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Chemical Reactions

Chemical Reactions

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Chemical Reactions. BELLWORK. BRIEFLY WRITE ABOUT A SCIENTIFIC OBSERVATION YOU MADE RECENTLY. Chemical equations. WE USE CHEMICAL EQUATIONS TO DESCRIBE CHEMICAL REACTIONS. Burning Coal. This is a chemical reaction - PowerPoint PPT Presentation

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Page 1: Chemical Reactions

Chemical Reactions

Page 2: Chemical Reactions

BELLWORK

• BRIEFLY WRITE ABOUT A SCIENTIFIC OBSERVATION YOU MADE RECENTLY

Page 3: Chemical Reactions

Chemical equations

• WE USE CHEMICAL EQUATIONS TO DESCRIBE CHEMICAL REACTIONS

Page 4: Chemical Reactions

Burning Coal

Page 5: Chemical Reactions

• This is a chemical reaction• The purpose of the equation is to

show what was present before the reaction (carbon and oxygen) and afterwards (carbon dioxide)

Page 6: Chemical Reactions

• The substances that undergo change are reactants (carbon and oxygen)

• New substances formed as a result of that change are called products

• REACTANTS PRODUCTS

Page 7: Chemical Reactions

• CARBON + OXYGEN CARBON DIOXIDE

• SIMPLIFY:C+O2 CO2

Page 8: Chemical Reactions

CHEMICAL EQUATION

• A CHEMICAL EQUATION IS A REPRESENTATION OF A CHEMICAL REACTION IN WHICH THE REACTANTS AND PRODUCTS ARE EXPRESSED AS FORMULAS.

Page 9: Chemical Reactions

CONSERVATION OF MASS

• THE LAW OF THE CONSERVATION OF MASS: MASS IS NEITHER CREATED NOR DESTROYED IN A CHEMICAL REACTION

• ALTHOUGH THE MASS OF THE COAL WAS REDUCED DURING THE REACTION, IT WAS NOT LOST

• THE MASS OF THE CARBON DIOXIDE CREATED WAS EQUAL TO THE MASS OF THE COAL THAT WAS LOST

Page 10: Chemical Reactions

BALANCING EQUATIONS

• ACCORDING TO THE LAW OF CONSERVATION OF MASS, EACH SIDE OF AN EQUATION MUST BE EQUAL

• H2 + O2 H2O

• WHAT IS WRONG WITH THIS EQUATION?

Page 11: Chemical Reactions

• TO BALANCE WE SIMPLY ADD COEFFICIENTS:–THE NUMBERS THAT APPEAR BEFORE THE

EQUATIONH2 + O2 H2O =

H2 + O2 2H2O

• WHAT IS WRONG WITH THIS EQUATION?• HOW CAN WE FIX IT?

Page 12: Chemical Reactions

ANSWER

• 2H2 + O2 2H2O

• WHICH MEANS:–TWO MOLECULES OF HYDROGEN

REACT WITH ONE MOLECULE OF OXYGEN TO YIELD TWO MOLECULES OF WATER

Page 14: Chemical Reactions

MATH SKILLS

• READ OVER THE MATH SKILLS EXAMPLES AND STEPS FOR BALANCING EQUATIONS ON PAGE 195

• THEN, TRY THE MATH PRACTICE 1-3

Page 15: Chemical Reactions

Balancing equations tutorials

• http://www.youtube.com/watch?v=RnGu3xO2h74

• http://www.youtube.com/watch?v=gskm-dfKv5g

Page 16: Chemical Reactions

BELLWORK

• BALANCE THE FOLLOWING CHEMICAL EQUATION:

• H2+O2 H2O

Page 17: Chemical Reactions

• WHAT ARE SOME UNITS OF MEASURE THAT YOU KNOW OF?

Page 18: Chemical Reactions
Page 19: Chemical Reactions

A. What is the Mole?

• A counting number (like a dozen)

• Avogadro’s number (NA)

• 1 mol = 6.02 1023 items

A large amount!!!!

Page 20: Chemical Reactions

Counting with Moles

• MOLE: (MOL) AN AMOUNT OF A SUBSTANCE THAT CONTAINS APPROXIMATELY 6.02 X 1023 PARTICLES OF THAT SUBSTANCE.

• KNOWN AS AVOGADRO’S NUMBER• A MOLE OF A SUBSTANCE GENERALLY

CONTAINS 6.02 X 1023 ATOMS, MOLECULES, OR IONS OF THAT SUBSTANCE

Page 21: Chemical Reactions
Page 22: Chemical Reactions

1 mole of hockey pucks would equal the mass of the moon!

A. What is the Mole?

• 1 mole of pennies would cover the Earth 1/4 mile deep!

1 mole of basketballs would fill a bag the size of the earth!

Page 23: Chemical Reactions
Page 24: Chemical Reactions

Molar Mass

• THE MASS OF DIFFERENT ELEMENTS ARE DIFFERENT, AS IS THEIR MOLAR MASS

• THE MOLAR MASS OF AN ELEMENT IN THE SAME AS ITS ATOMIC MASS EXPRESSED IN GRAMS

Page 25: Chemical Reactions

MASS OF COMPOUNDS• YOU CAN FIND THE MASS OF

COMPOUNDS BY ADDING THE MASS OF THEIR COMPONENTS

• A CARBON DIOXIDE MOLECULE:• CARBON= 12 GRAMS• OXYGEN = 16 GRAMS X 2 = 32 GRAMS• 12 + 32 = 44 GRAMS• CARBON DIOXIDE HAS A MOLAR MASS

OF 44 GRAMS

Page 26: Chemical Reactions

LETS TRY

• MOLAR MASS OF C• MOLAR MASS OF Fe• MOLAR MASS OF H2O

Page 27: Chemical Reactions

MOLE-MASS CONVERSIONS

• TO FIND HOW MANY MOLES ARE IN A CERTAIN # OF GRAMS OF AN ELEMENT OR MOLECULE:

• Y GRAMS x1/z grams= x moles

Page 28: Chemical Reactions
Page 29: Chemical Reactions

Example

• WE HAVE 55 GRAMS OF CO2

• HOW DO WE FIND HOW MANY MOLES WE HAVE?

• 55 X 1 mol/44 g• 1 mol/44 g=.02272727 mol• .02272727mol X 55 g = 1.25 mol CO2

Page 30: Chemical Reactions

BELLWORK

WHAT IS A MOLE?WHY DO WE USE MOLES?HOW MUCH IS ONE MOLE OF BARIUM IN GRAMS?CARBON DIOXIDE?WATER?

Page 31: Chemical Reactions

REVIEW:

• A mole is just a number, nothing else

• That number is 6.02 x 1023

• We use this number to make otherwise incredibly small numbers (such as the mass of an atom) easy to use in chemical formulas

Page 32: Chemical Reactions

Review

• There are two conversions we will do with moles:–Find how many moles there are in a

certain number of grams (mass) an element or molecule

–Find the the number of grams (mass) there are in a certain number of moles of an element or molecule

Page 33: Chemical Reactions

Two conversion factors

a) Grams b)1 Mol

1 Mol or Grams

How many grams, use conversion factor aHow many moles, use conversion factor b

Page 34: Chemical Reactions

Practice

• Suppose we have 55 grams of CO2

• How do we find how many moles of CO2 there are in 55 grams of CO2?

• Step 1: find the molar mass of CO2

44 grams/mole• Step 2: set up the equation

55 grams CO2 x 1 mol CO2 = ? mol CO2

44 grams CO2

Page 35: Chemical Reactions

• Step 3: Solve the equation55 grams CO2 x 1 mol CO2 = ? mol CO2 44 grams CO2

1/44= .022755 x .0227 = 1.25

There are 1.25 moles of CO2 in 55 grams of CO2

Page 36: Chemical Reactions

Flip it!

• Now, suppose we have 2.4 moles of sulfur.

• How do we find how many grams there are in 2.4 moles of sulfur?

• Step 1: Find the molar mass of sulfur.32.07 grams/mole

• Step 2: Set up the equation:2.4 moles x 32.07 grams S = ? Grams S

1 mol S

Page 37: Chemical Reactions

• Step 3: solve the equation:2.4 x 32.07 = 77 grams sulfer

There are 77 grams of sulfur in 2.4 moles of sulfur

Page 38: Chemical Reactions

Get into the groups I assigned the other day.

• Work on the worksheet together.• Do as many problems as you can.