Conveyor+Calculation

7/27/2019 Conveyor+Calculation

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4603.166666667

: PT Newmont

750 mm Friction Factor (f)EP 500/4 f 0.03 Density Table

42 m Lo 49 TABEL 1L 43 m TABEL 2H 7 m Slope, Radiant 0.2V 30 m/min 11.5 Degree K Value 0.625

Fly Ash 0.0625Material density 0.72 T/Cu.m

Q' 77.76 Ton/hours = 60 min/jam x Area (A) x Material Density x Belt Speed (m/min)0.06 Sq.m 0.72 T/cum 30 m/min A=K(0.9B-0.05)

= 0.060078

Weight of moving parts without material carriedQ 150 Ton/hours W 53

= ower requ re o move emp y e = ower o move r pper = 0.06 x f x W x V (L + Lo) 2.65

367

= 0.72 kW

P2 = Power required to move load on level (kW) 1.666666667= f x Q (L + Lo) 628

367= 1.13 kW

P3 = Power to Lift load (kW) P = Total Power = H x Q ( + ) value for ascent conveyor = P1 + P2 + P3 + Pt

367 ( - ) value for descent conveyor = 7.37 kW= 2.87 kW

11.06 kW Safety factor 1.5Choice = 12.00 kW Safety factor 1.63

17.00 hp= 6120 x P

FP V FRICTION FACTOR WEIGHT OF ROTATING PARTS OFCARRIER= 1503.48 kg 0.2 Wc = 13.9 kg/set

= Te x 1/e (Driving Coeffecient Factor) DRIVING COEFFECIENT FACTOR WEIGHT OF ROTATING PARTS OF RETURN ROLLERF2 0.5 Wr = 12.2 kg/set

= 751.74 kg TABEL

= W1 ( H +/- f x L ) BELT WEIGHT STANDART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYORF3 = 107.77 kg 13 kg/m Wm = Qt0.06 x V

= 50/8 x Lr x W1 RETURN IDLER SPACING (Lr)F4 3 m = 83.33 kg/m

= 243.75 kgCARRY IDLER SPACING (Lc)

1 mMINIMUM TENSION OF CARRIER SIDE

Counter Weight Calculation (Wt) ~ 2 x T2 = 1503.48 kg Choise the Larger Tension F4c = 12.5 Lc ( Wm + W1 )~ 2 x T4 = 487.5 kg

= 1204.17 kg

= 7 5 ~ 10 MINIMUM TENSION OF RETURN SIDE~ 2751.54 kg = Fp + F4c - Fr F4r = 12.5 Lr . W1or 2034.88 kg = Fp + F4r - Fr or 2255.22 kg = Fp + F2 = 487.50 kgor 487.50 kg = Fp + F4r

= 2255.22 kgFr = f ( L + Lo)(w1 + Wr/Lr) - (H.W1)

= 75 cm= 4 nos = -43.896 kg

Breaking Strength of tension layer = FM x SFBW x n

= 52.6218 kg/cm.ply

= 210.4872 kg/cm

EP 500/4 Table Tensile Strength

Maximum Tension (FM)

Choice Bigest Tension

Number of ply (n)

CHOICE

Belt Width (BW)

Horizontal length of conveyor C to C conveyor length

Height of level head pulleyBelt speed

POWER MOTOR & COUNTER WEIGHT CALCULATOR

PROJECT

Belt widthTensile strength of belt

Safety factor (SF)

Material to handled

Calculation Conveyor Capacity

Conveyor Capacity

Effective tension (Te)

Slack Side Tension (T2)

Slope Tension (T3)

Sag Tension (T4)


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COUNTER WEIGHT CALCULATOR

: PT. CAMCO OMYA

450 mm Friction Factor (f)EP500 f 0.03

200 m Lo 49L 250 mH 30 mV 45 m/min

Calcium Carbonate Weight of moving partQ 60 Ton/hours W 28

= ower requ re to move empty e t= 0.06 x f x W x V (L + Lo)

367

= 1.85 kW

P2 = Power required to move load on level (kW)= f x Q (L + Lo)

367= 1.47 kW

P3 = Power to Lift load (kW)= H x Q ( + ) value for ascent conveyor

367 ( - ) value for descent conveyor = 4.91 kW

= 6120 x PV FRICTION FACTOR

= 1119.28 kg 0.2

= Te x 1/e (Driving Coeffecient Factor) DRIVING COEFFECI0.418

= 467.86 kg

= W1 ( H +/- f x L ) BELT WEIGHT STAN= 337.5 kg 9 kg/m

= 50/8 x Lr x W1 RETURN IDLER SPA3 m

= 168.75 kg

Counter Weight Calculation (Wt) ~ 2 x T2 = 935.72 kg Choise the Larger Te~ 2 x T4 = 337.5 kg

PROJECT



Slope Tension (T3)

Sag Tension (T4)



Belt speedMaterial to handledConveyor Capacity

Height of level head pulley


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without material carried

t = ower to move r pper

P = Total Power = P1 + P2 + P3 + Pt= 8.23 kW

NT FACTOR

ART (W1)

ING (Lr)

sion


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: EMOMI

450 mm Friction Factor (f)EP500 f 0.03

201.7 m Lo 49L 98.7 mH 21.3 mV 90 m/min

ASH WASTE Weight of moving partQ 5 Ton/hours W 28

= ower requ re to move empty e t

= 0.06 x f x W x V (L + Lo)367

= 1.83 kW

P2 = Power required to move load on level ( kW )= f x Q (L + Lo)

367= 0.07 kW




= 149.6 kg 0.2


= 170.55 kg

= W1 ( H +/- f x L ) BELT WEIGHT STAN

= 169.83 kg 7 kg/m


= 131.25 kg


PROJECT


Horizontal length of conveyor

Sag Tension (T4)

Conveyor Capacity



Slope Tension (T3)

C to C conveyor lengthHeight of level head pulley

Belt speedMaterial to handled


6/32

Belt Spesification : Scandura PN150 x 3 x 5 + 1.5




NT FACTOR

ART (W1)

ING (Lr)

sion


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: EMOMI

450 mm Friction Factor (f)PN150 x 3 f 0.03

93.647 m Lo 49L 98.7 mH 22.133 mV 60 m/min



= 0.06 x f x W x V (L + Lo)367

= 1.22 kW


367= 0.13 kW




= 199.92 kg 0.2


= 227.91 kg


= 175.66 kg 7 kg


= 131.25 kg


PROJECT



Sag Tension (T4)

Conveyor Capacity



Slope Tension (T3)




8/32





NT FACTOR

ART (W1)

ING (Lr)

sion


9/32


: EMOMI


93.647 m Lo 49L 97.947 mH 22.133 mV 72 m/min



= 0.06 x f x W x V (L + Lo)367

= 1.46 kW


367= 0.13 kW




= 187 kg 0.2


= 213.18 kg


= 175.5 kg 7 kg/m


= 131.25 kg


PROJECT



Sag Tension (T4)

Conveyor Capacity



Slope Tension (T3)




10/32





NT FACTOR

ART (W1)

ING (Lr)

sion


11/32

: PT. FREEPORT Mc.MORRAN INDONESIA

750 mm Friction Factor (f)NN200 x 5 X 5/1.5 f 0.03

13 m Lo 49L 12.76 mH 0 mV 142 m/min

SPLIT STONE Weight of moving partQ 200 Ton/hours W 154


= 0.06 x f x W x V (L + Lo)367

= 6.63 kW


367= 1.01 kW


367 ( - ) value for descent conveyor = 0 kW


= 329.28 kg 0.2


= 375.38 kg


= 4.98 kg 13 kg/m


= 243.75 kg





PROJECT


Slope Tension (T3)

Sag Tension (T4)

Material to handledConveyor Capacity




12/32




NT FACTOR

ART (W1)

ING (Lr)

sion


13/32

: PT. Krakatau Bandar Samudra

1000 mm Friction Factor (f)EP800/4 f 0.03

25.5 m Lo 49L 25 mH 0 mV 142 m/min

SOYBEANS Weight of moving partQ 600 Ton/hours W 154


= 0.06 x f x W x V (L + Lo)367

= 7.94 kW


367= 3.63 kW




= 498.66 kg 0.2


= 568.48 kg


= 9.75 kg 13 kg/m


= 243.75 kg



Slope Tension (T3)

Sag Tension (T4)





PROJECT




14/32




NT FACTOR

ART (W1)

ING (Lr)

sion


15/32

: PT. FREEPORT Mc.MORRAN INDONESIA


25.5 m Lo 49L 28.3 mH 9.3 mV 142 m/min

SPLIT STONE Weight of moving partQ 200 Ton/hours W 154


= 0.06 x f x W x V (L + Lo)367

= 8.3 kW


367= 1.27 kW




= 630.97 kg 0.2


= 719.31 kg


= 131.94 kg 13 kg/m


= 243.75 kg





PROJECT


Slope Tension (T3)

Sag Tension (T4)





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NT FACTOR

ART (W1)

ING (Lr)

sion


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: PLN SURALAYA


528.8 m Lo 49L 548.5 mH 9.8 mV 198 m/min

COAL Weight of moving partQ 2400 Ton/hours W 154


= 0.06 x f x W x V (L + Lo)367

= 89.36 kW


367= 117.23 kW




= 8366.48 kg 0.2


= 9537.79 kg


= 1207.73 kg 46 kg/m


= 862.5 kg

Counter Weight Calculation (Wt) ~ 2 x T2 = 19075.58 kg Choise the Larger Te~ 2 x T4 = 1725 kg



PROJECT



Sag Tension (T4)


Conveyor Capacity



Slope Tension (T3)


18/32




NT FACTOR

ART (W1)

ING (Lr)

sion


19/32


: EMOMI


93.647 m Lo 49L 98.7 mH 22.133 mV 72 m/min



= 0.06 x f x W x V (L + Lo)367

= 1.47 kW


367= 0.13 kW




= 187.85 kg 0.2


= 214.15 kg


= 175.66 kg 7 kg/m


= 131.25 kg


PROJECT



Sag Tension (T4)

Conveyor Capacity



Slope Tension (T3)




20/32





NT FACTOR

ART (W1)

ING (Lr)

sion


21/32

: MODIFIKASI CONV. BF11 / BF.12 PLN SURALAYA

1400 mm Friction Factor (f)EP500/4 f 0.03

9.5 m Lo 49L 8.5 mH 0 mV 165 m/min

COAL Weight of moving partQ 2000 Ton/hours W 154


= 0.06 x f x W x V (L + Lo)367

= 7.17 kW


367= 9.41 kW



= 6120 x PFP V FRICTION FACTOR

= 614.97 kg 0.2

= Te x 1/e (Driving Coeffecient Factor) DRIVING COEFFECIEF2 0.638

= 392.36 kg

= W1 ( H +/- f x L ) BELT WEIGHT STANF3 = 8.42 kg 33 kg/m

= 50/8 x Lr x W1 RETURN IDLER SPAF4 3 m

= 618.75 kgCARRY IDLER SPACI

0.7 m


PROJECT







Slope Tension (T3)

Sag Tension (T4)


22/32


= 7 5 ~ 10~ 2598.66 kg = Fp + F4c - Fr or 1779.73 kg = Fp + F4r - Fr or 1007.33 kg = Fp + F2or 1237.50 kg = Fp + F4r

= 2598.66 kg

= 140 cm= 4 nos


= 32.48324085 kg/cm.ply

= 129.9329634 kg/cm

EP 500/4 Table Tensile Strength


Belt Width (BW)Number of ply (n)

CHOICE

Safety factor (SF)Maximum Tension (FM)


23/32

Density TableTABEL 1TABEL 2

K Valuewithout material carried



20.73 kW Safety factor 25%21.00 kW Round up

WEIGHT OF ROTATING PARTS OFCARRIERWc = 90 kg/set

NT FACTOR WEIGHT OF ROTATING PARTS OF RETURN ROLLERWr = 27.5 kg/set

TABEL

ART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYORWm = Qt0.06 x V

ING (Lr)= 202.02 kg/m

NG (Lc)

MINIMUM TENSION OF CARRIER SIDE


24/32

sion F4c = 12.5 Lc ( Wm + W1 )

= 2056.43 kg

MINIMUM TENSION OF RETURN SIDEF4r = 12.5 Lr . W1

= 1237.50 kg

Fr = f ( L + Lo)(w1 + Wr/Lr) - (H.W1)

= 72.7375 kg


25/32

: MODIFIKASI CON-1014, PLANT FEED CONVEYOR

750 mm Friction FaPN450/3 f 0.03

74 m Lo 49L 85 mH 10.5 mV 102 m/min

COAL Weight of Q 360 Ton/hours W 154

= ower requ re to move empty e t= 0.06 x f x W x V (L + Lo)

367

= 10.33 kW


367= 3.95 kW

P3 = Power to Lift load (kW)= H x Q ( + ) value for ascent convey

367 ( - ) value for descent conve= 10.3 kW

= 6120 x PFP V FRICTION

= 1474.8 kg 0.2

= Te x 1/e (Driving Coeffecient Factor) DRIVINGF2 0.638

= 940.93 kg

= W1 ( H +/- f x L ) BELT WEIF3 = 430.65 kg 33

= 50/8 x Lr x W1 RETURN IF4 3

= 618.75 kgCARRY ID

0.7

Counter Weight Calculation (Wt) ~ 2 x T2 = 1881.86 kg Choise the~ 2 x T4 = 1237.5 kg

Slope Tension (T3)

Sag Tension (T4)






PROJECT




26/32

= 7 5 ~ 10~ 2455.25 kg = Fp + F4c -or 2889.29 kg = Fp + F4r -or 2415.73 kg = Fp + F2or 1237.50 kg = Fp + F4r

= 2889.29 kg

= 75 cm= 4 nos


= 67.41676667 kg/cm.ply

= 269.6670667 kg/cm

EP 500/4

Safety factor (SF)Maximum Tension (FM)

Table Tensile Strength



CHOICE


27/32

tor (f)Density TableTABEL 1TABEL 2

K Valueoving parts without material carried


P = Total Power or = P1 + P2 + P3 + Ptyor = 24.58 kW

30.73 kW Safety factor 25%15.00 kW Round up

FACTOR WEIGHT OF ROTATING PARTS OFCARRIERWc = 90 kg/set

OEFFECIENT FACTOR WEIGHT OF ROTATING PARTS OF RETURN ROLLERWr = 27.5 kg/set

TABEL

HT STANDART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYORkg/m Wm = Qt

0.06 x VLER SPACING (Lr)

m = 58.82 kg/m

ER SPACING (Lc)m

MINIMUM TENSION OF CARRIER SIDELarger Tension F4c = 12.5 Lc ( Wm + W1 )

= 803.46 kg


28/32

MINIMUM TENSION OF RETURN SIDEFr F4r = 12.5 Lr . W1r

= 1237.50 kg

Fr = f ( L + Lo)(w1 + Wr/Lr) - (H.W1)

= -176.99 kg


29/32

: PT. SELAT NASIK INDOKWARSA


47.5 m Lo 49 TABEL 1L 50 m TABEL 2H 15.5 mV 65 m/min K Value

PASIR KWARSAQ' 9.009 Ton/hours = Area (A) x Material Density x Belt Speed (m/min)

0.066 Sq.m 2.1 T/cum 65 m/min

Weight of moving parts without material carried

Q 20 Ton/hours W 154

= ower requ re o move emp y e = ower o move r pper = 0.06 x f x W x V (L + Lo)

367

= 4.87 kW


367= 0.17 kW




= 6120 x PFP V FRICTION FACTOR WEIGHT OF ROTATING PARTS OFCARRIER

= 554.57 kg 0.2 Wc = 13.9 kg/set


= 632.21 kg TABEL

= W1 ( H +/- f x L ) BELT WEIGHT STANDART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYORF3 = 391 kg 23 kg/m Wm = Qt

0.06 x V= 50/8 x Lr x W1 RETURN IDLER SPACING (Lr)F4 3 m = 5.13 kg/m

= 431.25 kgCARRY IDLER SPACING (Lc)

1 mMINIMUM TENSION OF CARRIER SIDE

Counter Weight Calculation (Wt) ~ 2 x T2 = 1264.42 kg Choise the Larger Tension F4c = 12.5 Lc ( Wm + W1 )~ 2 x T4 = 862.5 kg

= 351.60 kg



= 75 cm= 4 nos = -276.112 kg


= 27.58663983 kg/cm.ply

= 110.3465593 kg/cm

EP 400/3


Sag Tension (T4)


Slope Tension (T3)



PROJECT





Material to handled

Conveyor Capacity


Safety factor (SF)

CHOICE




30/32

: PT.PURABARUTAMA - KUDUS


10 m Lo 49 TABEL 1L 10 m TABEL 2H 0 mV 65 m/min K Value

PULP PAPERQ' 15.288 Ton/hours = Area (A) x Material Density x Belt Speed (m/min)

0.112 Sq.m 2.1 T/cum 65 m/min




367

= 2.9 kW


367= 0.1 kW


367 ( - ) value for descent conveyor = 3 kW= 0 kW



= 282.47 kg 0.2 Wc = 13.9 kg/set


= 322.02 kg TABEL

= W1 ( H +/- f x L ) BELT WEIGHT STANDART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYOR

F3 = 6.9 kg 23 kg/m Wm = Qt0.06 x V= 50/8 x Lr x W1 RETURN IDLER SPACING (Lr)

F4 3 m = 5.13 kg/m= 431.25 kg

CARRY IDLER SPACING (Lc)1 m

MINIMUM TENSION OF CARRIER SIDECounter Weight Calculation (Wt) ~ 2 x T2 = 644.04 kg Choise the Larger Tension F4c = 12.5 Lc ( Wm + W1 )

~ 2 x T4 = 862.5 kg= 351.60 kg



= 100 cm= 3 nos = 47.908 kg


= 25.59806667 kg/cm.ply

= 76.7942 kg/cm

EP 400/3


PROJECT




Material to handled



Conveyor Capacity

Sag Tension (T4)

Safety factor (SF)





CHOICE


Slope Tension (T3)


31/32

: PT. SUMATERA PRIMA FIBREBOARD


47.5 m Lo 49 TABEL 1L 70 m TABEL 2H 5 m Slope, Radiant 0.104877V 65 m/min 6.1 Degree K Value

WOOD CHIPQ' 120 Ton/hours = Area (A) x Material Density x Belt Speed (m/min)

Sq.m T/cum 65 m/min




367

= 5.85 kW


367= 1.17 kW





= 815.38 kg 0.2 Wc = 13.9 kg/set


= 929.54 kg TABEL

= W1 ( H +/- f x L ) BELT WEIGHT STANDART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYOR

F3 = 163.3 kg 23 kg/m Wm = Qt0.06 x V= 50/8 x Lr x W1 RETURN IDLER SPACING (Lr)

F4 3 m = 30.77 kg/m= 431.25 kg



~ 2 x T4 = 862.5 kg= 672.12 kg



= 120 cm= 4 nos = -18.372 kg


= 21.96056603 kg/cm.ply

= 87.8422641 kg/cm

EP 400/3


PROJECT




Material to handled



Conveyor Capacity

Sag Tension (T4)

Safety factor (SF)





CHOICE


Slope Tension (T3)


32/32

: PT. ABC


200 m Lo 49 TABEL 1L 200 m TABEL 2H 4 m Slope, Radiant 0.02V 120 m/min 1.2 Degree K Value

BATUBARAMaterial density 0.95 T/Cu.m

Q' 1012.32 Ton/hours = 60 min/jam x Area (A) x Material Density x Belt Speed (m/min)0.148 Sq.m 0.95 T/cum 120 m/min

Weight of moving parts without material carriedQ 1000 Ton/hours W 154


367

= 22.57 kW


367= 20.36 kW





= 2745.33 kg 0.2 Wc = 13.9 kg/set


= 3129.68 kg TABEL

= W1 ( H +/- f x L ) BELT WEIGHT STANDART (W1) WEIGHT OF MATERIAL PER METER LOADED ON CONVEYORF3 = 230 kg 23 kg/m Wm = Qt

0.06 x V= 50/8 x Lr x W1 RETURN IDLER SPACING (Lr)

F4 3 m = 138.89 kg/m= 431.25 kg



~ 2 x T4 = 862.5 kg= 2023.61 kg

= 7 5 ~ 10 MINIMUM TENSION OF RETURN SIDE~ 4658.75 kg = Fp + F4c - Fr F4r = 12.5 Lr . W1

or 3497.64 kg = Fp + F4r - Fr or 5875.01 kg = Fp + F2 = 862.50 kgor 862.50 kg = Fp + F4r


= 120 cm= 4 nos = 110.188 kg


= 85.67722917 kg/cm.ply

= 342.7089167 kg/cm

EP 630/4


Safety factor (SF)

Material to handled


Conveyor Capacity



Slope Tension (T3)

Sag Tension (T4)

POWER MOTOR & COUNTER WEIGHT CALCULATOR

PROJECT






Number of ply (n)

CHOICE

Belt Width (BW)

Documents

Conveyor+Calculation