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CHEG511 Advanced Reaction Engineering. S(Ch4)
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Ahmed Abdala
Department of Chemical EngineeringThe Petroleum InstituteAbu Dhabi, UAE
ππ =1
π
πππππ‘
= π ππππππ‘ππππ π€ππ‘βππ π‘βπ ππππππ ππ π£πππ’ππ π
Homogenous reactor type⦠Batch reactors⦠Steady state flow reactors⦠Unsteady state semibatch reactor
1
Fj
Consider the volume enclosed by the boundaries (system volume)
The mole balance of species j:
πΌπ β ππ’π‘ + πΊππππππ‘πππ = π΄πππ’ππ’πππ‘πππ
πππ‘π ππππππ€
ππ π intoπ‘βπ π π¦π π‘ππ
πππππ /π‘πππ
β
πππ‘π ππ ππππ€ππ π ππ’π‘ πππ‘βπ π π¦π π‘ππ
πππππ /π‘πππ
+
πππ‘π ππ πππππππ‘πππππ π ππ¦ πβπππππππππππ‘πππ π€ππ‘βπππ‘βπ π π¦π π‘ππ
πππππ /π‘πππ
=
πππ‘π ππ ππππ’ππ’πππ‘πππππ π π€ππ‘βπππ‘βπ π π¦π π‘ππ
πππππ /π‘πππ
πΉπ0 β πΉπ + πΊπ =πππ
ππ‘
The energy balance equation
πππ‘π ππβπππ‘ππππ€ πππ‘ππππππππ‘ππ π£πππ’ππ
π½ππ’ππ/π‘πππ
β
πππ‘π ππβπππ‘ππππ€ ππ’π‘ πππππππππ‘ππ π£πππ’ππ
π½ππ’ππ/π‘πππ
+
πππ‘π ππ πππππππ‘πππππ βπππ‘ ππ¦ πππππ‘ππππ€ππ‘βππ πππππππ‘ππ π£πππ’ππ
π½ππ’ππ/π‘πππ
=
πππ‘π ππππππ’ππ’πππ‘πππ ππ βπππ‘
π€ππ‘βππ πππππππ‘πππ£πππ’ππ
π½ππ’ππ/π‘πππ
Fj0
System volume
Gj
Constant density batch or flow reactor
β¦ ππ΄ = 1 βπΆπ΄
πΆπ΄0and dππ΄ = β
ππΆπ΄
πΆπ΄0
β¦πΆπ΄
πΆπ΄0= 1 β ππ΄ and dπΆπ΄ = βπΆπ΄0πππ΄
3
Flow Reactor
Batch Reactor
Gas phase and Constant and Tβ¦ π = π0 1 + ππ΄ππ΄
β¦ ππ΄ =πΆπ΄0βπΆπ΄
πΆπ΄0+ππ΄πΆπ΄and dππ΄ = β
πΆπ΄0 1+ππ΄
πΆπ΄0+ππ΄πΆπ΄2
β¦πΆπ΄
πΆπ΄0=
1βππ΄
1+ππ΄ππ΄and
dπΆπ΄
πΆπ΄0= β
1+ππ΄
1+ππ΄ππ΄2 πππ΄
β¦ Ξ΅π΄ =πππ΄=1βπππ΄=0
πππ΄=0
πππ΄
πΆπ΄0=
βππππΆπ0
πΆπ΄0ππ΄
π=
βπΆπ0ππ
π
4
Gas phase and variable and T
β¦ ππ΄ =1β
πΆπ΄0πΆπ΄
ππ0π0π0
1+ππ΄πΆπ΄0πΆπ΄
ππ0π0π0
β¦πΆπ΄
πΆπ΄0=
1βππ΄
1+ππ΄ππ΄
π0π0ππ0
β¦πΆπ
πΆπ΄0=
π
π+π
πππ΄
1+ππ΄ππ΄
π0π0
πππ΄
πΆπ΄0=
βππππΆπ0
πΆπ΄0ππ΄
π=
βπΆπ0ππ
π
5
A continuous stream of fluid enters a vessel at
temperature T0 and pressure 0, reacts there,
and leaves at T and .
a) A gaseous feed, T0 = 400 K, 0= 4 atm, CA0= 100,
CBO= 200, A + B 2 R , T = 300 K , = 3 atm, C A = 20 .
Find XA, XB, CB .
b) A gaseous feed, T0 = 1000 K, B= 5 atm, CA0= 100,
CBO= 200, A + B 5R, T = 400 K, = 4 atm, CA = 20.
Find XA,XB,CB.
6