Upload
sunil-pulikkal
View
24
Download
1
Embed Size (px)
DESCRIPTION
composite beam design as per IRC
Citation preview
Design Calculation Job No: IA-PB-****
Design By : ***
Checked By : ***
Page # : 1
Reference Codes
IRC-22
IRC-24
IRC-21
GIVEN DATA
Span (L) = 18 m
Concrete slab width (cbf) = 2000.00 mm
Thickness of slab (cth) = 300.00 mm
fck, Grade of concrete = 40 N/mm2
Live Load (LL) = 700.00 kN
Super imposed dead load = 20% slab wt
Steel Beam I- Section
dw, Web Depth = 1000 mm
tw, Web Thickness = 10 mm
bf, Flange Width = 500 mm
tfo, Flange Thickness = 30 mm
bf, Bottom Flange Width = 500 mm
tfi, Bottom Flange Thickness = 30 mm
D, Total Depth = 1060 mm
Type of Construction : Unshored
DATA ASSUMED
Ec = 32500 N/mm2
(IRC-21:2000, Table-9)
Density of Concrete = 24 kN/m3
Es, Modulus of Elasticity = 211000 N/mm2
(IRC-24:2001, 505.1.1)
Density of steel = 78.5 kN/m3
Yield strength of steel 250 Mpa
Y
Concrete Flange = 2000 x 300
Z Z
Web =1000x10
Top & Bottom Flange=500x30
Y
Load Calculation
Dead Loads
Self weight of slab = 14.40 kN/m
Self weight of beam = 3.14 kN/m
Super imposed dead load ( 20% slab wt ) = 2.88 kN/m
Total Dead Load (DL) = 20.42 kN/m
DL moment ( wl^2/8) = 827.01 kN.m
LL moment ( Wl / 8) = 1575.00 kN.m
DL Shear 183.78 kN
LL Shear 350.00 kN
Design Calculation Job No: IA-PB-****
Design By : ***
Checked By : ***
Page # : 2
M, Moment = wL2/8 = 583.2 kN.m
V, Shear Force = 129.6 kN
Modular Ratio
For Permenant Loads, m = Es / ( Kc x Ec ) = 12.98461538
For Transient Loads, m = Es / ( Ec ) = 6.492307692
Properties of I - Beam (STEEL)
A, Area = 40000 mm2
yg, centroid of section from bottom flange = 530 mm
Iz, Inertia about major axis = 8,792,333,333 mm4
Iy, Inertia about minor axis = 625,083,333 mm4
ry Radius of gyration about yy 125
Z, Section Modulus 16,589,308 mm3
Composite proerties for Transient Loads
transformed Effective width of flange ( cbf/m) = 308.06 mm
transformed Area for concrete flange () = 92417 mm2
Design Calculation Job No: IA-PB-****
Design By : ***
Checked By : ***
Page # : 3
Combined Properties of I-beam + Concrete flange
Total Depth = 1360 mm
Total area = 132417 mm2
C. G. of section from bottom flange = 1005 mm
Iz, for combined section = 22,394,265,877 mm4
Zzbottom flange, for combined section = 22,291,981 mm3
Z top, for combined section = 63,009,384 mm3
Calculation of elastic Critical stress fcb
fcb = k1 ( X + k2 Y ) ( c2 / c1 ) 191.72
X = Y sqrt ( 1 + 1/20 ( l T / ( ry D )^ 2 ) 127.814206
Y = 26.5 x 10 ^ 5 / ( l / ry ) ^ 2 Mpa 127.81411
c1, c2 = lesser & greater distance of of extreme
fiber from N.A 530.0 Mpa
k1 1
k2 0.50
sigma bc 87 Mpa
1) Checking of the stress
CONSTRUCTION STAGE
During construction stage, since
Due to Dead Loads ( Unshored condition )
bending compressivestress @ top flange 49.85
Allowable stress
bending tensile stress @ bottom flange = 49.85 N/mm2
Allowable bending stress = 0.62 * Fy = 155 N/mm2
Unity Check = 0.32 < 1.0 Hence ok
Shear stress (average) = 18.38 N/mm2
Allowable shear stress = 0.38 * Fy = 95 N/mm2 ( Table 6.2, IRC-24-2001 )
Unity Check = 0.19 < 1.0 Hence ok
Deflection check
Allowable deflection ( span / ) = 600
Deflection ((5/384)*w*L4/(E*I) = 5.9070 mm
span / deflection = 3047 O.K.
Composite action for additional live load
Additional tesile stress in steel 71 N/mm2
Total tensile stress in steel 121 N/mm2
Allowable bending stress = 0.62 * Fy = 155 N/mm2
Unity Check = 0.78 < 1.0 Hence ok
Compressive stress in concrete = 3.85 N/mm2
Allowable stress 15.00 N/mm2 ( Table - 9 of IRC 21)
Vertical Shear
Total Vertical shear is assumed to be resisted by steel beam
Total Vertical shear = 533.78 kN
Shear stress (average) = 53.38 N/mm2
Allowable shear stress = 0.38 * Fy = 95 N/mm2 ( Table 6.2, IRC-24-2001 )
Unity Check = 0.56 < 1.0 Hence ok
Design of shear connectors
High tensile shear Connector from fatigue strength consideration
IRC:22-2000: Cl 611.4.1.2
VR = 350.00 kn
Area of transformed concrete salb = Ac = 92417 mm2
Y bar = 205
I = 22,394,265,877 mm4
Vr 0.2967 kN/mm
P = Spacing of connectors required
Design Calculation Job No: IA-PB-****
Design By : ***
Checked By : ***
Page # : 4
dia of shear stud, d 25
stud height , h 120
h/d 5 > 4
No of shear studs / cross section 2
Qr = Alpha. A. 10^-2 27 kN
P 182 mm
High tesile shear Connector from the consideration of ultimate flexural strength
Maximum horizontal force based on CL 611.4.1.2.1
H1 = Ast . Fy . 10-3
= 10000 kN
H2 = 0.85 fc. bf. hf. 10-3
20400 kN
Maximum horizontal force in the slab =minimim of H1 & H2
10000 kN
The ultimate strength of shear connector Qu = 0.5A sqrt (fck.Ec) x 10^-3
279.84
number of shear connectors between the mid span and end support, n = H/ ( lamda Qu ), Lamda = 0.85
42.04
The number of shear connecters based on fatigue 98.91 Hence the fatigue strength requirement governs
Design of transverse reinforcement
VL = V . Ac . Y / I
Since it is unshored construction, the V is the shear from Live load & super imposed dead load
350.00
VL 0.30 kN/mm
0.4 Ls sqrt (fck)
Ls, length of shear plane 1-1 as per Fig 5a of IRC 22
600 mm
Ls, for shear plane 2-2 as per Fig 5a of IRC 22 740 mm
0.4 Ls sqrt (fck) 1517.89
0.7 As sigma y + 0.08 Ls sqrt (fck) 486.01
Reinforcement provided = 0.2% in each direction 600.00 mm^2 / m length
Diameter of reinforcement 10.00 mm
spacing of top & bottom bar 0.26 m
Provide 10mm dia bars @ 250k=mm spacing at top & bottom in both directions