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Copyright © 2007 Pearson Education, Inc. Slide 7-2 Chapter 7: Systems of Equations and Inequalities; Matrices 7.1Systems of Equations 7.2Solution of Linear

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Copyright © 2007 Pearson Education, Inc. Slide 7-2

Chapter 7: Systems of Equations and Inequalities; Matrices

7.1 Systems of Equations

7.2 Solution of Linear Systems in Three Variables

7.3 Solution of Linear Systems by Row Transformations

7.4 Matrix Properties and Operations

7.5 Determinants and Cramer’s Rule

7.6 Solution of Linear Systems by Matrix Inverses

7.7 Systems of Inequalities and Linear Programming

7.8 Partial Fractions

Copyright © 2007 Pearson Education, Inc. Slide 7-3

7.1 Systems of Equations

• A set of equations is called a system of equations.

• The solutions must satisfy each equation in the system.

• A linear equation in n unknowns has the form where the variables are of first-degree.

• If all equations in a system are linear, the system is a system of linear equations, or a linear system.

bxaxaxa nn 2211

Copyright © 2007 Pearson Education, Inc. Slide 7-4

• Three possible solutions to a linear system in two variables:

1. One solution: coordinates of a point,

2. No solutions: inconsistent case,

3. Infinitely many solutions: dependent case.

7.1 Linear System in Two Variables

Copyright © 2007 Pearson Education, Inc. Slide 7-5

7.1 Substitution Method

Example Solve the system.

Solution

4

31

1

55

11623

11)3(23

3

y

y

x

x

xx

xx

xy Solve (2) for y.

Substitute y = x + 3 in (1).

Solve for x.

Substitute x = 1 in y = x + 3.

Solution set: {(1, 4)}

3

1123

yx

yx (1)

(2)

Copyright © 2007 Pearson Education, Inc. Slide 7-6

7.1 Solving a Linear System in Two Variables Graphically

ExampleSolve the system graphically.

Solution Solve (1) and (2) for y.

3

1123

yx

yx (1)

(2)

Copyright © 2007 Pearson Education, Inc. Slide 7-7

7.1 Elimination Method

Example Solve the system.

Solution To eliminate x, multiply (1) by –2 and (2)

by 3 and add the resulting equations.

3696

286

yx

yx (3)

(4)

2

3417

y

y

1232

143

yx

yx (1)

(2)

Copyright © 2007 Pearson Education, Inc. Slide 7-8

7.1 Elimination Method

Substitute 2 for y in (1) or (2).

The solution set is {(3, 2)}.

• Check the solution set by substituting 3 in for x and 2 in for y in both of the original equations.

3

93

1)2(43

x

x

x

Copyright © 2007 Pearson Education, Inc. Slide 7-9

7.1 Solving an Inconsistent System

Example Solve the system.

Solution Eliminate x by multiplying (1) by 2 and adding the result to (2).

Solution set is .

746

423

yx

yx (1)

(2)

746

846

yx

yx

150 Inconsistent System

Copyright © 2007 Pearson Education, Inc. Slide 7-10

7.1 Solving a System with Dependent Equations

Example Solve the system.

Solution Eliminate x by multiplying (1) by 2 and adding the result to (2).

Each equation is a solution of the other. Choose either equation and solve for x.

The solution set is e.g. y = –2:

42824

yxyx (1)

(2)

428

428

yx

yx

00

42

24

y

xyx

.,4

2

yy

)}2,1()}2,{( 422

Copyright © 2007 Pearson Education, Inc. Slide 7-11

7.1 Solving a Nonlinear System of Equations

Example Solve the system.

Solution Choose the simpler equation, (2), and solve for y since x is squared in (1).

Substitute for y into (1) .

43

523 2

yx

yx (1)

(2)

(3)3

4

43

xy

yx

34 x

Copyright © 2007 Pearson Education, Inc. Slide 7-12

7.1 Solving a Nonlinear System of Equations

Substitute these values for x into (3).

The solution set is

97

or 10)1)(79(

0729

15)4(29

53

423

2

2

2

xxxx

xx

xx

xx

1

314

or2743

34 9

7

yy

.1,1,, 2743

97

Copyright © 2007 Pearson Education, Inc. Slide 7-13

7.1 Solving a Nonlinear System Graphically

Example Solve the system.

Solution (1) yields Y1 = 2x; (2) yields Y2 = |x + 2|.

The solution set is {(2, 4), (–2.22, .22), (–1.69, .31)}.

(2)

(1)

02

2

yx

y x

Copyright © 2007 Pearson Education, Inc. Slide 7-14

7.1 Applications of Systems

• To solve problems using a system1. Determine the unknown quantities2. Let different variables represent those

quantities3. Write a system of equations – one for each

variable

Example In a recent year, the national average spent on two varsity athletes, one female and one male, was $6050 for Division I-A schools. However, average expenditures for a male athlete exceeded those for a female athlete by $3900. Determine how much was spent per varsity athlete for each gender.

Copyright © 2007 Pearson Education, Inc. Slide 7-15

7.1 Applications of Systems

Solution Let x = average expenditures per male y = average expenditures per female

100,1260502

yxyxAverage spent on

one male and one female

(2)

(1)

3900

12100

yx

yx

160002 x8000x

Average Expenditure per male: $8000, andper female: from (2) y = 8000 – 3900 = $4100.