Chapter 03 - Mesh Analysis

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Fundamental of Electric Circuit : Chapter 3 ; Method of Analysis : Mesh &Nodal

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  • ECE 1131

    Chapter 3 Methods of Analysis

    1

  • Outlines

    Nodal analysis without voltage sources

    Nodal analysis with voltage sources

    Mesh analysis without current sources

    Mesh analysis with current sources

    Nodal analysis by inspection

    Mesh analysis by inspection

    2

  • Nodal Analysis without Voltage Sources

    3

    Nodal analysis is based on KCL.

    It makes use of node voltages as circuit variables.

    Steps to determine node voltages - assume a circuit with n nodes:

    1. Select a node as the reference node.

    Reference node a node with 0 potential.

    2. Assign voltages v1, v2, , vn-1 to the remaining n-1 nodes.

    The voltages are referenced with respect to the reference node.

    3. Apply KCL to each of the n-1 non-reference nodes.

    Use Ohms law to express the branch currents in terms of node voltages.

    4. Solve the resulting simultaneous equations to obtain the unknown node voltages.

  • Example 1

    4

    Obtain node voltages for the circuit shown.

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    Answers:

    v1=-2V

    v2=-14V

  • Example 2

    5

    Find the voltages at the three non-reference nodes.

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    Answers:

    v1=80V

    v2=-64V

    v3=156V

  • Nodal Analysis with Voltage Sources

    6

    Two cases to consider:

    Case 1: A voltage source is connected between a reference node and a non-reference node.

    Set the voltage at the non-reference node equal to the voltage of the voltage source.

    Case 2: A voltage source is connected between two non-reference nodes.

    The two non-reference nodes form a supernode.

    Apply both KCL and KVL to determine the node voltages.

    NOTE:

    Supernode it is formed by enclosing a (dependent/independent) voltage source connected between two non-reference nodes and any elements connected in parallel with it.

  • Example 3 (Fig. 3.7)

    7

    Find the node voltages in the circuit below.

  • Example 4 (approximately same as p.p 3.3

    page 90)

    8

    Find v and i in the circuit below.

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    Answers:

    v=-600mV

    i=4.2A

  • Example 5 (about same as p.p 3.4 page 93)

    9

    Find v1, v2 and v3 in the circuit shown.

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    Answers:

    v1=3.043V

    v2=-6.956V

    v3=652.2mV

  • Mesh Analysis

    10

    A mesh is a loop that does not contain any other loops

    within it.

    Recap: a loop is any closed path with no node pass more than

    once.

    Mesh analysis is only applicable to a circuit that is planar.

    Planar circuit a circuit that can be drawn in a plane with no branches crossing one another; otherwise, it is non-planar.

  • A Planar Circuit

    11

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  • A Non-Planar Circuit

    12

    No way to redraw it and avoid the branches crossing.

    A non-planar circuit can be handled using nodal analysis.

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  • Mesh Analysis without Current Sources

    13

    Mesh analysis is based on KVL.

    It makes use of mesh currents as circuit variables.

    Steps to determine node voltages - assume a circuit with

    n meshes:

    1. Assign mesh currents i1, i2, , in to the n meshes.

    Assume each mesh current flows clockwise.

    2. Apply KVL to each of the n meshes.

    Use Ohms law to express the voltages in terms of the mesh

    currents.

    3. Solve the resulting simultaneous equations to get the mesh

    currents.

  • Example 6

    14

    Calculate the mesh currents, i1 and i2.

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    Answers:

    i1=2A

    i2=0A

  • Example 7

    15

    Find I0 in the circuit shown using mesh analysis.

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    Answers:

    I0=-5A

  • Mesh Analysis with Current Sources

    16

    Two cases to consider:

    Case 1: A current source exists in only one mesh.

    Set the mesh current = current source.

    Case 2: A current source exists between two meshes.

    Create a supermesh by excluding the current source and any

    elements connected in series with it.

    NOTE:

    A supermesh results when two meshes have a (dependent or

    independent) current source in common.

  • Example 8

    17

    Use mesh analysis to determine i1, i2 and i3 in the circuit

    shown.

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    Answers:

    i1=3.474A

    i2=473.7mA

    i3=1.1052A

  • Nodal Analysis by Inspection

    18

    Implemented when all

    sources in the circuit are

    independent current

    sources.

    Convert resistors to

    conductors.

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  • Example 9

    19

    By inspection, obtain the node-voltage equations for the

    circuit below.

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  • Mesh Analysis by Inspection

    20

    Implemented when all sources are independent

    voltage sources.

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  • Example 10

    21

    By inspection, obtain the mesh-current equations for the

    circuit below.

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