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UNIT 1.6 PART 2

Chapter 1.6 Part 2 Equations and Inequalities.pdf

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  • UNIT 1.6 PART 2

  • Example 1.6.6

    21 1 2 3

    3 3 3 3

    If 3,

    1 is undefined

    3

    3 is an ext raneous solu t ion

    1

    x x

    x x x x

    x

    x

    S S

  • : no. of boys

    7 : no. of gir ls

    x

    x

    Example 1.6.7

    A man gave Php 120M to 7 children,giving Php 60M to the boys and thesame amount to the gir ls. In th is way,each boy received Php 5M more thaneach gir l. F ind the number of boys andgir ls.

  • 60: money in M received by each boy

    60: money in M received by each girl

    7

    60 605

    7

    : 7

    x

    x

    x x

    LCD x x

    Example 1.6.7

  • 2

    2

    60 607 7 5

    7

    420 60 60 5 7 , 0,7

    420 60 60 35 5 , 0,7

    5 155 420 0, 0,7

    x x x xx x

    x x x x x

    x x x x x

    x x x

    Example 1.6.7

  • 2

    2

    5 155 420 0, 0,7

    31 84 0

    28 3 0

    28 3

    There are 3 boys and 4 girls.

    x x x

    x x

    x x

    x x

    Example 1.6.7

  • Discriminant

    2

    2

    4

    2

    Discr iminant : 4

    b b acx

    a

    D b ac

  • Discriminant

    2 4

    2

    0 : only one rea l solut ion

    0 : two dist inct rea l solut ions

    0 : two dist inct complex solut ions

    b b acx

    a

    D

    D

    D

  • Example 1.6.8

    2

    2

    Find the na ture of the solu t ions

    of 4 8 3 0.

    4 8 3

    4 64 4 4 3 16 0

    The equa t ion has 2 dist inct

    rea l solu t ions.

    x x

    a b c

    b ac

  • Sum/Product of Roots

    2 2

    Sum:

    4 4

    2 2

    2

    2

    b b ac b b ac

    a a

    b

    a

    b

    a

  • Sum/Product of Roots

    2 2

    22 2

    2

    2 2

    2

    Product :

    4 4

    2 2

    4

    4

    4

    4

    b b ac b b ac

    a a

    b b ac

    a

    b b ac

    a

  • Sum/Product of Roots

    2 22

    2 2

    2

    2

    4

    4

    4

    4

    4

    4

    b b ac

    a

    b b ac

    a

    ac

    a

    c

    a

  • Sum/Product of Roots

    2 0

    Sum of Roots:

    Product of Roots:

    ax bx c

    b

    a

    c

    a

  • Example 1.6.9

    2

    2

    2

    Find the sum and product of the

    roots of 2 3 4.

    2 3 4

    2 3 4 0

    2 3 4

    3 3 4Sum: Product : 2

    2 2 2

    x x

    x x

    x x

    a b c

  • Cubic Equations

    3 2 0

    To solve:

    Factor ing

    Using quadra t ic formula

    ax bx cx d

  • Example 1.6.10

    3 1

    1 31

    2

    1 3 1 31, ,

    2 2

    x

    ix x

    i iS S

  • Division of Polynomials

    Long Division

    Synthet ic Division

  • Example 1.6.11

    3Divide 3 2 by 2 using

    1. long division

    2. synthet ic division

    x x x

  • 23 2

    3 2

    2

    2

    2 1

    1. 2 0 3 2

    2

    2 3

    2 4

    2

    2

    4

    x x

    x x x x

    x x

    x x

    x x

    x

    x

    Quotient

    Remainder

  • 3 2

    2

    2. 2 0 3 2

    2 1 0 3 2

    2 4 2

    1 2 1 4

    2 1 4

    x x x x

    x x r

  • Division of Polynomials

    If a polynomia l is divided

    by we get a quot ien t

    and a remainder .

    P x

    x a Q x

    R

    P x rQ x

    x a x a

    P x x a Q x r

  • 3

    2

    32

    3 2

    3 2 divided by 2

    2 1

    4

    3 2 42 1

    2 2

    3 2 2 2 1 4

    P x x x x

    Q x x x

    r

    x xx x

    x x

    x x x x x

  • Remainder Theorem

    If a polynomial is divided by ,

    the remainder is equal to .

    P x x a

    P a

  • Example 1.6.11

    3

    3

    3

    Use the remainder theorem to

    determine the remainder when

    3 2 is divided by 2.

    3 2

    2 2 3 2 2 8 6 2 4

    4 is the remainder .

    x x x

    P x x x

    P

  • 23 2

    3 2

    2

    2

    2 1

    1. 2 0 3 2

    2

    2 3

    2 4

    2

    2

    4

    x x

    x x x x

    x x

    x x

    x x

    x

    x

    Quotient

    Remainder

  • Factor Theorem

    is a root of the equat ion 0

    if and only if is a factor of .

    a P x

    x a P x

  • Example 1.6.11

    4 3

    4 3

    4 3

    4 3

    Use the factor theorem to determine

    if 1 is a factor of 2 4 1.

    1 1

    Is 1 a solu t ion to 2 4 1 0

    1 2 1 1 4 1 1 2 1 4 1 0

    1 is a factor of 2 4 1.

    x x x x

    x x

    P x x x x

    P

    x x x x

  • Example 1.6.11

    3 2

    3 2

    3 2

    3 2

    3 2

    23

    Using the Factor Theorem, solve the equa t ion

    6 11 6 (Hint : Show tha t 1 is a factor .)

    6 11 6

    6 11 6 0

    Is 1 a factor of 6 11 6 ?

    6 11 6

    1 1 6 1 11 1 6 0

    1 is a factor of

    x x x x

    x x x

    x x x

    x x x x

    P x x x x

    P

    x

    3 2 6 11 6.x x x

  • 3 2

    3 2

    2

    3 2

    2

    6 11 6 1

    1 6 11 6

    1 1 6 11 6

    1 5 6

    1 5 6 0

    5 6 0

    6 11 6 0

    1 5 6 0

    x x x x

    x x x x

    x x r

    x x x

    x x x

  • 3 2

    2

    6 11 6 0

    1 5 6 0

    1 2 3 0

    1 0 2 0 3 0

    1 2 3

    1,2,3

    x x x

    x x x

    x x x

    x x x

    x x x

    S S