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8/7/2019 Chapter 3 partI
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Chapter 3 Independent
Assortment of Genes
Dihybrid Crosses
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Independent Assortment of Genes
What about looking at the inheritance of more then onegene in combination with other genes? How are allelesrecombined in gametes?
Recombination = bringing together of two or more pairsof alleles into new combinations
Recombinant products with new combinations ofparental alleles are generated by:
independent assortment of alleles on nonhomologouschromosomes depending how they line up metaphase I
Crossing over between genes occurs in meiosis I
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Independent assortmentConsequence of independent alignment
of chromosomes in meiotic bivalents
A/A ; B/B x a/a ; b/b
A/a ; B/b
A ; B P
A ; b R
a ; B R
a;b
P
OR
Alternate bivalants
A
Bb B
a aA
b
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Recombination For genes on different (nonhomologous) pairs ofchromosomes, recombinant frequency is always 50%
A/a
B/b
a/a
b/b
A/A
B/B
A
B
a
b
A
B
a
b
A
b
a
B
parental (P) genotypes recombinant (R) genotypes
parental genotypes
meiosis meiosis
meiosis
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What Dihybrid crosses tell us
Alleles at different loci(chromosomes)
segregate independently of one another
Hetrozygous both
In dihybrid meiosis, 50% recombinants
indicates either that genes are on different
chromosomes or that they are far apart on
the same chromosome. Predictable ratios for progeny of dihybrids
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Dihybrid testcross
Best way to study recombination is in adihybrid testcross
only dihybrid produces recombinant genotypes
all homozygous recessive tester gametes alike
Typical 1:1:1:1 ratio a result of independentassortment in dihybrid
Observed by Mendel in testcrosses with twopairs of traits
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Dihybrid testcross (1) Determines genotype of dihybrid by
crossing to homozygous recessive
testerA/A ; b/b x a/a ; B/B
A/a ; B/b x a/a ; b/b testcross
Parental
F1
F1 gametes
tester
gametes
a ; b
progeny
proportions
progeny
phenotypes
A ; B A/a ; B/b AB
A ; b A/a ; b/b A b
a ; B a/a ; B/b a B
a ; b a/a ; b/b a b
1:1:1:1
ratio
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Dihybrid selfing Cross between two A/a ; B/b dihybrids
recombination occurs in both members of cross
recombination frequency is 50%
A ; B A ; b a ; B a ; b
A ; B A/A ; B/B A/A ; B/b A/a ; B/B A/a ; B/b
A ; b A/A ; B/b A/A ; b/b A/a ; B/b A/a ; b/b
a ; B A/a ; B/B A/a ; B/b a/a ; B/B a/a ; B/b
a ; b A/a ; B/b A/a ; b/b a/a ; B/b a/a ; b/b
Ratio: 9 A/ ; B/ 3 A/ ; b/b 3 a/a ; B/ 1 a/a ; b/b
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Deducing genotypes from ratios
Genetic analysis works in two directions predict genotypes in offspring
determine genotypes of parents in cross
Specific expectations, e.g., 1:1:1:1 and 9:3:3:1
can be used to deduce genotypes
Testcross example:
Phenotype # observed
A/ ; B/ 310
A/ ; b/b 295
a/a ; B/ 305
a/a ; b/b 290
The observed results are
close to 1:1:1:1, allowingthe deduction that the
tested genotype was a
dihybrid.
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Read text pg 89-109
Try these problems
Problem #1 page 121
Problem #9 page 121
Problem # 17 page122