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Chemistry Chemistry Chapter 3 Chapter 3 Scientific Measurement Scientific Measurement

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Chemistry Chapter 3. Scientific Measurement. A) 241 2.41 x 10 2 B) 6015 6.015 x 10 3 C) 0.0162 1.62 x 10 -2. D) 0.512 5.12 x 10 -1 E) 6.62 x 10 2 662 F) 3.4 x 10 -3 0.0034. Scientific Notation Convert to or from Scientific Notation:. - PowerPoint PPT Presentation

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Page 1: Chemistry  Chapter 3

Chemistry Chemistry Chapter 3Chapter 3

Scientific MeasurementScientific Measurement

Page 2: Chemistry  Chapter 3

Scientific NotationScientific NotationConvert to or from Scientific Convert to or from Scientific Notation:Notation:

A) 2412.41 x 102

B) 60156.015 x 103

C) 0.01621.62 x 10-2

D) 0.5125.12 x 10-1

E) 6.62 x 102

662

F) 3.4 x 10 -3

0.0034

Page 3: Chemistry  Chapter 3

Accuracy -how close measurements are to the correct or accepted value.

Precision - closeness of a set of measurements.

Page 4: Chemistry  Chapter 3
Page 5: Chemistry  Chapter 3

Percent error – compares the accuracy of an individual value or average values to the correct or accepted value.

Page 6: Chemistry  Chapter 3

% error = Accepted value – Experimental value x 100% Accepted value

STAAR CHART FORMAT

Page 7: Chemistry  Chapter 3

Example: What is the percent error for a Example: What is the percent error for a mass measurement of 17.7g, given that the mass measurement of 17.7g, given that the

correct value is 21.2g?correct value is 21.2g?

% error = 21.2g – 17.7g x 100% = 21.2g

16.5%16.5%

Page 8: Chemistry  Chapter 3

Significant Figures RulesSignificant Figures Rules1. Nonzero Digits – every nonzero

digit is significant.

Ex: a) 32.8 m has three sig figs b) 981.78 km has five sig figs

Page 9: Chemistry  Chapter 3

2. Sandwich zeros – zeros appearing between nonzero digits are significant.

Ex: c) 101.2 g has four sig figs d) 50.1 L has three sig figs

Page 10: Chemistry  Chapter 3

3. Placeholder – leftmost zeros appearing in front of nonzero digits are not significant.

Ex: e) 0.000007 has one sig fig f) 0.0003809 has four sig figs

Page 11: Chemistry  Chapter 3

4. Trailer zeros – zeros at the end of a number and to the right of the decimal point are significant.

Ex: g) 2000. m has four sig figs h) 34.0 mL has three sig figs

Uncertainty in Measurement

Page 12: Chemistry  Chapter 3

STAAR CHART FORMAT FOR STAAR CHART FORMAT FOR SIG. FIGS.SIG. FIGS.

Page 13: Chemistry  Chapter 3

RoundingRounding

*The calculated value cannot be more precise than the measured values used to obtain it.

Page 14: Chemistry  Chapter 3

Example: Round each measurement to Example: Round each measurement to the three sig. figs.the three sig. figs.

a) 45.89m 45.9m

b) 3004 m3.00 x 103m

c) 17.32 cm 17.3 cm

d) 20019 L2.00x104 L

Page 15: Chemistry  Chapter 3

Rounding – Addition and Rounding – Addition and SubtractionSubtraction

Round the answer to the same number of decimal places (not digits) as the measurement with the least number of decimal places.

Page 16: Chemistry  Chapter 3

Example: Subtract 2.6103m Example: Subtract 2.6103m from 5.44m.from 5.44m.

5.44 m - 2.6103 m 2.8297 m

2.83m2.83m

Page 17: Chemistry  Chapter 3

Rounding – Multiplication and Rounding – Multiplication and DivisionDivision

Round the answer to the same number of sig. figs as the measurement with the least number of sig. figs.

Page 18: Chemistry  Chapter 3

Example: Multiply 2.4 mExample: Multiply 2.4 m22 and and 15.82m.15.82m.

2.4 m2 x 15.82 m = 37.968 m3

38 m38 m33

Extra Practice

Page 19: Chemistry  Chapter 3

SI Measurement – Le Systeme International d’Unites

Page 20: Chemistry  Chapter 3

7 SI Base Units7 SI Base Units Quantity Quantity

SymbolUnit Name Unit

Abbreviation

Length l meter mMass m kilogram kgTime t second sTemperatu

reT Kelvin K

Amount of Substance

n mole mol

Electric Current I ampere ALuminous

IntensityIv candela cd

Page 21: Chemistry  Chapter 3

SI PrefixesSI Prefixes Prefi

xUnit

abbreviation

Exponential

factor

Example

kilo k 103 1 kilometer(km)= 1000 m

100 1 meter (m)

deci d 10-1 10 decimeter(dm) = 1 m

centi

c 10-2 100 centimeter (cm) = 1m

milli m 10-3 1000 millimeter (mm) = 1m

micro

u 10-6 1000000 micrometer (um) =1m

nano

n 10-9 1000000000 nanometer (nm) = 1m

Page 22: Chemistry  Chapter 3

Mass – measure of the quantity of matter (SI unit is kg).

The gram, g, is ideal for expressing masses of small objects such as a beaker.

For even smaller masses like weighing out chemicals the milligram is used.

Page 23: Chemistry  Chapter 3

Mass vs WeightMass vs Weight

Mass is the measure of the amount of matter, whereas weight is the measure of the gravitational pull on matter.

Page 24: Chemistry  Chapter 3

Derived units are a combination of SI base units.

*Volume is the amount of space occupied by an object. The derived unit for volume is cubic meters, m3. (Volume = l x w x h)

Page 25: Chemistry  Chapter 3
Page 26: Chemistry  Chapter 3

Figure 01.20Figure 01.20

Page 27: Chemistry  Chapter 3

Density is a derived unit. It is mass divided by volume.

density = mass or D = m volume V

The SI units are kg/m3

Page 28: Chemistry  Chapter 3

Density…:Density…:

• is a physical property of a substance.• does not depend on the size of the

sample.• As the mass of the sample increases

so does the volume.

Page 29: Chemistry  Chapter 3
Page 30: Chemistry  Chapter 3

Density of a substance determines whether it floats or sinks in a liquid.

For instance, ice has a density of 0.92 g/mL, which is less than that of water (0.998 g/mL). Since ice is less dense, it will float on water.

Page 31: Chemistry  Chapter 3

Example: The density of water is 0.998 g/mL. If Example: The density of water is 0.998 g/mL. If copper pellets were placed in the water would it copper pellets were placed in the water would it

sink or float? (Density of copper is 8.92g/mL)sink or float? (Density of copper is 8.92g/mL)

The copper would sink as its density is higher than that of water.

Page 32: Chemistry  Chapter 3

Examples:Examples:A sample of aluminum metal has a A sample of aluminum metal has a mass of 8.40g. The volume of the sample is 3.1cmmass of 8.40g. The volume of the sample is 3.1cm33. . Calculate the density of aluminum.Calculate the density of aluminum.

D = m = 8.40g = 2.7g/cm2.7g/cm33

V 3.1cm3

Page 33: Chemistry  Chapter 3

A sheet of metal has a length of 32.0cm, a width of A sheet of metal has a length of 32.0cm, a width of 2.00cm, and a height of 1.000cm. The density 2.00cm, and a height of 1.000cm. The density of the metal is 9.7g/cmof the metal is 9.7g/cm33. Calculate the mass of . Calculate the mass of

the metal.the metal.

D = m/V m = D x V m = (9.7g/cm3)(32.0cm x 2.00cm x 1.000cm)

m = 620 g620 g

Page 34: Chemistry  Chapter 3

Specific GravitySpecific Gravity• Comparison of the density of a

substance with the density of a reference substance.

• A hydrometer is used to measure the specific gravity of a liquid.

Page 35: Chemistry  Chapter 3

TemperatureTemperature• Determines the direction of heat

transfer.

Page 36: Chemistry  Chapter 3

Temperature ScalesTemperature Scales• Celsius scale: Uses water as the

reference (i.e. 0oC and 100oC)

Page 37: Chemistry  Chapter 3

Temperature Scales (cont.)Temperature Scales (cont.)• Kelvin scale: Freezing point of water

is 273.15 K and its boiling point is 373.15 K.– Absolute Zero – all motion ceases

Page 38: Chemistry  Chapter 3
Page 39: Chemistry  Chapter 3

Converting between Celsius Converting between Celsius and Kelvinand Kelvin

K = oC + 273oC = K – 273

Page 40: Chemistry  Chapter 3

Liquid nitrogen boils at 77.2 K. What is Liquid nitrogen boils at 77.2 K. What is this temperature in degrees Celsius?this temperature in degrees Celsius?

oC = K – 273oC = 77.2 – 273

-195.8-195.8ooCC