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Chapter 8 Alpha Decay Introduction and some other properties of α-dec The simple theory of Coulomb barrier penetratio The angular momentum barrier

Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

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Page 1: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Chapter 8

Alpha Decay

◎ Introduction and some other properties of α-decay

● The simple theory of Coulomb barrier penetration

◎ The angular momentum barrier

Page 2: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

§ 8-1 Introduction and some other properties of α-decay

1. The theory of α-decay is an application of simple quantum mechanics and its presentation will not, in the simple approach that we shall adopt, add much to our knowledge of nuclear structure.

2. We should answer the following question: why do the mean lives of α -emitting nuclei vary so dramatically

RaTh 22888

23290from τ= 2.03 × 1010 years for

to τ= 4.3 × 10-7 seconds for PbPo 20882

21284

This is a 24 orders of magnitude variation in transition rates !!

Page 3: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

3. There are many unstable heavy nuclei in nature. They tend to give away excessive energies and charges by emitting α- particles. Only a few will undergo nucleon emission.

4. We need to find out a reasonable explanation of why the α- particle decay turns out to be the preferable choice for a decay process to occur in unstable heavy nuclei.

5. An α- particle being kicked out from an unstable nucleus is basically the effect of Coulomb repulsion. An α- particle is much less massive than a parent nucleus and has a more stable structure with large binding energy (EB = 28.3 MeV). A heavy nucleus with too many protons can reduce some Coulomb repulsion energy by emitting an α- particle.

Page 4: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Emitted Particle

Energy Release (MeV)

Emitted Particle

Energy Release (MeV)

n -7.26 4He +5.41

1H -6.12 5He -2.59

2H -10.70 6He -6.19

3H -10.24 6Li -3.79

3He -9.92 7Li -1.94

Energy Release (Q value) for Various Modes of Decay of 232U

Page 5: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

The energy-level diagram for two nucleic connected by α-decay

The energy-level diagram for the α-decay of 242Pu

He)4,2(),( 42 AZAZ 2)]4,2()4,2(),([ cMAZMAZMQ

α-particle decay

The available energy Qα goes into the kinetic energies of the α-particle and of the recoil of the daughter nucleus.

If Qα > 0, α-decay is energetically possible; however, it may not occur for other reasons.

Page 6: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

We now have to apply the energy conditions for α-decay to occur in real nuclei and to find where in the periodic table it is expected to occur.

Rewrite the definition of Qα in terms of the nuclear binding energies.

),()4,2()4,2( AZBBAZBQ

He)4,2(),( 42 AZAZ

Thus α-decay is energetically allowed if

A

B

A

ABA

A

B

AZBAZBB

d

)/(d4

d

d4

)4,2(),()4,2(

A

B

A

B

AA

A

A

A

B

A

B

AA

A

BA

AA

B

d

d

d

d

d

d

d

d

d

d

(1)

(2)

Page 7: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

A

A

B 3107.743.28 which is AA

B 3107.7075.7

Above A ≈ 120, d(B/A)/dA is about −7.7×10−3 MeV. Now B(2,4), the helium nuclear binding energy, is 28.3 MeV, so the critical A must satisfy the following relation:

A = 151

A

B

A

ABA

A

B

AZBAZBB

d

)/(d4

d

d4

)4,2(),()4,2(

(3)

Above this A the inequality of equation (3) is satisfied by most nuclei and α-decay becomes, in principle, energetically possible. In fact from A = 144 to A = 206, 7 α-emitters are known amongst the naturally occurring nuclides.

Page 8: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

From A = 144 to A =206, there are 7 α-emitters of naturally occurring nuclides. When α-emitters are found in this range of A, the energies of the emitted α-particle are normally less than 3 MeV. It is known that the lower the energy release the greater is the lifetime. Their existence implies mean lifetimes comparable to or greater than the age of the earth (about 4 × 109 years). Most nuclei in this range on the line stability may be energetically able to decay by α-emission. They do not do so at a detectable level because the transition rate is too small.

From A = 144 to A =206

Most of the heavy nuclei to be found on earth were probably produced in one or more supernova explosions of early massive stars. Such explosions can produce very heavy nuclei including trans-uranic elements (Z > 92) and their subsequent decay by α-emission will take them down the periodic table in steps of ΔA = −4. Each α-decay increases the ration N/Z until a β- decay intervenes to restore the nucleus closer to the line of stability.

Above Z = 82 many naturally occurring α-emitters are found, many with short lives.

Why are they to be found when their lifetime is so short?

Above Z = 82 (A > 206)

Page 9: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

α- emitter Natural Abundance Mean life τ144Nd84 23.8% 1.04×1016 years

147Sm125 15.1% 2.74×1011 years

190Pt112 0.0127% 8.51×1011 years

192Pt114 0.78% ≈ 1015 years

209Bi126 100% 3×1017 years

232Th142 100% 2×1010 years

238U146 99.2739% 6.3×109 years

7 α-emitters of naturally occurring nuclides.

The age of the earth is ~ 4×109 years.

Page 10: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Very long lifetime comparable to the age of the earth

Relatively long lifetime

Fast-decaying daughter nuclei are in secular equilibrium.

Page 11: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Early observations on α-decay established that, for a unique source, the majority of the emitted α-particles had the same kinetic energy.

For each α-emitter, this kinetic energy, Tα, is a fraction MD/(MD+Mα) of Qα where MD and Mα are the masses of the daughter nucleus and of an α-particle respectively.

From the previous transparency we see the values of Qα and the mean life of the principal α-emitter in one of the naturally occurring radioactive series.

It is clear that that transition rates (ω) are a strong function of the kinetic energy.

CRB 1010 loglog

The empirical rule connection the two is known as the Geiger-Nuttal rule (1911).

R α is the range in air at 15ºC and 1 atmosphere pressure of the α-particles emitted in a decay with transition rate ω. (4)

Page 12: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

About 6 MeV which is the nucleon

separation energy

neutron proton

Effective potential for an α-particle

Z = 90, A ≈ 236

Page 13: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

For heavy nuclei, the nucleon separation energy is about 6 MeV, so the nucleons fill energy levels up to about 6 MeV below zero total energy.

If two protons and two neutrons from the top of the filled levels amalgamate into an α-particle, the binding energy of 28.3 MeV is sufficient to provide the four separation energies and leave the α-particle with positive energy of about 4 MeV.

Now we have an α-particle with positive energy leaving it in a potential well. The effective potential is the result of nuclear and Coulomb repulsion potentials.

An α-particle is able to tunnel through the “Coulomb barrier” and become free. The tunneling probability can be calculated quantum mechanically.

6 MeV

Page 14: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

This is the effective mechanical potential for an α-particle as a function of distance between the center of the α-particle and the center of the system which is the parent nucleus less the α-particle.

The whole range of potential is separated into three regions:

Region I At distances less than R, approximately the nuclear radius, the α-particle is in a potential well of unspecified depth but representing the effect of the nuclear binding force on the

α-particle.

Region II At a distances R this potential becomes positive and reaches a maximum value of U(R) = zZe2/4πε0R, where z = 2 and Z is the atomic number of the remaining nucleus.

Region III At a distances greater than R the potential is Coulomb, U(r) = zZe2/4πε0r.

Page 15: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

If the parent nucleus Z+2, is energetically capable of emitting an α-particle of kinetic energy T α, then there are two possibilities:

(1). T α > U(R): the α-particle, if inside the nucleus, is free to leave and will do so almost instantaneously. (That means in a time comparable to the time taken for the α-particle to cross the nucleus, which is

less than 10-21 second.)

(2). T α < U(R): classically the α-particle is confined to the nucleus. Quantum mechanically it is free to tunnel through the potential barrier, emerging with zero kinetic energy at radius b (where b = zZe2/4 πε 0 T α, z = 2) and to move to large r, where it will have the full kinetic energy T α.

We need to find the barrier penetration probability.

Page 16: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

First we consider a simple square potential barrier with height U and thickness t. The whole area can be separated into three parts.

tr

tr U

r

rV

,

,

- ,

0

0

00

)( (5)

The wave function of the α-particle must satisfy the Schrödinger’s equation.

EuurVdr

ud

m )(

2 2

22(6)

m is the mass of the α-particleu is the wave function of the α-particle [u = u (r)]E is the energy of the α-particle

Page 17: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Solutions of the Schrödinger’s equation in three different sections:

where T is the kinetic energy of the α-particle and p is its

linear momentum.

(I) pmT

kBeeu irikr 21 ,

(II) )(2

2

TUmKeeu KrKr

,

(III) pmT

kDeCeu irikr 23 ,

(7)In the section (III) there is no reflection wave therefore D = 0. The probability of transmission is then proportional to |C|2.

Page 18: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Since the wave function u(r) and its first derivative du/dr are continuous on boundaries we are able to summarize the following equations:

rr = 0 r = t

On the boundary r = t, (1) )()( 32 tutu trtr dr

du

dr

du

32

We may havetKike

K

ikC )(12

tKike

K

ikC )(12

(8)

Page 19: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

rr = 0 r = t

On the boundary r = 0, (2) )0()0( 32 uu 0

3

0

2

rr dr

du

dr

du

We may have (9) B1 )(1 ik

KB

Page 20: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Combine four equations from (8) and (9) we have the following relation:

KtKtikt e

ik

K

K

ike

ik

K

K

ikCe 1111

4(10)

In evaluating the quantity K )(2 TUm

K

But t ~ several fm

-1fm 2.3~K MeV 5 MeV, 60 TU

The value of e-Kt is extremely small and can be neglected.

Ktikt eik

K

K

ikCe 11

4

(11)

Page 21: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier
Page 22: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

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Page 23: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier
Page 24: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier
Page 25: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier
Page 26: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Tα (MeV) lnTα 3.6999 - 4.6791(Tα)-1/2

4.0 1.38629 1.36035

4.5 1.50408 1.49415

5.0 1.60948 1.60734

5.5 1.70475 1.70473

6.0 1.79176 1.78967

6.5 1.87180 1.86461

7.0 1.94591 1.93137

Page 27: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

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Page 28: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

This is a plot of lnω against the values of Z(M/MαQα)1/2 for the ground state to ground state transitions of many of the naturally occurring and man-made α-active elements.

There are deviations from a single straight line but there is a general tendency for the points to cluster near a linear relation between lnω and Z(M/MαQα)1/2 with a slope somewhat less steep than ̶ 3.97 MeV1/2. The deviation is due to the neglect of the term f’ of equation (19).

Thus we have a theory which goes some way towards adequately explaining the range of these mean lives.

Page 29: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

§ 8-3 The angular momentum barrier

There is an important effect in all processes involving nuclear and particle reactions and decays. We want to introduce the idea in the context of α-particle decay.

Consider the α-particle decay:

He),()4,2( 42 AZAZ

Suppose the parent and daughter nuclei have spins of quantum number jp and jD.

The total angular momentum must be conserved. If jP≠jD the α-particle must eme

rge with relative orbital angular momentum (with quantum number l) with respect to the recoiling daughter nucleus.

With the zero spin of the α-particle the conservation of the vector of angular momentum requires that:

PDPD jjljj (20)

Page 30: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

PDPD jjljj

The quantum number l must be zero or a positive integer.

Let us now write down the Schrödinger equation for an α-particle (z = 2) leaving a recoiling nucleus (Z,A). For r > R

)()(4

)(2 0

22

2

rQrr

zZer

M

Here M is the reduced mass of the system. We do the usual separation of variables: let

),(cos)()( mlYrRr

The spherical harmonic Y defines the orbital angular momentum l and its z-component m for the outgoing α-particle.

(20)

(21)

(22)

Page 31: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Putting R (r) = U(r)/r and substituting into equation (21) the radial function U(r) should satisfy the following equation:

)()(2

)1(

4d

)(d

2 2

2

0

2

2

22

rUQrUMr

ll

r

zZe

r

rU

M

(23)

r

zZe

0

2

4

2

2

2

)1(

Mr

ll

The Coulomb barrier

The angular momentum barrier

It is clear that the total barrier is harder to penetrate and the transition rate will be lower (and the mean life longer) than with the Coulomb barrier alone.

Page 32: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

Blatt and Weisskopf (1952) have given some figures for the suppression factors in α-decay transition rates due to the angular momentum barrier.

l 0 1 2 3 4 5 6

ωl/ω0 1.0 0.7 0.37 0.137 0.037 0.0071 0.0011

Values of the suppression factor due to the angular momentum barrier in an α-decay for which Z = 86, Tα = 4.88 MeV, R = 9.87 fm

Note that we have assumed that the particle is emerging from the nucleus.

However, both the Coulomb and angular momentum barrier effects can apply also to particles entering the nucleus.

And this is relevant to the rates of nuclear reactions where the first step is the penetration into the nucleus by an incident particle.

Page 33: Chapter 8 Alpha Decay ◎ Introduction and some other properties of α-decay ● The simple theory of Coulomb barrier penetration ◎ The angular momentum barrier

~ The End ~

Rosetta stone,

offered the first step for modern historians to decipher the ancient Egyptian’s written scripts.