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C H E M I S T R Y Chapter 4 Reactions in Aqueous Solution

Chapter 4 Reactions in Aqueous Solution

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Chapter 4 Reactions in Aqueous Solution. HCl( aq ) + H 2 O( aq ). HCl( aq ). HA( aq ). H 3 O 1+ ( aq ) + Cl 1- ( aq ). H 1+ ( aq ) + A 1- ( aq ). H 1+ ( aq ) + Cl 1- ( aq ). Acids, Bases, and Neutralization Reactions. - PowerPoint PPT Presentation

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Page 1: Chapter 4 Reactions in Aqueous Solution

C H E M I S T R Y

Chapter 4Reactions in Aqueous Solution

Page 2: Chapter 4 Reactions in Aqueous Solution

H3O1+(aq) + Cl1-(aq)HCl(aq) + H2O(aq)

Acid (Arrhenius): A substance that dissociates in water to produce hydrogen ions, H1+:

H1+(aq) + A1-(aq)HA(aq)

In water, acids produce hydronium ions, H3O1+:

H1+(aq) + Cl1-(aq)HCl(aq)

Page 3: Chapter 4 Reactions in Aqueous Solution

Ammonia, commonly called “ammonium hydroxide” is a base:

M1+(aq) + OH1-(aq)MOH(aq)

Na1+(aq) + OH1-(aq)NaOH(aq)

NH41+(aq) + OH1-(aq)NH3(aq) + H2O(aq)

Base (Arrhenius): A substance that dissociates in water to produce hydroxide ions, OH1-:

Page 4: Chapter 4 Reactions in Aqueous Solution

Weak acids and weak bases are weak electrolytes.Strong acids and strong bases are strong electrolytes.

Page 5: Chapter 4 Reactions in Aqueous Solution

MA + H2OHA + MOH

These acid-base neutralization reactions are double-replacement reactions just like the precipitation reactions:

or

MA + HOHHA + MOH

WaterAcid Base Salt

Page 6: Chapter 4 Reactions in Aqueous Solution

Write the chemical formulas of the products (use proper ionic rules for the salt).

1.

Write the molecular, ionic, and net ionic equations for the reaction of aqueous HBr and aqueous Ba(OH)2.

H2OHBr(aq) + Ba(OH)2(aq) + BaBr2

SaltAcid Base Water

Page 7: Chapter 4 Reactions in Aqueous Solution

Write the molecular, ionic, and net ionic equations for the reaction of aqueous NaOH and aqueous HF.

Write the chemical formulas of the products (use proper ionic rules for the salt).

1.

SaltAcid Base Water

H2OHF(aq) + NaOH(aq) + NaF

Page 8: Chapter 4 Reactions in Aqueous Solution

ExamplesPredict the product and write a molecular

equation, ionic equation and net ionic equation for the following reactionsK2CO3(aq) + NiCl2(aq)

HNO3(aq) + LiOH(aq)

HCN(aq) + Mg(OH)2

Page 9: Chapter 4 Reactions in Aqueous Solution

2Fe2O3(s)4Fe(s) + 3O2(g) Rusting of iron:an oxidation of Fe

4Fe(s) + 3CO2(g)2Fe2O3(s) + 3C(s)Manufacture of iron: a reduction of Fe

Page 10: Chapter 4 Reactions in Aqueous Solution

1. An atom in its elemental state has an oxidation number of 0.

Rules for Assigning Oxidation Numbers

Oxidation Number (State): A value which indicates whether an atom is neutral, electron-rich, or electron-poor.

Na H2 Br2 S Ne

Oxidation number 0

Page 11: Chapter 4 Reactions in Aqueous Solution

2. A monatomic ion has an oxidation number identical to its charge.

Na1+

+1

Ca2+

+2

Al3+

+3

Cl1-

-1

O2-

-2

Page 12: Chapter 4 Reactions in Aqueous Solution

b) Oxygen usually has an oxidation number of -2.

H O1-

-2+1

HH Ca

-1-1 +2

3. An atom in a polyatomic ion or in a molecular compound usually has the same oxidation number it would have if it were a monatomic ion.a) Hydrogen can be either +1 or -1.

OH O

-1+1 -1

HH O

+1+1 -2

H

+1

Page 13: Chapter 4 Reactions in Aqueous Solution

H Cl

+1 -1

c) Halogens usually have an oxidation number of -1.3.

ClCl O

+1+1 -2

Page 14: Chapter 4 Reactions in Aqueous Solution

Cr2O72-

-2+1 x

4. The sum of the oxidation numbers is 0 for a neutral compound and is equal to the net charge for a polyatomic ion.

x = +6

2(x) + 7(-2) = -2 (net charge)

H2SO3

x -2

x = +4

2(+1) + x + 3(-2) = 0 (net charge)

Page 15: Chapter 4 Reactions in Aqueous Solution

ExampleDetermine the oxidation number for each

atom in the following compounds/moleculesCO2

CCl4

CoSO4

K2O2

Page 16: Chapter 4 Reactions in Aqueous Solution

Oxidation: losing one or more electrons decreasing in oxidation number Reducing agent

2Fe23O2(g)+4Fe(s) O3 (s)

+30

oxidation

reduction

-20

Reduction: gaining one or more electron increasing in oxidation number

Oxidizing agent

Page 17: Chapter 4 Reactions in Aqueous Solution

Reducing Agent

Causes reductionLoses one or more electronsUndergoes oxidationOxidation number of atom increases

Oxidizing Agent

•Causes oxidation •Gains one or more electrons•Undergoes reduction•Oxidation number of atom decreases

Page 18: Chapter 4 Reactions in Aqueous Solution

ExampleIdentify each of the following as

1) oxidation or 2) reduction.

__A. Sn(s) Sn4+(aq) + 4e−

__B. Fe3+(aq) + 1e− Fe2+(aq)__C. Cl2(g) + 2e− 2Cl-(aq)

18

Page 19: Chapter 4 Reactions in Aqueous Solution

Writing Oxidation and Reduction Reactions

Write the separate half oxidation and reduction reactions for the following equation.

2Cs(s) + F2(g) 2CsF(s)

3 Na(l) + AlCl3(l) 3 NaCl(l) + Al(l)

19

Page 20: Chapter 4 Reactions in Aqueous Solution

2Ag1+(aq) + Cu(s)2Ag(s) + Cu2+(g)

Cu2+(aq) + 2Ag(s)Cu(s) + 2Ag1+(g)

Which one of these reactions will occur?

Page 21: Chapter 4 Reactions in Aqueous Solution

Fe2+(aq) + Cu(s)Fe(s) + Cu2+(aq)

Page 22: Chapter 4 Reactions in Aqueous Solution

Elements that are higher up in the table are more likely to be oxidized.

Thus, any element higher in the activity series will reduce the ion of any element lower in the activity series.

Page 23: Chapter 4 Reactions in Aqueous Solution

2Ag1+(aq) + Cu(s)2Ag(s) + Cu2+(g)

Cu2+(aq) + 2Ag(s)Cu(s) + 2Ag1+(g)

Which one of these reactions will occur?

Page 24: Chapter 4 Reactions in Aqueous Solution

ExamplePredict whether the following redox reactions

will occurred or not. If so, predict the products

Zn(s) + FeCl2(aq)

Ni(s) + Mg(NO3)2(aq)

Page 25: Chapter 4 Reactions in Aqueous Solution

If the unknown concentration is the potassium permanganate solution, MnO4

1-, it can be slowly added to a known amount of oxalic acid, H2C2O4, until a faint purple color persists.

Titration: A procedure for determining the concentration of a solution by allowing a carefully measured volume to react with a solution of another substance (the standard solution) whose concentration is known.

5H2C2O4(aq) + 2MnO41-(aq) + 6H1+(aq)

10CO2(g) + 2Mn2+(aq) + 8H2O(l)

Page 26: Chapter 4 Reactions in Aqueous Solution

5H2C2O4(aq) + 2MnO41-(aq) + 6H1+(aq)

10CO2(g) + 2Mn2+(aq) + 8H2O(l)

A solution is prepared with 0.2585 g of oxalic acid, H2C2O4. 22.35 mL of an unknown solution of potassium permanganate are needed to titrate the solution. What is the concentration of the potassium permanganate solution?

Page 27: Chapter 4 Reactions in Aqueous Solution

Moles ofH2C2O4

Mass ofH2C2O4

Moles ofKMnO4

Molarity ofKMnO4

Mole Ratio

Molarity of KMnO4

Molar Mass of H2C2O4

Page 28: Chapter 4 Reactions in Aqueous Solution

ExampleA 0.0484M standard solution of potassium

permanganate was titrated against 25.00mL of an iron (II) sulfate solution. The equivalence point, as indicated by a faint pink color, was reached when 15.50mL of potassium permanganate solution had been added. Calculate the concentration of the iron (II) sulfate solution