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Chapter 24 Inductance and Circuit Oscillations
Main Points
• Inductance and Inductors
• Energy in Inductors and in the Magnetic Field
• RL and RC Circuits
• LC Circuits
• RLC Circuits, Damped Oscillations
• Faraday’s Law: Changing current in a circuit will induce emf in that circuit as well as others nearby
24-1 Inductance and Inductor
Self-Inductance: Circuit induces emf in itself
Mutual Inductance: Circuit induces emf in second circuit
Self Inductance
Switch closes
Self-Induction: changing current through a loop inducing an opposing emf in that same loop.
• The flux, therefore, is also proportional to the current.
I• The magnetic field produced by
the current in the loop shown is proportional to that current:
• We define this constant of proportionality between flux and current to be the inductance, L.
LIB
• Combining with Faraday’s Law gives the emf induced by a changing current:
Self-induced emf
The minus sign indicates that—as the law states—the self-induced emf has the orientation such that it opposes the change in current I
The inductance L is a proportionality constant that depends on the geometry of the circuit
SI :H (Wb/A)
(a) The current i is increasing and the self-induced appears along the coil in a direction such that it opposes the increase.
(b) The current i is decreasing and the self-induced emf appears in a direction such that it opposes the decrease.
• The inductance of an inductor (a set of coils in some geometry; e.g., solenoid) then, can be calculated from its geometry alone if the device is constructed from conductors and air (similar to the capacitance of a capacitor).
• If extra material (e.g., an iron core) is added, the inductance will increase (just as adding a dielectric increases capacitance)
• Archetypal inductor is a long solenoid, just as a pair of parallel plates is the archetypal capacitor.
d
A
- - - - -
+ + + +r << l
l
r
N turns
B
The self-inductance of the long, tightly wound solenoid is
The magnetic flux through N turns of wires is
The magnitude of magnetic field in the solenoid is
Solution:
Example: The length and radius of a long, tightly wound solenoid with N turns are l and R respectively. Find its self-inductance?
VnL 2
The magnetic flux through an element area dA in a rectangular region as shown in the figure is
I
I
1R
2R
r
r
l
dr
self-inductance per unite lengthIn series
1 2
Mutual Induction
1BA changing current i1 in
circuit 1 causes a changing flux 21 through circuit 2. Then an induced emf appears in circuit 2 .
The magnetic flux through circuit 2 is
12121 IMΨ
M21 is a constant that depends on the geometry of the two circuits and the magnetic properties of the material.
1IdA
emf induced in circuit 2 by changing currents in circuit 1, through mutual inductance:
emf induced in circuit 1 by changing currents in circuit 2, through mutual inductance:
Example Calculate the mutual inductance for two tightly wound concentric solenoids shown in figure below
Solution:
A current I1 in the inner solenoid sets up a magnetic field B1
the flux 21 is
The mutual inductance is
We can calculate the mutual inductance by assuming that the outer solenoid carries a current I2
The mutual inductances are equal
This is a general result
I
a
2a
23a
Solution:
rd
r
The magnetic flux through the rectangular loop is
The mutual inductance is
The mutual induced emf in the rectangular is
Example: A long, straight wire carrying a current I=I0sint and a rectangular loop whose short edges are parallel to the wire, as shown in the figure. Find the mutual inductance and the mutual induced emf in the rectangular loop.
Kirchhoff’s First Rule“Loop Rule” or “Kirchhoff’s Voltage Law (KVL)”
"When any closed circuit loop is traversed, the algebraic sum of the changes in potential must equal zero."
KVL:
Rules for potential differences across various circuit elements.
ba VV
ba VIRV
ba VC
QV
ab VV
ab VIRV
ab VC
QV
R1
R2I
IR1 IR2 0
Our convention:•We choose a direction for the current and move
around the circuit in that direction.•When a battery is traversed from the negative
terminal to the positive terminal, the voltage increases, and hence the battery voltage enters KVL with a + sign.
•When moving across a resistor, the voltage drops, and hence enters KVL with a - sign.
Modification of Kirchhoff’s loop rule:
In moving across an inductor of inductance L along the presumed direction of the current I, the potential change is = –L dI/dt
Example A device as shown below is constructed from conductors. Find the self-inductance.
Solution Suppose there is a current I in the conductor
a
a
ll
d
I
If there is a magnetic field which is parallel to the axis of the cylindrical shell, Find the current
a
a
ll
d
I
24-2 Energy in Inductors
An RL circuitWork done by the battery
Energy stored in the inductor
Energy lost in a resistor in the form of thermal energy
Loop rule
An inductor is a device for storing energy in a magnetic field.
Where is the Energy Stored?
We can integrate that term to find an expression for UL (starting from zero current)
24-3 Energy in Magnetic Fields
giving the energy density of the magnetic field:
For an ideal solenoid
We can express UL in terms of B(=nI)
Energy is stored in the magnetic field itself (just as in the capacitor / electric field case).
A general result
Energy is located within the electric and magnetic fields themselves
Example A long coaxial cable consists of two thin-walled concentric conducting cylinders with radii a and b. The inner cylinder carries a steady current I, the outer cylinder providing the return path for that current. The current sets up a magnetic field between the two cylinders. (a) Calculate the energy stored in the magnetic field for a length l of the cable.(b) Calculate the self inductance for a length l of the cable.
I I
I I
Solution find H by using Ampere's law
The energy density
The energy
Example An air-filled, closely wound toroidal solenoid with inner radius R1 and outer radius R2 , has
N turns. Its cross-section is rectangular. Find
magnetic-field energy.
By using Ampere’s Law, the magnitude of the magnetic field is
Solution:
The magnetic energy density
hdr r
The volume of a thin cylinder with radius r and thickness dr, as shown in the figure, is
The total magnetic energy
What is the inductance of this toroid?
24-4 Time Dependence in RL Circuits
When the switch K1 is closed, the inductor keeps the current from attaining its maximum value immediately.
Current as a function of time:
An RL circuit
L
R
1k
2k
L
II
The current in an inductor never changes instantaneously, but after the current settles down to a constant value, the inductor plays no role in the circuit
An RL circuit
L
R
1k
2k
L
II
L
R
1k
2k
IIWhen the switch is thrown to K2 the inductor keeps the current from dropping to zero immediately.
Current as a function of time: 0 t
I
RI
0
063.0 I
037.0 I
R
L
time constant
The time constant determines how fast the current changes with time
General rule: inductors resist change in current
• Hooked to current source Initially, the inductor behaves like an open switch. After a long time, the inductor behaves like an ideal wire.
• Disconnected from current source Initially, the inductor behaves like a current source. After a long time, the inductor behaves like an open switch.
Close switch Open switch
Li
demo
ACT At t=0 the switch is thrown from position b to position a in the circuit shown:
(a) I = 0 (b) I = /2R (c) I = 2/R
(a) I0 = 0 (b) I0 = /2R (c) I0 = 2/R
– What is the value of the current I0 immediately after the switch is thrown?
R
a
b
R
L
II
– What is the value of the current Ia long time after the switch is thrown?
– After a long time, the switch is thrown from position a to position b as shown:
(a) I0 = 0 (b) I0 = /2R (c) I0 = 2/R
What is the value of the current I0 just after the switch is thrown?
R
a
b
R
L
II
Just after the switch is thrown, the inductor induces an emf to keep current flowing: emf = L dI/dt (can be much larger than ) However, now there’s no place for the current to go charges build up on switch contacts high voltage across switch gapIf the electric field exceeds the “dielectric strength” (~30 kV/cm in air) breakdown SPARK!
R
a
R
L
II
If after a long time, the switch is opened abruptly from position a instead of being thrown to position b, What happens?
1) At time t = 0 the switch is closed. What is the current through the circuit immediately after the switch is closed?
a) I = 0 b) I = V/R c) I = V/2R
2) What is the current through the circuit a long time after the switch is closed?
a) I = 0 b) I = V/R c) I = V/2R
Initially, the inductor acts like an open switch
After a long time, the inductor acts like an ideal wire,
ACT
ACT At t=0, the switch is thrown from position b to position a as shown:
– Let tI be the time for circuit I to reach 1/2 of its asymptotic current.
– Let tII be the time for circuit II to reach 1/2 of its asymptotic current.
– What is the relation between tI and tII?
(a) tII < tI(b) tII = tI (c) tII > tI
a
bL
II
R
L
II
IR
a
b
L
I
R
I
We must determine the time constants of the two circuits by writing down the loop equations.
tII=2L/RtI=L/2R This confirms that inductors in series add
Time Dependence in RC Circuits
RC circuit with battery and switch
Switch at position a: battery charges capacitor
I
++ +- - -
Loop rule:
Charge as a function of time:
Current as a function of time:
Conclusion:
• Capacitor reaches its final charge(Q=C ) exponentially with time constant = RC.
• Current decays from max ( /R) with same time constant.
Suppose that the switch has been in position a for a long time, the capacity is fully charged, and there is no current. We throw the switch to position b: capacitor discharges through resistor
I
++ +- - -
Charge as a function of time:
Current as a function of time:
The negative sign indicates that the actual current is opposite in direction to the current we assumed
Conclusion:
• Capacitor discharges exponentially with time constant = RC
• Current decays from initial max value (-/R) with same time constant
Basic principle: Capacitor resists rapid change in Q resists rapid changes in V
• Charging (it takes time to put the final charge on) Initially, the capacitor behaves like a wire After a long time, the capacitor behaves like an open switch.
• Discharging Initially, the capacitor behaves like a battery. After a long time, the capacitor behaves like a wire.
ACT At t=0 the switch is thrown from position b to position a in the circuit shown: The capacitor is initially uncharged.– What is the value of the current I0+
just after the switch is thrown?
(a) I0+ = 0 (b) I0+ = /2R (c) I0+ = 2/R
a
b
R
C
II
R
(a) I = 0 (b) I = /2R (c) I > 2/R
– What is the value of the current I after a very long time?
ACT The two circuits shown below contain identical fully charged capacitors at t=0. Circuit 2 has twice as much resistance as circuit 1.
Compare the charge on the two capacitors a short time after t = 0
a) Q1 > Q2
b) Q1 = Q2
c) Q1 < Q2
Initially, the charges on the two capacitors are the same. But the two circuits have different time constants: = RC and 2 = 2RC. Since2 > 1 it takes circuit 2 longer to discharge its capacitor. Therefore, at any given time, the charge on capacitor 2 is bigger than that on capacitor 1.
24-5 Oscillations in LC Circuits
1. Set up the circuit above with capacitor, inductor, resistor, and battery.
2. Let the capacitor become fully charged.
3. Throw the switch from a to b
4. What happens?
Start with a fully charged capacitor
the loop rule:
Simple harmonic oscillator
Q0and are determined from initial conditions.
solution:
•Q0 (initial condition) determines the amplitude of the oscillations
•The frequency of the oscillations is determined by the circuit parameters (L, C)
Here,
It undergoes simple harmonic motion, just like a mass on a spring, with trade-off between charge on capacitor (Spring) and current in inductor (Mass)
ACT At t=0 the capacitor has charge Q0; the resulting oscillations have frequency 0. The maximum current in the circuit during these oscillations has value I0.
– What is the relation between 0 and 2, the frequency of oscillations when the initial charge = 2Q0?
(a) 2 = 1/2 0 (b) 2 = 0 (c) 2 = 20
(a) I = I (b) I = 2I (c) I = 4I
– What is the relation between I0 and I2, the maximum current in the circuit when the initial charge = 2Q0?
LC
+ +
- -Q Q 0
t=0
24-6 Damped Oscillations in RLC Circuits
Loop rule
Damped harmonic oscillatorsolution:
Solution:
Charge equation:
Where
And
Determines the rate of exponential damping
Q0 and are determined from initial conditions.
Comparison of an RLC circuit with and without damping
critical damping
When there is no oscillator behavior
We call this overdamping
The RLC circuit for various values of R.
critical damping
overdamping
24-7 Energy in LC and RLC Circuits
No Resistance
We take initial conditions:
Energy in capacitor
Energy in inductor
Total energy is conserved
In a pure LC circuit, energy is transferred back and forth between the capacitor’s electric field and the inductor’s magnetic field.
a resistor causes energy loss, which shows up as heat.
Resistance is Introduced
The power dissipated in the resistor
The rate of change of the energy in the capacitor and in the inductor
Equal to the power loss in the resistor
Example A 1.5 mF capacitor is charged to 57 V. The charging battery is then disconnected, and a 12 mH coil is connected in series with the capacitor so that LC oscillations occur at time t=0. (a) What is the maximum current in the coil? (b) What is the potential difference VL(t) across the inductor as a function of time?(c) What is the maximum rate (di/dt)max at which the current i changes in the circuit? Assume that the circuit contains no resistance.
Solution
(a)
Example A series RLC circuit has inductance L = 12 mH, capacitance C = 1.6 F, and resistance R = 1.5 . (a) At what time t will the amplitude of the charge oscillations in the circuit be 50% of its initial value?(b) How many oscillations are completed within this time?
Solution
Summary
• Definition of inductance:
• Induced emf:
• emf induced in a second loop:
• Energy in an inductor:
• Energy density of a magnetic field:
LIB
• LC circuit oscillations:
• RLC circuit oscillations:
• RL Circuits
• RC Circuits