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Chapter 9 “Heat” Honors Physics

Chapter 9 “Heat”

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Honors Physics. Chapter 9 “Heat”. Temperature. Adding or removing energy changes the temperature. Temperature is the average KE of the atoms and molecules present. High avg. KE = high temp. We use relative scales: ºF , ºC and absolute scales: K. Temperature. - PowerPoint PPT Presentation

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Page 1: Chapter 9 “Heat”

Chapter 9 “Heat”

Honors Physics

Page 2: Chapter 9 “Heat”

Temperature• Adding or removing energy changes

the temperature.• Temperature is the average KE of the

atoms and molecules present. High avg. KE = high temp.

• We use relative scales: ºF , ºC and absolute scales: K

Page 3: Chapter 9 “Heat”

Temperature• Internal energy (ΔU) is the

energy associated with atomic motion and is proportional to the substance's temperature.

• Temperature is changed by adding or removing energy.

Page 4: Chapter 9 “Heat”

Temperature

Celsius-Fahrenheit Temperature Conversions Tf = 9/5 Tc + 32.0

Celsius-Kelvin Temperature ConversionsT = Tc + 273.15

Page 5: Chapter 9 “Heat”

Concept Check

The lowest outdoor temperature ever recorded on Earth is -128.6°F,

recorded at Vostok Station, Antarctica in 1983. What is this temperature on the Celsius and

Kelvin scales?

Page 6: Chapter 9 “Heat”

Concept Check

-89.2° C, 184 K

Page 7: Chapter 9 “Heat”

Concept Check

The temperatures of one northeastern state range from 105° F in the summer to -25°F in the winter.

Express this temperature range in degrees Celsius and in kelvins.

Page 8: Chapter 9 “Heat”

Concept Check

41°C to -32°C, 314 K to 241 K

Page 9: Chapter 9 “Heat”

Concept Check

A pan of water is heated from 23°C to 78°C. What is the change in its temperature on the Kelvin and

Fahrenheit scales?

Page 10: Chapter 9 “Heat”

Concept Check

55 K, 99°F

Page 11: Chapter 9 “Heat”

Concept Check

Liquid nitrogen is used to cool substances to very low temperatures.

Express the boiling point of liquid nitrogen (77.34 K at 1 atm of

pressure) in degrees Celsius and in degrees Fahrenheit.

Page 12: Chapter 9 “Heat”

Concept Check

-195.81°C, -320.5°F

Page 13: Chapter 9 “Heat”

Heat• Heat is the energy transferred

between objects due to the difference in their temperatures.

• Heat will naturally go from objects of high KE to objects of low KE. To go in the opposite direction requires work.

Page 14: Chapter 9 “Heat”

Thermal (Heat) Units• We’ll be mostly using joules (J) or

calories (cal). However, you should be aware that there are others (p 307).

• 1 calorie is equal to the amount of energy required to heat 1 gram of water from 4º to 5 ºC.

• 1 cal = 4.184 J

Page 15: Chapter 9 “Heat”

Total energy is conserved.• Conservation of energy states that

the sum of the change in the potential energy and the change in kinetic energy and the change in internal energy must equal zero.

PE + KE + U = 0

Page 16: Chapter 9 “Heat”

Concept Check

Consider an arrangement similar to the one used to demonstrate energy

conservation on p.310. If a total mass of 11.5 kg falls 6.69 m and all

of the mechanical energy is converted to internal energy, by how much will the internal energy of the

water increase?

Page 17: Chapter 9 “Heat”

Concept Check

755 J

Page 18: Chapter 9 “Heat”

Concept CheckA worker drives a 0.500 kg spike into

a rail tie with a 2.50 kg sledgehammer. The hammer hits the

spike with a speed of 65.0 m/s. If one-third of the hammer's kinetic

energy is converted to the internal energy of the hammer and spike, how much does the total internal

energy increase?

Page 19: Chapter 9 “Heat”

Concept Check

1.76 x 103 J

Page 20: Chapter 9 “Heat”

Concept Check

A 3.0 x 10-3 kg copper penny drops a distance of 50.0 m to the ground. If 65% of the initial potential energy goes into increasing the internal

energy of the penny, determine the magnitude of that increase.

Page 21: Chapter 9 “Heat”

Concept Check

0.96 J

Page 22: Chapter 9 “Heat”

Concept Check

The amount of internal energy needed to raise the temperature of

0.25 kg of water by 0.2ºC is 209.3 J. How fast must a 0.25 kg baseball

travel in order for its kinetic energy to equal this internal energy?

Page 23: Chapter 9 “Heat”

Concept Check

41 m/s

Page 24: Chapter 9 “Heat”

Calorimetry• We can calculate the amount of the

change in internal energy through calorimetry.

• The equation Q = mct is used.• Q = internal energy change• m = mass• Cp = specific heat (unique)t = change in temperature.

Page 25: Chapter 9 “Heat”

Heat lost = Heat gained• In an insulated situation (no heat

escapes into the surroundings):Q lost = Q gained

•m1cp1t1 = -m2cp2t2

Page 26: Chapter 9 “Heat”

Calorimetry• Generally, we use water as the

substance that gains the heat since the specific heat of water is known.

Page 27: Chapter 9 “Heat”

Concept Check

What is the final temperature when a 3.0 kg gold bar at 99ºC is dropped

into 0.22 kg of water at 25ºC? (Use the table on p.314.)

Page 28: Chapter 9 “Heat”

Concept Check

47ºC

Page 29: Chapter 9 “Heat”

Concept Check

A 0.225 kg sample of tin initially at 97.5ºC is dropped into 0.115 kg of

water. The initial temperature of the water is 10.0ºC. If the specific heat capacity of tin is 230 J/kg*ºC, what is the final equilibrium temperature of

the tin-water mixture?

Page 30: Chapter 9 “Heat”

Concept Check

18ºC

Page 31: Chapter 9 “Heat”

Concept Check

Brass is an alloy made from copper and zinc. A 0.59 kg brass sample at

98.0ºC is dropped into 2.80 kg of water at 5.0ºC. If the equilibrium temperature is 6.8ºC, what is the specific heat capacity of brass?

Page 32: Chapter 9 “Heat”

Concept Check

390 J/kg*ºC

Page 33: Chapter 9 “Heat”

Concept Check

A hot, just minted copper coin is placed in 101 g of water to cool. The

water temperature changes by 8.39ºC, and the temperature of the

coin changes by 68.0ºC. What is the mass of the coin?

Page 34: Chapter 9 “Heat”

Concept Check

135 g

Page 35: Chapter 9 “Heat”

Phase Changes• Phase changes occur when an

object goes from one phase of matter to another.

• When an object is going through a phase change, added energy is used to make the change without raising the temperature. This is latent heat.

Page 36: Chapter 9 “Heat”

Equations for Phase Changes.• During heating (temperature

change) use Q = mct • During phase changes use heat of

fusion or heat of vaporization.• Q = mLf or Q = mLv • L = latent heat (unique)

Page 37: Chapter 9 “Heat”

Heating curve of water• Starting with ice at -4 º C and

going to steam at 120 ºC.

Adding energy

ice

liquid

steam

0 º C

100 º C

-4 º C

120 º C

Page 38: Chapter 9 “Heat”

Types of Heat Transfer• Thermal Conduction-requires objects to

touch in order to transfer heat.• Convection-requires the motion of a

fluid between objects in order to transfer heat.

• Radiation-energy moves in the form of electromagnetic radiation in order to transfer heat.

Page 39: Chapter 9 “Heat”

Conduction vs insulation• The ability to conduct heat is a

gradient from good conductors such as metals to poor conductors such as ceramics or plastics. Poor conductors are good insulators. An insulator doesn’t actually inhibit conduction, it is just a poor conductor.