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Cell phones off Open laptops in last row only

Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

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Page 1: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Cell phones off

Open laptops in last row only

Page 2: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Chapter 5

Newton’s Laws of Motion(sections 5.1-5.4)

Page 3: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Reading and Review

Page 4: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Dropping a Package

You drop a package from

a plane flying at constant

speed in a straight line.

Without air resistance,

the package will:

a) quickly lag behind the plane while falling

b) remain vertically under the plane while falling

c) move ahead of the plane while falling

d) not fall at all

Page 5: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

You drop a package from

a plane flying at constant

speed in a straight line.

Without air resistance,

the package will::

a) quickly lag behind the plane while falling

b) remain vertically under the plane while falling

c) move ahead of the plane while falling

d) not fall at all

Both the plane and the package have

the same horizontal velocity at the

moment of release. They will

maintain this velocity in the x-

direction, so they stay aligned.

Follow-up: : what would happen if air resistance is present?

Dropping a Package

Page 6: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

a b

c) both at the same time

A battleship simultaneously fires two shells at two enemy

submarines. The shells are launched with the same

magnitude of initial velocity. If the shells follow the

trajectories shown, which submarine gets hit first ?

Page 7: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

a b

c) both at the same time

A battleship simultaneously fires two shells at two enemy

submarines. The shells are launched with the same

magnitude of initial velocity. If the shells follow the

trajectories shown, which submarine gets hit first ?

The flight time is fixed by the motion in the y-direction. The higher an object goes, the longer it stays in flight. The shell hitting submarine #2 goes less high, therefore it stays in flight for less time than the other shell. Thus,

submarine #2 is hit first.

Follow-up: Did you need to know that they had the same initial speed?

Page 8: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Kinematics: Assumptions, Definitions and Logical

Conclusions• Defined displacement, velocity, acceleration (also

position, distance, speed)...

• Defined scalers (like speed) and vectors (like velocity)

• Laid out assumptions about free-fall

• noticed that 2-dimensional motion is really just two, simultaneous, 1-dimensional motions.

Used this to shoot a monkey, range out a small cannon, etc.

This wasn’t physics. This was preparing the language needed to talk about physics.

What have we done so far?

Page 9: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s Laws

How can we consistently and generally describe the way objects move and

interact?

Page 10: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Isaac Newton1643-1727

Newton in a 1702 portrait by Godfrey KnellerNewton in a 1689 portrait by Godfrey Kneller

Page 11: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Nature and nature's laws lay hid in night;God said "Let Newton be" and all was light.

Newton’s epitaph, Alexander Pope

I do not know what I may appear to the world, but to myself I seem to have been only like a boy playing on the sea-shore, and diverting myself in now and then finding a smoother pebble or a prettier shell than ordinary, whilst the great ocean of truth lay all undiscovered before me.

from a memoir by Newton

Page 12: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Force

Force: push or pull

Force is a vector – it has magnitude and direction

Page 13: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Mass

Mass is the measure of how hard it is to change an object’s velocity.

Mass can also be thought of as a measure of the quantity of matter in an object.

Page 14: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s First Law of Motion

If you stop pushing an object, does it stop moving?

Only if there is friction!

In the absence of any net external force, an object at rest will remain at rest.

In the absence of any net external force a moving object will keep moving at a constant speed in a straight line.

This is also known as the Law of Inertia.

Page 15: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Inertia

Page 16: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s First Law

a) more than its weight

b) equal to its weight

c) less than its weight but more than zero

d) depends on the speed of the puck

e) zero

A hockey puck slides on ice at constant velocity. What is the net force acting on the puck?

Page 17: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

The puck is moving at a constant velocity, and

therefore it is not accelerating. Thus, there must

be no net force acting on the puck.

Newton’s First Law

a) more than its weight

b) equal to its weight

c) less than its weight but more than zero

d) depends on the speed of the puck

e) zero

A hockey puck slides on ice at constant velocity. What is the net force acting on the puck?

Follow-up: Are there any forces acting on the puck? What are they?

Page 18: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

a) a net force acted on it

b) no, or insufficient, net force acted on it

c) it remained at rest

d) it did not move, but only seemed to

e) gravity briefly stopped acting on it

Newton’s First Law

You put your book on

the bus seat next to

you. When the bus

stops suddenly, the

book slides forward off

the seat. Why?

Page 19: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

a) a net force acted on it

b) no, or insufficient, net force acted on it

c) it remained at rest

d) it did not move, but only seemed to

e) gravity briefly stopped acting on it

The book was initially moving forward (because it was

on a moving bus). When the bus stopped, the book

continued moving forward, which was its initial state of

motion, and therefore it slid forward off the seat.

Newton’s First Law

You put your book on

the bus seat next to

you. When the bus

stops suddenly, the

book slides forward off

the seat. Why?

Page 20: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Calibrating force

Two equal weights exert twice the force of one; this can be used for calibration of a spring:

Page 21: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Experiment: Acceleration vs Force

Now that we have a calibrated spring, we can do more experiments.

Acceleration is proportional to force:

Page 22: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Experiment: Acceleration vs Mass

Acceleration is inversely proportional to mass:

Page 23: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s Second Law of Motion

Combining these two observations gives

Or, more familiarly,

Acceleration is proportional to force:

Acceleration is inversely proportional to mass:

Page 24: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s Second Law of Motion

SI unit for force Newton is defined using this equation as:

1 N is the force required to give a mass of 1 kg an acceleration of 1 m/s2

An object may have several forces acting on it; the acceleration is due to the net force:

Page 25: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Units of force: Newtons

Page 26: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

The weight of an object is the force acting on it due to gravity

Weight: W = Fg = ma = mg vertically downwards

Since , the weight of an object in Newtons is approximately 10 x its mass in kg

Force of Gravity

adult human

700 N ~ 160 lbs. 70 kg

There is no “conversion” from kg to pounds!(Unless you specify what planet you are assuming)

WHERE?

Page 27: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s First and Second LawsIn order to change the velocity of an object – magnitude or direction – a net force is required.

(I)

(II)

What about the bus... From the perspective of someone who didn’t know they were on the bus?

Page 28: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Inertial Reference Frames

Newton’s First and Second Laws do not work in an accelerating frame of reference

In order to change the velocity of an object – magnitude or direction – a net force is required.

(I)

(II)

An inertial reference frame is one in which the first and second laws are true.

Accelerating reference frames are not inertial.Was the bus an inertial reference

frame?Is the earth an inertial reference frame?No, but acceleration due to earth’s rotation around

Its axis (0.034 m/s2), and due to earth’s rotation around sun (smaller) are negligible compared to g; so approximately yes.

Page 29: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Analyzing the forces in a system

Free-body diagrams:

A free-body diagram shows every force acting on an object.

• Sketch the forces

• Isolate the object of interest

• Choose a convenient coordinate system

• Resolve the forces into components

• Apply Newton’s second law to each coordinate direction

Page 30: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Free-body Diagram

Example of a free-body diagram:

Page 31: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s First Law a) there is a net force but the book has too

much inertia

b) there are no forces acting on it at all

c) it does move, but too slowly to be seen

d) there is no net force on the book

e) there is a net force, but the book is too heavy to move

A book is lying at

rest on a table.

The book will

remain there at

rest because:

Page 32: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

There are forces acting on the book, but the

only forces acting are in the y-direction.

Gravity acts downward, but the table exerts an

upward force that is equally strong, so the two

forces cancel, leaving no net force.

Newton’s First Law a) there is a net force but the book has too

much inertia

b) there are no forces acting on it at all

c) it does move, but too slowly to be seen

d) there is no net force on the book

e) there is a net force, but the book is too heavy to move

A book is lying at

rest on a table.

The book will

remain there at

rest because:

Page 33: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s Third Law of Motion

Forces always come in pairs, acting on different objects:

If object 1 exerts a force on object 2, then object 2 exerts a force – on object 1.

These forces are called action-reaction pairs.

Page 34: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Some action-reaction pairs

Page 35: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Action-reaction pair?

a) Yes

b) No

Newton’s 3rd: F12 = - F21

action-reaction pairs are equal and opposite, but they act on different bodies

Page 36: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s Third Law of Motion

Although the forces are the same, the accelerations will not be unless the objects have the same mass.

Q: When skydiving, do you exert a force on the earth? Does the earth accelerate towards you?

Is the magnitude of the acceleration of the earth the same as the magnitude of your acceleration?

Page 37: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )
Page 38: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Newton’s Third Law of Motion

Contact forces:

The force exerted by one box on the other is different depending on which one you push.

Assume the mass of the two objects scales with size, and the forces pictured are the same. In which case is the magnitude of the force of box 1 on box 2 larger?

Page 39: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Truck on Frozen Lake

A very large truck sits on a frozen lake. Assume there is no friction between the tires and the ice. A fly suddenly smashes against the front window. What will happen to the truck?

a) it is too heavy, so it just sits there

b) it moves backward at constant speed

c) it accelerates backward

d) it moves forward at constant speed

e) it accelerates forward

Page 40: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

When the fly hit the truck, it exerted a force on the truck

(only for a fraction of a second). So, in this time period,

the truck accelerated (backward) up to some speed.

After the fly was squashed, it no longer exerted a force,

and the truck simply continued moving at constant

speed.

Truck on Frozen Lake

A very large truck sits on a frozen lake. Assume there is no friction between the tires and the ice. A fly suddenly smashes against the front window. What will happen to the truck?

a) it is too heavy, so it just sits there

b) it moves backward at constant speed

c) it accelerates backward

d) it moves forward at constant speed

e) it accelerates forward

Follow-up: What if the fly takes off, with the same speed in the direction from whence it came?

Page 41: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

Contact Force

2m m

F

Two blocks of masses 2m and m

are in contact on a horizontal

frictionless surface. If a force F0

is applied to mass 2m, what is

the force on mass m ?

a) 2F

b) F

c) ½F

d) 1/3F

e) ¼F

Page 42: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

The force F0 leads to a specific

acceleration of the entire system. In

order for mass m to accelerate at the

same rate, the force on it must be

smaller! For the two blocks together,

F0 = (3m)a. Since a is the same for

both blocks, Fm = ma

Contact Force

Two blocks of masses 2m and m

are in contact on a horizontal

frictionless surface. If a force F0

is applied to mass 2m, what is

the force on mass m ?

a) 2F

b) F

c) ½ F

d) 1/3 F

e) ¼ F

2m m

F

Page 43: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

A 71-kg parent and a 19-kg child meet at the center of an ice rink. They place their hands together and push.

(a) Is the force experienced by the child more than, less than, or the same as the force experienced by the parent?

(b) Is the acceleration of the child more than, less than, or the same as the acceleration of the parent? Explain.

(c) If the acceleration of the child is 2.6 m/s2 in magnitude, what is the magnitude of the parent’s acceleration?

Page 44: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )
Page 45: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

On vacation, your 1300-kg car pulls a 540-kg trailer away from a stoplight with an acceleration of 1.9 m/s2

(a) What is the net force exerted by the car on the trailer? (b) What force does the trailer exert on the car? (c) What is the net force acting on the car?

Page 46: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )
Page 47: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )

An archer shoots a 0.022-kg arrow at a target with a speed of 57 m/s. When it hits the target, it penetrates to a depth of 0.085 m.

(a) What was the average force exerted by the target on the arrow? (b) If the mass of the arrow is doubled, and the force exerted by the

target on the arrow remains the same, by what multiplicative factor does the penetration depth change? Explain.

Page 48: Cell phones off Open laptops in last row only. Chapter 5 Newton’s Laws of Motion (sections 5.1-5.4 )