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8/3/2019 Chapter 4_part 2
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Line Parameters
An electric transmission line is characterized by fourparameters:
series resistance
series inductance
shunt capacitance
shunt conductance
The inductance is the dominant series element due toits effect on power transmission capacity and voltage
drop It is associated with the induced voltage caused by the
change in flux that affect the conductivity and exchangecurrents in the circuit
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The capacitance is the dominating shunt element and itrepresents a source of reactive power.
Mvars VL2, the importance of the shunt capacitance
parameter increases with an increase in the magnitudeof the operating voltage.
The series resistance and shunt conductance are theleast important parameters as their effect on thetransmission capacity is relatively very less.
However, the series resistance completely determinesthe real power transmission loss and its presence mustbe considered.
Line Parameters
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The shunt conductance accounts for the resistiveleakage current
The leakage current:
flows along the insulator strings and ionised pathways
in the air varies appreciably with changes in the weather,
atmospheric humidity, pollution and salt content
The effect of the shunt conductance under normal
operating conditions is usually neglected Consider only three parameters for the development of
a transmission line model for use in power systemstudies
Line Parameters
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Line Resistance
Resistance causes power loss in a transmission line.
Direct current resistance Rdcis given as:
Where = conductor resistivity in -m
l = conductor length in m
A = conductor cross-sectional area in m2
A
lR
dc
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The conductor resistance affected by three factors:frequency, spiraling, and temperature.
When AC flows in a conductor, current distribution is notuniform over the conductor cross-sectional area
current density is greatest at the surface of the conductor(skin effects)
Thus, at 60 Hz, the ac resistance is about 2% higherthan DC resistance.
Stranded conductor is spiraled, each strand is longerthan the finished conductor this results a slightlyhigher resistance than the value calculated usingformula:
Line Resistance
A
lRdc
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Power losses cause a rise in temperature of the lineconductors.
The resistance of a conductor also depends on itstemperature.
Resistance Rt1 of a conductor at t10C is obtained fromthe relation:
where R0
= resistance of conductor at 00C
0 = temperature coefficient of the conductor at 00C
Line Resistance
11 001 tRRt
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The conductor resistance increase as temperatureincreases.
The resistance Rt2of a conductor at temperature t20C
can be found out from the expression:
Line Resistance
10
20
1
2
/1
/1
t
t
R
R
t
t
OR
1
2
1
2
tT
tT
R
R
t
t
1
2
12
tT
tTRR
tt
Where T = 1/0 temperature
constants
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Values of T for certain types of conductor:
Aluminium = 228
Annealed hard drawn copper = 234.5
(100% conductivity) Hard drawn copper = 241
(97.3% conductivity)
The conductor resistance is best determined from
manufacturers data.
Line Resistance
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Line Conductance
Under normal operating conditions, the effect of shuntconductance, G, is usually neglected because it isnegligible.
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Line Inductance
The inductance of a conductor is defined as the fluxlinkages per unit current in it, given by:
Flows of alternating current in conductor will change theflux which links the conductor
This flux consist of two: internal flux and external flux
Internal flux due to the current inside the conductor External fluxdue to conductors current and due to the
current of other conductors in the vicinity
Henry
I
NL
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The inductance due to internal flux internal inductance,Lin
The inductance due to external flux externalinductance, L
ex
The total inductance:
Line Inductance
exin LLL
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Line Inductance
Internal Inductance
Figure A shows the crosssection of a long cylindricalconductor with radius randcarrying a current Iamperes.
Assume the return path of thecurrent is far away does noteffect the magnetic field of theconductor
Therefore, we can assume thatthe magnetic flux lines to beconcentric with the conductor
dxxr
Figure A
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Line Inductance
The magnetic field intensity atthat distance x m is given by:
where IX = the current in dx2x = the length of the flux
path
Assuming N=1, then:
dxxr
Figure A
mATx
NIH XX /
2
x
IHx
X
2 (1)
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Line Inductance
IX = current density x areaenclosed
=
Substitute 2 in 1:
The flux density is given as:
Where =r0 = permeability
dxxr
Figure A
AIr
xx
r
I2
2
2
2
(2)
mATr
xI
xI
r
xHX /
224
12
2
2
2
2/
2mwb
r
xIHB Xx
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Line Inductance
The flux, d is given as:
Where Ax = the elemental area
normal to the flux path. Consider 1 m length of the
conductor, then the flux, dx isgiven as:
The flux linkages per meterlength of conductor is given as:
dxxr
Figure A
xxx ABd
wbdxr
xI
dxBd xx 22)1(
2
4
3
2
2
/
2
mWbTdx
r
Ixd
r
xd xx
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Line Inductance
The internal flux linkages isgiven as:
Thus, the internal inductancesis given as:
If relative permeability, r = 1and 0 = 4 x 10
-7 H/m, then:
dxxr
Figure A
mWbTI
dxr
Ixr
inx /82
0
4
3
Henry
I
L rinin
88
0
mHLin /10
2
1 7Internal inductance
independent of conductordimension
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External Inductance
Assume the flux lines betweenA1 and A2 lie within theconcentric cylindrical surfacepassing A1 and A2
The magnetic field intensity ata distance x meters from thecenter of the conductor is:
The flux density BX is given by:
Line Inductance
dx
x
D1
D2
A1
A2
Figure B
mATx
I
HX /2
2/
2
mWb
x
IHB XX
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The flux d in the tubularelement of thickness dx metersis (for an axial length 1 m):
The flux linkage for the solidconductor (assume N=1) is:
Line Inductance
dx
x
D1
D2
A1
A2
Figure B
mWbdx
x
IABd XXx /
2
1
212 ln
22
2
2
1DDIdx
xI
dxx
Idd
D
D
X
XX
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The external inductance isgiven as:
We take = 0 = 4 x 10-7 H/m
because outside theconductor, the medium is air(r = 1).
Line Inductance
dx
x
D1
D2
A1
A2
Figure B
1
27
1
20 ln102ln2 D
D
D
D
IL X
ex t
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r
D
Line Inductance
The total inductance for asingle conductor A is the sumof its internal and externalinductance which is given as:
'ln102ln102
ln1
ln102
lnln102
ln
4
1102
ln102102
1
ln102
102
1
7
4/1
7
4/1
7
4/17
7
77
7
7
r
D
re
D
r
D
e
r
De
r
D
r
DLLL
r
DL
L
ex tin
ex t
in
A
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D
1 2
r1 r
2
mH
r
DLLL /
'
ln1047
21
Inductance for Single Phase 2 WireLine
kmmH
r
DL /
'
log921.0OR
The inductance in line 1 is given as:
The inductance in line 2:
The total inductance value:
mHr
DL /
'ln102
1
7
1
mHrDL /ln102
'
2
72
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Example 4.1
Inductance for Single Phase 2 WireLine
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Exercise (Single Phase Trans. Line)