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Conjugation action of G on itself.
Stabilizer subgroup of
XEGis Cacx ) = ( ge G :
gxg- '
=x ) centralizer subgroup of
G .
Orbit of X C
is Kacx ) = ( gxg' '
:
g EG ) is the conjugacy class ofx in G .
ZCG ) is kernel of action :
Note ZEZCG ) ⇐ gzg'
=z for all g EG
⇐ Conjugacy class of z is Ez)
Thedasseguatiori
Let G be a finite group and gig . . .
, gr EG
representatives of the distinct conjugacy classesof G not contained in
'
the centre ZCG ) .
Then lol = 17h01 t E. [ G : Cacgc ))
Proofs In any group action of G on X
we have X = G . Xi where Xc,
at,
. . .
,s
are the distinct representatives . of the G- orbits on
×Orbit Stabilizer Theorem says
.la.xl=[ G : Gx )
So lXl= I,
[ a : axe ]
We have X -
-G and Gxi = Cath
This would be sufficient if it weren't for
the IZCOII term.
But each ett of ZCG ) is In its own conjugacyclass ( orbit )
.
So suppose ZCG ) -- Lz
,. . .
Ztt
and the other representatives of thedistinct conjugacy classes are Cgi ,
. .
, gr )
thenG= If ,
⇐ I U Kacgc )
⇒ lol = E. I t E,
[ G : Cacgc) )
= IZCGH t €,
[ G :C aegis I
F-tya.me#willshowlKoCdl=k.i.nm!iI..ksl.msksif o has cycle type mi "
Z . - . 2ms"
including I cycles .
S4 has cycle types :
(4) : 6
C3,1 ) : 8( 22) : 3
( 2,17 : 6
( 14 ) : I
17h54)
1=124--1541--12-4,54
) ) t Gt3 t 8.16
theorem If p is a prime a P is a p -
groupie IPI = pa for Sore azl
then IZCPH > I
IPI = IZCP ) I t I,
LP :
Cpcgc) ]
where g. ,. . .
, gr are distinctconjugacy
class
representatives not in Zca )
lkpcge) I = [ P : Cpcgcj] 71 a [ P :
cpcgcs.tl/PllPjla--lZCP)/i I,
[ p : cpcg, ]⇒ p
I [ P : Cpcgc, ]
TI divisible by pBy equation IZCPH = O mod'p
So IZCPH= I is impossible .
So IZCP)17 I ⇒ ZCP ) t Ll ).
Lemme If GIG ) is cyclic ,then G must
be abelian.
Cyzca , =LgZ⑥ 7 for some GE G .
Let x, ye G ⇒ XZCG ) -
- g" ZCG )
YZCG) =geZCG)
So x = gkz y = glz '
Xy = gkzglz'
= gktlzz ' =gl' - ' '
z' z = glz '
gkz.
= yx .
Corollary If IPI =p' for some prime p
then P is abelian .
In fact P IZlyprz,
Or Z4pz×4pzProof . Since ZCP ) t I then IZLPII =p or p
-
If IZCPH=p then Hunt =p ⇒ Plzcp) I Cp
⇒ P is abelian .
So all groups of order p'
are abelian.
If P has an ett x of order p'
then 47 s P a thx > I =P ⇒ p=Lx7
Otherwise, any
I #EP must have order p .
Let y E P - Cx ?
< x7 E Lx ,y7EPKx, y ? I =p'
and so ex, y > =P
±
Cf : Cp x Cp → P Check this is
exa , yb) → xayb a groupiso
It is clearly a bijection
Fritsylowtheorem-i.fra prime divisor p of 1Gt
,a Sylow
p - subgroup is a subgroup P of order p"
where I Gl=pi 'r and Ptr .
That is p"
is maximal power ofp divisor
of IGI.
)
Firstsylowtheoremforevery prime p I IGI
,G has a
Sylow p- subgroup .
Pro Proof by strong induction on nzl.
Pln ) : If G is a groupof order
pnthen G has a Sylow p - subgroupPll) -
If IGI =p then GE Cp and
so a is itself a Sylow p- subgroup .
Assume Pcm ) for all mlnLet IGI = pn and n=pa
- 'r ptr
Corset pl IZCGHThen 7h01 has an element of order p
by Cauchy 's theoremN = Lx ) EZCG )
Then NEC
1%1 = pair
So GN has Sylow p-
sabyp Pym
where NEPSG⇒ IPINI =p
" 'r ⇒ 1Pl= par
Case I px IZCG )
Kl= IZCG ) I t EI,
[ G : Caged CH
for godistinct
representativesSuppose p
I [ G : Cacgc) ] for all i of conjugacyClasses .
not
and pl IGI in ZCG )
Then p I IZCGIISo by contradiction
, pH [ a : Cacgc) ] for some
But then lol = lcacge ) I Co : Cages ]t -
Recall lol = par rptr'
Then if m = [ a :C Cgc ) )gcdcpgm ) =L C since gcdcpgm) =p
's
Absa ).
a pxmBut then in
pal lcacgc ) I [ G : Cacgc) ]
⇒ pal lcacgcslSo I Cacgc) I = pas
lol = lcacgo ) t [ C : Cacgc) ]par= pas rn ⇒ r -
- Sm
& ptr ⇒ ptsSo lcocgc )l = pas pts
kacgcsl a lol⇒ By inductive hypothesis , Cacgc )
has Sylow p- subgp P of size p
"
PE Cacgc ) E GP is
.
ii. so Sylow p - subgroup of G .