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Chapter16 Solutions 16.1 Properties of Solutions

Chapter16 Solutions 16.1 Properties of Solutions

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Page 1: Chapter16 Solutions 16.1 Properties of Solutions

Chapter16 Solutions

16.1 Properties of Solutions

Page 2: Chapter16 Solutions 16.1 Properties of Solutions

Chemistry

Today we are learning to:-

1. Understand what is meant by solubility

2. Identify factors that affect solubility of a substance

Page 3: Chapter16 Solutions 16.1 Properties of Solutions

Types of Solutions

Solutions are a homogenous mixture of substances. Atoms, ions or molecules are

spread out evenly throughout another substance.

i. All three states of matter form solutions for example a solid may be

dissolved in another solid. Ex. Brass (zinc and copper alloy)

ii. Usually we think of liquids as forming solution. Ex. Salt/water solution

Some vocabulary you must know:

Solute: the substance that dissolves. Ex salt.

Solvent: the substance that does the dissolving. Ex. water.

Solution: the solute dissolved in the solvent forms this. Ex. Salt solution.

Solubility: describes how easily a solute will dissolve in a solvent

Soluble: it dissolves

Insoluble: it doesn’t dissolve

Page 4: Chapter16 Solutions 16.1 Properties of Solutions

Types of Solutions

How do you know you have a solution?

i. Homogeneous mixture

ii. Light passes straight through (not dispersed)

iii. May be colored

iv. Does not settle on standing

v. Doesn’t separate out when filtered

Page 5: Chapter16 Solutions 16.1 Properties of Solutions

Chapter 15&16 Solutions

16.1 Properties of Solutions

Page 6: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Factors Affecting Solubility

1. The type of solvent and solute

A.Ionic solids and polar molecules will dissolve in polar solvents but not in non polar ones. Ex. in the ionic solid NaCl(s), Na+ ions are attracted to the negative pole of water molecules and Cl- ions to the positively charged pole of water molecules.

B.Nonpolar molecules will dissolve in nonpolar solvents but not in polar ones such as water Ex. Oils and fats are nonpolar. The will not dissolve in water (polar solvent) but will dissolve in gasoline (nonpolar solvent)

Like dissolves like

Page 7: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Page 8: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Factors Affecting Solubility

2. Temperature

Usually as temperature increases substances become more soluble in water.

• Exceptions to this rule include gases, which come out of solution as temperature increases.

Page 9: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Factors Affecting Solubility

3. Pressure

Usually has no effect on solubility of solids or liquids.

• Solubility of gases increases as pressure increases.

• Ex. Soda water has a lot of carbon dioxide gas dissolved in it as it is under high pressure. When a can is opened the pressure in the can drops and the carbon dioxide escapes as bubbles

Now try review questions 1-12 on page 120 and 121

Page 10: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Solubility Graphs

1. The type of solvent and solute

A.Ionic solids and polar molecules will dissolve in polar solvents but not in non polar ones. Ex. in the ionic solid NaCl(s), Na+ ions are attracted to the negative pole of water molecules and Cl- ions to the positively charged pole of water molecules.

B.Nonpolar molecules will dissolve in nonpolar solvents but not in polar ones such as water Ex. Oils and fats are nonpolar. The will not dissolve in water (polar solvent) but will dissolve in gasoline (nonpolar solvent)

Like dissolves like

Page 11: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Solubility Graphs (Table G)

• Shows number of grams of substance that can be dissolved in 100g of water at a given temperature.

• The line shows the maximum amount of that substance that can dissolve at that temperature.

0 10 20 30 40 50 60 70 80 90 100

Solubility vs. Temperature for Solids

Sol

ubili

ty (

gram

s of

sol

ute/

100

g H

2O)

KI

KCl

20

10

30

40

50

60

70

80

90

110

120

130

140

100

NaNO3

KNO3

HCl NH4Cl

NH3

NaCl KClO3

SO2

gases

solids

Look at the solubility curve for potassium nitrate only

Page 12: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Solubility Graphs (Table G)

0 10 20 30 40 50 60 70 80 90 100

Solubility vs. Temperature for Solids

Sol

ubili

ty (

gram

s of

sol

ute/

100

g H

2O)

20

10

30

40

50

60

70

80

90

110

120

130

140

100

KNO3

Where the temperature is 40C

Below the curve the solution is unsaturated. This means we could dissolve more KNO3

On the curve the solution is saturated. This means we are at the maximum mass of KNO3 that will dissolve at that temperature

Above the curve the solution is supersaturated. The solution is unstable. Addition of a single crystal will cause rapid crystalization

Page 13: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Solubility Graphs (Table G)

0 10 20 30 40 50 60 70 80 90 100

Solubility vs. Temperature for Solids

Sol

ubili

ty (

gram

s of

sol

ute/

100

g H

2O)

20

10

30

40

50

60

70

80

90

110

120

130

140

100

KNO3

Where the mass of KNO3 is 60 g/100g H2O

Unsaturated solution cools

On the curve the solution is saturated. This means we are at the maximum mass of KNO3 that will dissolve at that temperature

The solution is supersaturated. The solution is unstable. Addition of a single crystal will cause rapid crystalization

Page 14: Chapter16 Solutions 16.1 Properties of Solutions

Ex1:What substance has a solubility of 73 g/100 cm3 of water at a temperature of 90ºC ?

NH4Cl (ammonium chloride)

Ex2:At what temperature will potassium nitrate have a solubility of 95 g/100 cm3 ?

55ºC

Ex3:30 grams of potassium nitrate has been added to 100 cm3 of water at a temperature of 50ºC. How many additional grams of solute must be added in order to make it saturated?

Page 15: Chapter16 Solutions 16.1 Properties of Solutions

From graph you can see that the solubility for potassium nitrate at 50ºC is 84 grams

So we need to add 84-30 = 54g of potassium nitrate.

Ex3:30 grams of potassium nitrate has been added to 100 cm3 of water at a temperature of 50ºC. How many additional grams of solute must be added in order to make it saturated?

Page 16: Chapter16 Solutions 16.1 Properties of Solutions

Exothermic and Endothermic Processes

17.1

Now try review questions 13-23 on page 123

Page 17: Chapter16 Solutions 16.1 Properties of Solutions

END OF SHOW