CONTENTS VOL 1 - deewanbittal.files.wordpress.com · AM 5 Kinematics of Particle AM 128 AM 6 Kinetics of Particles AM 157 AM 7 Plane Kinematics of Rigid body AM 190 AM 8 Plane Kinetics

CONTENTS VOL 1

ENGINEERING MECHANICS

AM 1 Equilibrium of Forces AM 3

AM 2 Structure AM 40

AM 3 Friction AM 81

AM 4 Virtual Work AM 117

AM 5 Kinematics of Particle AM 128

AM 6 Kinetics of Particles AM 157

AM 7 Plane Kinematics of Rigid body AM 190

AM 8 Plane Kinetics of Rigid body AM 206

STRENGTH OF MATERIALS

SM 1 Stress and Strain SM 3

SM 2 Axial Loading SM 41

SM 3 Torsion SM 86

SM 4 Shear Force and Bending Moment SM 118

SM 5 Transformation of Stress and Strain SM 179

SM 6 Design of Beams and Shafts SM 226

SM 7 Deflection of Beams and Shafts SM 270

SM 8 Column SM 315

SM 9 Energy Methods SM 354

THEORY OF MACHINES

TM 1 Analysis of Plane Mechanism TM 3

TM 2 Velocity and Acceleration TM 20

TM 3 Dynamic Analysis of Slider - Crank and Cam TM 38

TM 4 Gear - Trains TM 59

TM 5 Fly Wheel TM 91

TM 6 Vibration TM 109

MACHINES DESIGN

MD 1 Static and Dynamic Loading MD 3

MD 2 Joints MD 22

MD 3 Shaft and Shaft Components MD 54

MD 4 Spur Gears MD 71

MD 5 Bearings MD 88

MD 6 Clutch and Brakes MD 105

CONTENTS VOL 2

FLUID MECHANICS

FM 1 Basic Concepts and Properties of Fluids FM 3

FM 2 Pressure and Fluid Statics FM 33

FM 3 Fluid Kinematics & Bernouli Equation FM 80

FM 4 Flow Analysis Using Control Volumes FM 124

FM 5 Flow Analysis Using Differential Method FM 172

FM 6 Internal Flow FM 211

FM 7 External Flow FM 253

FM 8 Open Channel Flow FM 289

FM 9 Turbo Machinery FM 328

HEAT TRANSFER

HT 1 Basic Concepts & Modes of Heat-Transfer HT 3

HT 2 Fundamentals of Conduction HT 34

HT 3 Steady Heat Conduction HT 63

HT 4 Transient Heat Conduction HT 94

HT 5 Fundamentals of Convection HT 114

HT 6 Free and Force Convection HT 129

HT 7 Radiation Heat Transfer HT 155

HT 8 Heat Exchangers HT 181

THERMODYNAMICS

TD 1 Basic Concepts and Energy Analysis TD 3

TD 2 Properties of Pure Substances TD 28

TD 3 Energy Analysis of Closed System TD 52

TD 4 Mass and Energy Analysis of Control Volume TD 76

TD 5 Second Law of Thermodynamics TD 106

TD 6 Entropy TD 136

TD 7 Gas Power Cycles TD 166

TD 8 Vapor and Combined Power Cycles TD 199

TD 9 Refrigeration and Air Conditioning TD 226

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CONTENTS VOL 3

MANUFACTURING PROCESS

INDUSTRIAL ENGINEERING

OPERATION RESEARCH

CONTENTS VOL 4

ENGINEERING MATHEMATICS

EM 1 Linear Algebra EM 1

EM 2 Differential Calculus EM 24

EM 3 Integral Calculus EM 46

EM 4 Directional Derivatives EM 67

EM 5 Differential Equation EM 79

EM 6 Complex Variable EM 103

EM 7 Probability and Statistics EM 123

EM 8 Numerical Methods EM 142

VERBAL ANALYSIS

VA 1 Synonyms VA 1

VA 2 Antonyms VA 16

VA 3 Agreement VA 26

VA 4 Sentence Structure VA 37

VA 5 Spellings VA 58

VA 6 Sentence Completion VA 87

VA 7 Word Analogy VA 111

VA 8 Reading Comprehension VA 135

VA 9 Verbal Classification VA 148

VA 10 Critical Reasoning VA 153

VA 11 Verbal Deduction VA 168

QUANTITATIVE ANALYSIS

QA 1 Number System QA 1

QA 2 Surds, Indices and Logarithm QA 14

QA 3 Sequences and Series QA 28

QA 4 Average, Mixture and Alligation QA 44

QA 5 Ratio, Proportion and Variation QA 59

QA 6 Percentage QA 75

QA 7 Interest QA 89

QA 8 Time, Speed & Distance QA 99

QA 9 Time, Work & Wages QA 112

QA 10 Data Interpretation QA 126

QA 11 Number Series QA 145

SOLVED PAPER

SP 1 Engineering Mathematics SP 3

SP 2 Engineering Mechanics SP 65

SP 3 Strength of Materials SP 90

SP 4 Theory of Machines SP 138

SP 5 Machine Design SP 189

SP 6 Fluid Mechanics SP 218

SP 7 Heat Transfer SP 265

SP 8 Thermodynamics SP 303

SP 9 Refrigeration and Air-Conditioning SP 358

SP 10 Manufacturing Engineering SP 375

SP 11 Industrial Engineering SP 448

SP 12 General Aptitude SP 496

SM 1STRESS AND STRAIN

Common Data For Q. 1 and 2A long wire of tungsten ( 190 /kN mT

3g = ) hangs vertically from a high-altitude balloon, is shown in figure.

SM 1.1 If the ultimate strength (or breaking strength) is 1500 MPa, the greatest length that it can have without breaking, is(A) 3950 m (B) 7900 m

(C) 1975 m (D) 790 m

SM 1.2 If the same wire hangs from a ship at sea ( 10 / )kN msea water3g = , the greatest

length is(A) 8300 m (B) 2075 m

(C) 7500 m (D) 3750 m

Common Data For Q. 3 and 4The 650 N load is applied along the centroidal axis of the member as shown in figure. Take 60cq = .

SM 1.3 The resultant internal normal and shear forces in the member at section a a- , which passes through point A, is(A) N 0= , V 0= (B) 50 NN = , 650 NV =(C) N 0= , 650 NV = (D) 650 NN = , V 0=


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SM 1.4 The resultant internal normal and shear forces in the member at section b b- , which passes through point A, is(A) 325 NN = , 563 NV = (B) 650 NN = , 563 NV =(C) 563 NN = , 325 NV = (D) 325 NN = , 1126 NV =

SM 1.5 In the figure shown, link BC of 6 mm thickness is made of a steel with a 450 MPa ultimate strength in tension. If the structure is being designed to support a 20 kN load P with a factor of safety of 3, its width w should be

(A) 13.9 mm (B) 55.6 mm

(C) 27.8 mm (D) 41.7 mm

SM 1.6 In figure shown, the two-member frame is subjected to the distributed loading. Member CB has a square cross section of 35 mm on each side and take 8 /kN mw =. The average normal stress and average shear stress acting at section b-b , are

(A) 4.41MPas = , 5.88 MPat = (B) 11.76 MPas = , 4.41MPat =(C) 8.82 MPas = , 5.88 MPat = (D) 5.88 MPas = , 4.41MPat =

Common Data For Q. 8 and 9A solid bar of circular cross section has a hole of diameter /d 4 drilled laterally through the center of the bar as shown in figure below. The allowable average tensile stress on the net cross section of the bar is allows .

SM 1.7 The formula for the allowable load Pallow that the bar can carrying in tension, is(A) . d0 27 allow

2# s (B) . d0 54 allow

2# s

(C) . d0 675 allow2# s (D) . d0 54 allow# s


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SM 1.8 If the bar is made of brass with diameter 40 mmd = and 80 MPaallows = , the value of Pallow is(A) 86.5 kN (B) 70 kN

(C) 172 kN (D) 35 kN

SM 1.9 An axial load P is supported by a short 250 0.67W # column of cross-sectional area 8580 mmA 2= and is distributed to a concrete foundation by a square plate as shown in figure. If the average normal stress in the column must not exceed 150 MPa and the bearing stress on the concrete foundation must not exceed 12.5 MPa, the side a of the plate which will provide the most economical and safe design is

(A) 103 mm (B) 321 mm

(C) 8.6 mm (D) 160 mm

SM 1.10 The column shown in figure, is subjected to an axial force of 8 kN at its top. What is the average normal stress acting at section a -a ?

(A) 1.82 MPa (B) 3.64 MPa

(C) 0.91MPa (D) 2.73 MPa

SM 1.11 A round bar of 10 mm diameter is made of aluminum alloy, as shown in figure. When the bar is stretched by axial forces P , its diameter decreases by 0.016 mm. The magnitude of the load P is (Take 72 GPaE = , 0.33n = , 480 MPaYs = )

(A) 27.4 kN (B) 54.8 kN

(C) 13.7 kN (D) . kN37 7

SM 1.12 A steel bar of length 2.5 m with a square cross section 100 mm on each side is subjected to an axial tensile force of 1300 kN as shown in figure. The increase in





volume of the bar is (Take 250 MPaYs = , 200 GPaE = , .0 3n = )

(A) 8112 mm3 (B) 4868 mm3

(C) 3245 mm3 (D) 6490 mm3

Common Data For Q.14 and 15Three steel plates, each 16 mm thick, are joined by two 20 mm diameter rivets as shown in the figure.

SM 1.13 If the load 50 kNP = , the largest bearing stress acting on the rivets is(A) 39 MPa

(B) 156 MPa

(C) 78 MPa

(D) 117 MPa

SM 1.14 If the ultimate shear stress for the rivets is 180 ,MPa what force Pu is required to cause the rivets to fail in shear ? (Disregard friction between the plates.)(A) 170 kN (B) 57 kN

(C) 226 kN (D) 113 kN

SM 1.15 The small block of 5 mm thickness is shown in figure. If the stress distribution at the support developed by the load varies as shown, the force F applied to the block and the distance d to where it is applied, respectively, are

(A) 220 mm (B) 110 mm

(C) 165 mm (D) 55 mm

SM 1.16 The bar has a cross-sectional area of (400 10 )m6 2#

- . If it is subjected to a uniform axial distributed loading along its length and to two concentrated loads as shown in figure, the average normal stress in the bar as a function of x for





0 0.5 mx< # , is

(A) . . MPax47 5 20 0-^ h (B) 67.5 MPax

(C) . . MPax47 5 20 0+^ h (D) 27.5 MPax

Common Data For Q. 18 and 19In the figure shown, a hollow box beam ABC of length L is supported at end A by a 20 mm diameter pin that passes through the beam and its supporting pedestals. The roller support at B is located at distance /L 3 from end A.

SM 1.17 If load P is equal to 10 kN, the average shear stress in the pin is(A) 15.9 MPa (B) 31.8 MPa

(C) 63.6 MPa (D) 7.95 MPa

SM 1.18 If the wall thickness of the beam is equal to 12 mm, the average bearing stress between the pin and the box beam will be(A) 41.7 MPa (B) 125.1MPa

(C) 83.4 MPa (D) 20.85 MPa

SM 1.19 Rods AB and BC shown in figure, have diameters of 4 mm and 6 mm, respectively. The vertical load of 8 kN is applied to the ring at B . If the average normal stress in each rod is equivalent then this stress will be





(A) 237 MPa (B) 316 MPa

(C) 474 MPa (D) 158 MPa

Common Data For Q. 20 amd 21A steel plate ( /kN m77 3g = ) of dimensions 2.5 1.2 0.1 m# # is hoisted by a cable sling that has a clevis at each end as shown in figure. The pins through the clevises are 18 mm in diameter and are located 2.0 m apart. Each half of the cable is at an angle of 32c to the vertical.

SM 1.20 For above conditions, the average shear stress avert in the pins will be(A) 8.9 MPa (B) 6.7 MPa

(C) 13.4 MPa (D) 26.8 MPa

SM 1.21 The average bearing stress bs between the steel plate and the pins is(A) 22.7 MPa (B) . MPa15 2

(C) 7.57 MPa (D) 30.3 MPa

SM 1.22 Two solid cylindrical rods AB and BC are welded together at B and loaded as shown in figure. If the average normal stress must not exceed 150 MPa in either rod, the smallest allowable values of the diameters d1 and d2 are





(A) 45.2 mmd1 = , 20.1 mmd2 = (B) 22.6 mmd1 = , 40.2 mmd2 =(C) 20.1 mmd1 = , 45.2 mmd2 = (D) 40.2 mmd1 = , 22.6 mmd2 =

SM 1.23 Members AB and AC of the truss as shown, consist of bars of square cross section made of the same alloy. It is known that a 20 mm square bar of the same alloy was tested to failure and that an ultimate load of 120 kN was recorded. If a factor of safety of 3.2 is to be achieved for both bars, the required dimension of the cross section of the bar AB is

(A) 27 mma = (B) 12 mma =(C) 13.5 mma = (D) 6 mma =

SM 1.24 The two steel members are joined together using a 60c scarf weld as shown in figure. The average normal and average shear stress resisted in the plane of the weld are

(A) 8 MPaavgs = , 4.62 MPaavgt = (B) 4.62 MPaavgs = , 8 MPaavgt =(C) 4.62 MPaavgs = , 16 MPaavgt = (D) 16 MPaavgs = , 4.62 MPaavgt =

SM 1.25 A steel pipe of 300 mm outer diameter is fabricated from 6 mm thick plate by welding along a helix which forms an angle of 25c with a plane perpendicular to the axis of the pipe. If a 250 kN axial force P is applied to the pipe, the normal and shearing stresses in directions respectively normal and tangential to the weld are





(A) 18.5 MPa- , 17.28 MPa (B) 37.1MPa- , 34.56 MPa

(C) 18.5 MPa- , 34.56 MPa (D) 37.1MPa- , 17.28 MPa

SM 1.26 A 6 kN load is supported by two wooden members of 75 125mm mm# uniform rectangular cross section which are joined by the simple glued scarf splice as shown in figure. The normal and shearing stresses in the glued splice respectively, are

(A) 565 kPa, 206 kPa (B) 282 kPa, 206 kPa

(C) 565 kPa, 103 kPa (D) 282 kPa, 103 kPa

SM 1.27 In the figure shown, the wooden members A and B are to be joined by plywood splice plates which will be fully glued on the surface in contact. If the clearance between the ends of the members is to be 8 mm and the average shearing stress in the glue is not to exceed 800 kPa, the smallest allowable length L will be

(A) 308 mm (B) 150 mm

(C) 300 mm (D) 292 mm





SM 1.28 In the figure shown, the frame is subjected to the distributed loading of 2 /kN m. What is the required diameter of the pins at A and B if the allowable shear stress for the material is 100 MPaallowt = ? Both pins are subjected to double shear.

(A) 2.6 mmd = (B) 7.8 mmd =(C) 5.2 mmd = (D) 10.4 mmd =

SM 1.29 A specially designed wrench is used to twist a circular shaft by means of a square key that fits into slots (or keyways) in the shaft and wrench as shown in the figure. The shaft has diameter ,d the key has a square cross section of dimensions b b# and the length of the key is c . The key fits half into the wrench and half into the shaft (i.e., the keyways have a depth equal to /b 2). When a load P is applied at distance L from the center of the shaft, the formula for the average shear stress avert in the key is( Hints : Disregard the effects of friction, assume that the bearing pressure between the key and the wrench is uniformly distributed)

(A) bc d b

PL2 +^ h

(B) bc d b

PL22

+^ h

(C) bc d b

PL23

+^ h (D)

bc d bPL

24

+^ h

SM 1.30 The two wooden members shown in figure supports a 20 kN load, are joined by plywood splices fully glued on the surface in contact. The ultimate shearing stress in the glue is 2.8 MPa and the clearance between the members is 8 mm. If





a factor of safety of 3.5 is to be achieved, the required length L of each splice is

(A) 216 mm (B) 208 mm

(C) 200 mm (D) 104 mm

SM 1.31 A torque T0 is transmitted between two flanged shafts by means of four 20 mm bolts as shown in figure. The diameter of the bolt circle is 150 mmd = . If the allowable shear stress in the bolts is 90 MPa, the maximum permissible torque will be

(A) 16.96 kN m- (B) 8.48 kN m-

(C) 12.72 kN m- (D) 4.24 kN m-

SM 1.32 The cross section of an aluminium tube serving as a compression brace in the fuselage of a small airplane is shown in the figure. The outer diameter of the tube is 25 mmd = and the wall thickness is 2.5 mmt = . If the factors of safety with respect to the yield stress and the ultimate stress are 4 and 5 respectively, the allowable compressive force Pallow is (Take 270 MPaYs = , 310 MPaus = )

(A) 9.5 kN (B) 12.0 kN

(C) 11.0 kN (D) 13.7 kN

SM 1.33 In the figure shown, a long steel wire ( 77.0 /kN m3g = ) hanging from a balloon carries a weight W at its lower end. The 4 mm diameter wire is 25 m long. The tensile yield stress for the wire is 350 MPaYs = and a margin of safety against yielding of 1.5 is desired. The maximum weight Wmax that can safety be carried is (Include the weight of the wire in the calculations.)





(A) 1783 N (B) 1711 N

(C) 1759 N (D) 1735 N

SM 1.34 What is the smallest dimensions of the circular shaft and circular end cap if the load it is required to support is 150 kNP = ? The allowable tensile stress, bearing stress and shear stress is ( ) 175 MPat allows = , ( ) 275 MPab allows = and

115 MPaallowt = .

(A) 15.8 mmd1 = , 26.4 mmd3 = , 44.6 mmt =(B) 26.4 mmd1 = , 44.6 mmd3 = , 15.8 mmt =(C) 44.6 mmd1 = , 26.4 mmd3 = , 15.8 mmt =(D) 44.6 mmd1 = , 15.8 mmd3 = , 26.4 mmt =

SM 1.35 The assembly shown in figure, consists of three disks A, B and C are used to support the load of 140 kN. The allowable bearing stress for the material is ( ) 350 MPab allows = and allowable shear stress is 125 MPaallowt = . The smallest diameter d1 of the top disk, the diameter d2 within the support space and the diameter d3 of the hole in the bottom disk are





(A) 27.6 mmd1 = , 22.6 mmd2 = , 35.7 mmd3 =(B) 22.6 mmd1 = , 35.7 mmd2 = , 27.6 mmd3 =(C) 22.6 mmd1 = , 27.6 mmd2 = , 35.7 mmd3 =(D) 35.7 mmd1 = , 22.6 mmd2 = , 27.6 mmd3 =

SM 1.36 In the structure shown, an 8 mm diameter pin is used at A and 12 mm diameter pins are used at B and D . The ultimate shearing stress is 100 MPa at all connections and the ultimate normal stress is 250 MPa in each of the two links joining B and D . If an overall factor of safety of 3.0 is desired, the allowable load P is

(A) 7.7 kN (B) 14.04 kN

(C) 3.97 kN (D) 3.72 kN

SM 1.37 The bar shown in figure, is held in equilibrium by the pin supports at A and B. The support at A has a single leaf and therefore it involves single shear in the pin and the support at B has a double leaf and therefore it involves double shear. The allowable shear stress for both the pins is 125 MPaallowt = . If 1 mx = and

12 /kN mw = , the smallest required diameter of pins A and B are (Neglect any axial force in the bar.)

(A) 957 mmdA = , 20.6 mmdB = (B) 10.3 mmdA = , 9.57 mmdB =(C) 19.14 mmdA = , 10.3 mmdB = (D) 9.57 mmdA = , 10.3 mmdB =

SM 1.38 Two plates, each 3 mm thick, are used to splice a plastic strip as shown below. If the ultimate shearing stress of the bonding between the surface is 900 kPa and

1500 NP = , the factor of safety with respect to shear will be

(A) 2 (B) 3.6

(C) 5.4 (D) 1.8





SM 1.39 The cable shown in figure has a specific weight g (weight/volume) and cross-sectional area A. If the sag s is small, so that its length is approximately L and its weight can be distributed uniformly along the horizontal axis, the average normal stress in the cable at its lowest point C is

(A) sL2

2

s g= (B) sL

8s g=

(C) sL8

2

s g= (D) sL4

2

s g=

SM 1.40 An elastomeric bearing pad consisting of two steel plates bonded to a chloroprene elastomer, is subjected to a shear force V during a static loading test as shown in figure. The pad has dimensions 150 mma = , 250 mmb = and the elastomer has thickness 50 mmt = . When the force V equals 12 kN, the top plate is found to have displaced laterally 8.0 mm with respect to the bottom plate.

The shear modulus of elasticity G of the chloroprene is(A) 0.5 MPa (B) 1MPa

(C) 4 MPa (D) 2 MPa

SM 1.41 A metal bar AB of weight W is suspended by a system of steel wires arranged as shown in the figure. The diameter of the wire is 2 mm and the yield stress of the steel is 450 MPa. The maximum permissible weight Wmax for a factor of safety of 1.9 with respect to yielding, is





(A) N685 (B) 10 N28

(C) 1370 N (D) 2740 N

Common Data For Q. 42 and 43In figure shown below, link BD consists of a single bar 30 mm wide and 12 mm thick. Each pin has a 10 mm diameter.

SM 1.42 If 0cq = , the maximum value of the average normal stress in link BD is (A) zero (B) 72 MPa

(C) 24 MPa (D) 48 MPa

SM 1.43 If 90cq = , the maximum value of the average normal stress in link BD is (A) 83 MPa (B) 125 MPa

(C) 42 MPa (D) 44.5 MPa

SM 1.44 The rigid beam AC shown in figure, is supported by a pin at A and wires BD and CE . If the load P on the beam causes the end C to be displaced 10 mm downward, the normal strain developed in wires CE and BD are

(A) .0 00025CEe = , 0.0107BDe = (B) .0 0025CEe = , .0 00107BDe =(C) .0 025CEe = , 0.0107BDe = (D) .0 00107CEe = , .0 0025BDe =

SM 1.45 The rigid beam shown in figure, is supported by a pin at A and wires BD and CE . If the load P on the beam is displaced 10 mm downward, the normal strain developed in wires CE and BD are





(A) .1 43 10CE3

#e = - , .3 58 10BD3

#e = -

(B) .1 43 10CE3

#e = - , .1 79 10BD3

#e = -

(C) .1 79 10CE3

#e = - , .1 43 10BD3

#e = -

(D) .2 86 10CE3

#e = - , .1 79 10BD3

#e = -

SM 1.46 A steel pipe is to carry an axial compressive load 1200 kNP = as shown in figure. A factor of safety of 1.8 against yielding is to be used. If the thickness t of the pipe is to be one-eighth of its outer diameter, the minimum required outer diameter dmin is (Take 270 MPaYs = )

.

(A) 153 mm (B) 76.5 mm

(C) 114.75 mm (D) 38.25 mm

Common Data For Q. 47 and 48A circular aluminum tube of length 400 mmL = is loaded in compression by forces P as shown in figure. The out-side and inside diameters are 60 mm and 50 mm, respectively. A strain gage is placed on the outside of the bar to measure normal strains in the longitudinal direction.

.

SM 1.47 If the measured strain is 550 10 6#e = - , the shortening d of the bar is

(A) 0.220 mm (B) 2.20 mm

(C) 0.022 mm (D) 1.10 mm

SM 1.48 If the compressive stress in the bar is intended to be 40 MPa, the load P should be(A) 17.35 kN (B) 34.6 kN

(C) 69.4 kN (D) 52.0 kN





Common Data For Q. 49 and 50A suspender on a suspension bridge consists of a cable that passes over the main cable is shown in figure and supports the bridge deck, which is far below. The suspender is held in position by a metal tie that is prevented from sliding downward by clamps around the suspender cable. Let P represent the load in each part of the suspender cable and q represent the angle of the suspender cable just above the tie. Also, let allows represent the allowable tensile stress in the metal tie.

SM 1.49 The minimum required cross-section area of the tie is

(A) tanA Pmin

allowsq= (B) /tanA P2min allowq s=

(C) /cotA P2min allowq s= (D) cotA Pmin

allowsq=

SM 1.50 If 130 kNP = , 75cq = and 80 MPaallows = , the minimum area will be(A) 6064 mm2 (B) 12130 mm2

(C) 435 mm2 (D) 870 mm2

SM 1.51 An elastomeric bearing pad consisting of two steel plates bonded to a chloroprene elastomer, is subjected to a shear force V during a static loading test as shown in figure. The pad has dimensions 150 mma = , 250 mmb = and the elastomer has thickness 50 mmt = . When the force V equals 12 kN, the top plate is found to have displaced laterally 8.0 mm with respect to the bottom plate.

The shear modulus of elasticity G of the chloroprene is(A) 0.5 MPa (B) 1MPa

(C) 4 MPa (D) 2 MPa

SM 1.52 Part of a control linkage for an airplane consists of a rigid member CBD and a





flexible cable AB . Originally the cable is unstretched. If a force is applied to the end D of the member and causes a normal strain in the cable of 0.0035 /mm mm, the displacement of point D is

(A) 21.9 mm (B) 4.38 mm

(C) 43.8 mm (D) 8.76 mm

Common Data For Q. 53 and 54The material distorts into the dashed position is shown in figure.

SM 1.53 The average normal strains xe , ye and the shear strain xyg at A are(A) 0x ye e= = , 0.0798 radxyg =(B) 0xe = , .0 00319ye = , 0.0798 radxyg =(C) .0 00319xe = , 0ye = , 0.0798 radxyg =(D) .0 00319x ye e= = , 0.0798 radxyg =

SM 1.54 The average normal strain along line BE is(A) 0.179 /mm mm- (B) 0.0179 /mm mm

(C) 0.0179 /mm mm- (D) 0.179 /mm mm

SM 1.55 In the figure shown, the bar is originally 300 mm long when it is flat. It is subjected to a shear strain defined by . x0 02xyg = , where x is in millimeters. It is distorted into the shape shown, where no elongation of the bar occurs in the x direction. The displacement yD at the end of its bottom edge will be





(A) 2.03 mm (B) 4.06 mm

(C) 1.015 mm (D) 3.045 mm

Common Data For Q. 56 and 57The steel wires AB and AC support the 200 kg mass. The allowable axial stress for the wires is 130 MPaallows = . Take the unstretched length of AB to be 750 mm and 200 GPaEst = .

SM 1.56 The required diameter of each wire is(A) 3.23 mmdAC = , 7.08 mmdAB = (B) 3.54 mmdAC = , 3.23 mmdAB =(C) 3.23 mmdAC = , 3.54 mmdAB = (D) 6.46 mmdAC = , 3.54 mmdAB =

SM 1.57 What is the new length of wire AB after the load is applied ? (A) 749.51 mm (B) 750.49 mm

(C) 751 mm (D) 749.00 mm

SM 1.58 The plug shown in figure has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. Both the plug and the sleeve are 50 mm long. What is the axial pressure p , that must be applied to the top of the plug to cause it to contact the sides of the sleeve ? (Take 5 MPaE = , .0 45n = )

(A) 926.25 kPa (B) 370 kPa

(C) 741 kPa (D) 555.75 kPa

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CONTENTS VOL 1 - deewanbittal.files.wordpress.com · AM 5 Kinematics of Particle AM 128 AM 6 Kinetics of Particles AM 157 AM 7 Plane Kinematics of Rigid body AM 190 AM 8 Plane Kinetics