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Chem. 31 – 3/11 Lecture
Announcements I• Exam 1
– Grading error on p. 3 (problem 4); was graded as though 10 pts for entire problem – not just part a)
– That was the reason for getting 96 pts total and giving everyone 4 additional points
– Average = 77• Cl lab report
– Due Today• Homework Set 2 – Turn in
Problem 2.1
100s 90s 80s 70s 60s 50s <500
2
4
6
8
10
12
14
16
Axis Title
Announcements II• Quiz 3 Today• Today’s Lecture – Chapter 7 “Advanced
Equilibrium Theory”– Why Equilibirum Theory Can Fail– Ionic Strength: What is it and how do we calculate it– Replacement Equations: Activity and Activity
Coefficients
Chapter 7“Adjustments” to Equilibrium Theory
• There are two areas where the general chemistry equilibrium theory can give wrong results:– When the solution has high
concentrations of ions– When multiple, interacting equilibria
occur– I had planned a demonstration, but due
to distance to class plus finding equipment, I’m skipping the demonstration this year
Demonstration – Slide 1
• Summary of Observation:– Two saturated solutions
of MgCO3 are prepared.– One is prepared in
water and the other is prepared in ~0.1 M NaCl.
– 5.0 mL of each solution was transferred (and filtered) into a beaker.
– 3.5 mL of 0.002 M HCl needed for saturated MgCO3 and 6.0 mL needed in 0.1 M NaCl
SaturatedMgCO3
SaturatedMgCO3 in NaCl(aq)
Demonstration – Slide 2
• Did the moles of HCl used match expectations? and Why did the solution containing NaCl need more HCl?– First Question:How many mL of HCl were expected?MgCO3(s) Mg2+ + CO3
2- Ksp = 3.5 x 10-8 T = 25°CKsp = 3.5 x 10-8 = [Mg2+][CO3
2-]since [Mg2+] = [CO3
2-] (assuming no other reactions), [CO32-] =
(3.5 x 10-8)0.5 = 1.87 x 10-4 Mn(HCl) = (2 mol HCl/mol CO3
2-)(1.87 x 10-4 mmol/mL)(5.0 mL) = 0.001875 mmol HCl
Calculate V(HCl) = 0.001875 mmol HCl/[HCl]= 0.001875 mmol HCl/0.002 mmol/mL = 0.935 mLActual V(HCl) > 1 mL
• ConclusionsIt takes more HCl than expected, so more CO3
2- dissolved than expected.
Also, the NaCl increased the solubility of MgCO3
Demonstration – Slide 3
• What was the affect of the NaCl?– More CO3
2- (and Mg2+) was found to dissolve in the 0.10 M NaCl
• Why?– The Na+ and Cl- ions stabilize CO3
2- and Mg2+ ions
Ionic Strength EffectsSpheres Surrounding Ions
Mg2+
Low Ionic Strength
CO32- H O
H
+d
HO
H
H O
H
Ion – dipole interaction
HO
H HO H
HO
H
Mg2+
CO32- H O
H
H O
H
HO
H
-d
High Ionic Strength
Na+
Stronger ion – ion interaction replaces ion - dipole
Cl-
HO H
Ionic Strength• Definition : m = 0.5*SCiZi
2
where i is an ion of charge Z and molar concentration C.
• But What is Ionic Strength– A measure which allows us to correct for
ion – ion effects• Examples:
– 0.10 M NaCl– 0.010 M MgCl2– 0.010 M Ce(SO4)2
Effects of Ionic Strength on Equilibria
• Equilibrium Equation Learned Previously:– for reaction A ↔ B, K = [B]/[A]
• Replacement Equation:– K = AB/AA – So what is AX?– AX is the activity of X– AX = gX[X], where gX = activity
coefficient– The activity coefficient depends on the
ionic strength
Determination of Activity Coefficients
• Use of Debye-Hückel Equation:
- where Zx = ion charge, ax = hydrated ion radius (pm)- useful for 0.0001 M < m < 0.1 M
• Can also use Table 7-1 for specific m value• Calculate g(Mg2+) at m = 0.050 M a(Mg2+) = 800
pm
3051
51.0log
2
x
xx
Z
Factors Influencing g
• Ionic Strength: as m increase, g decreases• Charge of Ion: a larger decrease in g
occurs for more highly charged ions• Size of Ion: Note: very small ions like Li+
actually have large hydrated spheresGamma Plots
0.00
0.20
0.40
0.60
0.80
1.00
1.20
0.00 0.02 0.04 0.06 0.08 0.10 0.12
Ionic Strength (M)
Act
ivit
y co
effi
cien
t
Li+
Ba2+
PO43-
Li+ Rb+
ion
Hydrated sphere
Ionic Strength Effects on Equilibria
Qualitative Effects• An increase in ionic strength shifts
equilibria to the side with more ions or more highly charged ions
• Example Problems: (predict the shift as m increases)– NH3(aq) + H2O(l) ↔ NH4
+ + OH-
– Cu2+ + 4OH- ↔ Cu(OH)42-
– 2HSO3- ↔ S2O3
2- + H2O(l)
– HSO4- ↔ SO4
2- + H+
Ionic Strength EffectsEffects on Equilibrium - Quantitative
• Calculate expected [Mg2+] in equilibrium with solid MgCO3 for cases both with and without NaCl.– Go to Board