Code u2 Manual Calculation(22!08!09)

8/13/2019 Code u2 Manual Calculation(22!08!09)

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Vessel Design General Data

Design Code: ASME Sec VIII Div 2 , Edition 2007 + 08 Addenda

All calculations are done in S Costu!ar" unit o# !easure!ent

Internal Design Pressure, Pi =200 psi

Internal Design Temperature, Ti = Fo150

External Design Pressure, Pe =NA

External Design Temperature, Ti =NA

Shell Type !ylin"ri#al

$ea" Type Semi Ellips%i"al

Inner Diameter %& 'essel, Din = ()*Internal !%rr%si%n All%+an#e, !A = 0125*

!%rr%"e" Insi"e Diameter, Di# = ()25* mm-aterial %& !%nstru#ti%n Shell, -.! SA 51/ r0 N%rmalie"

-aterial %& !%nstru#ti%n $ea", -.! SA 51/ r0 N%rmalie"

N%+, as per ta3le 5 A %& AS-E Se# II part D, 200 E" 4 0) A"

P N% 1

r%up N% 2

-in Tensile Strength 0 x 10psi

-in 6iel" Strength ) x 10psi

External Pressure !hart N% !S2

-ax All%+a3le Stress at Co150 2) 10psi

N%+, as per ta3le T- %& AS-E Se# II part D, 200 E" 4 0) A"

Et 270 x 10/psi

8%int E&&e#ien#y as per #%lumn 13 %& ta3le 2,

E = 1

E1


2/35

sed Material $ro%erties

&' S(E)) * DIS( EDS

-.! 9 SA 51/ r 0 N%rmalie"

Temperature %& #%nsi"erati%n 9 150 Fo

-%"ulus %& Elasti#ity, E 9 270 x 10/PSI :as per ta3le T- %& AS-E

Se# II Part D, 200 E" 4 0) A";

6iel" Strength at gi


3/35

2' --)E EC.S * /)AGES

-.! 9 SA 105 N%rmalie"


-%"ulus %& Elasti#ity, E 9 270 x 10/PSI :as per ta3le T- %& AS-E

Se# II Part D, 200 E" 4 0) A";



4/35

' /AS1EES

-.! 9 SA 17 @

-aximum N%minal Sie 9 1 1)*$en#e the N%minal sie C 2 *


-%"ulus %& Elasti#ity, E 9 2)5 x 10PSI :as per ta3le T- %& AS-E

Se# II Part D, 200 E" 4 0) A";



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&' C3)IDICA) S(E))

INTENA> PESSE !A>!>ATI.N

>ength %& !ylin"ri#al Shell, >s = // &teFuire" Thi#Gness "ue t% Internal Pressur,

ti = CAeDic ES

Pi

+

12

:(1;

= 125012

25() 12)00200

+

e *

= 020/*40125*

= 02)/*N%+ the gi


6/35

$en#e $eat Treatment is n%t reFuire" as per Se# /12

S4ell 1olerance is as %er 5''2'&

Co!6ined loading code as %er 5''&0'2

!ir#um&erential stress in a #ylin"ri#al shell, , is gi


7/35

= 201 x57A2

700

15

= 0)())Hin" pressure , F

= 00025/ x G x Gt x G" x I x '2

= 00025/ x 0)()) x 1 x 1 x 075 x 1 x 752

= 1)/ ps&

T%tal +in" &%r#e %n x D

= 1)/ x /0/ x (5 = 5/5 l3

N%+ 3en"ing m%ment &%r


8/35

= ( )[ ] ++ 2)7/1()1777)7/1()177750

= 1777) psi

2 = ( )[ ]

++ 22 (50 smmsmm :((2;

= ( )[ ]

+ 2)7/1()1777)7/1()177750

= 7/1() psi

= ( )p50 :((;

= 05 x 200 psi

= 100 psi

N%+,

( ) 5,0222 ;1:;2:;21:2

1 ++

= ( ) 50222 ;1777)100:;1007/1():;7/1()1777):

2

1 +++

= 1/)/1/ psi

At any p%int %n the shell the a3%


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N%minal @lanG Thi#Gness, tn%m = 0()*

Insi"e Diameter, Di = ()*

Insi"e Diameter #%rr%"e", Di# = ()25*STEP1

Insi"e height, h= D 2 x as per rati% 4 !A

= 1250(

() +

= 12125

N%+ G =h

Dic

2

=125122

25()

= 17)7

$ere, 1 17)7 22, (2

EFuati%n is satis&ie", s% the "ish #an 3e "esigne" as per se#ti%n (

N%+ Gnu#Gle ra"ius r = Di# x

0)050k

= ()25 x

0)07)71

50

= )2/5* (2(

!r%+n ra"ius > = Di# x :0(( G 4 002;

= ()25 x :0(( x 17)7 4 002;

= (20/ (25

STEP2

ati%Dic

L= )7550

25()

20/( =

N%+ 0 > D 10 (2

ati%Dic

r= 110

25()

2/5) =

D

rO 00/ (/

E7


10/35

ati% )25212;125050:

20/(=

=

t

L

20 tL 2000 (

N%+ all the eFuati%ns as per (5, / ? are satis&ie", hen#e the "esign #an 3e pr%#e"e"

STEP

N%+ Parameter

th = ar#%s K:05xDi# r; :>r;L

= ar#%s K:05 x ()25 )2/5; :(20/) )2/5;L

= #%s1:0(55);

= 1077/ ra"

th =r

tL

=2/5)

25020/(

= 07/5 ra"

N%+, th C th

Br%m eFuati%n (10

th =( )thth

rDic

#%s

5,04r

=( )7/50077/1#%s

2/5)25()50

4)2/5

= 270551

Step(

$ere rDi# Q 00), s% &r%m eFuati%n (1

!1 = 0/72 x :rDi#; 4 0/05= 0/72 x 011 x 0/05

= 025

Br%m eFuati%n (15

!2 = 1(/ 2/ x :rDi#;

= 1(/ 2/ x 011

E10


11/35

= 101(/2

Step 5

Internal Pressure expe#te" t% pr%"u#e Elasti# @u#Gling %& Jnu#Gle

Peth = ( )rRRC

tEC

tht

T

h

2A2

1 2

(1/

=( )2/5)2A05512705512701(/21

2502700000250 2

= 112/7 psi (1/

Step /

Internal Pressure that +ill result in a maximum stress in the Jnu#Gle

Py = ( )1;2A:2

rRRC

tC

thth

(1

The All%+a3le stress at the "esign temperature is g%


12/35

PaG = P#G15

= 52/1 psi (21

Step 7All%+a3le Pressure 3ase" %n the rupture %& the !r%+n

Pa# = 2x S x E K:>t;405L

= 2 x 2)00 : 12)252405;

= 2(/2) psi (22

Step 10

-aximum All%+a3le Internal Pressure, Pa = -in :PaG, Pa#;

Pa =2(/2) psi (2Step 11

(ere t4e Mai!u! Alloa6le Internal $ressure is greater t4an t4e design %ressure, so t4e %rovided

t4ic9ness is satis#actor" and t4e design is sa#e

@lanG Diameter &%r "ishe" hea", D3 = 5)*

.utsi"e "iameter %& "ishe" hea", D% = ()5*

N%minal Thi#Gness %& Dishe" $ea", t = 0(2*

Per#entage %& el%ngati%n as per Ta3le /1 = 100 x lnKD3: D% 2 x t;L

= 100 x ln K:5) :)5 2 x 05;

= 2(5

14e reduction 6" cold #or!ing #ro! t4e as rolled t4ic9ness s4ould 6e less t4an &0 at an" location

4ere t4e etre!e #i6re elongation eceeds ;'

14e te!%erature o# t4e !aterial during #or!ing s4ould 6e less t4an &20 oC

I!%act testing is not re


13/35

=

D

DoE

p

ln2 (5

-eri"%nial stress in a spheri#al shell, sm , is gi


14/35

= 00025/ x 0)()) x 1 x 1 x 075 x 1 x 752

= 1)/ ps&

T%tal +in" &%r#e %n x D

= 1)/ x /0/ x (5

= 5/5 l3

N%+ 3en"ing m%ment &%r


15/35

1 = ( )[ ]

+++ 22 (50

smmsmm :((1;

= ( )[ ]

+++

22

/20()7/1(5)10)7/1(5)1050

= 7/1() psi

2 = ( )[ ]

++ 22 (50

smmsmm :((2;

= ( )[ ] ++ 22 /20()7/1(5)10)7/1(5)1050

= 5)10

= ( )p50 :((;

= 05 x 200 psi

= 100 psi

N%+,

( ) 5,0222 ;1:;2:;21:2

1 ++

= ( ) 50222 ;7/1()100:;1005)10:;5)107/1():

2

1 +++

= )()7 psi

At any p%int %n the shell the a3%


16/35

' o@@le Mana"

adial o@@le Attac4ed to S4ell

Design Pressure &%r N%le is taGen as the -AHP %& the


17/35

A#tual n%le thi#Gness #%rresp%n"ing t% the sie = 05*

N%le Ne#G -aterial SA 105 N%rmalie"

N%le Blange -aterial SA 105 N%rmalie"All%+a3le stress at "esign temperature, Sn = 22/00 psi

Billet Hel" >eg Sie at the n%le an" Shell 8%int A(1 = 05(*

The rein&%r#ement is pr%pr = 1/*

N%minal Thi#Gness %& the n%le +all at the shell = $u3 ThG !Atn = 1( 0125

= 125*

N%minal Thi#Gness %& the n%le +all at the &lange = 05*

N%le Pr%Ve#ti%n Br%m the .utsi"e %& the


18/35

N%+, > = min K ;2501252(: , 2x 7/25L

= min K2(557, 1725L

= 2(557*

Step 2

>$1 = t 4 te 4 ;: tnRn (5)

= 025 4 0 4 ;251/257:

= 51*

>$2 = >pr14 t &%r n%le inserte& thr%ugh the +all (57

= / 4 025

= /25*>$ = ) x :t 4 te; (511

= ) x :025 4 0;

= 2*

N%+, >imit %& ein&%r#ement al%ng the N%le +all pr%Ve#ting %utsi"e the $is gi$ = -in K >$1, >$2, >$L (512

= 2*

Step is n%t Appli#a3le sin#e the n%le has n% insi"e pr%Ve#ti%n

E&&e#ti


19/35

Area !%ntri3ute" 3y 'essel Hall

A1 = :t x >; x max

1,

5

)50

(51)

= 025 x 2(557 x max

1,5

)7((5 )50

= 025 x 2(557 x 11501

= 00/15 in#h2

Area #%ntri3ute" 3y n%le %utsi"e the pr 4 t = 1/* 4 025*

= 1)5*$ere >$Q >pr 4 t

A2 = tn x :>pr 4 t;40) 22

2

tnRntn

tn

(520

=125 x :1/4025;40) 50/27251

50 2t

= 25521 in#h2

Area #%ntri3ute" 3y %utsi"e &illet +el"

A(1 = 05 x >(12 (52

=05 x :05(;2

=00/2 in#h2

Area 3y pa" &illet +el", A(2=0

Area 3y B pa", A5=0

N%+ t%tal a


20/35

STEP

Appli#a3le &%r#es

B%r#e &r%m internal pressure in the n%le %utsi"e %& the $ 1; (5(

xn =

+

Rn

tnRnn

tn

(5

=

+

/257

251/257

251

n

= 102(7*f N = 200 x 102(7 :2 025;

= 5)255 l3

B%r#e &r%m internal pressure in the shell

f s = P ns: >4 tn; (55

xs =

+ff

teffffn

teff

Ee

Ee

(5)

=

+

1252(

2501252(250

n

=2(2(7)*

f s = 200 x2 (2(7) x :2(5574125;

= 1)07(15) l3

f y = P x xs x n# (5/

B%r ra"ial n%le n# = n

f y = 200 x 2(2(7) x 7/25=(//)0)/5 l3

STEP)

A


21/35

= 2

172,

)/5,(//)015),1)07(5),255

inch

!++

= 21(1(715) psieneral primary mem3rane stress

Y#ir= teffPRxs

(5(0

=250

2(7)2(200

=1777)( psi

STEP7

-aximum l%#al primary mem3rane stress at the n%le interse#ti%n

P>= max K :2Ya= max K2 x 21(1(715) 1777)(, 1777)(L

=2(27772 psi

STEP10

All%+a3le sress Sall%+ = 15 x S x > (5(

= 15 x 22/00 psi

= 700 psi

N%+ P> Sall%+ (5(2

The #al#ulate" maximum l%#al primary mem3rane stress satis&ies eFn (5(0 s% the gi


22/35

=250

2(7)2(

172

1(2522

700

=27)( psi

P max2 = S x :t xs; (5(/

= 2,)00 x :025 2(2(7);

= 2(5/2) psi

-aximum All%+a3le H%rGing Pressure %& N%le,

Pmax = -in K Pmax1, Pmax2 L (5(

= -in K27)(, 2(5/2) L

= 2(5/2) psi

Streangt4 o# o@@le Attac4!ent Belds as %er 5';'&5

Step 1

$ere the N%le is inserte" thr%ugh the (1T = 0001 x >(1 (51)

= 0001 x 05(

= 025/0*

>(2T = 0

Step (

Hel" >%a" 'alue, & +el" = -in ]&y x Gy, 15 x Sn x :A2 4 A; (51(

E22


23/35

= -in K(//)0)/5 x 1125, 15 x 22/00 x :25521 4 0L

= -in K 52)//07/, )/51/17 L

&+el" = 52)//07/ l3 (51(N%le t% Shell Hel" r%%Z x :0(7 x >(1T ;4 0/1 x t+14 0(7 x >(T L (51(1= 52)//07/ K1121/ x :0(7 x 0250 4 0/ x 05 4 0;

Z = )))1//2/ psi

N%+, Z C= S (51(2(ere t4e a6ove condition >e


24/35

o as %er '&&'2';

ts = tr x E^ : tn !A;

= 01051 x 1 : 05 0125;= 02)0

-inimum 6iel" Streangth &%r SA 105 is / Gsi

S%, -inimum 6iel" Streangth C= 50 Gsi

N%+ &r%m Ta3le 1/ e"u#ti%n in the -D-T is 51// Fo

N%+ the re"u#e" -D-T = 5(2/ Fo

I!%act 1est is ece!%ted

5' o@@le Vent

(illside o@@le Attac4ed to Dis4ed (ead

Design Pressure &%r N%le is taGen as the -AHP %& the


25/35

Billet Hel" >eg Sie at the n%le an" Shell 8%int A(1 = 05(*

$ere there is n% a""iti%nal rein&%r#ement is pr%


26/35

(ill side o@@le in /or!ed Elli%soidal (ead nder $ressure )oading

Step 1

$ere +e haimit %& ein&%r#ement al%ng the = min K ;25025()(: , 2x 0)5L

= min K2))(, 15L

= 15*

Step

>imit %& ein&%r#ement al%ng the N%le +all pr%Ve#ting %utsi"e the $is gi


27/35

Bp = 0)20

B%r n%le inserte" thr%ugh the $1 =-in K t 4 te 4 Bp x ;: tnRn , >pr1 4 tL (5

= -in K025 4 0 4 0)20 x ((0)50: , /402L

= 05))**

Step ( is n%t Appli#a3le sin#e the n%le has n% insi"e pr%Ve#ti%n

Step 5

Area !%ntri3ute" 3y the 'essel Hall

A1 = :t x >; (5)(

= 025 x 15= 0( in#h2

Area #%ntri3ute" 3y n%le %utsi"e the (12 (5))

=05 x :05(;2

=00/2 in#h2

Area 3y pa" &illet +el", A(2=0

Area 3y B pa", A5=0

N%+ t%tal a


28/35

&N =P xn :>$ 1; (575

xn =

+Rn

tnRnn

tn

(57)

=

+

)550

((0)50

((0

n

= 10)01*

f N = 200 x 10)01 x :05)) 025;

= 107711 l3

B%r#e &r%m internal pressure in the shellf s = P xs: >4 tn;2 (57/

xs =

+ff

teffffn

teff

Ee

Ee

(577

=

+

25()(

25025()(

250

n

= (7*

f s = 200x(7x :1540((;2

= 750015( l3

f y = P x xs x n# 2 (57

B%r the hillsi"e n%le n# = 0))//5*

f y = 200 x (7 x 0))//52= )(/2/11 l3

STEP)

A


29/35

eneral primary mem3rane stress

Y#ir#=teff

PRxs

2(5102

=2502

7(200

=151)) psi

STEP7

-aximum l%#al primary mem3erse stress at the n%le interse#ti%n

P>= max K :2Ya= max K2 x 1/(((/2 151)), 151))L =151)) psi

STEP10

All%+a3le sress Sall%+ = 15 x S x > (5(1

= 15 x 22/00 psi

= 700 psi

N%+ P> Sall%+ (510(

The #al#ulati%n maximum l%#al primary mem3rane stress satis&ie" eFn (510( s% the gi


30/35

P max2 =2 x S x :t xs; (510/

= 2 x 2,)00 x :025 (7;

= 2(22 psi-aximum All%+a3le H%rGing Pressure %& N%le,

Pmax = -in K Pmax1, Pmax2 L (510

= 2(22 psi

Streangt4 o# o@@le Attac4!ent Belds as %er 5';'&5'2

Step 1

$ere the N%le is inserte" thr%ugh the ength resisting "is#%ntinuity &%r#e

B%r N%le t% Shell Hel" %& n%n ra"ial n%le

>Z = [2 x _K]:n# 4 tn ;24:n4tn;2`2L (515

= [2 x_K ]:0))//540((;24:0)540((;2`2L

= 20()*

Step

Hel" Thr%at Dimensi%n

>(1T = 0001 x >(1 (51)

= 0001 x 05(

= 025/0*

>(2T = 0Step (

Hel" >%a" 'alue, & +el" = -in ]&y x Gy, 15 x Sn x :A2 4 A; (51(

= -in K)(/7/)2 x 1(7/25, 15 x 22/00 x :07 4 0L

= -in K 55(7/)2, 111721 L

&+el" = 55(7/)2 l3 (51(

E0


31/35

N%le t% Shell Hel" r%%Z x :0(7 x >(1T ;4 0/1 x t+14 0(7 x >(T L (51(1= 55(7/)2 K20() x :0(7 x 0250 4 0/ x 05 4 0;

Z = 7)/2) psi

N%+, Z C= S (51(2(ere t4e a6ove condition >eIC(?

MAB$

>$SI?

S4ell 0'28= 0'7; 25;'=

Dis4ed (eads 0'0= 0'7; 275'=28

Mana" 0'20& 0'; 25;'=

Vent 0'=2 0';=; 275'22

("drostatic 1est $ressure esults:

Test Pressure at high p%int in


32/35

= 1( x 2(5/

= 50)/0 psi

Test Pressure at high p%int in egs Nleg (

!r%ss Se#ti%nal Area &%r >050 Aleg 2110 sFin

Se#ti%n Inertia : str%ng axis ; 1/0 in^^(Se#ti%n Inertia : +eaG axis ; 1/0 in^^(

Se#ti%n -%"ulus : str%ng axis ; 0) in

Se#ti%n -%"ulus : +eaG axis ; 0) in

a"ius %& yrati%n : str%ng axis ; 071 in

a"ius %& yrati%n : +eaG axis ; 071 in

E2


33/35

>eg .rientati%n Diag%nal

.egs )751 &tl3

T%tal Height >%a" at t%p %& >egs H 217)) l3

T%tal Shear &%r#e at t%p %& >egs 0) l3

A""iti%nal &%r#e in >eg "ue t% @ra#ing Ba"" 00 l3

.##asi%nal >%a" Ba#t%r .##&a# 1

E&&e#tieg En" !%n"iti%n Ba#t%r G 1000

N%te9 The >egs are N%t !r%ss @ra#e"

The >eg Shear B%r#e in#lu"es Hin" an" Seismi# E&&e#ts

-aximum Shear at t%p %& %ne >eg K'legL9

= : -ax:Hin", Seismi#; 4 Ba"" ; x : Imax It%t ;

= : 0) 4 00 ; x : 2) 0( ;

= 1221/ l3

Axial !%mpressi%n, >eg &uthest &r%m NA KSmaL

= ::HNleg;4:-leg:Nlegmxn;;;Aleg;

= ::217) ( ; 4 :10(0 : 2 x 212 ;;; 2110 ;

= /057 psi

Axial !%mpressi%n, >eg #l%sest t% NA KS


34/35

Distan#e t% ge%metri# #entr%i"9 0)))00 0)))00

Arm a3%ut 669 00050 07750

Arm a3%ut MM9 0/1200 00050>eg areas9 11250 07)()

e%metri# inertia #%mp%nents 669 05/522 117(5

e%metri# inertia #%mp%nents MM9 12/51 0(7(5

e%metri# inertias Iy ? I9 157 157

Pr%"u#t %& inertia9 10/

-%hrs a"ius9 10/

A


35/35

HeaG Axis @en"ing 9 0)702 1/20) psi

Str%ng Axis @en"ing 9 17/)05 1/20) psi

Axial !%mpressi%n 9 /057 2()27 psi

NIT6 !$E!JS AE9 $11 0000

$12 0000

$1 01(

AIS! nity !he#G 9 01( Sh%ul" 3e C= t% 1

olting Si@e eength D 100000 in

@aseplate Hi"th @ 100000 in

@aseplate Thi#Gness @T$J 0500 in

>eg Dimensi%n Al%ng @aseplate >ength " 0000 in

>eg Dimensi%n Al%ng @aseplate Hi"th 3 0000 in

Dist &r%m the >eg E"ge t% @%lt $%le !enter 0000 in

@%lt -aterial SA0 @

@%lt All%+a3le Stress ST@A 00000 psi

An#h%r @%lt N%minal Diameter @.D 10000 in

Num3er %& An#h%r @%lts in Tensi%n per >eg N@ 1

T%tal Num3er %& An#h%rs @%lt per >eg N@T 1ltimate 2)"ay !%n#rete Strength B!PI-E 000000 psi

Documents

Code u2 Manual Calculation(22!08!09)