Chapter 3b Chemical Formulae

Embed Size (px)

Citation preview

  • 8/8/2019 Chapter 3b Chemical Formulae

    1/38

    ChemicalChemicalFormulaeFormulae

  • 8/8/2019 Chapter 3b Chemical Formulae

    2/38

    Chemical formula is a representation

    of a chemical substance.

    NH3Each ammonia molecule consists of 1

    nitrogen atom & 3 hydrogen atoms.

    Number of

    hydrogen atoms

    Types of atoms

  • 8/8/2019 Chapter 3b Chemical Formulae

    3/38

    Based on chemical formula, we

    know

    the composition of a substance

    the elements that make up thesubstance.

    the ratio ornumber of atoms of

    each element in the substance.

  • 8/8/2019 Chapter 3b Chemical Formulae

    4/38

    Compound Chemical

    Formula

    Elements

    present

    Ratio of numbers

    of atom

    Carbon

    dioxide

    CO2

    Water H2O

    Ammonia NH3

    Sulphuric

    acidH2SO4

    Magnesium

    hydroxide

    Mg(OH)2

  • 8/8/2019 Chapter 3b Chemical Formulae

    5/38

    Molecular FormulaMolecular Formula

    Shows the actual number of

    atoms of each element present in

    one molecule of the compound.

  • 8/8/2019 Chapter 3b Chemical Formulae

    6/38

    Empirical FormulaEmpirical Formula

    Gives the simplest whole number

    ratio of atoms of each elements

    present in the compound.

  • 8/8/2019 Chapter 3b Chemical Formulae

    7/38

    Example :

    Hexene :

    Molecular formula : C6H12.

    Empirical formula : CH2.

  • 8/8/2019 Chapter 3b Chemical Formulae

    8/38

    Example :

    Dinitrogen tetraoxide :

    Molecular formula : N2O4.

    Empirical formula : NO2.

  • 8/8/2019 Chapter 3b Chemical Formulae

    9/38

    Example :

    Glucose :

    Molecular formula : C6H12O6.

    Empirical formula : ?

  • 8/8/2019 Chapter 3b Chemical Formulae

    10/38

    Example :

    Ethanoic acid :

    Molecular formula : CH3COOH.

    Empirical formula : ?

  • 8/8/2019 Chapter 3b Chemical Formulae

    11/38

    Example :

    Vitamin C :

    Molecular formula : C6H8O6.

    Empirical formula : ?

  • 8/8/2019 Chapter 3b Chemical Formulae

    12/38

    Example :

    Carbon dioxide :

    Molecular formula : CO2.

    Empirical formula : ?

  • 8/8/2019 Chapter 3b Chemical Formulae

    13/38

    Empirical Formula Molecular Formula

    Similarities

    Both show the elements present in the

    compound.

    Both show the ratio ofatoms of each

    elementin the compound.

  • 8/8/2019 Chapter 3b Chemical Formulae

    14/38

    Empirical Formula Molecular Formula

    Differences

    Shows the simplest

    ratio ofatoms of

    each elements in

    a compound.

    Shows the actual

    ratio ofatoms of

    each elements in

    a molecule.

  • 8/8/2019 Chapter 3b Chemical Formulae

    15/38

    Determining Empirical FormulaeDetermining Empirical Formulae

    By experiments.

    Steps :

    1. Find the mass of each element

    2. Convert to moles of atoms

    3. Find the simplest ratio of moles

  • 8/8/2019 Chapter 3b Chemical Formulae

    16/38

    Example 1

    1.08 g of aluminium combines chemically

    with 0.96 g oxygen to form an oxide.

    What is the empirical formula of theoxide ?

    [ Relative atomic mass: O, 16 ; Al, 27 ]

  • 8/8/2019 Chapter 3b Chemical Formulae

    17/38

    Example 2

    1.69 g of iron combines chemically

    with 0.72 g of oxygen.

    Find the empirical formula of the oxide.[ Relative atomic mass: O, 16 ; Fe, 56 ]

  • 8/8/2019 Chapter 3b Chemical Formulae

    18/38

    Example 3

    0.91 g of aluminium burns in air to

    form 1.7 g of aluminium oxide.

    Find the empirical formula of theoxide.

    [ Relative atomic mass: O, 16 ; Al, 27 ]

  • 8/8/2019 Chapter 3b Chemical Formulae

    19/38

    Example 7

    The decomposition of 7.36 g of acompound produces 6.93 g of oxygen.The rest of the mass is hydrogen.

    If the relative molecular mass of thiscompound is 34.0 g, calculate itsmolecular formula.

    [ Relative atomic mass : H, 1 ; O, 16 ]

  • 8/8/2019 Chapter 3b Chemical Formulae

    20/38

    Determining empirical formula of

    Magnesium oxide

    A crucible & its lid are weighed.

    A magnesium ribbon is cleanedwith sand paper remove the oxide layer.

    The ribbon is coiled & is placed

    in the crucible. The content isweighed.

  • 8/8/2019 Chapter 3b Chemical Formulae

    21/38

    The crucible is heated

    strongly without the lid.

    When magnesium starts

    to burn, the crucible is

    covered with its lid.

    Using a pair of tongs, the

    lid is raised a little at

    intervals allow oxygen

    to enter the crucible &react with Mg.

    The crucible is then quickly

    covered with its lid to

    prevent the white fumesfrom escaping. This would

    affect the accuracy of the

    mass obtained.

    When burning is complete,

    the lid is removed & the

    crucible is heated strongly

    for 1 to 2 min.

  • 8/8/2019 Chapter 3b Chemical Formulae

    22/38

    The crucible is

    allowed to cool toroom temperature

    with its lid on.

    The crucible & itscontent is weighed

    again.

    The process of

    heating, cooling &weighing are

    repeated until a

    constant mass is

    obtained ensurethat the reaction is

    complete.

  • 8/8/2019 Chapter 3b Chemical Formulae

    23/38

  • 8/8/2019 Chapter 3b Chemical Formulae

    24/38

    Example 4

    Phosphoric acid has the percentage

    composition as follows :

    H, 3.06% ; P, 31.63% ; O, 65.31%What is the empirical formula of the acid?

    [Relative atomic mass: H, 1; O, 16; P, 31]

  • 8/8/2019 Chapter 3b Chemical Formulae

    25/38

    Example 5

    The percentage composition ofcalcium carbonate :

    Ca, 40% ; C, 12% ; O, 48%

    What is the empirical formula ofcalcium carbonate ?

    [Relative atomic mass: Ca, 40 ; C, 12;

    O, 16]

  • 8/8/2019 Chapter 3b Chemical Formulae

    26/38

    Example 6

    The empirical formula of ethene is(CH3)n. Its molecular mass is 30.

    Calculate the formula of this

    compound.

  • 8/8/2019 Chapter 3b Chemical Formulae

    27/38

    Determining empirical formula of

    copper (II) oxide

    Zinc

    Hydrochloric

    acid

    Combustion tube

    (brown)

  • 8/8/2019 Chapter 3b Chemical Formulae

    28/38

    Mass of combustion tube with porcelain

    dish is weighed. A spatulaful of copper (II) oxide is added

    on the porcelain dish. Weigh again.

    Hydrogen gas is allowed to flow into thecombustion tube to remove air in the tube.

    Function ofanhydrous calcium chloride is

    to dry the hydrogen gas.

  • 8/8/2019 Chapter 3b Chemical Formulae

    29/38

    Air in the combustion tube must be totally

    removed before heating. A mixture ofhydrogen gas & oxygen gas will cause an

    explosion when lighted.

    To determine whether all the air has beenremoved, gas that comes out from small

    hole is collected in a test tube. Gas is

    tested with a lighted wooden splinter. Gas

    burns without pop shows air has beentotally removed.

  • 8/8/2019 Chapter 3b Chemical Formulae

    30/38

    Excess hydrogen gas flows out from small

    hole is burnt to prevent air from enteringthe tube again.

    Copper (II) oxide (black) is heated strongly

    until it turns completely brown (copper). Flame is turn off but the flow of hydrogen

    is continued until it is cool or the hot

    copper produced will react with oxygen

    from the air to form copper (II) oxide again.

  • 8/8/2019 Chapter 3b Chemical Formulae

    31/38

    Mass of combustion tube with copper is

    weighed again. The process ofheating, cooling &

    weighing are repeated until a constant

    mass is obtained. This is to ensure that all

    copper (II) oxide has changed into copper.

    This method applicable for oxides oflow

    reactivity metals : tin (II) oxide, lead (II)

    oxide.

  • 8/8/2019 Chapter 3b Chemical Formulae

    32/38

    Mg + copper (II) oxide ?

    Cannot. Both the reactants & products aresolids & thus the mass of copper & oxygen

    cannot be determined.

    Mg(s) + CuO(s) MgO(s) + Cu(s)

  • 8/8/2019 Chapter 3b Chemical Formulae

    33/38

    Ionic Formulae

    Made up ofpositively-charged ions (cations)& negatively-charged ions (anions).

    Zinc bromide

    Zn2+ Br

    ZnBr2

  • 8/8/2019 Chapter 3b Chemical Formulae

    34/38

    Cation Formula Anion Formula

    Sodium ion Na+ Chloride ion Cl

    Potassium ion K+ Bromide ion Br

    Zinc ion Zn2+ Iodide ion I

    Magnesium ion Mg2+ Oxide ion O2

    Calcium ion Ca2+ Hydroxide ion OH

    Iron (II) ion Fe2+ Sulphate ion SO42

    Iron (III) ion Fe3+ Carbonate ion CO3

    2

    Copper (II) ion Cu2+ Nitrate ion NO3

    Ammonium ion NH 4+ Phosphate ion PO4

    3

  • 8/8/2019 Chapter 3b Chemical Formulae

    35/38

    Construct the chemical formula :

    Sodium chloride

    Iron (II) iodide

    Potassium sulphate

    Ammonium hydroxide

    Copper (II) phosphate

    Zinc carbonate

    Magnesium nitrate

  • 8/8/2019 Chapter 3b Chemical Formulae

    36/38

    Name the ionic compounds :

    AgCl

    Ba(NO3)2

    CaSO4

    K2CO3

    (NH4)3PO4

  • 8/8/2019 Chapter 3b Chemical Formulae

    37/38

    Homework :

    Text book

    Activity 3.9 (P.46)

    Activity 3.10 (P.47)

  • 8/8/2019 Chapter 3b Chemical Formulae

    38/38