is the set of numbers between –2 and 4. We can graph the solution set on a number line, or we can describe the solution set in interval notation as (–2, 4).
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 26
SolutionTo verify our result, we check that, for values of x between –2 and 4, the graph of y = 2x – 1 is between the horizontal lines y = –5 and y = 7.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 27
Example: Using Models to Compare Two Quantities
We can model the one-day pickup truck costs (in dollars) B(d) and U(d) at Budget and U-Haul, respectively, by the system
C = B(d) = 0.19d + 39.95C = U(d) = 0.49d + 19.95
where d is the number of miles driven. Use inequalities to estimate for which mileages Budget offers the lower price.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 28
Solution
Budget offers the lower price when B(d) < U(d). Substitute 0.19d + 39.95 for B(d) and 0.49d + 19.95 for U(d) to get a linear inequality in one variable:
0.19d + 39.95 < 0.49d + 19.95
Solve the inequality by isolating d on the left side of the inequality (see the next slide):
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 29
Solution0.19 39.95 0.49 19.95d d
0.490.19 39.95 0.49 19.95 0.49d dd d 0.30 39.95 19.95d
39.950.30 39.95 19.9 39.955d 0.30 20d 0.30 200.30 0.30
d
66.6d
Budget offers the lower price if the truck is driven over miles.66.6
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 3.5, Slide 30
Solution
To verify our result, we check that, for inputs greater than the outputs of y = 0.19x + 39.95 are less than the outputs of y = 0.49x + 19.95.
66.6,