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1 Circular Motion Circular Motion

Circular Motion

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Circular Motion. 1. Rotation and Revolution. Rotation. the motion or spin on an internal axis. Revolution . the motion or spin on an external axis. Rotational Speed. Rotational Speed. Number of rotations per unit of time Rpm or Rps All objects that rotated on same axis have the - PowerPoint PPT Presentation

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Page 1: Circular Motion

1

Circular MotionCircular Motion

Page 2: Circular Motion
Page 3: Circular Motion

the motion or spin the motion or spin on an internal axison an internal axis

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the motion or spin the motion or spin on an external axison an external axis

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• Number of rotations per unit of timeRpm or Rps

• All objects that rotated on same axis have the same rotational speed. • Also called Frequency

(cycles/s or Hertz) • Period (seconds) is the inverse of Frequency

Page 7: Circular Motion

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 Gymnast on a High BarA gymnast on a high bar swings through two rotations or cycles in a time of 1.90s. Find the average rotational speed (in rps) or frequency (in Hz) of the gymnast.

Page 8: Circular Motion

Given: t = 1.90 s & 2 rotation (cycle)Given: t = 1.90 s & 2 rotation (cycle)Find the average rotational speed (in rps) RpsRps = = rotationsrotations secondsecond

= = 2 rotation 2 rotation 1.90 seconds1.90 seconds

= 1.05 rps = 1.05 cycles/second= 1.05 rps = 1.05 cycles/second

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    A Helicopter BladeA Helicopter BladeFind the rotational speed or frequency at #1 if it takes 0.154 s for one rotation (cycle)?

Page 10: Circular Motion

Given: t = 0.154 s & 1 rotation (cycle)Given: t = 0.154 s & 1 rotation (cycle)Find the average rotational speed (in rps) RpsRps = = rotationsrotations secondsecond

= = 1 rotation 1 rotation 0.154 seconds0.154 seconds

= 6.49 rps = 6.49 cycles/second= 6.49 rps = 6.49 cycles/second

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    A Helicopter BladeA Helicopter BladeFind the rotational speed or frequency at #2 if takes 0.154 s for one rotation (cycle)?

Page 12: Circular Motion

Given: t = 0.154 s & 1 rotation (cycle)Given: t = 0.154 s & 1 rotation (cycle)Find the average rotational speed (in rps) RpsRps = = rotationsrotations secondsecond

= = 1 rotation 1 rotation 0.154 seconds0.154 seconds

= 6.49 rps = 6.49 cycles/second= 6.49 rps = 6.49 cycles/second

Page 13: Circular Motion

Do Frequency/ Do Frequency/ Rotational Speed Rotational Speed

ProblemsProblems

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• The speed in m/s of something moving along a circular path.

• It always tangent to the circle.

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• The distance moved The distance moved per unit of time.per unit of time.

• Linear speed is Linear speed is greater on the outer greater on the outer edge of a rotating edge of a rotating object than it is object than it is closer to the axis.closer to the axis.

Linear SpeedLinear Speed

Page 16: Circular Motion

Distance traveled in one period is the

circumference 22ππrr

Time for one “cycle” is the “period” (TT)

Tangential Speed Tangential Speed = = CircumferenceCircumference / Period / Period

Tangential Speed Tangential Speed = = 22ππrr TT

Page 17: Circular Motion

But remember that period is the inverse of

frequencySo instead of dividing by period you multiply by

frequency

Page 18: Circular Motion

18

    A Helicopter BladeA Helicopter BladeA helicopter blade has an angular speed of 6.50 rps. For points 1 on the blade, find the tangential speed

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Page 20: Circular Motion

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    A Helicopter BladeA Helicopter BladeA helicopter blade has an angular speed of 6.50 rps. For points 2 on the blade, find the tangential speed

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Do Tangential SpeedDo Tangential SpeedLinear VelocityLinear Velocity

Problems Problems

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23

Centripetal AccelerationCentripetal Acceleration

rva T

c

2

(centripetal acceleration)

Page 24: Circular Motion

24

    A Helicopter BladeA Helicopter BladeA helicopter blade has an angular speed of 6.50 rps. For points 1 on the blade, find the tangential acceleration

Page 25: Circular Motion

Given: r = 3.00 m & Given: r = 3.00 m & Tangential Speed Tangential Speed = 122 m/s= 122 m/s

Tangential Tangential Acceleration Acceleration == (122 m/s) (122 m/s)22 / 3.00m / 3.00m

== 4,960 m/s 4,960 m/s22

== 4.96 x 10 4.96 x 1033 m/s m/s22

rva T

c

2

Page 26: Circular Motion

26

    A Helicopter BladeA Helicopter BladeA helicopter blade has an angular speed of 6.50 rps. For points 2 on the blade, find the tangential acceleration

Page 27: Circular Motion

Given: r = 6.70 m & Given: r = 6.70 m & Tangential Speed Tangential Speed = = 273 m/s 273 m/s

Tangential Tangential Acceleration Acceleration == (273 m/s) (273 m/s)22 / 6.70m / 6.70m

== 11,200 m/s 11,200 m/s22

== 1.12 x 10 1.12 x 1044 m/s m/s22

rva T

c

2

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Do CentripetalDo CentripetalAccelerationAcceleration

Problems Problems

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Page 30: Circular Motion

Centripetal ForceCentripetal ForceFFcc = ma = macc

FFcc = = mvmvTT22

rr

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Page 32: Circular Motion

Vertical drum rotates, you’re pressed against wallFriction force against wall matches gravitySeem to stick to wall, feel very heavy

The forces real and perceived

Real Forces:

Friction; upCentripetal; inwardsGravity (weight); down

Perceived Forces:

Centrifugal; outwardsGravity (weight); down

Perceived weight; down and out

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Page 34: Circular Motion

Weight the force due to gravity on an objectWeight = Mass Acceleration of GravityW = m g

Weightlessness - a conditions wherein gravitational pull appears to be lackingExamples:

AstronautsFalling in an ElevatorSkydivingUnderwater

Page 35: Circular Motion
Page 36: Circular Motion

From 2001: A Space Odysseyrotates like bicycle tire

• Just like spinning drum in amusement park, create gravity in space via rotation

• Where is the “floor”?• Where would you

still feel weightless?• Note the windows on

the face of the wheel

Page 37: Circular Motion

Do CentripetalDo CentripetalForce Problems Force Problems

Page 38: Circular Motion

What makes something rotate?What makes something rotate?

TORQUE

AXLE

How do I apply a force to make the rod rotateabout the axle? Not just anywhere!

Page 39: Circular Motion

Torque = force times lever armTorque = force times lever arm

Torque = F Torque = F LL

Page 40: Circular Motion

Torque exampleTorque example

FF

LL

What is the torque on a boltWhat is the torque on a boltapplied with a wrench that applied with a wrench that has a lever arm of 30 cmhas a lever arm of 30 cmwith a force of 30 N?with a force of 30 N?

Torque = F x LTorque = F x L = 30 N x 0.30 m= 30 N x 0.30 m = 9 N m= 9 N m

For the same force, you get more torqueFor the same force, you get more torquewith a bigger wrench with a bigger wrench the job is easier! the job is easier!

Page 41: Circular Motion

Net Force = 0 , Net Torque ≠ 0Net Force = 0 , Net Torque ≠ 0

10 N10 N 10 N10 N

> The net force = 0, since the forces are applied in> The net force = 0, since the forces are applied in opposite directions so it will not accelerate.opposite directions so it will not accelerate.. .

Page 42: Circular Motion

Net Force = 0 , Net Torque ≠ 0Net Force = 0 , Net Torque ≠ 0

10 N10 N

10 N10 N

> However, together these forces will make the rod> However, together these forces will make the rod rotate in the clockwise direction. rotate in the clockwise direction.

Page 43: Circular Motion

Net torque = 0, net force ≠ 0Net torque = 0, net force ≠ 0

The rod will accelerate upward under theseThe rod will accelerate upward under thesetwo forces, but will not rotate.two forces, but will not rotate.

Page 44: Circular Motion

Balancing torquesBalancing torques

10 N10 N 20 N20 N

1 m1 m 0.5 m0.5 m

Left torque = 10 N x 1 m = 10 n mLeft torque = 10 N x 1 m = 10 n mRight torque = 20 N x 0.5 m = 10 N mRight torque = 20 N x 0.5 m = 10 N m

Page 45: Circular Motion

Balancing torquesBalancing torques

10 N10 N 20 N20 N

1 m1 m 0.5 m0.5 mLeft torque = 10 N x 1 m = 10 n mLeft torque = 10 N x 1 m = 10 n m

Right torque = 20 N x 0.5 m = 10 N mRight torque = 20 N x 0.5 m = 10 N mHow much force is exerted up by the Fulcrum? How much force is exerted up by the Fulcrum?

Page 46: Circular Motion

Torque = force times lever armTorque = force times lever arm

Torque = F Torque = F LL

Page 47: Circular Motion

EquilibriumEquilibrium• To ensure that an object To ensure that an object

does not accelerate or does not accelerate or rotate two conditions must rotate two conditions must be met:be met:

net force = 0net force = 0 net torque = 0 net torque = 0

Page 48: Circular Motion

Example 1Given M = 120 kg.Neglect the mass of the beam.

Find the Torque Find the Torque exerted by the massexerted by the mass

Torque Torque = = F F LL == 120 kg (9.8 m/s 120 kg (9.8 m/s22) ) (7 (7 m)m)

= = 8232 N m8232 N m

Page 49: Circular Motion

W beam

T le ft T right

W box

8 m2 m

A B C D

Example

Given:Given: WWboxbox=300 N=300 NFind: Find: FFTRTR = = FFCC CC = = ? N? N

ACD

TorqueTorqueCC == TorqueTorqueCCCC

FFCCL L == FFCCCCLL 300 N (6 m) 300 N (6 m) == FFCCCC (8 m) (8 m)

225 N 225 N == FFCCCC

Page 50: Circular Motion

W beam

T le ft T right

W box

8 m2 m

A B C D

Example

Given:Given: WWboxbox=300 N=300 NFind: Find: FFTLTL = = FFCCCC = = ? N? N

ACD

TorqueTorqueCC == TorqueTorqueCCCC

FFCCL L == FFCCCCLL FFC C (8 m) (8 m) == 300N (2 m) 300N (2 m)

FFC C = 75 N= 75 N

Page 51: Circular Motion

Example

W beam

T le ft T right

W box

8 m2 m

A B C D

ACD

Does this make sense?Does this make sense?FFTL TL = 75 N= 75 NFFTR TR = 225 N= 225 NDoes the Does the FFUP UP = = FFDOWN DOWN ?? FFUP UP = 75 N + 225 N = 300 N == 75 N + 225 N = 300 N =FFDOWN(Box)DOWN(Box)

Given:Given: WWboxbox=300 N=300 N

Page 52: Circular Motion

Another ExampleGiven: W=50 N, Given: W=50 N,

L=0.35 m, L=0.35 m, x=0.03 mx=0.03 m

Find the tension in the muscleFind the tension in the muscle xL

W

TorqueTorqueCC == TorqueTorqueCCCC

FFCCL L == FFCCCCLL 50N (0.350 m) 50N (0.350 m) == FFCCCC (0.030m) (0.030m) 50N (0.350 m) / 50N (0.350 m) / (0.030m) (0.030m) == FFCCCC

583 N = F583 N = FCCCC

Page 53: Circular Motion

StabilityStabilityCM &TorqueCM &Torque

Page 54: Circular Motion

Condition for stability Condition for stability

If the CG is above If the CG is above the edge, the objectthe edge, the objectwill not fallwill not fallCGCG

Page 55: Circular Motion

when does it fall over?

CG CG

STABLE NOT STABLE

If the vertical lineextending down fromthe CG is inside theedge the object willreturn to its uprightposition the torquedue to gravity bringsit back.

Page 56: Circular Motion

Stable and UnstableStable and Unstable

stablestable unstableunstabletorque due to gravitytorque due to gravitypulls object backpulls object back

torque due to gravitytorque due to gravitypulls object downpulls object down

Page 57: Circular Motion

Stable structuresStable structures

Structures areStructures arewider at theirwider at their

base to lower theirbase to lower theircenter of gravitycenter of gravity

Page 58: Circular Motion

If the center of gravity If the center of gravity is supported, the is supported, the blocks do not fall overblocks do not fall over

Playing with your blocksPlaying with your blocks

CGCG

Page 59: Circular Motion

Rotational InertiaRotational InertiaThe rotational “laziness” of an object

Page 60: Circular Motion

Recall : Recall : inertiainertiaA measure of the “laziness” of an A measure of the “laziness” of an

object because of object because of

Quantified by the mass (kg) of objectQuantified by the mass (kg) of object

a Fnet

m

Page 61: Circular Motion

Rotational Inertia (Rotational Inertia (II))A measure of an object’s “laziness” to A measure of an object’s “laziness” to

changes in rotational motionchanges in rotational motion

Depends on mass Depends on mass ANDAND

distance of mass from axis of rotationdistance of mass from axis of rotation

Page 62: Circular Motion

QuickTime™ and aTIFF (Uncompressed) decompressor

are needed to see this picture.

Balancing Pole increases Rotational InertiaBalancing Pole increases Rotational Inertia

Page 63: Circular Motion
Page 64: Circular Motion
Page 65: Circular Motion
Page 66: Circular Motion

Angular MomentumAngular Momentum

Page 67: Circular Motion

Angular MomentumAngular MomentumMomentum resulting Momentum resulting from an object moving in from an object moving in linear motion is called linear motion is called linear momentumlinear momentum. . Momentum resulting Momentum resulting from the rotation (or from the rotation (or spin) of an object is spin) of an object is called called angular angular momentummomentum..

Page 68: Circular Motion

Conservation of Angular Conservation of Angular MomentumMomentum

Angular momentum is Angular momentum is important because it important because it obeys a conservation obeys a conservation law, as does linear law, as does linear momentum. momentum. The total angular The total angular momentum of a closed momentum of a closed system stays the same.system stays the same.

Page 69: Circular Motion

Calculating angular momentumCalculating angular momentum

Angular momentum is calculated in a similar way to linear Angular momentum is calculated in a similar way to linear momentum, except the mass and velocity are replaced by the momentum, except the mass and velocity are replaced by the moment of inertia and angular velocity.moment of inertia and angular velocity.

AngularAngularvelocityvelocity(rad/sec)(rad/sec)

AngularAngularmomentummomentum(kg m/sec(kg m/sec22))

L = I L = I ww

Moment of Moment of inertiainertia(kg m(kg m22))

Page 70: Circular Motion

Gyroscopes Angular MomentumGyroscopes Angular Momentum

A A gyroscopegyroscope is a device that contains a spinning object is a device that contains a spinning object with a lot of angular momentum. with a lot of angular momentum.

Gyroscopes can do amazing tricks because they Gyroscopes can do amazing tricks because they conserve angular momentum. conserve angular momentum.

For example, a For example, a spinning spinning gyroscope can easily balance gyroscope can easily balance on a pencil point. on a pencil point.

Page 71: Circular Motion

A gyroscope on the space shuttle is mounted at the center of A gyroscope on the space shuttle is mounted at the center of mass, allowing a computer to measure rotation of the mass, allowing a computer to measure rotation of the spacecraft in three dimensions.spacecraft in three dimensions.

An on-board computer is able to accurately measure the An on-board computer is able to accurately measure the rotation of the shuttle and maintain its orientation in rotation of the shuttle and maintain its orientation in space.space.

Gyroscopes Angular MomentumGyroscopes Angular Momentum

Page 72: Circular Motion

http://www.worsleyschool.net/science/files/whichway/isdown.html

http://www.worsleyschool.net/science/files/whichway/isdown.html

http://electronics.wups.lviv.ua/KREM_literatura/hyperphysics/hbase/cf.html

http://www.universetoday.com/45766/centripetal-force/centripetal-force/

http://www.stockcarscience.com/scienceTopics/scsRacing_CentrifugalForce.phphttp://images.yourdictionary.com/centripetal-force

http://images.yourdictionary.com/centripetal-force

http://www.skylanternballoons.com/tangential-speed&page=7

http://www.ux1.eiu.edu/~cfadd/3050/Exams/OldExams/Key2Su99.html

http://www.ehow.com/how_8027055_science-method-measure-rotational-speed.html

http://qwikstep.eu/search/speed-of-baseball.html

http://forum.digital-digest.com/showthread.php?t=67288

http://www.ritsumei.ac.jp/~akitaoka/rotate-e.html

http://www.medievalists.net/2010/07/22/traveling-around-the-empire-iberian-voyages-the-sphere-and-the-atlantic-origins-of-the-scientific-revolution/

http://nexus404.com/Blog/2008/09/10/the-rotation-bicycle-by-yirong-yang-blows-people-away-at-international-bicycle-design-challenge/