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    CHNG 2: PLC S7 X00

    (30 cu)

    Cu 1 Trn PLC S7x00 ta thy cc cha kha cng tc :

    A RUN-P, STOP, MRES, RUN.

    B STOP, MRES, RUN, SF.

    C BATF, STOP, MRES, RUN-P.

    D RUN, STOP, FRCE, MRES.

    p n A

    Cu 2 Pht biu no sau y l ng:

    A RUN-P: trng thi chy RUN, iu khin chng trnh t my tnh v c thsa c chng trnh.

    B RUN -P: CPU thc hin chng trnh hay iu khin chng trnh t mytnh.

    C RUN-P: trng thi chy RUN, CPU thc hin chng trnh hay iu khin

    chng trnh t my tnh, tuy nhin ch c c chng trnh m khngsa c.

    D RUN-P: trng thi chy RUN, CPU thc hin chng trnh hay iu khinchng trnh t my tnh.

    p n D

    Cu 3 Pht biu no l ng khi ni vPLC S7-200 loi cp in p 220VAC:

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    A Ng vo tch cc mc 1 mc in p +24VDC (15 - 30VDC). Ng ra lr le c th s dng nhiu cp in p 0V, 24V, 220V

    B Ng vo tch cc mc 1 mc in p +24VDC (15-30VDC). Ng ra ltransistor c th s dng nhiu cp in p 0V, 24V, 220V

    C Ng vo tch cc mc 1 mc in p 220VAC. Ng ra l rle mt mcin p duy nht 24VDC.

    D Ng vo tch cc mc 1 mc in p +24VDC (15-30VDC).. Ng ra ltransistor ch c mt mc in p duy nht l +24VDC.

    p n A

    Cu 4 Pht biu no l ng khi ni v PLC S7-200 loi cp in p 24VDC:

    A Ng vo tch cc mc 1 mc in p 220VAC. Ng ra l transistor, chc mt mc in p duy nht l +24VDC

    B Ng vo tch cc mc 1 mc in p +24VDC (15-30VDC). Ng ra lrle c th s dng nhiu mc in p 0V, 24V, 220V

    C Ng vo tch cc mc 1 cp in p +24VDC (15 30VDC). Ng ra ltransistor ch c mt cp in p duy nht l +24VDC

    D Ng vo tch cc mc 1 cp in p 220VAC. Ng ra l rle c th sdng nhiu cp in p 0V, 24V, 220V

    p n C

    Cu 5 Loi PLC no m s dng ng ra iu rng xung, hoc output tc cao:

    A PLC S7-200 loi cp in p 220VAC, ng ra rle

    B PLC S7-300, S7-400

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    C PLC S7- 200 loi cp in p 24VDC, ng ra l transistor.

    D S7-200 loi cp in p +24VDC (15-30VDC), ng ra l transistor.

    p n C

    Cu 6 Loi PLC no m s dng ng ra cho ng dng rng xung, hoc output tc cao:

    A PLC S7-200 loi cp in p 220VAC, ng ra rle.

    B PLC S7-200 loi cp in p 24VAC, ng ra transitor.

    C PLC S7-200 loi cp in p 220VAC, ng ra rle.D PLC S7-200 loi cp in p 24VAC, ng ra transitor.

    p n A

    Cu 7 Ch ci IFM i sau cc tn ca PLC h S7-300 l vit tt ca cm t nosau y:

    A Intergrated Function Module

    B Integrable Function Mode

    C Integrated Function Module

    D Intergrated Function Modulle

    p n C

    Cu 8 Ch ci DP i sau cc tn ca PLC h S7-300 l vit tt ca cm t no sauy:

    A Distrubited Portal

    B Distrubited Port

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    C Disturb Port

    D Distrubite Port

    p n B

    Cu 9 Pht biu no sau y l ng:

    A H PLC S7 300 c nhiu loi CPU khc nhau: CPU 312, CPU 314, CPU315... nhng module s dng cng cc b vi x l khc nhau v cc cngonboard cng nh cc khi hm c bit tch hp sn trong h iu hnhphc v vic s dng cc cng vo/ra onboard ny

    B H PLC S7 300 c nhiu loi CPU khc nhau: CPU 312, CPU 314, CPU

    315... nhng module cng s dng cng mt loi b vi x l v cc cngonboard cng nh cc khi hm c bit tch hp sn trong h iu hnhphc v vic s dng cc cng vo/ra onboard ny

    C H PLC S7 300 c nhiu loi CPU khc nhau: CPU 312, CPU 314, CPU315... nhng module cng s dng cc loi b vi x l nhng ging nhau vcng onboard cng nh cc khi hm c bit tch hp sn trong h iuhnh phc v vic s dng cc cng vo/ra onboard ny

    D H PLC S7 300 c nhiu loi CPU khc nhau: CPU 312, CPU 314, CPU

    315... nhng module cng s dng cng mt loi b vi x l nhng khcnhau v cng onboard cng nh cc khi hm c bit tch hp sn trong hiu hnh phc v vic s dng cc cng vo/ra onboard ny.

    p n D

    Cu 10 Vic ghp ni cc module m rng ca PLC S7-200 c thc hin:

    A Ti a ni c 8 module v vic ghp ni ch din ra ti pha bn phi caPLC.

    B Ti a ni c 7 module m rng v ghp ni theo hai bn

    C Ti a ni c 8 module m rng v c th hai bn ca PLC

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    D Ti a ni c 7 module m rng v vic ghp ni ch din ra pha bnphi ca PLC

    p n D

    Cu 11: Hnh no sau y ch ng vic ghp ni module m rng cho PLC S7-300:

    A

    B

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    C

    D

    p n A

    Cu 12: Hnh no sau y l ng khi xc nh a ch ca cc module s ca PLCS7-300:

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    A

    B

    C

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    D

    p n D

    Cu 13: Hnh no sau y l ng khi xc nh a ch ca cc module tng t caPLC S7-300:

    A

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    B

    C

    D

    p n C

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    Cu 14: Hnh no m t ng v vng qut chng trnh ca PLC S7 x00:

    A

    B

    C

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    D

    p n D

    Cu 15 Khi thc hin vng qut cc cng vo s v cng ra s s c PLC thchin:

    A Thc hin ly d liu t cng vo s trc tip v truyn d liu ra qua cngra s qua b m Q.

    B Thc hin ly d liu t cng vo s qua b m I v truyn d liu ra quacng ra s qua b m Q.

    C Thc hin ly d liu t cng vo s v truyn d liu ra qua cng ra s mtcch trc tip.

    D Thc hin ly d liu t cng vo s qua b m I v truyn d liu ra quacng ra s mt cch trc tip.

    p n B

    Cu 16 Khi thc hin vng qut cc cng tng t s c PLC thc hin:A Cc lnh truy nhp cng tng t c thc hin qua b m ca cng

    tng t.

    B Cc lnh truy nhp cng tng t c thc hin trc tip vi cng vt lch khng thng qua b m.

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    C Cc lnh truy nhp cng tng t khi c thc hin trc tip vi cng vtl ch khng thng qua b m, khi th c thc hin thng qua b m.

    D Cc lnh truy nhp cng tng t c thc hin trc tip vi cng vt lthng qua b m.

    p n B

    Cu 17 Thi gian vng qut ca PLC S7 x00 l:

    A Thi gian cn thit PLC S7 x00 thc hin ht chng trnh.

    B Thi gian cn thit PLC S7-X00 thc hin c 1 lnh.

    C Thi gian cn thit PLC S7-x00 thc hin mt vng qut.

    D Thi gian cn thit PLC S7-x00 thc hin xong mt khi lnh.

    p n C

    Cu 18: PLC S7-200 loi Loi AC/DC/RLY c c im:

    A in p ngun cung cp t 85-264 VAC, tn s 47- 63Hz; in pvo: c ngun cung cp chun cho sensor l 24 VDC. in p ra s

    dng qua ngun in ngoi, c th l DC hoc AC nhng khng vtqu 220v. Nu s dng i vi nhng thit b tiu th c cng sutnh khong vi Woat th c th s dng trc tip ngun ca cmbin.

    B in p ngun cung cp t 85-264 VAC, tn s 50- 63Hz; in pvo: c ngun cung cp chun cho sensor l +24 VDC. in p ra sdng qua ngun in ngoi, c th l DC hoc AC nhng khng vtqu 220v. Nu s dng i vi nhng thit b tiu th c cng sut

    nh khong vi Woat th c th s dng trc tip ngun ca cmbin.

    C in p ngun cung cp t 220 380 VAC, tn s 47- 63Hz; in pvo: c ngun cung cp chun cho sensor l 24 VDC. in p ra sdng qua ngun in ngoi, c th l DC hoc AC nhng khng vt

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    qu 220v. Nu s dng i vi nhng thit b tiu th c cng sutnh khong vi Woat th c th s dng trc tip ngun ca cmbin.

    D in p ngun cung cp t 85-264 VAC, tn s 47- 63Hz; in pvo: c ngun cung cp chun cho sensor l 24 VDC. in p ra sdng qua ngun in ngoi, c th l DC hoc AC nhng khng vtqu 220v. Nu s dng i vi nhng thit b tiu th c cng sutnh khong vi Woat th s dng ngun ca cm bin thng qua bbin i in.

    p n A

    Cu 19: PLC S7-200 loi DC/DC/DC c c im:

    A Ngun nui s dng in p +24VDC (15-30VDC). Ngun nui cm

    bin 24VDC. u ra transistor h collector ngun cung cp 24VDC.

    B Ngun nui s dng in p 24VDC. Ngun nui cm bin 24VDC.

    u ra transistor collector ngun cung cp 24VDC.

    C Ngun nui s dng in p 24 VDC. Ngun nui cm bin 24VDC.

    u ra transistor h collector ngun cung cp 24VDC.

    D Ngun nui s dng in p 24VDC (15-30VDC). Ngun nui cm

    bin 24VDC (15-30VDC).. u ra transistor h collector ngun cung

    cp 24VDC (15-30VDC)..

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    p n C

    Cu 20: Ngn xp ca PLC S7-x00 l ngn xp c 8 bt c sp xp nh hnh

    no sau:A.

    S0: bit th nht ca stack

    S1: bit th hai ca stack

    S2: bit th ba ca stack

    S3: bit th t ca stack

    S4: bit th nm ca stack

    S5: bit th su ca stack

    S6: bit th by ca stack

    S7: bit th tm ca stack

    B.

    S1: bit th nht ca stack

    S2: bit th hai ca stack

    S3: bit th ba ca stack

    S4: bit th t ca stack

    S5: bit th nm ca stack

    S6: bit th su ca stack

    S7: bit th by ca stack

    S8: bit th tm ca stack

    C.

    S8: bit th tm ca stack

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    S7: bit th by ca stack

    S6: bt th su ca stack

    S5: bit th nm ca stack

    S4: bit th t ca stack

    S3: bit th ba ca stack

    S2: bit th hai ca stack

    S1: bit th nht ca stack

    D.

    S1: bit th tm castack

    S2: bit th by castack

    S3: bit th su castack

    S4: bit th nm castack

    S5: bit th t castack

    S6: bit th ba castack

    S7: bit th hai castack

    S8: bit th nht castack

    Cu 20 Ngn xp ca PLC S7-x00 l ngn xp c 8 bt csp xp nh hnh no sau:

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    p n B

    Cu 21. S b timer trong PLC S7-x00 l:

    A Trong S7 200 c 256 timer, trong S7 300 c 128 timer.

    B Trong S7 200 c 256 timer, trong S7 300 c 256timer.

    C Trong S7 200 c 128 timer, trong S7 300 c 128 timer.

    D Trong S7 200 c 128 timer, trong S7 300 c 256 timer.

    p n A

    Cu 22. S m c cha trong vng nh d liu h thng dng trong Counter caPLC S7-200 c c im g?

    A Dng nh phn v c gi tr trong khong t 1 n 999.

    B Dng hexa v c gi tr trong khong t 0 n 999.

    C Dng nh phn v c gi tr trong khong t 0 n 999.

    D Dng hexa v c gi tr trong khong t 1 n 999.

    p n C

    Cu 23. PLC S7-200 s dng cc phn mm lp trnh c c im g?

    A PLC S7-200 s dng phn mm lp trnh Micro Win vi cc version hinnay l v3.2,v4.0 v cc version ny u c th chy m phng trn phnmm m phng PLC.

    B PLC S7-200 s dng phn mm lp trnh Micro Win vi cc version hinnay l v3.2,v4.0 v cc version di v4.0 mi c th chy m phng trn

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    phn mm m phng PLC.

    C PLC S7-200 s dng phn mm lp trnh Micro Win vi cc version hinnay l v3.2,v4.0 v cc version v4.0 tr ln mi c th chy m phngtrn phn mm m phng PLC.

    D PLC S7-200 s dng phn mm lp trnh Micro Win vi cc version hinnay l v3.2,v4.0 v ch c version v3.2 mi c th chy m phng trnphn mm m phng PLC.

    p n C

    Cu 25 PLC S7-200 s dng cc phn mm lp trnh c c im g?

    A PLC S7 300 s dng phn mm lp trnh Simatic Manager vi cc versionl v5.2, v5.3, v5.4... tt c cc version ny u c th chy m phng.

    B PLC S7 300 s dng phn mm lp trnh Simatic Manager vi cc version

    l v5.2, v5.3, v5.4... cc version t v5.4 tr ln mi c th chy m phng.

    C PLC S7 300 s dng phn mm lp trnh Simatic Manager vi cc version

    l v5.2, v5.3, v5.4... ch c version v5.4 mi c th chy m phng.

    D PLC S7 300 s dng phn mm lp trnh Simatic Manager vi cc version

    l v5.2, v5.3, v5.4... tt c cc version ny phi c phn mm chy mphng mi c th chy m phng.

    p n A

    Cu 26 CPU 314 c c im g?

    A B nh lm vic 16Kb, chu k lnh 0.1 s

    B B nh lm vic 16Kb, chu k lnh 0.3 s

    C B nh lm vic 24Kb; chu k lnh 0.3 s

    D B nh lm vic 32Kb; chu k lnh 0.3 s

    p n C

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    Cu 27 CPU 314C-2PtP c c im g?

    A

    B nh lm vic 48KB, chu k lnh 0.1s; tch hp sn 24DI/16DO,

    5AI/2AO, 4 knh xut tc cao, 4 knh c xung tc cao; 2 cng giao

    tip.

    B B nh lm vic 48KB, chu k lnh 0.3s; tch hp sn 24DI/16DO,

    5AI/2AO, 4 knh xut tc cao, 4 knh c xung tc cao; 2 cng giao

    tip.

    C B nh lm vic 48KB, chu k lnh 0.3s; tch hp sn 16DI/24DO,

    5AI/2AO, 4 knh xut tc cao, 4 knh c xung tc cao; 2 cng giao

    tip.

    D B nh lm vic 48KB, chu k lnh 0.3s; tch hp sn 24DI/16DO,5AI/2AO, 4 knh xut tc cao, 4 knh c xung tc cao; 2 cng giaotip.

    p n A

    Cu 28 FM355 PID Module l module c chc nng g?

    A Module iu khin PID, 4 knh iu khin PID, 4AI/8DI/4AO.

    B Module iu khin PID, 4 knh iu khin PID, 4AI/8DI/8AO.

    C Module iu khin PID, 4 knh iu khin PID, 8AI/8DI/4AO.

    D Module iu khin PID, 4 knh iu khin PID, 4AI/4DI/4AO.

    p n A

    Cu 29 Module FM353 Fstepper Motor l module c c im g?

    A Module iu khin ng c servo 4DI/4DO

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    B Module iu khin ng c bc

    C Module iu khin ng c bc 4DI/4DO

    D Module iu khin ng c servo 4DI/1DO

    p n C

    Cu 30 Theo cch u ni cho PLC S7 200 th S7 200 c phn ra lm my

    loi? gm nhng loi no?

    A Gm 2 loi. Loi AC/DC/RLY v DC/DC/DC.

    B Gm 2 loi. Loi AC/AC/AC v DC/DC/DC.

    C Gm nhiu loi v d: CPU 212, 214, 224, 226

    D Gm 2 loi. Loi cp in p xoay chiu v loi cp in mt chiu

    p n A

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    Cu 31 Cho s u ni ca PLC sau, cho bit l s u ni cho loi PLC

    no?

    A PLC S7 200 loi AC/DC/RELAY

    B PLC S7 300 loi DC/DC/DC

    C PLC S7 200 loi AC/DC/RLY

    D C ba loi trn.p n C

    Cu 32. Cho s u ni ca PLC sau, cho bit l s u ni cho loi PLC

    no?

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    A CPU S7 200 loi DC/DC/RLY

    B CPU S7 300 loi DC/DC/DCC CPU S7 200 loi DC/DC/DC

    D CPU S7 200 loi AC/DC/RLY

    p n C

    Cu 33 Cp PPI dng u ni cho PLC S7 200 v my tnh hay my lp trnh cchc nng g?

    A Dng chng trnh t my tnh hay my lp trnh sang PLC vupload chng trnh t PLC tr li my tnh hay my lp trnh.

    B Dng giao tip gia ngi lp trnh v PLC thng qua chng trnhlp trnh cho PLC.

    C Dng chuyn i tn hiu s sang tn hiu tng t v ngc li PLC c th giao tip c vi my tnh hay my lp trnh.

    D Dng kt ni mng PLC

    p n C

    Cu 34 Cp PPI s dng kt ni PLC S7- 200 vi my tnh hay my lp trnh lvit tt ca t no?

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    A Point to Point Interface

    B Point Point Interface.

    C Point of Point Interface.

    D C ba p n trn.

    p n A

    Cu 35 Cp kt ni PPI c hai u l RS 232 v RS 485 c ni nh th no?

    A u ni RS 232 c ni vo my tnh hay my lp trnh; u ni RS 485c ni vo PLC.

    B u ni RS 485 c ni vo my tnh hay my lp trnh; u ni RS 232c ni vo PLC.

    C C th thay i v tr u cho hai u cp.

    D C ba p n trn.

    p n A

    Cu 36. Cp PPI vi giao tip cng COM c tc giao tip mc nh l bao nhiu?

    A 9600 baud.

    B 19200 baud/s.

    C 4800 baud.

    D 9600 baud/s.

    p n A

    Cu 37. Cp MPI dng u ni cho PLC S7 300 v my tnh hay my lp trnh cchc nng g?

    A Dng chng trnh t my tnh hay my lp trnh sang PLC v uploadchng trnh t PLC tr li my tnh hay my lp trnh.

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    B Dng giao tip gia ngi lp trnh v PLC thng qua chng trnh lp trnhcho PLC.

    C Dng chuyn i tn hiu s sang tn hiu tng t v ngc li PLC cth giao tip c vi my tnh hay my lp trnh.

    D Dng kt ni mng PLC.

    p n C

    Cu 38 Cp MPI s dng kt ni PLC S7- 300 vi my tnh hay my lp trnh lvit tt ca t no?

    A Multi media Point Interface

    B Multi of Point Interface.

    C Multi Point Interface.

    D Multi to Point Interface.

    p n C

    Cu 39 Cp kt ni MPI c hai u l RS 232 v RS 485 c ni nh th no?

    A u ni RS 485 c ni vo my tnh hay my lp trnh; u ni RS 232c ni vo PLC.

    B C th thay i v tr u cho hai u cp.

    C u ni RS 232 c ni vo my tnh hay my lp trnh; u ni RS 485c ni vo PLC.

    D C ba p n trn.

    p n C

    Cu 40 Cp MPI vi giao tip cng COM c tc giao tip mc nh l baonhiu?

    A 19200 baud/s

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    B 9600 baud

    C 9600 baud/s

    D 19200 baud

    p n D

    Cu 41 Cu lnh sau y to ra thi gian l bao nhiu?

    A 30s

    B 300s

    C 3000s

    D 3s

    p n B

    Cu 42 Cho bit on lnh sau thc hin cng vic g?

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    A Sau thi gian T37 = 2s trng thi SCR1 kt thc v trng thi SCR2 hotng v sau thi gian T38 = 25s th trng thi SCR3 hot ng thit lpcc u ra Q0.4; Q0,5; Q0.2.

    B Trng thi SCR1;SCR2 v SCR3 hot ng bt cc u ra Q0.4; Q0,5;Q0.2 trong thi gian 2s, 25s.

    C Cc u ra Q0.4; Q0.5; Q0.2 c bt ln trong thi gian 25s.

    D Khng c p n no ng.

    p n

    Cu 43 Kt qu ca on lnh sau l g?

    L IW 10

    L MW 14+I

    T DB1.MDBM25

    A Cng hai s nguyn 32 bit cha trong IW10, MW14 v ct kt qu

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    vo nh DBW25 ca khi d liu DB1.

    B Cng hai s nguyn 16 bit cha trong IW0, MW14 v ct kt qu vo nh DB1.DBW25.

    C Cng hai s nguyn 32bit cha trong IW10, MW14 v ct kt quvo nh DB1.DBW25.

    D Cng hai s nguyn 16 bit cha trong IW0, MW14 v ct kt quvo nh DBW25 ca khi d liu DB1.

    p n D

    Cu 44 on lnh sau thc hin cho kt qu l g?

    L MD 10

    L MD 14

    /D

    T MD20

    A Thc hin chia 2 s nguyn MD10:MD14 v kt qu ct vo nh MD20.

    B Thc hin chia 2 s nguyn 16 bit MD10:MD14 v kt qu ct vo nh

    MD20.

    C Thc hin chia 2 s nguyn 32 bit MD10:MD14 v kt qu ct vo nhMD20.

    D Thc hin chia 2 s nguyn 8 bit MD10:MD14 v kt qu ct vo nhMD20.

    p n C

    Cu 45 on lnh sau khi thc hin s cho kt qu g?

    A Q4.0

    L MD10

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    L -1

    -D

    X < > 0

    = Q4.0

    A Nu s nguyn 16 bit x trong MD10 -1 th o trng thi n Q4.0

    B Nu s nguyn 32 bit x trong MD10 0 th trng thi n Q4.0 sng.

    C Nu s nguyn 16 bit x trong MD10 0 th o trng thi n Q4.0

    D Nu s nguyn 32 bit x trong MD10 -1 th o trng thi n Q4.0

    p n D

    Cu 46 on lnh sau khi thc hin s cho kt qu g?

    A Q4.0

    L MD10

    L 2.8

    -R

    X >= 0

    = Q4.0

    A Nu s thc x trong MD10 tha mn >= 0 th o trng thi n Q4.0

    B Nu s thc x trong MD10 tha mn >= 2.8 th o trng thi nQ4.0

    C Nu s thc x trong MD10 tha mn >= 0 th trng thi n Q4.0

    sng

    D Nu s thc x trong MD10 tha mn >= -2.8 th o trng thi nQ4.0

    p n B

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    Cu 47 on lnh sau khi thc hin s cho kt qu g?

    L PIW304

    ITD

    DTR

    L 3276.7

    /R

    T MD0

    A i s nguyn 16 bits c t cng tng t PIW304 thnh s nguyn 32bitsc gi tr ng bng gi tr in p ti cng v kt qu ct vo nh MD0.

    B i s nguyn 16 bits c t cng tng t PIW304 thnh s thc c gi trng bng gi tr in p ti cng v kt qu ct vo nh MD0.

    C i s nguyn 32 bits c t cng tng t PIW304 thnh s nguyn 32bitsc gi tr ng bng gi tr in p ti cng v kt qu ct vo nh MD0.

    D i s nguyn 32 bits c t cng tng t PIW304 thnh s thc c gi trng bng gi tr in p ti cng v kt qu ct vo nh MD0.

    p n B

    Cu 48 Sau khi thc hin on chng trnh sau th kt qu s l g?

    L 1 BEC

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    L MW0

    +I

    T MW0

    L 1000

    < > I

    L 0

    T MW0

    AN Q4.0

    = Q4.0

    BEU

    A Chng trnh s i trng thi ca cng ra Q4.0 vng qut th 1000v khng lm g cc vng khc.

    B Chng trnh s i trng thi ca cng ra Q4.0 cui chng trnh.

    C Chng trnh s i trng thi ca cng ra Q4.0 vng qut c th t

    chia ht cho 1000 v khng lm g cc vng qut khc.D Chng trnh s i trng thi ca cng ra Q4.0 1000 vng qut

    u tin v khng lm g cc vng qut tip theo.

    p n C

    Cu 49 on chng trnh sau s to thi gian bao nhiu?Loi timer s dng l g?

    A I4.0

    FR T1

    A I4.0

    L W#16#2127

    A Thi gian tr l 2127s v loi timer tr theo sn ln.B Thi gian tr l 2*127s v loi theo sn ln timer tr.

    C Thi gian tr l 127s v loi timer tr theo sn ln c nh.

    D Thi gian tr l 127s v loi timer tr theo sn ln.

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    p n D

    Cu 50 Khi thc hin on chng trnh sau kt qu l gi?

    OPN DB3

    OPN DB5

    L DBLG

    L DILG

    > D

    = Q1.0

    A Nu di ca DBLG ln hn ca DILG th n Q1.0 s sng.

    B Nu di ca DB3 ln hn DB5 th n Q1.0 s sng.

    C Nu di ca DB5 ln hn DB3 th n Q1.0 s sng.

    D Nu di ca DILG ln hn ca DBLG th n Q1.0 s sng

    p n B

    Cu 51 on chng trnh sau khi thc hin kt qu l g?

    L #OB1_MAX_CYCLE

    L 59

    > I

    L #OB1_MIN_CYCLE

    L 45

    - I

    A < 0

    A Q0.0

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    A Chng trnh vit cho OB1 s bo sng n Q1.0 nu c mt vng qut thchin trong 59s v c mt vng qut thc hin trong 45s.

    B Chng trnh vit cho OB1 s bo sng n Q1.0 nu c mt vng qut thchin trong lu hn 59s v c mt vng qut thc hin nhanh hn 45s.

    C Chng trnh vit cho OB1 s bo sng n Q1.0 nu c mt vng qut thchin trong trong khong t 45s n 59s.

    D Khng c p n no ng.

    p n B

    Cu 52 Kt qu ca on chng trnh sau khi thc hin l g?

    CALL FB 1,DB2

    CONG := PIW306

    KET_QUA := # analog_value

    OPN DB2

    L DBD202

    L #analog_value

    < R

    = Q0.0

    L DBW206

    L 50

    = Q0.1

    A Cho n Q0.0 sng nu gi tr c c ti cng tng t PIW306 nh hngi tr trung bnh 50 gi tr c c mi nht; ngc li cho n Q0.1 sngnu trong b m cha 50 gi tr.

    B Cho n Q0.0 sng nu gi tr c c ti cng tng t PIW306 nh hngi tr trung bnh 50 gi tr c c; ngc li cho n Q0.1 sng nu trong

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    b m cha 50 gi tr.

    C Cho n Q0.0 sng nu gi tr c c ti cng tng t PIW306 bng gitr trung bnh 50 gi tr c c mi nht; ngc li cho n Q0.1 sng nutrong b m cha 50 gi tr.

    D Cho n Q0.0 sng nu gi tr c c ti cng tng t PIW306 nh hn50; ngc li cho n Q0.1 sng nu trong b m cha 50.

    p n A