Chap04 - Laplace Transforms.ppt

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    Chapter 4

    Laplace Transforms

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    Overall Course Objectives

    Develop the skills necessary to function as anindustrial process control engineer.

    Skills

    Tuning loops

    Control loop design

    Control loop troubleshooting

    Command of the terminology

    Fundamental understanding

    Process dynamics

    Feedback control

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    Laplace Transforms

    Provide valuable insight into process

    dynamics and the dynamics of feedback

    systems.

    Provide a major portion of the terminology

    of the process control profession.

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    Laplace Transforms

    0

    )()()( sFdtetftf stL

    Useful for solving linear differential equations.

    Approach is to apply Laplace transform to

    differential equation. Then algebraically solve for

    Y(s). Finally, apply inverse Laplace transform to

    directly determine y(t).

    Tables of Laplace transforms are available.

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    Method for Solving Linear

    ODEs using Laplace Transforms

    Laplace Domain

    Time Domain

    dy/dt = f(t,y)

    sY(s) - y(0) =

    F(s,Y)Y(s) = H(s)

    y(t) = h(t)

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    Some Commonly Used Laplace

    Transforms

    2222

    2

    2

    2

    1

    )(

    )sin()sin(

    )0()0()()(1

    )0()()(!

    )()(/1

    as

    te

    s

    t

    ffssFsdt

    tfd

    ase

    fsFsdt

    tfd

    s

    nt

    esFtfsStepUnit

    at

    at

    n

    n

    s

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    Initial-Value Theorem

    )(lim)(lim 0 sFstf st

    Allows one to use the

    Laplace transform of afunction to determine

    the initial conditions

    of the function.

    A good consistency

    check

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    Apply Initial- and Final-Value

    Theorems to this Example

    Laplace

    transform of the

    function.

    Apply final-value

    theorem

    Apply initial-

    value theorem

    )4()2(

    2)(

    ssssY

    4

    1

    )40()20()0(

    )0(2)(lim

    tft

    0)4()2()(

    )(2)(lim 0

    tft

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    Partial Fraction Expansions

    32)3()2(

    1

    s

    B

    s

    A

    ss

    s Expand into a term for

    each factor in the

    denominator.

    Recombine RHS

    Equate terms in s and

    constant terms. Solve. Each term is in a form so

    that inverse Laplace

    transforms can be applied.

    )3()2(2)3(

    )3()2(

    1

    ss

    sBsA

    ss

    s

    3

    2

    2

    1

    )3()2(

    1

    ssss

    s

    1BA 123 BA

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    Heaviside Method

    Individual Poles

    1 2

    1 2

    1 2

    ( ) ( )( )

    ( ) ( )( ) ( )

    ( )Equation 4.4.2 :( ) /( )

    i

    n

    n

    n

    i

    i s a

    N s N sY s

    D s s a s a s a

    CC C

    s a s a s a

    N sCD s s a

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    Heaviside Method

    Individual Poles

    1 2

    1 21 2

    3( )

    ( 1)( 2) 1 2

    ( )Equation 4.4.2 :( ) /( )

    3 3

    2; 12 1

    3 2 1( )

    ( 1)( 2) 1 2

    i

    i

    i s a

    s s

    s C CY s

    s s s s

    N sCD s s a

    s s

    C Cs s

    sY s

    s s s s

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    Heaviside Method

    Repeated Poles

    1 2

    2

    ( ) ( )( )

    ( ) ( )

    ( ) ( )

    1 ( ) ( )Equation 4.4.2 :( )

    i

    n

    n

    n

    i n

    i i

    s a

    N s N sY s

    D s s a

    CC C

    s a s a s a

    d s a N sCi ds D s

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    Heaviside Method

    Example with Repeated Poles

    31 22 2

    2 3 2

    1 2

    1 2

    1 1

    2

    ( ) 3( )( ) ( 1) ( 2) 1 ( 1) 2

    3 32; 1

    2 ( 1)

    1 ( ) ( )Equation 4.5.3:

    ( )

    1 3 1 31

    1 2 2 ( 2)

    3( )

    ( 1) (

    i

    s s

    i n

    i i

    s a

    s s

    CN s s C CY sD s s s s s s

    s sC C

    s s

    d s a N sC

    i ds D s

    d s sC

    ds s s s

    sY s

    s

    2

    1 2 1

    2) 1 ( 1) 2s s s s

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    Example of Solution of an ODE

    0)0(')0(2862

    2

    yyydt

    dy

    dt

    yd ODE w/initial conditions

    Apply Laplace transform

    to each term

    Solve for Y(s)

    Apply partial fractionexpansions w/Heaviside

    Apply inverse Laplace

    transform to each term

    ssYsYssYs /2)(8)(6)(2

    )4()2(

    2)(

    ssssY

    )4(4

    1

    )2(2

    1

    4

    1)(

    ssssY

    424

    1)(

    42 tt eety

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    Overview

    Laplace transforms are an effective way tosolve linear ODEs.