Tutorial 1 solutions
Tutorial 2 solutionsLecturer: Miss Anis Atikah AhmadTel: +604
976 8190Email: [email protected] exothermic reaction
A--->B + Cwas carried out adiabatically and the following data
recorded:
The entering molar flow rate of A was 300 mol/min.(a) What are
the PFR and CSTR volumes necessary to achieve 40 % conversion? (b)
Over what range of conversions would the CSTR and PFR reactor
volumes be identical?(c) What is the maximum conversion that can be
achieved in a 105 dm3 CSTR?(d) What conversion can be achieved if a
72 dm3 PFR is followed in series by a 24 dm3 CSTR?(e) What
conversion can be achieved if a 24 dm3 CSTR is followed in a series
by a 72 dm3 PFR?(f) Plot the conversion and rate of reaction as a
function of PFR reactor volume up to a volume of 100 dm3.
QuestionsX00.20.40.450.50.60.80.9-rA
(mol/dm3.min1.01.675.05.05.05.01.250.91Part (A)Recall Simpson
One-Third Rule Formula:PFR Volume:
Using Simpson One-Third Rule;
What are the PFR and CSTR volumes necessary to achieve 40 %
conversion?Part (A)X00.20.40.450.50.60.80.9-rA
(mol/dm3.min)1.01.675.05.05.05.01.250.91FA0/-rA
(dm3)30018060606060240330
Levelspiel PlotVPFRPart (a)CSTR Volume:
Substituting the value of FA0/rA at X=0.4;
VCSTRLevelspiel PlotPart (B)Over what range of conversions would
the CSTR and PFR reactor volumes be identical?
The volume of both reactors are identical at X=0.4-0.6,
From Levelspiel Plot; Part (B)Over what range of conversions
would the CSTR and PFR reactor volumes be identical?
Using Simpson One-Third RuleProving by calculation;
Volume of PFRVolume of CSTRBy trial and error, calculate what is
X that gives a CSTR volume of 105 dm3
Trial 1: X=0.6,
Part (c)What is the maximum conversion that can be achieved in a
105 dm3 CSTR?
Trial 2: X=0.8,
Trial 3: X=0.7,
X=0.7
The max conversion can be achieved in 105 dm3 of CSTR is 0.7By
trial and error, calculate what is X2 that gives a CSTR volume of
24 dm3
Trial 1: X=0.6,
Trial 2: X=0.7,
Part (d)What conversion can be achieved if a 72 dm3 PFR is
followed in series by a 24 dm3 CSTR?
X2=?X1=0.4FA0=300 mol/dm3VCSTR=24 dm3VPFR=72 dm3
Now, we know that the conversion must be between 0.6-0.7.From
part (a)Trial 3: X=0.64,
Part (d)What conversion can be achieved if a 72 dm3 PFR is
followed in series by a 24 dm3 CSTR?
X2=?X1=0.4FA0=300 mol/dm3VCSTR=24 dm3VPFR=72 dm3 X=0.64
X=0.64 can be achieved if a 72 dm3 PFR is followed in series by
a 24 dm3 CSTR. By trial and error, calculate what is X2 that gives
a PFR volume of 72 dm3 Trial 1: X=0.8,
Part (e)What conversion can be achieved if a 24 dm3 CSTR is
followed in a series by a 72 dm3 PFR?X2=?X1=0.4FA0=300
mol/dm3VCSTR=24 dm3VPFR=72 dm3
From part (a)By trial and error, calculate what is X2 that gives
a PFR volume of 72 dm3 Trial 2: X=0.9,
Part (e)What conversion can be achieved if a 24 dm3 CSTR is
followed in a series by a 72 dm3 PFR?X2=?X1=0.4FA0=300
mol/dm3VCSTR=24 dm3VPFR=72 dm3
Trial 3: X=0.91,
Part (e)What conversion can be achieved if a 24 dm3 CSTR is
followed in a series by a 72 dm3 PFR?
X=0.91 can be achieved if a 24 dm3 CSTR is followed in a series
by a 72 dm3 PFR13Part (f)Plot the conversion and rate of reaction
as a function of PFR reactor volume up to a volume of 100
dm3?X00.20.40.450.50.60.80.9-rA
(mol/dm3.min)1.01.675.05.05.05.01.250.91FA0/-rA
(dm3)30018060606060240330VPFR (dm3)0487276.58084104130.5Part
(f)Plot the conversion and rate of reaction as a function of PFR
reactor volume up to a volume of 100 dm3?THANK YOU
