Challenging Star Pattern Programs in C Interview Mantra

2/29/12 10 Challenging star pattern programs in C | Interview Mantra

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10 Challenging star pattern programs in Cby U TS A V B A N E R JE E on OCTOB E R 1 9 , 2 009

25 Votes

Computer languages are not as easy as human

languages, they need you to become a

computer yourself, think like a computer and

write an algorithm. Computer programs are

fun if you take them up as a challenge, as

unsolved puzzles. There is lot of fun in taking

up the challenge, understanding the problem,

writing an algorithm, writing a program and

most importantly running the program and

obtaining required output.

Here are few challenging C program questions for you. Let’s see how many of them you

would be able to write without seeing the program solution given below. These questions

are to print patterns using asterisk(star) character. Comment below if you have tougher

pattern questions.

Also read Number Pattern Programs

1. Write a C program to print the following pattern:

*

* *

* * *

* * * *


* *

* * * * * *

* * * * * * * * * *

* * * * * * * * * * *


* *

* *

* * * *

* * * *

* * * * *

* * * *

* * * *

* *

* *


* * * * *

* * * *

* * *

* *

*

* *

* * *

* * * *

* * * * *


*

* * *

* * * * *

* * * * * * *

* * * * * * * * *

* * * * * * *

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* * * * *

* * *

*

* * *

* * * * *


*

* *

* * *

* * * *

* * *

* *

*


* * * * * * * * *

* * * * * * * *

* * * * * *

* * * *

* *

* * * *

* * * * * *

* * * * * * * *

* * * * * * * * *


* * * * * * * * * * * * * * * * *

* * * * * * * * * * * * * *

* * * * * * * * * *

* * * * * *

* * * * * * * * *

* * * * * * *

* * * * *

* * *

*


*

* * *

* * * * *

* * * * * * *

* *

* * * *

* * * * * *

* * * * * * *

* * * * * *

* * * *

* *

* * * * * * *

* * * * *

* * *

*


* * * * * * * * * * * * * * * * * * * * * * * * *

* * * * * *

* * * * * *

* * * * * *

* * *

* * * * * *

* * * * * *

* * * * * *

* * * * * * * * * * * * * * * * * * * * * * * * *




*

* *

* * *

* * * *

Program:

/* This is a simple mirror-image of a right angle triangle */

#include

int main() {

char prnt = '*';

int i, j, nos = 4, s;

for (i = 1; i <= 5; i++) { for (s = nos; s >= 1; s--) { // Spacing factor

printf(" ");

}

for (j = 1; j <= i; j++) {

printf("%2c", prnt);

}

printf("\n");

--nos; // Controls the spacing factor

}

return 0;

}

Dow n loa d Code

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2. Write C program to print the following pattern:

* *

* * * * * *

* * * * * * * * * *

* * * * * * * * * * *

Program:

#include

int main() {

char prnt = '*';

int i, j, k, s, c = 1, nos = 9;

for (i = 1; c <= 4; i++) {

// As we want to print the columns in odd sequence viz. 1,3,5,.etc

if ((i % 2) != 0) {

for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (s = nos; s >= 1; s--) { //The spacing factor

if (c == 4 && s == 1) {

break;

}

printf(" ");

}

for (k = 1; k <= i; k++) {

if (c == 4 && k == 5) {

break;

}


}

printf("\n");

nos = nos - 4; // controls the spacing factor

++c;

}

}

return 0;

}

Dow n loa d Code

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3. Write C program to print the following pattern:

* *

* *

* * * *

* * * *

* * * * *

* * * *



* * * *

* *

* *

Program:

#include

int main() {

char prnt = '*';

int i, j, k, s, p, r, nos = 7;

for (i = 1; i <= 5; i++) {

for (j = 1; j <= i; j++) { if ((i % 2) != 0 && (j % 2) != 0) { printf("%3c", prnt); } else if ((i % 2) == 0 && (j % 2) == 0) { printf("%3c", prnt); } else { printf(" "); } } for (s = nos; s >= 1; s--) { // for the spacing factor

printf(" ");

}

for (k = 1; k <= i; k++) { //Joining seperate figures if (i == 5 && k == 1) { continue; } if ((k % 2) != 0) { printf("%3c", prnt); } else { printf(" "); } } printf("\n"); nos = nos - 2; // space control } nos = 1; // remaining half.. for (p = 4; p >= 1; p--) {

for (r = 1; r <= p; r++) { if ((p % 2) != 0 && (r % 2) != 0) { printf("%3c", prnt); } else if ((p % 2) == 0 && (r % 2) == 0) { printf("%3c", prnt); } else { printf(" "); } } for (s = nos; s >= 1; s--) {

printf(" ");

}

for (k = 1; k <= p; k++) {

if ((k % 2) != 0) {


}

else {

printf(" ");

}

}

nos = nos + 2; // space control

printf("\n");

}

return 0;

}

Dow n loa d Code

Explanation:

This can be seen as an inverted diamond composed of stars. It can be noted that the

composition of this figure follows sequential pattern of consecutive stars and spaces.

In case of odd row number, the odd column positions will be filled up with ‘*’, else a

space will be spaced and vice-versa in case of even numbered row.

In order to achieve this we will construct four different right angle triangles

aligned as per the requirement.

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* * * * *

* * * *

* * *

* *

*

* *

* * *

* * * *

* * * * *

Program:

#include

int main() {

char prnt = '*';

int i, j, s, nos = 0;

for (i = 9; i >= 1; (i = i - 2)) {

for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {

if ((i % 2) != 0 && (j % 2) != 0) {


} else {

printf(" ");

}

}

printf("\n");

nos++;

}



nos = 3;

for (i = 3; i <= 9; (i = i + 2)) { for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {

if ((i % 2) != 0 && (j % 2) != 0) {


} else {

printf(" ");

}

}

nos--;

printf("\n");

}

return 0;

}

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*

* * *

* * * * *

* * * * * * *

* * * * * * * * *

* * * * * * *

* * * * *

* * *

*

* * *

* * * * *

Program:

#include

int main() {

char prnt = '*';

int i, j, k, s, nos = 4;

for (i = 1; i <= 5; i++) { for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {


}

for (k = 1; k <= (i - 1); k++) { if (i == 1) { continue; } printf("%2c", prnt); } printf("\n"); nos--; } nos = 1; for (i = 4; i >= 1; i--) {

for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {


}

for (k = 1; k <= (i - 1); k++) {


}

nos++;

printf("\n");

}

nos = 3;

for (i = 2; i <= 5; i++) { if ((i % 2) != 0) { for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {


}

}

if ((i % 2) != 0) {

printf("\n");

nos--;

}



}

return 0;

}

Dow n loa d Code

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*

* *

* * *

* * * *

* * *

* *

*

Program:

/*

This can be seen as two right angle triangles sharing the same base

which is modified by adding few extra shifting spaces

*/

#include

// This function controls the inner loop and the spacing

// factor guided by the outer loop index and the spacing index.

int triangle(int nos, int i) {

char prnt = '*';

int s, j;

for (s = nos; s >= 1; s--) { // Spacing factor

printf(" ");

}

for (j = 1; j <= i; j++) { //The inner loop


}

return 0;

}

int main() {

int i, nos = 5;

//draws the upper triangle

for (i = 1; i <= 4; i++) { triangle(nos, i); //Inner loop construction nos++; // Increments the spacing factor printf("\n"); } nos = 7; //Draws the lower triangle skipping its base. for (i = 3; i >= 1; i--) {

int j = 1;

triangle(nos, i); // Inner loop construction

nos = nos - j; // Spacing factor

printf("\n");

}

return 0;

}

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* * * * * * * * *

* * * * * * * *

* * * * * *

* * * *

* *

* * * *

* * * * * *

* * * * * * * *

* * * * * * * * *

Program:

#include

int main() {

char prnt = '*';

int i, j, k, s, nos = -1;

for (i = 5; i >= 1; i--) {

for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (s = nos; s >= 1; s--) {

printf(" ");

}

for (k = 1; k <= i; k++) {

if (i == 5 && k == 5) {

continue;



}


}

nos = nos + 2;

printf("\n");

}

nos = 5;

for (i = 2; i <= 5; i++) {

for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (s = nos; s >= 1; s--) {

printf(" ");

}

for (k = 1; k <= i; k++) {

if (i == 5 && k == 5) {

break;

}


}

nos = nos - 2;

printf("\n");

}

return 0;

}

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* * * * * * * * * * * * * * * * *

* * * * * * * * * * * * * *

* * * * * * * * * *

* * * * * *

* * * * * * * * *

* * * * * * *

* * * * *

* * *

*

Program:

#include

int main() {

char prnt = '*';

int i, j, k, s, sp, nos = 0, nosp = -1;

for (i = 9; i >= 3; (i = i - 2)) {

for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) { printf("%2c", prnt); } for (sp = nosp; sp >= 1; sp--) {

printf(" ");

}

for (k = 1; k <= i; k++) { if (i == 9 && k == 1) { continue; } printf("%2c", prnt); } nos++; nosp = nosp + 2; printf("\n"); } nos = 4; for (i = 9; i >= 1; (i = i - 2)) {

for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {


}

nos++;

printf("\n");

}

return 0;

}

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*

* * *

* * * * *

* * * * * * *

* *

* * * *

* * * * * *

* * * * * * *

* * * * * *

* * * *

* *



* * * * * * *

* * * * *

* * *

*

Program:

#include

/*

* nos = Num. of spaces required in the triangle.

* i = Counter for the num. of charcters to print in each row

* skip= A flag for checking whether to

* skip a character in a row.

*

*/

int triangle(int nos, int i, int skip) {

char prnt = '*';

int s, j;

for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) {

if (skip != 0) {

if (i == 4 && j == 1) {

continue;

}

}


}

return 0;

}

int main() {

int i, nos = 4;

for (i = 1; i <= 7; (i = i + 2)) {

triangle(nos, i, 0);

nos--;

printf("\n");

}

nos = 5;

for (i = 1; i <= 4; i++) { triangle(1, i, 0); //one space needed in each case of the formation triangle(nos, i, 1); //skip printing one star in the last row. nos = nos - 2; printf("\n"); } nos = 1; for (i = 3; i >= 1; i--) {

triangle(1, i, 0);


nos = nos + 2;

printf("\n");

}

nos = 1;

for (i = 7; i >= 1; (i = i - 2)) {


nos++;

printf("\n");

}

return 0;

}

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* * * * * * * * * * * * * * * * * * * * * * * * *

* * * * * *

* * * * * *

* * * * * *

* * *

* * * * * *

* * * * * *

* * * * * *

* * * * * * * * * * * * * * * * * * * * * * * * *

Program:

#include

/*

* nos = Num. of spaces required in the triangle.

* i = Counter for the num. of characters to print in each row

* skip= A flag for check whether to

* skip a character in a row.

*

*/



Like

Sort by popular now

int triangle(int nos, int i, int skip) {

char prnt = '*';

int s, j;

for (s = nos; s >= 1; s--) {

printf(" ");

}

for (j = 1; j <= i; j++) { if (skip != 0) { if (i == 9 && j == 1) { continue; } } if (i == 1 || i == 9) { printf("%2c", prnt); } else if (j == 1 || j == i) { printf("%2c", prnt); } else { printf(" "); } } return 0; } int main() { int i, nos = 0, nosp = -1, nbsp = -1; for (i = 9; i >= 1; (i = i - 2)) {


triangle(nosp, i, 1);

triangle(nbsp, i, 1);

printf("\n");

nos++;

nosp = nosp + 2;

nbsp = nbsp + 2;

}

nos = 3, nosp = 5, nbsp = 5;

for (i = 3; i <= 9; (i = i + 2)) {


triangle(nosp, i, 1);

triangle(nbsp, i, 1);

printf("\n");

nos--;

nosp = nosp - 2;

nbsp = nbsp - 2;

}

return 0;

}

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Tagged as: pattern programs

Showing 1 00 of 1 28 comments

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tel l me the code of fol lowing

*

***

****

*****

****

***

*

Abiha_kazm i32

Li k e Repl y3 months ago 4 Li k es

Snehalvjadhav



tel l me the code of fol lowing pattern.

*

* *

* * *

* *

*


#inclu de<stdio.h>

main()

{

int i ,j,k,n;

printf(how many l ines you want to enter:");

scanf("%d",&n);

for(i=1;i<=n;i++)

{

for(j=n;j>=i;j--)

{

printf(" ");

}

for(k=1;k<=i-1;k++)

{

printf("*");

printf(" ");

}

printf("\n");

}

for(i=1;i<=n;i++)

{

for(j=1;j<=i-1;j++)

{

printf(" ");

}

for(k=n;k>=i;k--)

{

printf("*");

printf(" ");

}

printf("\n");

}

}</stdio.h>

Mansi

Li k e Repl y4 months ago i n r epl y to Snehal v jadhav 6 Li k es

give me the code of fol lowing pattern

*

***

*****

*******

abc


void main()

{

int a,b;

a=b=7/2+1;//n=no of rows..n+(n-1)=7(for 4 rows)

for(int i=1;i<=4;i++)

{

for(int j=1;j<=7;j++)

{

i f(j>=a&&j<=b)

print("*");

}

a--;

b++;

}

}

Sarvesh445

Li k e Repl y2 months ago i n r epl y to abc

can u tel l me how to pu t tis pattern

*

* * *

* * * * *

* * *

*

vidhy a


This is code for Loveneesh 's ou tpu t l ike

*****

****

***

**

*

#inclu de

#inclu de

S.V.Ram ana



void main()

{

int i ,j,n;

clrscr();

printf("Enter n valu e");

scanf("%d",&n);

for(i=n;i>0;i--)

{

for(j=1;j<=i;j++)

{

printf("*");

}

printf("\n");

}

getch();

}


how can i print '**'s fou r sides of screen????

example l ike th is............

************************************************************************

* *

* *

* *

* *

* *

* *

* *

* *

* *

* *

*************************************************************************

can any 1 help me??????please.......

Hari


can U give you r Email id I Wil l Send u program solu tion b-coz content not Fit on i t,,,,,,,,,,,,,,,,If Y ou

have A lready Solved th is problem then V ery Good Try...........

Jay esh5101992sapkale

Li k e Repl y1 month ago i n r epl y to Har i

int first_term=1;

void main()

{

int a[100][100];

int c=1,i=0,j=0,k=0,m=0,n=0,x=0;

clrscr();

printf("Enter Rows and colu mns for the squ are matrix \n");

scanf("%d",&n);

x=n;

while(n>=1)

{

for(k=0;k<n;k++) else{a[k+m][n-1+m]="0;}" else{a[m][k+m]="0;}" for(k="1;k<n;k++)"

i f(first_term){a[k+m][n-1+m]="c++;}" i f(first_term){a[m][k+m]="c++;}">=0;k--)

i f(first_term){a[n-1+m][k+m]=c++;}

else{a[n-1+m][k+m]=0;}

for(k=n-2;k>0;k--)

i f(first_term){a[k+m][m]=c++;}

else{a[k+m][m]=0;}

i f(x==n){

first_term=0;}

n-=2;

m++;

}

for(i=0;i<x;i++) ");}="" ;}="" else{printf("="" for(j="0;j&l t;x;j++)" getch();="" i f(a[i][j]="=0)

{printf("" printf("\n");="" {="" }="" ="" *")=""></x;i++)></n;k++)>


Li k e Repl y1 month ago i n r epl y to Jay esh51 01 992sapk al e

Remove al l

last l ine from it



#inclu de <conio.h>

#inclu de <stdio.h>

int first_term=1;

void main()

{

int a[100][100];int c=1,i=0,j=0,k=0,m=0,n=0,x=0;clrscr();

printf("Enter the nu mber of rows and colu mns for the squ are matrix \n");scanf("%d",&n);x=n;

</stdio.h></conio.h>





Hi Hari ,,,,,Check th is code in c langu age..........i f any Error Plz Fix i t....

Code:

#inclu de <conio.h>#inclu de <stdio.h>int first_term=1;void main(){int a[100][100];int

c=1,i=0,j=0,k=0,m=0,n=0,x=0;clrscr();printf("Enter the nu mber of rows and colu mns for the squ are

matrix \n");scanf("%d",&n);x=n;while(n>=1){for(k=0;k<n;k++)if(first_term){a[m]

[k+m]=c++;}else{a[m][k+m]=0;}for(k=1;k<n;k++)if(first_term){a[k+m][n-1+m]=c++;}else{a[k+m][n-

1+m]=0;}for(k=n-2;k>=0;k--)i f(first_term){a[n-1+m][k+m]=c++;}else{a[n-1+m][k+m]=0;}for(k=n-

2;k>0;k--)i f(first_term){a[k+m][m]=c++;}else{a[k+m][m]=0;}i f(x==n){first_term=0;}n-

=2;m++;}for(i=0;i<x;i++){for(j=0;j<x;j++){ ");} ="" ;}}printf("\n");}getch();}="" else{printf("="" i f(a[i]

[j]="=0){printf("" ="" *")=""></x;i++){for(j=0;j<x;j++){ ></n;k++)if(first_term){a[m]

[k+m]=c++;}else{a[m][k+m]=0;}for(k=1;k<n;k++)if(first_term){a[k+m][n-1+m]=c++;}else{a[k+m][n-

1+m]=0;}for(k=n-2;k></stdio.h></conio.h>



sorry th is is not su itable.,,,,I wi l l provide in to parts



void main()

{

for(int i=1;i<=n;i++)//n is any integer valu e

for(int j=1;j<=n;j++)

i f(i==1||i==n||j==1||j==n)

print("*");

}

Sarvesh445

Li k e Repl y2 months ago i n r epl y to Har i


1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

abc


great

Rohitarg91


give me the code of fol lowing character A B C D E F G F E D C B A

A B C D E F F E D C B A

A B C D E E D C B A

A B C D D C B A

A B C C B A

A B B A

A A

pls reply sir code

regards

Raj vishwakarma

Rajsharm aj2ee

Li k e Repl y2 months ago 1 Li k e

#inclu de<stdio.h>

#inclu de<conio.h>

void main()

int i ,j,k,l ,a=1,d=2,x;

char p='A ';

for(i=1;i<=6-1;i++)

{

for(j=1;j<=7-i ;j++)

{

printf("%c",p);

p++;

}

x=a+(i-1)*d;

for(k=1;k<=x;k++)

{

printf(" ");

}

for(l=1;l<=7-i ;l++)

{

Bindu Kam boj



printf("%c",p-1);

p--;

}

printf("\n");

}

getch();

}

</conio.h></stdio.h>

Li k e Repl y1 month ago i n r epl y to Rajshar maj2ee

plz someone tel l me program for fol lowing ou tpu t

* *

* * * *

* * * * * *

* * * * * * * *

* * * * * * * * * *

* * * * * * * *

* * * * * *

* * * *

* *

AT UBH BHAWARE


#inclu de<stdio.h>

main()

{

int n , c, k, space = 1;

printf("Enter nu mber of rows\n");

scanf("%d",&n);

space = n - 1;

for ( k = 1 ; k <= n ; k++ )

{

for ( c = 1 ; c <= space ; c++ )

printf(" ");

space--;

for ( c = 1 ; c <= 2*k-1 ; c++)

printf("*");

printf("\n");

}

space = 1;

for ( k = 1 ; k <= n - 1 ; k++ )

{

for ( c = 1 ; c <= space; c++)

printf(" ");

space++;

for ( c = 1 ; c <= 2*(n-k)-1 ; c++ )

printf("*");

printf("\n");

}

retu rn 0;

}</stdio.h>

Suhani6y adav

Li k e Repl y2 months ago i n r epl y to ATU BH BHAW ARE

plz tel l the code....

1

2 3

4 5 6

7 8 9 10

supantha kum ar pal


#inclu de<stdio.h>

void main()

{

int i ,j,a=1;

for(i=1;i<=4;i++)

{

for(j=1;j<i+1;j++)<br> {

printf("%d",a);

a++;

}

printf("\n");

}

getch();

}</i+1;j++)<br></stdio.h>

Bindu Kam boj



Li k e Repl y1 month ago i n r epl y to supantha k umar pal 1 Li k e

#inclu de<stdio.h>

void main()

{int i ,j,temp=0;

clrscr();

for(i=0;i<n;i++) for(j="0;j&l t;n;j++)" printf("%d",temp);="" temp++;="" {="" }=""></n;i++)></stdio.h>

subbanaidu

Li k e Repl y3 months ago i n r epl y to supantha k umar pal

#inclu de<stdio.h>

main()

{

int n , c, k,p=1;


scanf("%d",&n);

for ( c = 1 ; c <= n ; c++ )

{

for( k = 1 ; k <= c ; k++ )

{ printf("%d",p); p=p+1;

}

printf("\n");

}

retu rn 0;

}</stdio.h>

Dharm u1994


can u please give me a coding of th is pattern?

*

* *

* *

* * * * * * *

jasleen


* *

* *

*

* *

* *

no. of rows to be entered by u ser ?

anony m ous


plz tel l me coding ****** and send me code on my email -id

* * my id [email protected]

* *

******

rashm i


i need simple c program to print l ike a fol lowing pattern

*

* * *

* * * * *

* * *

*

R.Mahalakshm i


class pattern21st

{

pu bl ic static void main ()

{

for(int i = 1 ; i <=5 ; i++)

{

for(int j = 1 ; j <= i ; j++)

{

System.ou t.print( "*" + " " );

}

System.ou t.println();

}

for(int i = 4 ; i >=1 ; i --)

{

for(int j = 1 ; j <= i ; j++)

{


}


}

Dineshrockzzz8



}

}

Li k e Repl y1 month ago i n r epl y to R.Mahal ak shmi 1 Li k e


abcdedcba

abcd dcba

abc cba

ab ab

a a

jy otish



*

* *

* * *

* * * * *

AT UBH BHAWARE


to print as

* * *

* *

*

sai


sir,How can we print stars in a circle?

saurabh chopra


hey i want to print

******

* *

* *

* *

******

tejas chachad

Li k e Repl y1 0 months ago 1 Li k e

#inclu de<stdio.h>#inclu de<conio.h>

int main()

{ int i ,j,k,l ;

for(j=0;j<=5;j++)

printf("*");

for(i=0;i<=2;i++) {

printf("\n\n");

for(k=0;k<=1;k++)

printf("* ");

}

printf("\n\n");

for(l=0;l<=5;l++)

printf("*"); getch();

}</conio.h></stdio.h>

ankita srivastava

Li k e Repl y6 day s ago i n r epl y to tejas chachad 1 Li k e

plz help mi to write ths pattern program..

*****************

* *

* *

****** ******

1 * *

* *

**** ****

* *

***********

pratik

Li k e Repl y1 1 months ago 1 Li k e

*

* *

* *

* * * * * *

Pram od

Li k e Repl y1 y ear ago 1 Li k e

m athapelo



8 Write a separate algorithm for a program to ou tpu t each of the fol lowing patterns

[N ote: There are fou r triangles of stars label led (a) (b) (c) (d). Each triangle consists of ten l ines of stars.

Starting from l ine 1 to 10, the nu mber of stars

ei ther increases by 1 from 1 to 10

or decreases by 1 from 10 to 1]:

(a) (b) (c) (d)

* ********** ********** *

** ********* ********* **

*** ******** ******** ***

**** ******* ******* ****

***** ****** ****** *****

****** ***** ***** ******

******* **** **** *******

******** *** *** ********

********* ** ** *********

********** * * **********


A s the au thor of the post , I wou ld l ike to requ est everyone not to ask for ready made codes as I am strictly

against spoon feeding. Please try ou t the problem you rsel f post you r code in pastebin.com n refer u s the l ink so

that we can veri fy you r code, and help you solve the riddle.

Thanking Y ou

Utsav Banerjee

Utsav Banerjee


tel l me the code of th is

1

2 3

4 5 6

7 8 9 10

Sahil


#inclu de<stdio.h>

void main()

{

int i ,j,a=1;

for(i=1;i<=4;i++)

{

for(j=1;j<i+1;j++) a++;="" getch();="" printf("%d",a);="" printf("\n");="" {="" }="" }="" =""></i+1;j++)>

</stdio.h>

Bindu Kam boj

Li k e Repl y1 month ago i n r epl y to Sahi l

The credit of th is post goes to Utsav Banerjee.. Good work Utsav!

Editor,

Interview Mantra

sridhar

Li k e Repl y2 y ear s ago 1 Li k e

please tel l me the c code for the fol lowing pattern

* * * * *

* * * *

* * *

* *

*

Haem obindium

Li k e Repl y5 day s ago

want in java programming...

Aarthi

Li k e Repl y1 w eek ago

plz tel l me the code for

*******

*******

***

*

***

*******

Ridzi0207

Li k e Repl y1 month ago

#inclu de<stdio.h>

#inclu de<conio.h>

void main()

{

ankita srivastava



int i ,j,k,l ,m,n,o;{

for(i=0;i<=1;i++){printf("\n");

for(j=0;j<=6;j++)

printf("*");}for(k=0;k<=1;k++){printf("\n");for(l=0;l<=1+k;l++)printf(" ");for(m=0;m<=2-

2*k;m++)printf("*");}printf("\n ***\n");for(o=0;o<=6;o++){printf("*");}}getch();}</conio.h>

</stdio.h>

Li k e Repl y5 day s ago i n r epl y to Ri dzi 0207

*

* *

*

* * * *

*

* *

*

* * * * * * * *

*

* *

*

* * * *

*

* *

*Plz tel l the code to get th is pattern

Nkkoolguy


Give me the code of fol lowing pattern :

when we inpu t : 3

6

5 4

3 2 1

Bhom it Davara


#inclu de<stdio.h>

void main()

{

int i ,j,a=6;

for(i=1;i<=3;i++)

{

for(j=1;j<i+1;j++)<br> {

printf("%d",a );

a--;

}

printf("\n");

}

getch();

}</i+1;j++)<br></stdio.h>

Bindu Kam boj

Li k e Repl y1 month ago i n r epl y to Bhomi t Dav ar a

please giv me the code for fol lowing pattern!

1

11

21

1211

111221

312211

13112221

Ajay

Li k e Repl y2 months ago

Wou ld someone be able to help with creating a hol low triangle in Java looking l ike th is:

----*-------*-*-----*---*---*-----*-*********

Where the - equ als a space. A u ser enters a nu mber and the triangle height = the nu mber.

I have th is code so far bu t I can't get any fu rther. N ot even su re i f I'm on the right track anymore:

http://pastebin.com/rUrKaV W5 Thanks in advance.

Grissar


The drawing didn't come ou t ok. So, here's a photo.

Grissar

Li k e Repl y2 months ago i n r epl y to Gr i ssar

deepak singla




1

01

101

0101

10101


thanx dear

Bschinku


please can you provide the code for fol lowing pattern in C++

H H EEEEE L L OOOOH H E L L O OH H E L

L O OHHHHH EEEEE L L O OH H E L L O OH

H E L L O OH H EEEEE LLLLL LLLLL OOOOO

its a l i ttle distorted bu t you mu st have u nderstood what i am trying to printcan mail me at

SUDHIR14789@gmail .com

Sudhir


#inclu de<stdio.h>

void main()

{

printf("H H EEEEE L L OOOOH H E L L O OH

H E L \n");

printf(" L O OHHHHH EEEEE L L O OH H E L

L O OH\n");

printf(" H E L L O OH H EEEEE LLLLL LLLLL OOOOO\n");

}</stdio.h>

Dsasd

Li k e Repl y1 w eek ago i n r epl y to Sudhi r

so di ff to get!!!

siva


please give me help for printing below pattern.

i f inpu tn is 5 then

1 2 3 4 516 17 18 19 6

15 24 25 20 7

14 23 22 21 8

13 12 11 10 9

Manish Prajapati1991


PLS tel l me code to wether the given strig s pal ioderm or not

KALE SOMNAH


A im :

to find whether given string is pal indrome or not

Inpu t

: accept a string

Ou tpu t

: pal indrome or not

Program :

#inclu de<stdio.h>

int main(void)

{

char st[20],rev[20];

int l=0,i ;

cl rscr();

printf("enter a string");

scanf("%s",&st);

for(;st[l ]!='\0';l++); /*to

find length of a string*/

for(i=0;i<l ;i++) &="" *to="" 2="" ;="" a="" break="" break; ="" bu nny="" compare=""

else="" enter="" for(i="0;i&l t;l ;i++)" i f(i="=l) " i f(st[i ]!="rev[i]) " inpu t ="" lengths=""

loop*="" madam="" not="" of="" original="" ou tpu t:="" pal indrome="" pal indrome");="" printf("not=""

printf("pal indrome");="" rev[i]="st[l -i -1]; " rev[l ]="\0" reverse="" reversed="" srings*="" string=""

string*="" the="" {="" }="" ="" ="" ="" =""></l ;i++)></stdio.h>

Bujji

Li k e Repl y3 months ago i n r epl y to KALE SOMN AH 1 Li k e



#inclu de<stdio.h>

void main()

{

int r=0,x,y ,z;

printf("Enter the nu mber to be checked ");

scanf("%d",&x);

y=x;

while (x!=0)

{

r=(r*10)+(x%10);

x=x/10;

z=r;

}

i f (y==z)

{

printf("the given nu mber is a pal l indrome.");

}

else

{

printf("the given nu mber is not a pal l indrome.");

}

}</stdio.h>

Mallickanurag25

Li k e Repl y5 months ago i n r epl y to KALE SOMN AH

th is is not the optimized code th is wi l l u se more memory

ankur loved


mirror image of th is

*****

****

***

**

*

loveneesh


class pattern1st

{

pu bl ic static void main ()

{

for(int i = 1 ; i <=5 ; i++)

{

for(int j = 1 ; j <= i ; j++)

{


}


}

}

}

Dineshrockzzz8

Li k e Repl y1 month ago i n r epl y to l ov eneesh

#inclu de<stdio.h>

void main()

{

int n , c, k;


scanf("%d",&n);

for ( c = 1 ; c <= n ; c++ )

{

for( k = c ; k <= n ; k++ )

printf("*");

printf("\n");

}

}</stdio.h>

Dharm u1994

Li k e Repl y4 months ago i n r epl y to l ov eneesh

*****

****

***

**

*

loveneesh


Angad tom ar



for(i=n;i>0;i--)

{

printf(" ");

for(j=1;j<=i;j++)

{

printf("*");

}

printf("\n");

}

Li k e Repl y1 month ago i n r epl y to l ov eneesh

how can i print the pattern

*****

****

***

**

*

loveneesh


1

1 4 1

1 3 5 3 1

1 3 5 7 5 3 1

1 3 5 3 1

1 4 1

1

Vjy


i have problem in my codes please sent me and email on asterisk patterns please!!!!!!!!

jevie m ar galaura


code to print the fol lowing pattern:

1

1 3 1

1 3 5 3 1

1 3 5 7 5 3 1

1 3 5 3 1

1 3 1

1

sushant choudhary


above is not exact pattern may b some problem in printing

the pattern is :

there is three spaces and then star in first l ine

in second l ine two spaces then star then one space and again star

in th ird l ine one space one star then three spaces one star

in fou rth l ine seven stars.

jasleen


can u please give me a coding of th is pattern?

*

jasleen


1 1 1 1 1 1 1

1 2 2 1

1 3 3 1

1 4 1

1 3 3 1

1 2 2 1

1 1 1 1 1 1 1

can any one do th is?????????

Rajitha


heloo friends you r mind is very sharp becou se you r programing is very di l iciou s

saurabh


th is is so goood for begainer

am it sisodiaa




ye s th is is perfect .bu t i t wi l l not ru n properly so modify i t now.

ajit sujit


* * * * *

* * * *

* * *

* *

*

Try th is>>>>>

accesscode


#inclu de<stdio.h>

#inclu de<conio.h>

void main()

{

int i ,j,;

cl rscr();

for(i=6;i>0;i--)

{

for(j=1;j<=i;j++)

{

printf("*");

}

printf("\n");

}

getch();

}</conio.h></stdio.h>

Him karjha2042

Li k e Repl y4 months ago i n r epl y to accesscode 1 Li k e

#inclu de

#inclu de

#inclu de

#inclu de

#inclu de

#inclu de

#inclu de

u sing namespace std;

int main()

{

for(int i=1;i<=5;i++)

{

for(int j=1;j<=i;j++)

{

cou t<<"**";

}

cou t<=1;i--)

{

for(int j=i ;j>=1;j--)

{

cou t<<"**";

}

cou t<<endl ;

}

retu rn 0;

}

jadoo


th is is the best for bigners

nitesh


thanks . th is is very helpfu l

Ashu


Hey Su shant Ur Code is Here now ,.....Mahendra(Mayu r)

#inclu de

#inclu de

void main()

{

int i ,j,n;

clrscr();

printf(“\n Enter the nu mber :”);

scanf(“%d”,&n);

for(i=n;i>0;i–)

{

for(j=i ;j<=n;j++)

{

Mahendra



printf("*");

}

printf("\n");

}

for(i=0;i<=n;i++)

{

for(j=i ;j<n-1;j++)

{

printf("*");

}

printf("\n");

}

getch();

}

/*

Enter the nu mber :5

*

**

***

****

*****

****

***

**

*

*/


code for the patern:

1

2 6

3 7 10

4 8 11 13

5 9 12 14 15

here i t goes:

#inclu de

#inclu de

void main()

{

int i ,j,a,n;

clrscr();

printf("\n Enter the no. of l ines to be printed.");

scanf("%d",&n);

for(i=1;i<=n;i++)

{

printf("\n");

a=i;

for(j=1;j<=i;j++)

{

printf("%d ",a);

a=a+n-j;

}

}

getch();

}

Enjoy bu dies...;)

Am an


* * * * *

* *

* *

* * * *

Nikhil


sry dere was problm is pasting d code,,,,,,,,dis is ryt code V IDHY A

#inclu de

int main()

{

int k,m,n,i ,j,l ;

printf("enter the size of the prog:");

scanf("%d",&n);

m=n;

for(j=1;j<=n;j++)

{

i f((j<=n/2+1))

{

k=j*2-1;

for(l=1;ln/2+1)

{

k=m-2;

m=k;

for(i=1;i<=k;i++)

{

printf("*");

}

printf("\n");

}

else

rishav



{

continu e;

}}

retu rn 0;

}


dis is u r code ,,,,,,,,,,,,V IDHY A

#inclu de

int main()

{

int k,m,n,i ,j,l ;

printf("enter the size of the prog:");

scanf("%d",&n);

m=n;

for(j=1;j<=n;j++)

{

i f((j<=n/2+1))

{

k=j*2-1;

for(l=1;ln/2+1)

{

k=m-2;

m=k;

for(i=1;i<=k;i++)

{

printf("*");

}

printf("\n");

}

else

{

continu e;

}}

retu rn 0;

}

rishav


plz tel l me of th is code..

1

12

123

1234

12345

supantha kum ar pal


void main()

{

int i ,j,k=1;

for(i=1;i<=5;i++)

{

for(j=1;j<=k;j++)

{

printf("%d",j);

}

k++;

printf("\n");

}

getch();

}

Sam adhan Nirali


@preethi

here is u r programme

#inclu de

void main()

{

int i ,j;

for(i=1;i<=5;i++)

{

printf("\n");

for(j=1;j<=i;j++)

printf("a ");

}

}

and u r ou t pu t is...

a

a a

a a a

a a a a

a a a a a

supantha kum ar pal


preethi



tel l me the code for

a

a a

a a a

a a a a

a a a a a


here is you r code ,,,,,,,,, shahnawaz

#inclu de

int main()

{

int m,i ,j,k,p;

printf("enter the size of the program");

scanf("%d",&m);

k=p=m;

for(i=0;i<m;i++)

{

for(j=0;j<m;j++)

{

i f(i<=j)

{

printf("%d",p);

p--;

}}

p=k;

printf("\n");

}

retu rn 0;

}

rishav


#inclu de

int main()

{

int m,n,i ,j;

m=6;

n=11;

for(i=0;i<6;i++)

{

for(j=0;j<11;j++)

{

i f(i<5&&j<2)

printf("*");

else i f(i==5)

printf("*");

else

continu e;

}

printf("\n");

}

retu rn 0;

}

here is code for printing...........

**

**

**

**

**

***********

rishav


#inclu de

int main()

{

int m,i ,j;

printf("enter the size of program \n");

scanf("%d",&m);

for(i=0;i<m;i++)

{

for(j=0;j<m;j++)

{

i f(i<=j)

printf("*");

}

printf("\n");

}

retu rn 0;}

rishav


plz tel l me how to print the fol lowing pattern?

* * * * * *

* * * * *

* * * *

* * *

* *

*

m anali



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plz help me to write th is program

54321

5432

543

54

5

shahnawaz


for(j=1;j<=5;j++)

{

for(i=5;i ,=j;i --)

printf('i ");

printf("\n"0;

}

Reply saptapratim Bose

Saptapratim Bose

Li k e Repl y3 months ago i n r epl y to shahnaw az

for(j=1;j<=5;j++)

{

for(i=5;i ,=j;i --)

printf('i ");

printf("\n");

}

Reply saptapratim Bose

Saptapratim Bose

Li k e Repl y3 months ago i n r epl y to Saptapr ati m Bose

* *

* *

*

* *

* *

jy othi


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Challenging Star Pattern Programs in C Interview Mantra