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Chapter 30 Capacitance
Capacitors
A device that stores charge (and then energy in electrostatic field) is called a capacitor.
A cup can store water
charge
The capacitance of an isolated conductor
04q
C aV
aaq
rr
qE ˆ
4 20
a
qdr
r
qV
a0
20 44
What is the capacitance of the Earth, viewed as an isolated conducting sphere of radius R=6370km?
Example)1085.8(14.34 12
)1037.6( 6
F710F101.7 4 μ
qC
V ( , , )F F pF
A capacitor consists of A capacitor consists of two conductorstwo conductors a and b of a and b of arbitrary shape: arbitrary shape:
These two conductors are called These two conductors are called platesplates (no matter (no matter what their shapes).what their shapes).
Symbolically, a capacitor is represented as:
CC
CCor
C stands for the capacitance of the capacitor.
The charge q appears on the capacitor plates
There is a potential difference V between the plates
The charge q is always directly proportional to the potential difference V between the plates
VVVq
VCq
capacitance
Remarks :A capacitor is said to be charged if its plates carry equal and opposite charges +q and -q. q is not the net charge on the capacitor, which is zero.
V
qC
Capacitors in Series and Parallel
1. Capacitors connected in 1. Capacitors connected in ParallelParallel ::
CC11
aabb
CC22
Question: If we identify the above capacitors connected in parallel as a single capacitor,
aa bb
CCeqeq
what is its capacitance?
VV
VV
VCqVCq 2211 ,
21 qqq VCeq VCC )( 21
21 CCCeq
i ieq CC
2. Capacitors connected in Series :
CC11
aa bb
CC22
VV22VV11
qqqqqq qq
VVV 21
eqCCC
111
21
VV
qqqqCCeqeq
aa bb
21 CqCq eqCq
iieq CC
11
The capacitance is a geometrical factor that depends on the size, shape and separation of the capacitor plates, as well as the material that occupies the space between the plates.
The SI unit of capacitance is farad :
1 farad = 1 F = 1 coulomb/volt
1 1 F = 10F = 10-6-6 F F 1 pF = 10-12 F
Calculating the capacitanceProcedure: 1.Suppose that the capacitor is charged, with ±q on the two plates respectively. 2. Find the electric field E in the region between the plates.3. Evaluate the potential difference between the positive and negative plates, by using the formula:
sEVVV
d
4.The expected capacitance is then: 4.The expected capacitance is then:
VqC
A Parallel-plate Capacitor :
EEE
0
A
qdEdV
0
A
q
0
d
A
V
qC 0
A Cylindrical Capacitor :A Cylindrical Capacitor :
brar
rLqE ,
2
ˆ)(
0
sEV
d
b
arr
rL
rqˆˆ
2
d
0
a
b
L
qln
2 0
ab
LVqC
ln2 0
The capacitor has length The capacitor has length LL, , and and LL>>>>aa, , bb. .
q
q
L
b
a
A Spherical Capacitor :
brar
rqE ,
4
ˆ2
0
sEV
d
b
arr
r
qdrˆˆ
4 20
ba
q 11
4 0 ab
abVqC
04
Capacitor with Dielectric
We now consider the effect of filling the interior of a capacitor with a dielectric material
The effect of the dielectric material is to reduce the strength of the electric field in its interior from the initial E0 in vacuum to E =E0/ke.
q
-q
AqE 00
dAC /0
AqEE ee 00 /
AqdEdV e 0
dAVqC e //' 0 CC e'
⊕⊕⊕⊕ ⊕⊕⊕⊕ ⊕⊕⊕⊕ q
qq0E q A
Capacitor with Dielectric
1e2e
AA
dd
1 1 0 1/ /e eE E q A
2 2 0 2/ /e eE E q A
0 1 0 20 1 2
1 1/ 2 / 2 ( )
2e ee e
qdV qd A qd A
A
0 1 2
1 2
2 e e
e e
AqC
V d
⊕⊕⊕⊕ ⊕⊕⊕⊕ ⊕⊕⊕⊕ q
qq02E q A
Capacitor with Dielectric
1e 2eAA
dd
1 1 0 1/ 2 /e eE E q A
2 2 0 2/ 2 '/e eE E q A
1 0 12 / eV qd A
0 11
1 2e Aq
CV d
2 0 22 ' / eV q d A
0 22
2
'
2e Aq
CV d
1 2
01 2 ( )
2 e e
C C C
A
d
q q’q q’
-q --q -q’q’
CqqVqU ddd
If the process is continued until a total charge q has been transferred, the total potential energy is:
C
qqqUU
qU
2/C'd'd
2
00
VqVC 2
1)(
2
1 2
Energy storage
Suppose that at the instant t, the capacitor has been charged with charge q', the voltage between its plates is V´.
During the next time interval [t, t+dt], if an additional charge dq' is added on the plates, then the increase of the electrostatic energy is,
CqV dq′
q′ΔV´
Why do we say that the energy is stored in the electric field between the capacitor plates?
Take the parallel-plate capacitor as an example.
dAC 0
charged with q, then: AqE 0
q
q
C
qU
2
2
A
dq
0
2
2
AdA
q2
002
1
ΩE 2
02
1
q
q
2'
CC
UU 2double the volume
double the energy
Why do we say that the energy is stored in the electric field between the capacitor plates?
Take the parallel-plate capacitor as an example.
dAC 0
charged with q, then: AqE 0
q
q
C
qU
2
2
A
dq
0
2
2
AdA
q2
002
1
ΩE 2
02
1
2'
CC
UU 2energy density
202
1E
Ω
Uu
AA 2'
Why do we say that the energy is stored in the electric field between the capacitor plates?
Take the parallel-plate capacitor as an example.
dAC 0
charged with q, then: AqE 0
q
q
C
qU
2
2
A
dq
0
2
2
AdA
q2
002
1
ΩE 2
02
1
2'
CC
UU 2energy density
202
1E
Ω
Uu
AA 2' ?2' UU ?2/' UU
q
q
q2
q2
?2' UU
Energy storage
Charge storage
Electric Potential
Energy storage
Charge storage
Electric field
Energy storage
VqVCqC
U 2
1)(
2
1
2
1 22 ΩEU 202
1
An isolated conducting sphere of radius R carries a charge q.
R
qRqCqU
0
2
022
8)4(22
Example
How much energy is stored?
V
N
iii qVVqU d
2
1
2
1
1
0
1'
2 4
qU dq
R
0
1
2 4
qds
R
2
0
442
1R
R
q
R
q
0
2
8
00
''
4
q qU dq
R
2
0 0
'
8
R
R
q
0
2
8
An isolated conducting sphere of radius R carries a charge q.
Example
How much energy is stored?
202
1E
Ω
Uu udU dE 2
02
1
rRrqrE ,4)( 20
22
0 2 2 40
14 d
2 16R
qU r r
r
R
q
0
2
8
What is the radius b of an imaginary spherical surface such as one thirds of the stored energy lie within it?
bRqU 0
2 243
rrrqb
Rd432 24
022
b
Rrrru d4)( 2
rrqb
Rd8 2
02
bRq 118 02
bRR
11
3
1
23Rb
R
qU
0
2
8
VVqq
e
U
CC e
'2'
2
C
qU ?
If the potential difference between the capacitor plates are the same, the electric fields inside the capacitor are the same also.
AqE 0 0( )eq A qq e
eq
eq
22 ( )''
2 ' 2e
e
qqU
C C
eU
e
U
CC e
'2'
2
C
qU
If the potential difference between the capacitor plates are the same, the electric fields inside the capacitor are the same also.
AqE 0 0( )eq A qq e22 ( )'
'2 ' 2
e
e
qqU
C C
eU
' / eE E
' / eV V 2'( ')
'2
C VU
e
U
Dielectrics and Gauss’ Law
)(
d
00
000
AqE
qAEAE
EbbdEsEV
)(d 0
V
qC
ebEbdE
q
/)( 00
)1/1(0
ebd
A
qsdE
00
A
qE
00
qsdEe
0
A
qE
e 0
Example
e
? C
Dielectrics and Gauss’ Law
)(
d
00
000
AqE
qAEAE
A dielectric slab is inserted,
)()( d 000 AqAqEqqAE
q ’ is induced surface charge.
A
q
A
q
A
q
A
qEE
eee 0000
0 ,
)11
( e
/d0 eqAE
d0 qAEe
Gauss’ law should be amended as:
kkee instead of instead of
. . The charge The charge qq contained within the Gauss surface contained within the Gauss surface is taken to be the is taken to be the free chargefree charge only. only.
Dielectrics and Gauss’ Law
Electric polarization vectorElectric polarization vector
0 ep E
0 + D E p Electric displacement vectorElectric displacement vector
0 0+ eE E
0(1+ ) e E
0 E
'0 qqAdE
')'( 00 qqAdEE
qAdE
00
''0 qAdE
Adp
Adp
qAdpE
)( 00 qAdD
0D
E
0E
e
E
0
ExercisesP695 P695 27 27 ProblemsP 696~699 P 696~699 6, 9, 20, 24 6, 9, 20, 24