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combined footing design
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0 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 0.2 0.22
0.34 4.17 4.42 4.69 4.98 5.28 5.62 5.97
0.32 3.7 3.93 4.17 4.43 4.7 4.99 5.31 5.66 6.04 6.46
0.3 3.33 3.54 3.75 3.98 4.23 4.49 4.78 5.09 5.43 5.81 6.23 6.69
0.28 3.03 3.22 3.41 3.62 3.84 4.08 4.35 4.63 4.94 5.28 5.66 6.08
0.26 2.78 2.95 3.13 3.32 3.52 3.74 3.98 4.24 4.53 4.84 5.19 5.57
0.24 2.56 2.72 2.88 3.06 3.25 3.46 3.68 3.92 4.18 4.47 4.79 5.15
0.22 2.38 2.53 2.68 2.84 3.02 3.2 3.41 3.64 3.88 4.15 4.44 4.77
0.2 2.22 2.36 2.5 2.66 2.82 2.99 3.18 3.39 3.62 3.86 4.14 4.44
0.18 2.08 2.21 2.35 2.49 2.64 2.8 2.98 3.17 3.38 3.61 3.86 4.15
0.16 1.96 2.08 2.21 2.34 2.48 2.63 2.8 2.97 3.17 3.38 3.62 3.88
0.14 1.84 1.96 2.08 2.21 2.34 2.48 2.63 2.79 2.97 3.17 3.39 3.64
0.12 1.72 1.84 1.96 2.08 2.21 2.34 2.48 2.63 2.8 2.98 3.18 3.41
0.1 1.6 1.72 1.84 1.96 2.08 2.2 2.34 2.48 2.63 2.8 2.99 3.2
0.08 1.48 1.6 1.72 1.84 1.96 2.08 2.21 2.34 2.48 2.64 2.82 3.02
0.06 1.36 1.48 1.6 1.72 1.84 1.96 2.08 2.21 2.34 2.49 2.66 2.84
0.04 1.24 1.36 1.48 1.6 1.72 1.84 1.96 2.08 2.21 2.35 2.5 2.68
0.02 1.12 1.24 1.36 1.48 1.6 1.72 1.84 1.96 2.08 2.21 2.36 2.53
0 1 1.12 1.24 1.36 1.48 1.6 1.72 1.84 1.96 2.08 2.22 2.38
ex / Lx ez / Lzk1 = 1.000
0.00 0.00
ex / Lx ez / Lzk2 = 1.000
0.00 0.00
ex / Lx ez / Lzk3 = 1.000
0.00 0.00
k1 1.000k2 1.000k3 1.000
7.48337
ex/Lx
ey/Ly
0.24 0.26 0.28 0.3 0.32 0.34
6.56
6.01 6.51
5.55 6.01 6.56
5.15 5.57 6.08 6.69
4.79 5.19 5.66 6.23
4.47 4.84 5.28 5.81 6.46
4.18 4.53 4.94 5.43 6.04
3.92 4.24 4.63 5.09 5.66
3.68 3.98 4.35 4.78 5.31 5.97
3.46 3.74 4.08 4.49 4.99 5.62
3.25 3.52 3.84 4.23 4.7 5.28
3.06 3.32 3.62 3.98 4.43 4.98
2.88 3.13 3.41 3.75 4.17 4.69
2.72 2.95 3.22 3.54 3.93 4.42
2.56 2.78 3.03 3.33 3.7 4.17
G289+M293*K309-K309*(M299+(M297-M299)*(1-K309/B59))-0.5*K309*(M297-M299)/B59G289+M293*K309-K309*(M299+(M297-M299)*(1-K309/B59))-0.5*K309^2*(M297-M299)/B59
F316*(K309^2)/2+0.5*(M297-F316)*(K309^2)*2/3-G289*(K309-(B59-J59)/2)-G291-M293*K309^2/2F316*(K309^2)/2+0.5*(M297-F316)*(K309^2)*2/3-G289*(K309-(B59-J59)/2)-G291-M293*K309^2/2
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
DESIGN OF COMBINED FOUNDATION MARKED F5( With ground water table at FGL. )
LOAD TABLE ( Units kN & m )
Pedestal - I Pedestal - II
V1 Hx1 Hz1 Mx1 Mz1 V2 Hx2 Hz2 Mx2
3101 1 F 27 25 26 205 40 76 2 11.5 53
UNIT WEIGHTS ( Units Mton / cu.m. )
= 25= 20.0
SOIL PROPERTIES ( Units KN / sq.m.)
P_net = 175 Friction between conc.
= 0.4
MATERIAL GRADES ( Units MPa )
Concrete ( fck ) = 25Reinforcement ( fy ) = 460
CLEAR COVER ( Unit mm ):
In pedestal ( Cp ) = 50In footing ( Cf ) = 75
BAR DIAMETER ( Unit mm ):
In footing (X dir. top) = 12In footing (X dir. bott) = 16In footing (Z dir. top) = 12In footing (Z dir. bott) = 16
TRIAL SIZE OF COLUMN & FOUNDATION ( Units m )
Lx Lz T Df lx lz Dw Dl L3.0 1.8 0.3 1.2 0.5 0.5 10 1.2 2
Node no.
Load comb.
Concrete ( gc )Soil ( gs )
& soil ( m )
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
LOAD & BEARING PRESSURE CALCULATION ( Units kN & m )
Total load & moments on foundation transferred from superstructure :
Vertcal load ( V ) = V1 + V2
Horizontal forces : Hx = Hx1 + Hx2 ; Hz = Hz1 + Hz2
Moment about X - axis ( Mx ) = Mx1 + Mx2
Eccentricity of direct load along X - axis ( e ) = L. [ 0.5 - { V1 / ( V1 + V2 )}]
Moment about Z - axis ( Mz ) = Mz1 + Mz2 + V.e
Calculated load & moments are tabulated below :
V Hx Hz Mx e Mz
3101 1 F 103 27 37.5 209.5 0.476 93.5
Weight of pedestal ( Wp ) = 15.00 kN
Weight of footing ( Wf ) = 41 kN
Weight of soil overburden ( Ws )= 88 kN
Total vertical load on foundation :
Total moment @ X direction :
Total moment @ Z direction :
Maximum gross bearing pressure :
Minimum gross bearing pressure :
Modified bearing pressure in case of tension being developed below footing :
Node no.
Load comb.
2.lx.lz.Dl.gc =
Lx.Lz.T.gc =
(Lx.Lz-2.lx.lz).(Df-T).gs =
SV = V+Wp+Wf+Ws-Fb
SMx = Mx
SMz = Mz
P_max = SV / (Lx.Lz) + 6.SMx / (Lx.Lz2) + 6.SMz / (Lz.Lx2)
P_min = SV / (Lx.Lz) - 6.SMx / (Lx.Lz2) - 6.SMz / (Lz.Lx2)
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
where, ' K ' is the bearing pressure co-efficient as given in section 6.9 of"FOUNDATION DESIGN" by W.C.Teng.
K = function of ( ex/Lz, ez/Lx ), &
Allowable gross bearing pressure :
= 199
Bearing pressure calculation is done in a tabular form as shown below :
P_max P_min ex/Lz ez/Lx P_mod
3101 1 F 246.70 265.75 134.00 259.36 -167.99 0.60 0.18 3.00 137.06
UNSAFE, SINCE LOSS OF CONTACT IS MORE THAN 30%.
CHECK FOR STABILITY
Overturning :
Sliding :
Allowable minimum factor of safety are as follows :
Against overturning = 1.5Against sliding = 1.5
Check against overturning :
Mrx Mrz
P_mod = K. SV / ( Lx. Lz )
ex = SMx / SV ez = SMz / SV
P_all = (P_net) + gs.x Df
Node no.
Load comb.
SV SMx SMz" K " after
"Teng"
Maximum overturning moment about Lx side = SMx
Maximum overturning moment about Lz side = SMz
Restoring moment about Lx side ( Mrx ) = SV. Lz / 2
Restoring moment about Lz side ( Mrz ) = SV. Lx / 2
Resultant sliding force ( Hm ) = Hx2 + Hz2 in respective load case.
Restoring force ( Hr ) = m. SV in respective load case.
Node no.
Load comb.
SMx F.O.S. = Mrx/SMx SMz F.O.S. =
Mrz/SMz
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
3101 1 F 265.75 222.03 0.84 134.00 370.05 2.8 UNSAFE
Check against sliding and uplift :
Hm Hr
3101 1 F 46.2 98.7 2.1 O.K.
V1 + Wp = P1 V2 + Wp = P2
M1 L M2
w
y2y1
x Point of Max. B.M.Lx
In the above diagram ( All units are Mton & m ),
P1 = V1 + Wp = 8.30 P2 = V2 + Wp =
M1 = Mz1 + Hx1.(Dl+T) = 0.1 M2 = Mz2 + Hx2. (Dl+T) =
Downward U.D.L. per unit length of footing w = ( Wf + Ws - Fb ) / Lx =
Ordinate of distributed reaction for full width below foundation :
246.7 134
Bending moment will be maximum at a distance ' x ' where shear force is zero.
Shear force at a distance ' x ' is given by
Node no.
Load comb.
F.O.S. = Hr/Hm
DESIGN OF FOOTING - For Load Combination, which yields maximum pressure.
Analysis of footing slab in X - direction : Free-body diagram is shown below.
For SV = & SMz = y1 = SV / Lx + 6. SMz / Lx2 =
y2 = SV / Lx - 6. SMz / Lx2 =
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
= P1 + w.x - { y2 + (y1 - y2).(Lx - x)/Lx }.x - 0.5 x.{ y1 - y2 - (y1 - y2).(Lx - x)/Lx }
Shear force will be 183.30 at a distance x = 3.5 m
Ordinate of bearing pressure at the point of maximum bending moment
y = y2 + (y1 - y2). (Lx - x)/Lx
y = -36.878 Mton / m
Bending moment in the footing slab about point located at " x "
BM1 =
BM1 = 337.509259 Mton-m Tension at bottom of footing
Bending moment per unit width of footing = BM1 / Lz = 187.51 Mton-m/m
Cantilever length ( lcx ) in m = ( Lx - L - lx ) / 2 = 0.25
4.02 Tension at bottomin the overhang part
Bending moment per unit width of footing = BM2 / Lz = 2.23 Mton-m/m
= 201
Shear force in Mton at a distance "d" from the face of pedestal towards the centreis obtained from equation - 1, putting x = 0.951
SF1 = -87.13
Shear force per unit width of footing = SF1 / Lz = -48.41 Mton/m
Shear force in Mton at a distance "d" from the face of pedestal towards cantilever sideis conservatively given by : SF2 = ( y1 - w ) x ( lcx - d )
SF2 = 6.30
Shear force per unit width of footing = SF2 / Lz = 3.50 Mton/m
subjected to an U.D.L., which is equal to the net bearing pressure.
Maximum gross bearing pressure Pg = 259.36
= P1 + w.x - x.{ y2 + (y1 - y2).(1 - x/Lx) } - 0.5 x2.(y1-y2)/Lx
y. x2/2 + 0.5. ( y1 - y ). x2. 2/3 - P1. { x - ( Lx - L )/2 } - M1 - w. x2/2
Bending moment ( BM2 ) in Mton-m = ( y1 - w ). lcx2 / 2 =
Effective depth ( d ) of footing slab in mm = T.103 - Cf - 1.5 x Bar dia.
Analysis of footing slab along Z - axis : Footing slab is analysed as cantilever of unit width
Mton / m2
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
= 226.558
Cantilever length ( lcz ) = ( Lz - lz ) / 2 = 0.650 m
47.86 Mton-m / m ( Tension at bottom )
Shear force at a distance "d" from the face of pedestal = Pn. ( lcz - d/1000 )
SF3 = 101.72 Mton / m
Analysis along Z - axis for tension at top:
Minimum gross bearing pressure ( Mton/sq.m. ) P_min = ###
Minimum net bearing pressure P'n ( Mton/sq.m. )
= -200.79
Since P'_net is ( - )ve, top reinforcement is required to be designed.
-42.42
Shear force in Mton / m. at the face of pedestal
= P'n. lcz
= -130.51
Computation of %age of steel as per SP:16, pertaining to the aforesaid B.M. & S.F.is tabulated below ( Minimum %age is considered as pt = 0.2 ) :
Tension at
X Top 0 0.00 0.00 -48.41 -3.51 5.55 5.55X Bottom 2.23 0.83 0.22 3.50 0.26 0.12 0.22Z Top 42.42 14.85 Err:502 130.51 9.46 -26.09 ###Z Bottom 47.86 17.77 Err:502 101.72 7.59 -22.03 ###
Reinforcement Summary :
Maximum net bearing pressure Pn = Pg - gs.Dw - ( gs -1.0 ).( Df - Dw )
Mton / m2
Bending moment ( BM3 ) = Pn. lcz2 / 2 =
= P_min - gs.Dw - ( gs -1.0 ).( Df - Dw )
Bending moment in Mton-m / m = P'n. lcz2 / 2 =
Direc- tion
B.M. (Mton-m/m)
Mu/bd2 (MPa)
pt (%) as per
SP:16
S.F. (Mton/m
)
Vu/bd (MPa)
pt (%) as per SP:16
pt (%) reqd.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Face
X Top 11154.7042 12 150 753.6X Bottom 433.995198 16 150 1339.73Z Top Err:502 12 175 645.943Z Bottom Err:502 16 175 1148.34
Check for punching shear :
Three faces of the column shall be effective in resisting punching shear.
Periphery of punching shear ( Bo ) in m = 2. [( lx + d ) + ( lz + d )]
= 2.80
Punching load ( Pp ) in Mton = Vmax + Wp Vmax = Maximum direct load on column
= 91.00 = 76 Mton
= 2.42
Allowable punching shear stress in MPa = 0.25 fck
= 1.25 UNSAFE
Direc- tion
Ast (mm2 /m)
= pt.b.d 100
Bar dia. (mm)
Spacing (mm)
Ast provided (mm2 /m)
Punching shear is critical at a distance of " d / 2 " from the face of column.
Punching shear stress ( tc ) in MPa = 1.5. Pp. 104 / ( Bo. d )
Calc No. 9558-360-POC-U-848
Pedestal - II
Mz2
4.5
Calc No. 9558-360-POC-U-848
Calc No. 9558-360-POC-U-848
Remarks
UNSAFE 45.68519 164.0432 49.62963 259.358
Calc No. 9558-360-POC-U-848
Point of Max. B.M.
8.40
0.1
42.90
171.57
-7.10
Calc No. 9558-360-POC-U-848
Mton-m/m
Tension at bottom
Mton-m/m
1
Calc No. 9558-360-POC-U-848
( Tension at bottom )
Calc No. 9558-360-POC-U-848
Vmax = Maximum direct load on column
Sheet 13DESIGN OF COMBINED FOUNDATION MARKED F1
LOAD TABLE ( Units kN & m )
Pedestal - I Pedestal - II
V1 Hx1 Hz1 Mx1 Mz1 V2 Hx2 Hz2 Mx2 Mz2
7&33 104 120 3 1 0 0 -83 2 21 0 0
UNIT WEIGHTS ( Units kN / cu.m. )
= 25= 18.0
SOIL PROPERTIES ( Units KN / sq.m.)
P_net = 150 Friction between conc.
= 0.4
MATERIAL GRADES ( Units MPa )
Concrete ( fcu ) = 40Reinforcement ( fy ) = 460
CLEAR COVER ( Unit mm ):
In pedestal ( Cp ) = 50In footing ( Cf ) = 75
BAR DIAMETER ( Unit mm ):
In footing (X dir. top) = 12In footing (X dir. bott) = 12In footing (Z dir. top) = 12In footing (Z dir. bott) = 12
TRIAL SIZE OF COLUMN & FOUNDATION ( Units m )
Lx Lz T Df lx lz Dw Dl L2.70 1.80 0.35 1.20 0.60 0.40 5.00 1.05 1.00
LOAD & BEARING PRESSURE CALCULATION ( Units kN & m )
Total load & moments on foundation transferred from superstructure :
Vertical load ( V ) = V1 + V2
Horizontal forces : Hx = Hx1 + Hx2 ; Hz = Hz1 + Hz2
Moment about X - axis ( Mx ) = Mx1 + Mx2
Eccentricity of direct load along X - axis ( e ) = L. [ 0.5 - { V1 / ( V1 + V2 )}]
Moment about Z - axis ( Mz ) = Mz1 + Mz2 + V.e
Calculated load & moments are tabulated below :
V Hx Hz Mx e Mz
7&33 104 37 5 22 0 2.743 101.5
Node no.
Load comb.
Concrete ( gc )Soil ( gs )
& soil ( m )
Node no.
Load comb.
Sheet 14Weight of pedestal ( Wp ) = 12.60 kN
Weight of footing ( Wf ) = 43 kN
Weight of soil overburden ( Ws )= 67 kN
Total vertical load on foundation :
Total moment @ X direction :
Total moment @ Z direction :
Maximum gross bearing pressure :
Minimum gross bearing pressure :
Modified bearing pressure in case of tension being developed below footing :
where, ' K ' is the bearing pressure co-efficient as given in section 6.9 of"FOUNDATION DESIGN" by W.C.Teng.
K = function of ( ex/Lz, ez/Lx ), &
Allowable gross bearing pressure :
= 171.6
Bearing pressure calculation is done in a tabular form as shown below :
P_max P_min ex/Lz ez/Lx P_mod Remarks
7&33 104 159.14 30.80 108.50 103.48 -37.99 0.11 0.25 3.72 121.65 O.K.
2.lx.lz.Dl.gc =
Lx.Lz.T.gc =
(Lx.Lz-2.lx.lz).(Df-T).gs =
SV = V+Wp+Wf+Ws-Fb
SMx = Mx
SMz = Mz
P_max = SV / (Lx.Lz) + 6.SMx / (Lx.Lz2) + 6.SMz / (Lz.Lx2)
P_min = SV / (Lx.Lz) - 6.SMx / (Lx.Lz2) - 6.SMz / (Lz.Lx2)
P_mod = K. SV / ( Lx. Lz )
ex = SMx / SV ez = SMz / SV
P_all = (P_net) + gs.x Df
Node no.
Load comb.
SV SMx SMz" K " after
"Teng"
Sheet 15CHECK FOR STABILITY
Overturning :
Sliding :
Allowable minimum factor of safety are as follows :
Against overturning = 1.5Against sliding = 1.5
Check against overturning :
Mrx Mrz
7&33 104 30.80 143.23 4.65 108.50 214.84 2.0 O.K.
Check against sliding :
Hm Hr
7&33 104 22.6 63.7 2.8 O.K.
Maximum overturning moment about Lx side = SMx
Maximum overturning moment about Lz side = SMz
Restoring moment about Lx side ( Mrx ) = SV. Lz / 2
Restoring moment about Lz side ( Mrz ) = SV. Lx / 2
Resultant sliding force ( Hm ) = Hx2 + Hz2 in respective load case.
Restoring force ( Hr ) = m. SV in respective load case.
Node no.
Load comb.
SMx F.O.S. = Mrx/SMx SMz F.O.S. =
Mrz/SMz
Node no.
Load comb.
F.O.S. = Hr/Hm
Sheet 16DESIGN OF FOOTING -
V1 + Wp = P1 V2 + Wp = P2
M1 L M2
w
Design pres.p = 121.65 X 1.2
Design = 146.0 (Factored)
Conservatively uniform pressure has been considered to get maximum moment and shear forceMoment at the Critical section (Centre): -34.49 KN-m/m Width of Footing.Shear at critical section d: 10.07 KN
Tensile Reinforcement:Effective depth d = 269.00 mm
= -0.01191 < 0.156= 272.52 mm
0.95*d = = 255.55 mmHence z = = 255.55 mm
= -308.81
Minimum Reinforcement 0.13% = = 455.00Reqd. Spacing of mm dia bar = 249 mmProvided Spacing = 200 mm 565
= 0.485 0.2102
0.037 Value for calc = 0.2102 O.K.
400/d = 1.487 Check for Punching Shear Value for calc = 1.487
0.415
d = average of effective depth in two directions = 263 mm
2000 mm
5156 mm
190.9668 KN (Factored)
0.141
5.060 O.K.
Analysis of footing slab in X - direction : Free-body diagram is shown below.
kN/m2
K= M/fcubd2 =z= d[0.5+Ö(0.25-k/0.9)] =
Ast = M/0.95fyz = mm2/m
mm2/m
Ast,provided mm2/m
Design Concrete shear stress uc = N/mm2 100As/bvd =
Ultimate shear stress v1 = N/mm2
U0 = 2(LX+LZ) =
U1 =U0 +12d =
Maximum ultimate Vertical load on column FY =
Ultimate shear stress for U1 = N/mm2
Maximum allowed 0.8Öfcu = N/mm2
UO
U1
1.5d
1.5d
Area, A 8.75 Zx 2.33
Depth of FDN, d 1.3 m Zz 4.08Support Reaction for FDN 2
Node L/C26 101 0.22 96.72 0.04 -37.36 0.01 0.34
102 -16.90 46.20 -18.44 -199.60 0.06 30.77103 -49.34 -20.88 -20.69 -217.95 -0.06 89.99104 7.48 107.58 -16.19 -181.24 0.18 -13.57105 -20.93 43.35 -31.46 -281.22 1.09 38.21106 -20.93 43.35 -5.43 -117.97 -0.97 38.21107 -26.75 26.29 -18.44 -199.60 0.06 48.62108 -15.11 60.41 -18.44 -199.60 0.06 27.81109 -20.93 43.35 -21.60 -227.21 0.18 38.21110 -20.93 43.35 -15.28 -171.99 -0.06 38.21111 -28.27 -15.75 -2.24 -30.71 -0.12 51.91112 28.55 112.71 2.26 6.00 0.12 -51.66113 0.14 48.48 -13.01 -93.98 1.03 0.13114 0.14 48.48 13.03 69.27 -1.03 0.12
27 101 -0.22 61.46 -0.04 -3.37 -0.09 0.69102 -5.75 125.10 -4.21 -45.64 -0.34 21.78103 -4.81 192.19 -1.96 -27.28 -0.40 17.94104 1.36 63.73 -6.46 -63.99 -0.27 -3.53105 -1.72 127.96 -15.36 -116.27 -0.42 7.20106 -1.72 127.96 6.94 25.00 -0.25 7.20107 -2.13 145.01 -4.21 -45.64 -0.34 8.98108 -1.31 110.90 -4.21 -45.64 -0.34 5.42109 -1.72 127.96 -7.28 -72.85 -0.34 7.20110 -1.72 127.96 -1.14 -18.42 -0.33 7.20111 -3.23 99.45 2.24 17.24 -0.10 11.16112 2.94 -29.01 -2.26 -19.47 0.04 -10.30113 -0.14 35.22 -11.16 -71.75 -0.12 0.43114 -0.14 35.22 11.14 69.52 0.06 0.43
m2 m3
m3
Force-X kN
Force-Y kN
Force-Z kN
Moment-X kNm
Moment-Y kNm
Moment-Z kNm
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
DESIGN OF COMBINED FOUNDATION MARKED F6( With ground water table at FGL. )
LOAD TABLE ( Units Mton & m )
Pedestal - I Pedestal - II
V1 Hx1 Hz1 Mx1 Mz1 V2 Hx2 Hz2 Mx2 Mz2
52&32 1203 25.1 -0.57 -6.4 -15.57 -1.042 24.6 0.34 -6.4 -15.66 0.357&37 1230 47.6 7.4 -0.08 0.4 18.87 47.1 7 -0.1 0.4 18.2157&37 1204 20.7 -7.1 -0.2 0.01 -18.6 20.4 -7.5 -0.2 0.01 -19.257&37 1171 47.9 0.23 5.5 14.6 0.4 47.1 -0.1 5.5 14.6 0.0857&37 1203 20.4 0.012 -5.8 -14.2 -0.17 20.4 -0.45 -5.8 -14.1 -0.94
###############
UNIT WEIGHTS ( Units Mton / cu.m. )
= 2.5= 1.6
SOIL PROPERTIES ( Units Mton / sq.m.)
P_net = 7.5 ( P_net is net bearing capacity at 3.5m depth. )Friction between conc.
= 0.55
MATERIAL GRADES ( Units MPa )
Concrete ( fck ) = 25Reinforcement ( fy ) = 415
CLEAR COVER ( Unit mm ):
In pedestal ( Cp ) = 50In footing ( Cf ) = 50
BAR DIAMETER ( Unit mm ):
In footing (X dir. top) = 12In footing (X dir. bott) = 16In footing (Z dir. top) = 12In footing (Z dir. bott) = 16
TRIAL SIZE OF COLUMN & FOUNDATION ( Units m )
Lx Lz T Df lx lz Dw Dl L7 3.5 0.5 4.7 0.6 0.4 4.7 0 2.6
Node no.
Load comb.
Concrete ( gc )Soil ( gs )
& soil ( m )
Change the digits in shaded area only.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
LOAD & BEARING PRESSURE CALCULATION ( Units Mton & m )
Total load & moments on foundation transferred from superstructure :
Vertcal load ( V ) = V1 + V2
Horizontal forces : Hx = Hx1 + Hx2 ; Hz = Hz1 + Hz2
Moment about X - axis ( Mx ) = Mx1 + Mx2
Eccentricity of direct load along X - axis ( e ) = L. [ 0.5 - { V1 / ( V1 + V2 )}]
Moment about Z - axis ( Mz ) = Mz1 + Mz2 + V.e
Calculated load & moments are tabulated below :
V Hx Hz Mx e Mz
52&32 1203 49.7 -0.23 -12.8 -31.23 0.013 -0.09257&37 1230 94.7 14.4 -0.18 0.8 0.007 37.7357&37 1204 41.1 -14.6 -0.4 0.02 0.009 -37.4157&37 1171 95 0.13 11 29.2 0.011 1.5257&37 1203 40.8 -0.438 -11.6 -28.3 0.000 -1.11
Weight of pedestal ( Wp ) = 0.00
Weight of footing ( Wf ) = 30.63
Weight of soil overburden ( Ws )= 161
Buoyant force ( Fb ) = Lx.Lz.(Df-Dw) = 0.00
Total vertical load on foundation :
Total moment in X direction :
Total moment in Z direction :
Maximum gross bearing pressure :
Node no.
Load comb.
2.lx.lz.Dl.gc =
Lx.Lz.T.gc =
(Lx.Lz-2.lx.lz).(Df-T).gs =
SV = V+Wp+Wf+Ws-Fb
SMx = Mx+Hz.(Dl+T)
SMz = Mz+Hx.(Dl+T)
P_max = SV / (Lx.Lz) + 6.SMx / (Lx.Lz2) + 6.SMz / (Lz.Lx2)
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Minimum gross bearing pressure :
Modified bearing pressure in case of tension being developed below footing :
where, ' K ' is the bearing pressure co-efficient as given in section 6.9 of"FOUNDATION DESIGN" by W.C.Teng.
K = function of ( ex/Lz, ez/Lx ), &
Allowable gross bearing pressure :
= 14.975
Bearing pressure calculation is done in a tabular form as shown below :
P_max P_min ex/Lz ez/Lx P_mod Remarks
52&32 1203 241.74 31.23 0.09 12.06 7.68 _ _ _ O.K.
57&37 1230 286.74 0.80 37.73 13.08 10.33 _ _ _ O.K.
57&37 1204 233.14 0.02 37.41 10.83 8.21 _ _ _ O.K.
57&37 1171 287.04 29.20 1.52 13.81 9.62 _ _ _ O.K.
57&37 1203 232.84 28.30 1.11 11.52 7.48 _ _ _ O.K.
###
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###
###
CHECK FOR STABILITY
Overturning :
P_min = SV / (Lx.Lz) - 6.SMx / (Lx.Lz2) - 6.SMz / (Lz.Lx2)
P_mod = K. SV / ( Lx. Lz )
ex = SMx / SV ez = SMz / SV
P_all = 1.25 (P_net) + gs. X 3.5
Node no.
Load comb.
SV SMx SMz" K " after
"Teng"
Maximum overturning moment about Lx side = SMx in respective load case.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Sliding :
Uplift :
Upward force = Fb
Downward force ( Fd ) = V + Wp + Wf + Ws
Allowable minimum factor of safety are as follows :
Against overturning = 1.5Against sliding = 1.5Against uplift = 1.2
Check against overturning :
Mrx Mrz
52&32 1203 31.23 423.04 13.55 0.09 846.1 9196.657&37 1230 0.80 501.79 627.24 37.73 1003.6 26.657&37 1204 0.02 407.99 20399.7 37.41 816.0 21.857&37 1171 29.20 502.32 17.20 1.52 1004.6 660.957&37 1203 28.30 407.47 14.40 1.11 814.9 734.2
Minimum F.O.S. against overturning about Lz = 13.5 O.K.
Minimum F.O.S. against overturning about Lx = 21.8 O.K.
Check against sliding and uplift :
Hm Hr Fb Fd
52&32 1203 12.8 133.0 10.4 0.0 217.1 N.A.57&37 1230 14.4 157.7 11.0 0.0 239.6 N.A.57&37 1204 14.6 128.2 8.8 0.0 212.7 N.A.
Maximum overturning moment about Lz side = SMz in respective load case.
Restoring moment about Lx side ( Mrx ) = SV. Lz / 2 in respective load case.
Restoring moment about Lz side ( Mrz ) = SV. Lx / 2 in respective load case.
Resultant sliding force ( Hm ) = Hx2 + Hz2 in respective load case.
Restoring force ( Hr ) = m. SV in respective load case.
Node no.
Load comb.
SMx F.O.S. = Mrx/SMx SMz F.O.S. =
Mrz/SMz
Node no.
Load comb.
F.O.S. = Hr/Hm
F.O.S. = Fd/Fb
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
57&37 1171 11.0 157.9 14.4 0.0 239.9 N.A.57&37 1203 11.6 128.1 11.0 0.0 212.4 N.A.
Mininmum F.O.S. against sliding = 8.78 O.K.
Mininmum F.O.S. against uplift = N.A. O.K.
V1 + Wp = P1 V2 + Wp = P2
M1 L M2
w
y2y1
x Point of Max. B.M.Lx
In the above diagram ( All units are Mton & m ),
P1 = V1 + Wp = 47.60 P2 = V2 + Wp = 47.10
M1 = Mz1 + Hx1.(Dl+T) = 18.9 M2 = Mz2 + Hx2. (Dl+T) = 18.21
Downward U.D.L. per unit length of footing w = ( Wf + Ws - Fb ) / Lx = 27.43
Ordinate of distributed reaction for full width below foundation :
287.04 1.52 41.19
40.82
DESIGN OF FOOTING - For Load Combination, which yields maximum pressure.
Analysis of footing slab in X - direction : Free-body diagram is shown below.
For SV = & SMz = y1 = SV / Lx + 6. SMz / Lx2 =
y2 = SV / Lx - 6. SMz / Lx2 =
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Bending moment will be maximum at a distance ' x ' where shear force is zero.
Shear force at a distance ' x ' is given by
= P1 + w.x - { y2 + (y1 - y2).(Lx - x)/Lx }.x - 0.5 x.{ y1 - y2 - (y1 - y2).(Lx - x)/Lx }
Shear force will be 0.01 at a distance x = 3.5 m
Ordinate of bearing pressure at the point of maximum bending moment
y = y2 + (y1 - y2). (Lx - x)/Lx
y = 41.0056 Mton / m
Bending moment in the footing slab about point located at " x "
BM1 =
BM1 = 3.105 Mton-m Tension at bottom of footing
Bending moment per unit width of footing = BM1 / Lz = 0.8871 Mton-m/m
Cantilever length ( lcx ) in m = ( Lx - L - lx ) / 2 = 1.9
24.83 Tension at bottomin the overhang part
Bending moment per unit width of footing = BM2 / Lz = 7.095 Mton-m/m
= 426
Shear force in Mton at a distance "d" from the face of pedestal towards the centreis obtained from equation - 1, putting x = 2.926
SF1 = 7.57
Shear force per unit width of footing = SF1 / Lz = 2.164 Mton/m
Shear force in Mton at a distance "d" from the face of pedestal towards cantilever sideis conservatively given by : SF2 = ( y1 - w ) x ( lcx - d )
SF2 = 20.28
Shear force per unit width of footing = SF2 / Lz = 5.79 Mton/m
= P1 + w.x - x.{ y2 + (y1 - y2).(1 - x/Lx) } - 0.5 x2.(y1-y2)/Lx
y. x2/2 + 0.5. ( y1 - y ). x2. 2/3 - P1. { x - ( Lx - L )/2 } - M1 - w. x2/2
Bending moment ( BM2 ) in Mton-m = ( y1 - w ). lcx2 / 2 =
Effective depth ( d ) of footing slab in mm = T.103 - Cf - 1.5 x Bar dia.
Analysis of footing slab along Z - axis : Footing slab is analysed as cantilever of unit width
1
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
subjected to an U.D.L., which is equal to the net bearing pressure.
Maximum gross bearing pressure Pg = 13.81
= 6.2922
Cantilever length ( lcz ) = ( Lz - lz ) / 2 = 1.550 m
7.56 Mton-m / m ( Tension at bottom )
Shear force at a distance "d" from the face of pedestal = Pn. ( lcz - d/1000 )
SF3 = 7.07 Mton / m
Analysis along Z - axis for tension at top:
Minimum gross bearing pressure ( Mton/sq.m. ) P_min = 7.48
Minimum net bearing pressure P'n ( Mton/sq.m. )
= -0.04
Since P'_net is ( - )ve, top reinforcement is required to be designed.
-0.04
Shear force in Mton / m. at the face of pedestal
= P'n. lcz
= -0.05
Computation of % age of steel as per SP:16, pertaining to the aforesaid B.M. & S.F.is tabulated below ( Minimum %age is considered as pt = 0.2 ) :
X Top 0 0.00 0.00 2.16 0.08 0.01 0.12X Bottom 7.09 0.59 0.17 5.79 0.20 0.07 0.20Z Top 0.04 0.00 0.00 0.05 0.00 0.00 0.12Z Bottom 7.56 0.62 0.18 7.07 0.25 0.11 0.20
Mton / m2
Maximum net bearing pressure Pn = Pg - gs.Dw - ( gs -1.0 ).( Df - Dw )
Mton / m2
Bending moment ( BM3 ) = Pn. lcz2 / 2 =
= P_min - gs.Dw - ( gs -1.0 ).( Df - Dw )
Bending moment in Mton-m / m = P'n. lcz2 / 2 =
Direc- tion
Tension at
B.M. (Mton-m/m)
Mu/bd2 (MPa)
pt (%) as per SP:16
S.F. (Mton/
m)
Vu/bd (MPa)
pt (%) as per SP:16
pt (%) reqd.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Reinforcement Summary :
Face
X Top 511.2 12 150 753.6X Bottom 852 16 150 1339.7Z Top 511.2 12 175 645.94Z Bottom 852 16 175 1148.3
Check for punching shear :
Three faces of the column shall be effective in resisting punching shear.
Periphery of punching shear ( Bo ) in m = 2. [( lx + d ) + ( lz + d )]
= 3.70
Punching load ( Pp ) in Mton = Vmax + Wp Vmax = Maximum direct load on column
= 47.90 = 47.9 Mton
= 0.46
Allowable punching shear stress in MPa = 0.25 fck
= 1.25 O.K.
Direc- tion
Ast (mm2 /m) = pt.b.d
100
Bar dia. (mm)
Spacing (mm)
Ast provided (mm2 /m)
Punching shear is critical at a distance of " d / 2 " from the face of column.
Punching shear stress ( tc ) in MPa = 1.5. Pp. 104 / ( Bo. d )
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
DESIGN OF COMBINED FOUNDATION MARKED F7( With ground water table at FGL. )
LOAD TABLE ( Units Mton & m )
Pedestal - I Pedestal - II
V1 Hx1 Hz1 Mx1 Mz1 V2 Hx2 Hz2 Mx2 Mz2
60&40 1230 33.8 5.4 0 0 11.5 33.9 5.1 0 0.01 11.260&40 1204 8 -5.2 0 -0.1 -11.3 8.1 -5.4 0 -0.1 -11.658&38 1203 16.9 -0.05 -1.7 -6.8 -0.2 16.8 -0.3 -1.8 -6.9 -0.5
#####################
UNIT WEIGHTS ( Units Mton / cu.m. )
= 2.5= 1.6
SOIL PROPERTIES ( Units Mton / sq.m.)
P_net = 7.5 ( P_net is net bearing capacity at 3.5m depth. )Friction between conc.
= 0.55
MATERIAL GRADES ( Units MPa )
Concrete ( fck ) = 25Reinforcement ( fy ) = 415
CLEAR COVER ( Unit mm ):
In pedestal ( Cp ) = 50In footing ( Cf ) = 50
BAR DIAMETER ( Unit mm ):
In footing (X dir. top) = 12In footing (X dir. bott) = 16In footing (Z dir. top) = 12In footing (Z dir. bott) = 16
TRIAL SIZE OF COLUMN & FOUNDATION ( Units m )
Lx Lz T Df lx lz Dw Dl L6 3 0.5 4.7 0.6 0.4 4.7 0 2.6
Node no.
Load comb.
Concrete ( gc )Soil ( gs )
& soil ( m )
Change the digits in shaded area only.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
LOAD & BEARING PRESSURE CALCULATION ( Units Mton & m )
Total load & moments on foundation transferred from superstructure :
Vertcal load ( V ) = V1 + V2
Horizontal forces : Hx = Hx1 + Hx2 ; Hz = Hz1 + Hz2
Moment about X - axis ( Mx ) = Mx1 + Mx2
Eccentricity of direct load along X - axis ( e ) = L. [ 0.5 - { V1 / ( V1 + V2 )}]
Moment about Z - axis ( Mz ) = Mz1 + Mz2 + V.e
Calculated load & moments are tabulated below :
V Hx Hz Mx e Mz
60&40 1230 67.7 10.5 0 0.01 0.002 22.8360&40 1204 16.1 -10.6 0 -0.2 0.008 -22.7758&38 1203 33.7 -0.35 -3.5 -13.7 0.004 -0.57
Weight of pedestal ( Wp ) = 0.00
Weight of footing ( Wf ) = 22.50
Weight of soil overburden ( Ws )= 118
Buoyant force ( Fb ) = Lx.Lz.(Df-Dw) = 0.00
Total vertical load on foundation :
Total moment in X direction :
Total moment in Z direction :
Maximum gross bearing pressure :
Node no.
Load comb.
2.lx.lz.Dl.gc =
Lx.Lz.T.gc =
(Lx.Lz-2.lx.lz).(Df-T).gs =
SV = V+Wp+Wf+Ws-Fb
SMx = Mx+Hz.(Dl+T)
SMz = Mz+Hx.(Dl+T)
P_max = SV / (Lx.Lz) + 6.SMx / (Lx.Lz2) + 6.SMz / (Lz.Lx2)
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Minimum gross bearing pressure :
Modified bearing pressure in case of tension being developed below footing :
where, ' K ' is the bearing pressure co-efficient as given in section 6.9 of"FOUNDATION DESIGN" by W.C.Teng.
K = function of ( ex/Lz, ez/Lx ), &
Allowable gross bearing pressure :
= 14.975
Bearing pressure calculation is done in a tabular form as shown below :
P_max P_min ex/Lz ez/Lx P_mod Remarks
60&40 1230 207.93 0.01 22.83 12.82 10.28 _ _ _ O.K.
60&40 1204 156.33 0.20 22.77 9.97 7.40 _ _ _ O.K.
58&38 1203 173.93 13.70 0.57 11.22 8.11 _ _ _ O.K.
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###
CHECK FOR STABILITY
Overturning :
P_min = SV / (Lx.Lz) - 6.SMx / (Lx.Lz2) - 6.SMz / (Lz.Lx2)
P_mod = K. SV / ( Lx. Lz )
ex = SMx / SV ez = SMz / SV
P_all = 1.25 (P_net) + gs. X 3.5
Node no.
Load comb.
SV SMx SMz" K " after
"Teng"
Maximum overturning moment about Lx side = SMx in respective load case.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Sliding :
Uplift :
Upward force = Fb
Downward force ( Fd ) = V + Wp + Wf + Ws
Allowable minimum factor of safety are as follows :
Against overturning = 1.5Against sliding = 1.5Against uplift = 1.2
Check against overturning :
Mrx Mrz
60&40 1230 0.01 311.90 31190 22.83 623.80 27.360&40 1204 0.20 234.50 1172.51 22.77 469.00 20.658&38 1203 13.70 260.90 19.04 0.57 521.80 915.4
Minimum F.O.S. against overturning about Lz = 19.0 O.K.
Minimum F.O.S. against overturning about Lx = 20.6 O.K.
Check against sliding and uplift :
Hm Hr Fb Fd
60&40 1230 10.5 114.4 10.9 0.0 174.0 N.A.60&40 1204 10.6 86.0 8.1 0.0 148.2 N.A.58&38 1203 3.5 95.7 27.2 0.0 157.1 N.A.
Maximum overturning moment about Lz side = SMz in respective load case.
Restoring moment about Lx side ( Mrx ) = SV. Lz / 2 in respective load case.
Restoring moment about Lz side ( Mrz ) = SV. Lx / 2 in respective load case.
Resultant sliding force ( Hm ) = Hx2 + Hz2 in respective load case.
Restoring force ( Hr ) = m. SV in respective load case.
Node no.
Load comb.
SMx F.O.S. = Mrx/SMx SMz F.O.S. =
Mrz/SMz
Node no.
Load comb.
F.O.S. = Hr/Hm
F.O.S. = Fd/Fb
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Mininmum F.O.S. against sliding = 8.11 O.K.
Mininmum F.O.S. against uplift = N.A. O.K.
V1 + Wp = P1 V2 + Wp = P2
M1 L M2
w
y2y1
x Point of Max. B.M.Lx
In the above diagram ( All units are Mton & m ),
P1 = V1 + Wp = 33.80 P2 = V2 + Wp = 33.90
M1 = Mz1 + Hx1.(Dl+T) = 11.5 M2 = Mz2 + Hx2. (Dl+T) = 11.2
Downward U.D.L. per unit length of footing w = ( Wf + Ws - Fb ) / Lx = 23.37
Ordinate of distributed reaction for full width below foundation :
207.93 22.83 38.46
30.85
DESIGN OF FOOTING - For Load Combination, which yields maximum pressure.
Analysis of footing slab in X - direction : Free-body diagram is shown below.
For SV = & SMz = y1 = SV / Lx + 6. SMz / Lx2 =
y2 = SV / Lx - 6. SMz / Lx2 =
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Bending moment will be maximum at a distance ' x ' where shear force is zero.
Shear force at a distance ' x ' is given by
= P1 + w.x - { y2 + (y1 - y2).(Lx - x)/Lx }.x - 0.5 x.{ y1 - y2 - (y1 - y2).(Lx - x)/Lx }
Shear force will be -0.02 at a distance x = 2.77 m
Ordinate of bearing pressure at the point of maximum bending moment
y = y2 + (y1 - y2). (Lx - x)/Lx
y = 34.9474 Mton / m
Bending moment in the footing slab about point located at " x "
BM1 =
BM1 = 5.7268 Mton-m Tension at bottom of footing
Bending moment per unit width of footing = BM1 / Lz = 1.9089 Mton-m/m
Cantilever length ( lcx ) in m = ( Lx - L - lx ) / 2 = 1.4
14.79 Tension at bottomin the overhang part
Bending moment per unit width of footing = BM2 / Lz = 4.9289 Mton-m/m
= 426
Shear force in Mton at a distance "d" from the face of pedestal towards the centreis obtained from equation - 1, putting x = 2.426
SF1 = 0.93
Shear force per unit width of footing = SF1 / Lz = 0.309 Mton/m
Shear force in Mton at a distance "d" from the face of pedestal towards cantilever sideis conservatively given by : SF2 = ( y1 - w ) x ( lcx - d )
SF2 = 14.70
Shear force per unit width of footing = SF2 / Lz = 4.90 Mton/m
= P1 + w.x - x.{ y2 + (y1 - y2).(1 - x/Lx) } - 0.5 x2.(y1-y2)/Lx
y. x2/2 + 0.5. ( y1 - y ). x2. 2/3 - P1. { x - ( Lx - L )/2 } - M1 - w. x2/2
Bending moment ( BM2 ) in Mton-m = ( y1 - w ). lcx2 / 2 =
Effective depth ( d ) of footing slab in mm = T.103 - Cf - 1.5 x Bar dia.
Analysis of footing slab along Z - axis : Footing slab is analysed as cantilever of unit width
1
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
subjected to an U.D.L., which is equal to the net bearing pressure.
Maximum gross bearing pressure Pg = 12.82
= 5.3014
Cantilever length ( lcz ) = ( Lz - lz ) / 2 = 1.300 m
4.48 Mton-m / m ( Tension at bottom )
Shear force at a distance "d" from the face of pedestal = Pn. ( lcz - d/1000 )
SF3 = 4.63 Mton / m
Analysis along Z - axis for tension at top:
Minimum gross bearing pressure ( Mton/sq.m. ) P_min = 7.40
Minimum net bearing pressure P'n ( Mton/sq.m. )
= -0.12
Since P'_net is ( - )ve, top reinforcement is required to be designed.
-0.10
Shear force in Mton / m. at the face of pedestal
= P'n. lcz
= -0.16
Computation of %age of steel as per SP:16, pertaining to the aforesaid B.M. & S.F.is tabulated below ( Minimum %age is considered as pt = 0.2 ) :
X Top 1.91 0.15 0.04 0.31 0.01 0.00 0.12X Bottom 4.93 0.41 0.12 4.90 0.17 0.05 0.20Z Top 0.10 0.01 0.00 0.16 0.01 0.00 0.12Z Bottom 4.48 0.37 0.10 4.63 0.16 0.04 0.20
Mton / m2
Maximum net bearing pressure Pn = Pg - gs.Dw - ( gs -1.0 ).( Df - Dw )
Mton / m2
Bending moment ( BM3 ) = Pn. lcz2 / 2 =
= P_min - gs.Dw - ( gs -1.0 ).( Df - Dw )
Bending moment in Mton-m / m = P'n. lcz2 / 2 =
Direc- tion
Tension at
B.M. (Mton-m/m)
Mu/bd2 (MPa)
pt (%) as per SP:16
S.F. (Mton/
m)
Vu/bd (MPa)
pt (%) as per SP:16
pt (%) reqd.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Reinforcement Summary :
Face
X Top 511.2 12 150 753.6X Bottom 852 16 150 1339.7Z Top 511.2 12 175 645.94Z Bottom 852 16 175 1148.3
Check for punching shear :
Three faces of the column shall be effective in resisting punching shear.
Periphery of punching shear ( Bo ) in m = 2. [( lx + d ) + ( lz + d )]
= 3.70
Punching load ( Pp ) in Mton = Vmax + Wp Vmax = Maximum direct load on column
= 33.90 = 33.9 Mton
= 0.32
Allowable punching shear stress in MPa = 0.25 fck
= 1.25 O.K.
Direc- tion
Ast (mm2 /m) = pt.b.d
100
Bar dia. (mm)
Spacing (mm)
Ast provided (mm2 /m)
Punching shear is critical at a distance of " d / 2 " from the face of column.
Punching shear stress ( tc ) in MPa = 1.5. Pp. 104 / ( Bo. d )
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
DESIGN OF COMBINED FOUNDATION MARKED F8( With ground water table at FGL. )
LOAD TABLE ( Units Mton & m )
Pedestal - I Pedestal - II
V1 Hx1 Hz1 Mx1 Mz1 V2 Hx2 Hz2 Mx2 Mz2
61&41 1230 32 3.6 -0.35 0.15 6.7 32 3.1 -0.33 0.15 6.261&41 1203 23.2 0.13 -4 -15.67 0.17 23.1 -0.3 -4 -15.8 -0.461&41 1204 21.6 -3.2 -0.4 0.95 -6.3 21.7 -3.6 -0.4 0.9 -6.8
#####################
UNIT WEIGHTS ( Units Mton / cu.m. )
= 2.5= 1.6
SOIL PROPERTIES ( Units Mton / sq.m.)
P_net = 7.5 ( P_net is net bearing capacity at 3.5m depth. )Friction between conc.
= 0.55
MATERIAL GRADES ( Units MPa )
Concrete ( fck ) = 25Reinforcement ( fy ) = 415
CLEAR COVER ( Unit mm ):
In pedestal ( Cp ) = 50In footing ( Cf ) = 50
BAR DIAMETER ( Unit mm ):
In footing (X dir. top) = 12In footing (X dir. bott) = 16In footing (Z dir. top) = 12In footing (Z dir. bott) = 16
TRIAL SIZE OF COLUMN & FOUNDATION ( Units m )
Lx Lz T Df lx lz Dw Dl L6 3 0.5 4.7 0.4 0.6 4.7 0 2.4
Node no.
Load comb.
Concrete ( gc )Soil ( gs )
& soil ( m )
Change the digits in shaded area only.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
LOAD & BEARING PRESSURE CALCULATION ( Units Mton & m )
Total load & moments on foundation transferred from superstructure :
Vertcal load ( V ) = V1 + V2
Horizontal forces : Hx = Hx1 + Hx2 ; Hz = Hz1 + Hz2
Moment about X - axis ( Mx ) = Mx1 + Mx2
Eccentricity of direct load along X - axis ( e ) = L. [ 0.5 - { V1 / ( V1 + V2 )}]
Moment about Z - axis ( Mz ) = Mz1 + Mz2 + V.e
Calculated load & moments are tabulated below :
V Hx Hz Mx e Mz
61&41 1230 64 6.7 -0.68 0.3 0.000 12.961&41 1203 46.3 -0.17 -8 -31.47 0.003 -0.1161&41 1204 43.3 -6.8 -0.8 1.85 0.003 -12.98
Weight of pedestal ( Wp ) = 0.00
Weight of footing ( Wf ) = 23.07
Weight of soil overburden ( Ws )= 120
Buoyant force ( Fb ) = Lx.Lz.(Df-Dw) = 0.00
Total vertical load on foundation :
Total moment in X direction :
Total moment in Z direction :
Maximum gross bearing pressure :
Node no.
Load comb.
2.lx.lz.Dl.gc =
Lx.Lz.T.gc =
(Lx.Lz-2.lx.lz).(Df-T).gs =
SV = V+Wp+Wf+Ws-Fb
SMx = Mx+Hz.(Dl+T)
SMz = Mz+Hx.(Dl+T)
P_max = SV / (Lx.Lz) + 6.SMx / (Lx.Lz2) + 6.SMz / (Lz.Lx2)
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Minimum gross bearing pressure :
Modified bearing pressure in case of tension being developed below footing :
where, ' K ' is the bearing pressure co-efficient as given in section 6.9 of"FOUNDATION DESIGN" by W.C.Teng.
K = function of ( ex/Lz, ez/Lx ), &
Allowable gross bearing pressure :
= 14.975
Bearing pressure calculation is done in a tabular form as shown below :
P_max P_min ex/Lz ez/Lx P_mod Remarks
61&41 1230 207.09 0.30 12.90 11.95 10.50 _ _ _ O.K.
61&41 1203 189.39 31.47 0.11 13.62 6.90 _ _ _ O.K.
61&41 1204 186.39 1.85 12.98 11.00 9.21 _ _ _ O.K.
###
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###
###
###
###
###
CHECK FOR STABILITY
Overturning :
P_min = SV / (Lx.Lz) - 6.SMx / (Lx.Lz2) - 6.SMz / (Lz.Lx2)
P_mod = K. SV / ( Lx. Lz )
ex = SMx / SV ez = SMz / SV
P_all = 1.25 (P_net) + gs. X 3.5
Node no.
Load comb.
SV SMx SMz" K " after
"Teng"
Maximum overturning moment about Lx side = SMx in respective load case.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Sliding :
Uplift :
Upward force = Fb
Downward force ( Fd ) = V + Wp + Wf + Ws
Allowable minimum factor of safety are as follows :
Against overturning = 1.5Against sliding = 1.5Against uplift = 1.2
Check against overturning :
Mrx Mrz
61&41 1230 0.30 315.81 1052.69 12.90 626.44 48.661&41 1203 31.47 288.81 9.18 0.11 572.89 5208.161&41 1204 1.85 284.24 153.64 12.98 563.82 43.4
Minimum F.O.S. against overturning about Lz = 9.2 O.K.
Minimum F.O.S. against overturning about Lx = 43.4 O.K.
Check against sliding and uplift :
Hm Hr Fb Fd
61&41 1230 6.7 113.9 16.9 0.0 175.1 N.A.61&41 1203 8.0 104.2 13.0 0.0 166.3 N.A.61&41 1204 6.8 102.5 15.0 0.0 164.7 N.A.
Maximum overturning moment about Lz side = SMz in respective load case.
Restoring moment about Lx side ( Mrx ) = SV. Lz / 2 in respective load case.
Restoring moment about Lz side ( Mrz ) = SV. Lx / 2 in respective load case.
Resultant sliding force ( Hm ) = Hx2 + Hz2 in respective load case.
Restoring force ( Hr ) = m. SV in respective load case.
Node no.
Load comb.
SMx F.O.S. = Mrx/SMx SMz F.O.S. =
Mrz/SMz
Node no.
Load comb.
F.O.S. = Hr/Hm
F.O.S. = Fd/Fb
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Mininmum F.O.S. against sliding = 13.02 O.K.
Mininmum F.O.S. against uplift = N.A. O.K.
V1 + Wp = P1 V2 + Wp = P2
M1 L M2
w
y2y1
x Point of Max. B.M.Lx
In the above diagram ( All units are Mton & m ),
P1 = V1 + Wp = 23.20 P2 = V2 + Wp = 23.10
M1 = Mz1 + Hx1.(Dl+T) = -15.67 M2 = Mz2 + Hx2. (Dl+T) = -15.67
Downward U.D.L. per unit length of footing w = ( Wf + Ws - Fb ) / Lx = 23.65
Ordinate of distributed reaction for full width below foundation :
189.39 0.11 31.32
31.29
DESIGN OF FOOTING - For Load Combination, which yields maximum pressure.
Analysis of footing slab in X - direction : Free-body diagram is shown below.
For SV = & SMz = y1 = SV / Lx + 6. SMz / Lx2 =
y2 = SV / Lx - 6. SMz / Lx2 =
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Bending moment will be maximum at a distance ' x ' where shear force is zero.
Shear force at a distance ' x ' is given by
= P1 + w.x - { y2 + (y1 - y2).(Lx - x)/Lx }.x - 0.5 x.{ y1 - y2 - (y1 - y2).(Lx - x)/Lx }
Shear force will be 0.00 at a distance x = 3.03 m
Ordinate of bearing pressure at the point of maximum bending moment
y = y2 + (y1 - y2). (Lx - x)/Lx
y = 31.3034 Mton / m
Bending moment in the footing slab about point located at " x "
BM1 =
BM1 = 22.899 Mton-m Tension at bottom of footing
Bending moment per unit width of footing = BM1 / Lz = 7.508 Mton-m/m
Cantilever length ( lcx ) in m = ( Lx - L - lx ) / 2 = 1.625
10.13 Tension at bottomin the overhang part
Bending moment per unit width of footing = BM2 / Lz = 3.3207 Mton-m/m
= 426
Shear force in Mton at a distance "d" from the face of pedestal towards the centreis obtained from equation - 1, putting x = 2.451
SF1 = 4.42
Shear force per unit width of footing = SF1 / Lz = 1.448 Mton/m
Shear force in Mton at a distance "d" from the face of pedestal towards cantilever sideis conservatively given by : SF2 = ( y1 - w ) x ( lcx - d )
SF2 = 9.20
Shear force per unit width of footing = SF2 / Lz = 3.02 Mton/m
= P1 + w.x - x.{ y2 + (y1 - y2).(1 - x/Lx) } - 0.5 x2.(y1-y2)/Lx
y. x2/2 + 0.5. ( y1 - y ). x2. 2/3 - P1. { x - ( Lx - L )/2 } - M1 - w. x2/2
Bending moment ( BM2 ) in Mton-m = ( y1 - w ). lcx2 / 2 =
Effective depth ( d ) of footing slab in mm = T.103 - Cf - 1.5 x Bar dia.
Analysis of footing slab along Z - axis : Footing slab is analysed as cantilever of unit width
1
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
subjected to an U.D.L., which is equal to the net bearing pressure.
Maximum gross bearing pressure Pg = 13.62
= 6.1513
Cantilever length ( lcz ) = ( Lz - lz ) / 2 = 1.225 m
4.62 Mton-m / m ( Tension at bottom )
Shear force at a distance "d" from the face of pedestal = Pn. ( lcz - d/1000 )
SF3 = 4.91 Mton / m
Analysis along Z - axis for tension at top:
Minimum gross bearing pressure ( Mton/sq.m. ) P_min = 6.90
Minimum net bearing pressure P'n ( Mton/sq.m. )
= -0.57
Since P'_net is ( - )ve, top reinforcement is required to be designed.
-0.43
Shear force in Mton / m. at the face of pedestal
= P'n. lcz
= -0.70
Computation of %age of steel as per SP:16, pertaining to the aforesaid B.M. & S.F.is tabulated below ( Minimum %age is considered as pt = 0.2 ) :
X Top 7.51 0.60 0.17 1.45 0.05 0.00 0.17X Bottom 3.32 0.27 0.08 3.02 0.11 0.02 0.20Z Top 0.43 0.03 0.01 0.70 0.02 0.00 0.12Z Bottom 4.62 0.38 0.11 4.91 0.17 0.05 0.20
Mton / m2
Maximum net bearing pressure Pn = Pg - gs.Dw - ( gs -1.0 ).( Df - Dw )
Mton / m2
Bending moment ( BM3 ) = Pn. lcz2 / 2 =
= P_min - gs.Dw - ( gs -1.0 ).( Df - Dw )
Bending moment in Mton-m / m = P'n. lcz2 / 2 =
Direc- tion
Tension at
B.M. (Mton-m/m)
Mu/bd2 (MPa)
pt (%) as per SP:16
S.F. (Mton/
m)
Vu/bd (MPa)
pt (%) as per SP:16
pt (%) reqd.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Reinforcement Summary :
Face
X Top 733.33 12 150 753.6X Bottom 852 16 150 1339.7Z Top 511.2 12 175 645.94Z Bottom 852 16 175 1148.3
Check for punching shear :
Three faces of the column shall be effective in resisting punching shear.
Periphery of punching shear ( Bo ) in m = 2. [( lx + d ) + ( lz + d )]
= 3.70
Punching load ( Pp ) in Mton = Vmax + Wp Vmax = Maximum direct load on column
= 32.00 = 32 Mton
= 0.30
Allowable punching shear stress in MPa = 0.25 fck
= 1.25 O.K.
Direc- tion
Ast (mm2 /m) = pt.b.d
100
Bar dia. (mm)
Spacing (mm)
Ast provided (mm2 /m)
Punching shear is critical at a distance of " d / 2 " from the face of column.
Punching shear stress ( tc ) in MPa = 1.5. Pp. 104 / ( Bo. d )
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
DESIGN OF COMBINED FOUNDATION MARKED F7( With ground water table at FGL. )
LOAD TABLE ( Units Mton & m )
Pedestal - I Pedestal - II
V1 Hx1 Hz1 Mx1 Mz1 V2 Hx2 Hz2 Mx2 Mz2
40&60 1230 35.3 6.1 0.1 0.2 12.7 35.4 5.8 0.1 0.15 1340&60 1204 6.5 -5.9 -0.1 -0.2 -13.1 6.6 -6.1 -0.1 -0.2 -12.933&58 1203 16.9 -0.05 -1.6 -6.4 -0.5 16.9 -0.3 -1.8 -6.5 -0.2
#####################
UNIT WEIGHTS ( Units Mton / cu.m. )
= 2.5= 1.6
SOIL PROPERTIES ( Units Mton / sq.m.)
Friction between conc.= 0.55
MATERIAL GRADES ( Units MPa )
Concrete ( fck ) = 25Reinforcement ( fy ) = 415
CLEAR COVER ( Unit mm ):
In pedestal ( Cp ) = 50In footing ( Cf ) = 50
BAR DIAMETER ( Unit mm ):
In footing (X dir. top) = 12In footing (X dir. bott) = 16In footing (Z dir. top) = 12In footing (Z dir. bott) = 16
TRIAL SIZE OF COLUMN & FOUNDATION ( Units m )
Lx Lz T Df lx lz Dw Dl L6 3 0.5 4.7 0.5 0.3 4.7 0 2.6
Node no.
Load comb.
Concrete ( gc )Soil ( gs )
& soil ( m )
Change the digits in shaded area only.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
LOAD & BEARING PRESSURE CALCULATION ( Units Mton & m )
Total load & moments on foundation transferred from superstructure :
Vertcal load ( V ) = V1 + V2
Horizontal forces : Hx = Hx1 + Hx2 ; Hz = Hz1 + Hz2
Moment about X - axis ( Mx ) = Mx1 + Mx2
Eccentricity of direct load along X - axis ( e ) = L. [ 0.5 - { V1 / ( V1 + V2 )}]
Moment about Z - axis ( Mz ) = Mz1 + Mz2 + V.e
Calculated load & moments are tabulated below :
V Hx Hz Mx e Mz
40&60 1230 70.7 11.9 0.2 0.35 0.002 25.8340&60 1204 13.1 -12 -0.2 -0.4 0.010 -25.8733&58 1203 33.8 -0.35 -3.4 -12.9 0.000 -0.7
Weight of pedestal ( Wp ) = 0.00
Weight of footing ( Wf ) = 22.50
Weight of soil overburden ( Ws )= 119
Buoyant force ( Fb ) = Lx.Lz.(Df-Dw) = 0.00
Total vertical load on foundation :
Total moment in X direction :
Total moment in Z direction :
Maximum gross bearing pressure :
Node no.
Load comb.
2.lx.lz.Dl.gc =
Lx.Lz.T.gc =
(Lx.Lz-2.lx.lz).(Df-T).gs =
SV = V+Wp+Wf+Ws-Fb
SMx = Mx+Hz.(Dl+T)
SMz = Mz+Hx.(Dl+T)
P_max = SV / (Lx.Lz) + 6.SMx / (Lx.Lz2) + 6.SMz / (Lz.Lx2)
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Minimum gross bearing pressure :
Modified bearing pressure in case of tension being developed below footing :
where, ' K ' is the bearing pressure co-efficient as given in section 6.9 of"FOUNDATION DESIGN" by W.C.Teng.
K = function of ( ex/Lz, ez/Lx ), &
Allowable gross bearing pressure :
= 14.975
Bearing pressure calculation is done in a tabular form as shown below :
P_max P_min ex/Lz ez/Lx P_mod Remarks
40&60 1230 212.14 0.35 25.83 13.26 10.31 _ _ _ O.K.
40&60 1204 154.54 0.40 25.87 10.07 7.10 _ _ _ O.K.
33&58 1203 175.24 12.90 0.70 11.21 8.26 _ _ _ O.K.
0 0 141.44 0.00 0.00 7.86 7.86 _ _ _ O.K.
0 0 141.44 0.00 0.00 7.86 7.86 _ _ _ O.K.
###
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###
CHECK FOR STABILITY
Overturning :
P_min = SV / (Lx.Lz) - 6.SMx / (Lx.Lz2) - 6.SMz / (Lz.Lx2)
P_mod = K. SV / ( Lx. Lz )
ex = SMx / SV ez = SMz / SV
P_all = P_net + gs. Dw + ( gs - 1.0 ). ( Df - Dw )
Node no.
Load comb.
SV SMx SMz" K " after
"Teng"
Maximum overturning moment about Lx side = SMx in respective load case.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Sliding :
Uplift :
Upward force = Fb
Downward force ( Fd ) = V + Wp + Wf + Ws
Allowable minimum factor of safety are as follows :
Against overturning = 1.5Against sliding = 1.5Against uplift = 1.2
Check against overturning :
Mrx Mrz
40&60 1230 0.35 318.22 909.19 25.83 636.4 24.640&60 1204 0.40 231.82 579.54 25.87 463.6 17.933&58 1203 12.90 262.87 20.38 0.70 525.7 751.0
Mininmum F.O.S. against overturning about Lz = 20.4 O.K.
Mininmum F.O.S. against overturning about Lx = 17.9 O.K.
Check against sliding and uplift :
Hm Hr Fb Fd
40&60 1230 11.9 116.7 9.8 0.0 176.7 N.A.40&60 1204 12.0 85.0 7.1 0.0 147.9 N.A.33&58 1203 3.4 96.4 28.2 0.0 158.3 N.A.
Maximum overturning moment about Lz side = SMz in respective load case.
Restoring moment about Lx side ( Mrx ) = SV. Lz / 2 in respective load case.
Restoring moment about Lz side ( Mrz ) = SV. Lx / 2 in respective load case.
Resultant sliding force ( Hm ) = Hx2 + Hz2 in respective load case.
Restoring force ( Hr ) = m. SV in respective load case.
Node no.
Load comb.
SMx F.O.S. = Mrx/SMx SMz F.O.S. =
Mrz/SMz
Node no.
Load comb.
F.O.S. = Hr/Hm
F.O.S. = Fd/Fb
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Mininmum F.O.S. against sliding = 7.08 O.K.
Mininmum F.O.S. against uplift = N.A. O.K.
V1 + Wp = P1 V2 + Wp = P2
M1 L M2
w
y2y1
x Point of Max. B.M.Lx
In the above diagram ( All units are Mton & m ),
P1 = V1 + Wp = P2 = V2 + Wp =
M1 = Mz1 + Hx1.(Dl+T) = M2 = Mz2 + Hx2. (Dl+T) =
Downward U.D.L. per unit length of footing w = ( Wf + Ws - Fb ) / Lx = 23.57
Ordinate of distributed reaction below foundation :
212.14 25.83 39.66
31.05
DESIGN OF FOOTING - For Load Combination, which yields maximum pressure.
Analysis of footing slab in X - direction : Free-body diagram is shown below.
For SV = & SMz = y1 = SV / Lx + 6. SMz / Lx2 =
y2 = SV / Lx - 6. SMz / Lx2 =
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Bending moment will be maximum at a distance ' x ' where shear force is zero.
Shear force at a distance ' x ' is given by
= P1 + w.x - { y2 + (y1 - y2).(Lx - x)/Lx }.x - 0.5 x.{ y1 - y2 - (y1 - y2).(Lx - x)/Lx }
Shear force will be -37.50 at a distance x = 3 m
Ordinate of bearing pressure at the point of maximum bending moment
y = y2 + (y1 - y2). (Lx - x)/Lx
y = 35.3573
Bending moment in the footing slab about point located at " x "
BM1 =
BM1 = 65.94 Mton-m Tension at bottom of footing
Bending moment per unit width of footing = BM1 / Lz = 21.98 Mton-m/m
Cantilever length ( lcx ) in m = ( Lx - L - lx ) / 2 = 1.45
16.91 Tension at bottomin the overhang part
Bending moment per unit width of footing = BM2 / Lz = 5.6376 Mton-m/m
= 426
Shear force in Mton at a distance "d" from the face of pedestal towards the centreis obtained from equation - 1, putting x = 2.376
SF1 = -34.18
Shear force per unit width of footing = SF1 / Lz = -11.39 Mton/m
Shear force in Mton at a distance "d" from the face of pedestal towards cantilever sideis conservatively given by : SF2 = ( y1 - w ) x ( lcx - d )
SF2 = 16.47
Shear force per unit width of footing = SF2 / Lz = 5.49 Mton/m
= P1 + w.x - x.{ y2 + (y1 - y2).(1 - x/Lx) } - 0.5 x2.(y1-y2)/Lx
Mton / m2
y. x2/2 + 0.5. ( y1 - y ). x2. 2/3 - P1. { x - ( Lx - L )/2 } - M1 - w. x2/2
Bending moment ( BM2 ) in Mton-m = ( y1 - w ). lcx2 / 2 =
Effective depth ( d ) of footing slab in mm = T.103 - Cf - 1.5 x Bar dia.
Analysis of footing slab along Z - axis : Footing slab is analysed as cantilever of unit width
1
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
subjected to an U.D.L., which is equal to the net bearing pressure.
Maximum gross bearing pressure Pg = 13.26
= 5.7397
Cantilever length ( lcz ) = ( Lz - lz ) / 2 = 1.350 m
5.23 Mton-m / m ( Tension at bottom )
Shear force at a distance "d" from the face of pedestal = Pn. ( lcz - d/1000 )
SF3 = 5.30 Mton / m
Analysis along Z - axis for tension at top :
Minimum gross bearing pressure ( Mton/sq.m. ) P_min = 7.10
Minimum net bearing pressure P'n ( Mton/sq.m. )
= -0.42
Since P'_net is ( - )ve, top reinforcement is required to be designed.
-0.38
Shear force in Mton / m. at the face of pedestal
= P'n. lcz
= -0.56
Computation of %age of steel as per SP:16, pertaining to the aforesaid B.M. & S.F.is tabulated below ( Minimum %age is considered as pt = 0.2 ) :
X Top 21.98 1.77 0.54 -11.39 -0.40 0.18 0.54X Bottom 5.64 0.47 0.13 5.49 0.19 0.06 0.20Z Top 0.38 0.03 0.01 0.56 0.02 0.00 0.20Z Bottom 5.23 0.43 0.12 5.30 0.19 0.06 0.20
Mton / m2
Maximum net bearing pressure Pn = Pg - gs.Dw - ( gs -1.0 ).( Df - Dw )
Mton / m2
Bending moment ( BM3 ) = Pn. lcz2 / 2 =
= P_min - gs.Dw - ( gs -1.0 ).( Df - Dw )
Bending moment in Mton-m / m = P'n. lcz2 / 2 =
Direc- tion
Tension at
B.M. (Mton-m/m)
Mu/bd2 (MPa)
pt (%) as per SP:16
S.F. (Mton/
m)
Vu/bd (MPa)
pt (%) as per SP:16
pt (%) reqd.
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Reinforcement Summary :
Face
X Top 2289.8 16 200 1004.8X Bottom 852 16 200 1004.8Z Top 852 12 125 904.32Z Bottom 852 16 200 1004.8
Check for punching shear :
Three faces of the column shall be effective in resisting punching shear.
Periphery of punching shear ( Bo ) in m = 2. ( lx + d ) + ( lz + d )
= 2.58
Punching load ( Pp ) in Mton = Vmax + Wp Vmax = Maximum direct load on column
= 35.40 = 35.4 Mton
= 0.48
Allowable punching shear stress in MPa = 0.25 fck
= 1.25 O.K.
Direc- tion
Ast (mm2 /m) = pt.b.d
100
Bar dia. (mm)
Spacing (mm)
Ast provided (mm2 /m)
Punching shear is critical at a distance of " d / 2 " from the face of column.
Punching shear stress ( tc ) in MPa = 1.5. Pp. 104 / ( Bo. d )
Sheet2
Page 55
Node no. P_max P_mod V1 V2 M1 M2 y1
52&32 1203 12.06 _ 25.1 24.6 -1.33 0.47 34.55
4&1 1230 13.08 _ 47.6 47.1 22.57 21.71 45.58
14&11 1204 10.83 _ 20.7 20.4 -22.15 -22.95 37.89
14&11 1171 13.81 _ 47.9 47.1 0.52 0.03 41.19
14&11 1203 11.52 _ 20.4 20.4 -0.16 -1.17 33.40
24&21 0 0.00 0.00 0 0 0.00 0.00 0.00
24&21 0 0.00 0.00 0 0 0.00 0.00 0.00
24&21 0 0.00 0.00 0 0 0.00 0.00 0.00
34&31 0 0.00 0.00 0 0 0.00 0.00 0.00
34&31 0 0.00 0.00 0 0 0.00 0.00 0.00
Load comb.
Sheet2
Page 56
y2
34.52
36.34
28.72
40.82
33.13
0.00
0.00
0.00
0.00
0.00
lx lx
X(+) lz Hx1 lz Hx2 Lz
Mx1 Mx2Mz1 Mz2
Z(+) Hz1 Hz2
L
Lx
PLAN
V1 V2
LOAD POINT Mz1 Mz2
Hx1 Hz2
F.G.L.
DwDl G.W.T.
Df
T
LEVELLING CONCRETE
ELEVATION
Client : NTPC Limited. Calc No. 9558-360-POC-U-848Project : Barh (3x660 MW) STPP Rev. 0 .Project No. : T413000 Page
Design of Isolated Foundation :
Nomenclature used for design of Isolated Foundation
Axis directions:X Direction : Along length of the buildingZ Direction : Along width of the buildingY Direction : Vertical direction
Hz
t
Ix
Hx
Mx
Mz
IzLz
Lx
Mz
Hx
DI
Df
T
PLAN
ELEVATION
FGL
Column
EL = -0.500m
Dw
NGL
Ds V
A Vertical Horizontal Horizontal Moment GNode L/C Fy kN Fx kN Fz kN Mx kNm Mz kNm
3101 1 F -1181.562 87.153 118.095 533.903 -462.2393101 2 S 803.868 125.818 -0.001 -0.004 -473.9143102 1 F 551.073 138.209 53.439 220.847 -470.263102 2 S -1010.165 99.394 0 0 -469.763
Sheet4
Page 60
2 11.2 22.412 12 144
6 9.36 56.162 11.2 22.41 24 246 25.08 150.483 17.92 53.761 19.6 19.6
492.8 0.858537574 1.164773