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Worksheet 8 – Answers to Critical Thinking Questions The worksheets are available in the tutorials and form an integral part of the learning outcomes and experience for this unit. Model 1: The Gas Laws 1. Boyle’s Law: 2. Charles’ Law: 3. Avogadro’s Hypothesis:
4. (a) V = nRT !!
kB = nRT
(b) V = !"!
T kC = !"!
(c) V = !"!
n kA = !"!
5. R = !"!"= !.!!! !"# ×(!!.!"! !)
!.!!! !"# × (!"#.!" !) = 0.08206 atm L mol-1 K-1
The units arise directly from the equation: (atm × L) / (mol × K). 6. (a) 22.414 L corresponds to 0.022414 m3.
(b) R = !"!"= !.!"#$% ×!"! !" ×(!.!""#$# !!)
!.!!! !"# ×(!"#.!" !) = 8.314 Pa m3 mol-1 K-1
The units arise directly from the equation: (Pa × m3) / (mol × K).
Model 2: Partial Pressures 7. (a) 𝑃!!= 0.80 × 1.0000 atm = 0.80 atm
} Ptotal = (0.20 + 0.80) atm = 1.00 atm 𝑃!! = 0.20 × 1.0000 atm = 0.20 atm
(b) As density ρ = !!
and m = nM, ρ = !"!"
, the molar mass M = !"�!
:
P
V
T
V
n
V
M = !.!"#!$ !"# ! !"#!! !!! × !"# ! ×(!.!"# ! !!!)
(!.!!! !"#) = 29.00 g mol-1
(c) 𝑀!! = 28.02 g mol-1 and 𝑀!!= 32.00 g mol-1. If x is the percentage by mass of O2 then: 29.00 = 32.00x + 28.02(1 - x) Solving this gives x = 0.25 and so air is 25% O2 and 75% N2 by mass.
Exercises 1. At 15.0 m, P = 2.50 atm. V15.0 m = 2.40 L. 2. At 30.0 m, P = 4.00 atm. Vsurface = 20. L. It will burst. 3. Air caught in a cavity will try to expand as the pressure is reduced during ascent. If trapped, it may cause
severe pain or a perforated eardrum in the ear or very severe toothache in a tooth. 4. P35 °C = 209 atm.
5. The increasing pressure leads to an increase in the density, ρ = !"!"
. More air is held in the same volume so the density increases.
6. From question 7 in Model 2, 𝑃!! = 0.20 atm at the surface. At a depth of 10.0 m, Ptotal = 2.0 atm and so
𝑃!! = 0.40 atm. The increase in total pressure does not affect the percentage composition of the air. 7. If 𝑃!! = 1.6 atm then Ptotal = 8.0 atm. This corresponds to a depth of 70.0 m.
Model 3: Osmotic pressure
1. See below.
2. See above. 3. The pressure is higher on the side with the higher water level.
4. (i) 0.35 M (ii) 0.15 M (iii) 0.50 M 5. 1.00 M = 1.00 mol L-1 = 1.0 × 103 mol m-3
6. π = (1.0 × 103 mol m-3) × (8.314 J K-1 mol-1) × (298 K) = 2.5 × 106 Pa = 24 atm. Pretty big! Model 4: Osmotic pressure in biology 1. See below