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Chapter 16 & 17 Discussion

Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

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Page 1: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Chapter 16 & 17 Discussion

Page 2: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Endo and exo are meaningless without substitutents to provide frame of reference

Meso = identical

Page 3: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

1) Recognize that this is a Diels Alder reaction by the diene and dienophile (on the right)

2) Draw a cyclohexene ring

3) Build models of the possible isomers that could result from the cycloaddition

4) Use resonance to help predict regioisomer

5) Temperature for endo/exo preference.

diene dienophile

Page 4: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

3) Build models of the possible isomers that could result from the cycloaddition

4) Use resonance to help predict regioisomer

5) Temperature for endo/exo preference.

endo

exo

Page 5: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Endo and exo

+ enantiomer + enantiomer

Exo (thermodynamic product)

Endo (kinetic product)

Page 6: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 7: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 8: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

?

1) Recognize that this is a Diels Alder reaction by the diene and dienophile (on the right)

2) Draw a cyclohexene ring

3) Build models of the possible isomers that could result from the cycloaddition

4) Use resonance to help predict regioisomer

5) Temperature for endo/exo preference.

Page 9: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Four possible regioisomers and diastereomers (+ enantiomers)

Page 10: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Resonance contributors show which regioisomers will form

Page 11: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Regiochemistry is established. How about endo or exo?

Page 12: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 13: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

?

Page 14: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

No meta.

Page 15: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 16: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 17: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 18: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Problem:Diels-Alder Reactants?

Page 19: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Flat, cyclic, conjugated pi system and 4n + 2 pi electrons

Page 20: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Aromatic if 2, 6, 10, 14, 18 pi electrons…..Anti-aromatic if 4, 8, 12, 16, ….. pi electrons

If neither then not aromatic or anti-aromatic.

Anti-aromatic more stable than expected.

Anti-aromatic – less stable and likely will not form at all.

Page 21: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 22: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

4 pi electrons. Antiaromatic

Cyclopropenyl anion

Page 23: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Aromatic?

Page 24: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 25: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

6 pi electrons, aromatic

Cyclopentadienyl anion

Page 26: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Aromatic?

Page 27: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 28: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

10 pi electrons aromatic

Lactarius azulene

chamomileYarrow

Azulene

Page 29: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 30: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

aromatic : cyclic, 10 electrons, flat, conjugated

Naphthalene

Page 31: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Why is naphthalene nonpolar and azulene polar?

Azulenenaphthalene

Page 32: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical
Page 33: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Aromatic, anti-aromatic or neither?

Page 34: Chapter 16 & 17 Discussion. Endo and exo are meaningless without substitutents to provide frame of reference Meso = identical

Aromatic, anti-aromatic or neither?

Depends on conformation. If flat and fully conjugated, antiaromatic!!!!

Lower energy conformation (than anti-aromatic) is not flat

8 pi electrons